Custom numbering style using the number of Symbols instead of Numbers
Is there any possible way to count by the number of a symbol ?
For instant, if I want to print 4 versions of a letter, I assigned arabic{#1} numbers which shows:
1 2 3 4
What I want is to show like this:
* ** *** ****
Or; different symbols instead of for each number.
for example:
* for 1
# for 2
and etc.
I'm preparing different versions of exam and I want to show version number by symbol instead of number.
Thanks in advance.
xetex symbols numbering counters arabic
asked 15 mins ago
Majid
304
add a comment |
Is there any possible way to count by the number of a symbol ?
For instant, if I want to print 4 versions of a letter, I assigned arabic{#1} numbers which shows:
1 2 3 4
What I want is to show like this:
* ** *** ****
Or; different symbols instead of for each number.
for example:
* for 1
# for 2
and etc.
I'm preparing different versions of exam and I want to show version number by symbol instead of number.
Thanks in advance.
xetex symbols numbering counters arabic
asked 15 mins ago
Majid
304
add a comment |
Is there any possible way to count by the number of a symbol ?
For instant, if I want to print 4 versions of a letter, I assigned arabic{#1} numbers which shows:
1 2 3 4
What I want is to show like this:
* ** *** ****
Or; different symbols instead of for each number.
for example:
* for 1
# for 2
and etc.
I'm preparing different versions of exam and I want to show version number by symbol instead of number.
Thanks in advance.
xetex symbols numbering counters arabic
asked 15 mins ago
Majid
304
Is there any possible way to count by the number of a symbol ?
For instant, if I want to print 4 versions of a letter, I assigned arabic{#1} numbers which shows:
1 2 3 4
What I want is to show like this:
* ** *** ****
Or; different symbols instead of for each number.
for example:
* for 1
# for 2
and etc.
I'm preparing different versions of exam and I want to show version number by symbol instead of number.
Thanks in advance.
xetex symbols numbering counters arabic
xetex symbols numbering counters arabic
asked 15 mins ago
Majid
304
asked 15 mins ago
Majid
304
edited 3 mins ago
asked 15 mins ago
Majid
304
asked 15 mins ago
Majid
304
asked 15 mins ago
Majid
304
304
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
I do not know if this already exists but it is easy to build something of this sort.
documentclass{article}
usepackage{pgffor}
newcommand{nbullets}[1]{%
foreach X in {1,...,#1}
{textbullet}}
begin{document}
3:nbullets{3}, 7:nbullets{7}
renewcommand{labelenumi}{nbullets{value{enumi}}}
begin{enumerate}
item first
item second
item third
item last
end{enumerate}
end{document}
answered 3 mins ago
marmot
85.5k497181
add a comment |
documentclass{article}
newcounter{mycntr}
makeatletter
newcommand{lettersymbols}[1]{%
begingroup
setcounter{mycntr}{0}
loopunlessifnumvalue{mycntr}=#1
mysymbol%
addtocounter{mycntr}{1}
repeat
endgroup
}
makeatother
newcommand{mysymbol}{textasteriskcentered}
begin{document}
setcounter{section}{5}
renewcommand{thesection}{lettersymbols{numbervalue{section}}}
thesection
end{document}
answered 26 secs ago
Christian Hupfer
147k14191381
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I do not know if this already exists but it is easy to build something of this sort.
documentclass{article}
usepackage{pgffor}
newcommand{nbullets}[1]{%
foreach X in {1,...,#1}
{textbullet}}
begin{document}
3:nbullets{3}, 7:nbullets{7}
renewcommand{labelenumi}{nbullets{value{enumi}}}
begin{enumerate}
item first
item second
item third
item last
end{enumerate}
end{document}
answered 3 mins ago
marmot
85.5k497181
add a comment |
I do not know if this already exists but it is easy to build something of this sort.
documentclass{article}
usepackage{pgffor}
newcommand{nbullets}[1]{%
foreach X in {1,...,#1}
{textbullet}}
begin{document}
3:nbullets{3}, 7:nbullets{7}
renewcommand{labelenumi}{nbullets{value{enumi}}}
begin{enumerate}
item first
item second
item third
item last
end{enumerate}
end{document}
answered 3 mins ago
marmot
85.5k497181
add a comment |
I do not know if this already exists but it is easy to build something of this sort.
documentclass{article}
usepackage{pgffor}
newcommand{nbullets}[1]{%
foreach X in {1,...,#1}
{textbullet}}
begin{document}
3:nbullets{3}, 7:nbullets{7}
renewcommand{labelenumi}{nbullets{value{enumi}}}
begin{enumerate}
item first
item second
item third
item last
end{enumerate}
end{document}
answered 3 mins ago
marmot
85.5k497181
I do not know if this already exists but it is easy to build something of this sort.
documentclass{article}
usepackage{pgffor}
newcommand{nbullets}[1]{%
foreach X in {1,...,#1}
{textbullet}}
begin{document}
3:nbullets{3}, 7:nbullets{7}
renewcommand{labelenumi}{nbullets{value{enumi}}}
begin{enumerate}
item first
item second
item third
item last
end{enumerate}
end{document}
answered 3 mins ago
marmot
85.5k497181
answered 3 mins ago
marmot
85.5k497181
answered 3 mins ago
marmot
85.5k497181
answered 3 mins ago
marmot
85.5k497181
85.5k497181
add a comment |
add a comment |
documentclass{article}
newcounter{mycntr}
makeatletter
newcommand{lettersymbols}[1]{%
begingroup
setcounter{mycntr}{0}
loopunlessifnumvalue{mycntr}=#1
mysymbol%
addtocounter{mycntr}{1}
repeat
endgroup
}
makeatother
newcommand{mysymbol}{textasteriskcentered}
begin{document}
setcounter{section}{5}
renewcommand{thesection}{lettersymbols{numbervalue{section}}}
thesection
end{document}
answered 26 secs ago
Christian Hupfer
147k14191381
add a comment |
documentclass{article}
newcounter{mycntr}
makeatletter
newcommand{lettersymbols}[1]{%
begingroup
setcounter{mycntr}{0}
loopunlessifnumvalue{mycntr}=#1
mysymbol%
addtocounter{mycntr}{1}
repeat
endgroup
}
makeatother
newcommand{mysymbol}{textasteriskcentered}
begin{document}
setcounter{section}{5}
renewcommand{thesection}{lettersymbols{numbervalue{section}}}
thesection
end{document}
answered 26 secs ago
Christian Hupfer
147k14191381
add a comment |
documentclass{article}
newcounter{mycntr}
makeatletter
newcommand{lettersymbols}[1]{%
begingroup
setcounter{mycntr}{0}
loopunlessifnumvalue{mycntr}=#1
mysymbol%
addtocounter{mycntr}{1}
repeat
endgroup
}
makeatother
newcommand{mysymbol}{textasteriskcentered}
begin{document}
setcounter{section}{5}
renewcommand{thesection}{lettersymbols{numbervalue{section}}}
thesection
end{document}
answered 26 secs ago
Christian Hupfer
147k14191381
documentclass{article}
newcounter{mycntr}
makeatletter
newcommand{lettersymbols}[1]{%
begingroup
setcounter{mycntr}{0}
loopunlessifnumvalue{mycntr}=#1
mysymbol%
addtocounter{mycntr}{1}
repeat
endgroup
}
makeatother
newcommand{mysymbol}{textasteriskcentered}
begin{document}
setcounter{section}{5}
renewcommand{thesection}{lettersymbols{numbervalue{section}}}
thesection
end{document}
answered 26 secs ago
Christian Hupfer
147k14191381
answered 26 secs ago
Christian Hupfer
147k14191381
answered 26 secs ago
Christian Hupfer
147k14191381
answered 26 secs ago
Christian Hupfer
147k14191381
147k14191381
add a comment |
add a comment |
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