Sstrhsrtj

up vote 1 down vote favorite My new ISP gives me a public IPv6 address with a /56 prefix to play around: 2001:b:c:d:5:6:7:8/56 I would like to create two subnets divided by a linux server like this: internet - fritzbox - server - pc But I need to understand how to propagate a prefix to the internal subnet. So far, I configured the external interface of my server to accept router advertisments and request an IPv6 prefix from the Fritz!Box: /etc/systemd/network/eth1.network [Match] Name=eth1 [Network] DHCP=ipv6 IPv6AcceptRA=yes IPv6PrefixDelegation=dhcpv6 IPForward=yes After a systemctl restart systemd-networkd the externel interface gets an address: ip -6 addr ... inet6 2001:b:e:f:1:2:3:4/64 scope global noprefixroute dynamic Is this correct so far? Also confusing: The prefix of the internet connec...

This page is only for reference, If you need detailed information, please check here

This page is only for reference, If you need detailed information, please check here

This page is only for reference, If you need detailed information, please check here

up vote 0 down vote favorite documentclass{article} usepackage{amsmath, amsfonts, amssymb}% usepackage[lite]{mtpro2} letnotsimeqrelax usepackage{unicode-math} setmainfont{XITS} setmathfont{XITS Math} begin{document} [ A(lambda) = PARENS{begin{matrix} a_{11}(lambda)&a_{12}(lambda) & cdots & a_{1n}(lambda)\ a_{21}(lambda)&a_{22}(lambda) & cdots & a_{2n}(lambda)\ a_{31}(lambda)&a_{32}(lambda) & cdots & a_{3n}(lambda)\ a_{41}(lambda)&a_{42}(lambda) & cdots & a_{4n}(lambda)\ vdots & vdots &{}& vdots \ a_{r1}(lambda)&a_{r2}(lambda) & cdots & a_{rn}(lambda)\ a_{s1}(lambda)&a_{s2}(lambda) & cdots & a_{sn}(lambda)\ a_{t1}(lambda)&a_{t2}(lambda) & cdots & a_{tn}(lambda)\ a_{m1}(lambda)&a_{m2}(lambda) & cdots & a_{mn}...