Writing an awk script that reads variable from cmmand line
I am trying to write an awk script that can read a users input from command line and store it as a variable.
I know that if I compile from command line and do
./myawk.awk -v ID=4 text.sql
ID will be a variable set to 4. However, the input test cases I am given for my script are just
./myawk.awk ID=4 text.sql
The final goal of the script is to take an ID, find any line that begins with
-- ID
and print the following line. What I have so far is
#!/bin/awk -f
{
if ($1 ~/--/ && $2 ~/^ID/){
x = NR+1
}
while (NR <= x){
print $0
}
}
Can someone explain to me how I am able to read the variable ID without altering the line and adding -v before it, as well maybe give me advice on my current awk script.
awk command-line regular-expression variable arguments
asked 17 mins ago
Connor HaleConnor Hale
1
New contributor
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am trying to write an awk script that can read a users input from command line and store it as a variable.
I know that if I compile from command line and do
./myawk.awk -v ID=4 text.sql
ID will be a variable set to 4. However, the input test cases I am given for my script are just
./myawk.awk ID=4 text.sql
The final goal of the script is to take an ID, find any line that begins with
-- ID
and print the following line. What I have so far is
#!/bin/awk -f
{
if ($1 ~/--/ && $2 ~/^ID/){
x = NR+1
}
while (NR <= x){
print $0
}
}
Can someone explain to me how I am able to read the variable ID without altering the line and adding -v before it, as well maybe give me advice on my current awk script.
awk command-line regular-expression variable arguments
asked 17 mins ago
Connor HaleConnor Hale
1
New contributor
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am trying to write an awk script that can read a users input from command line and store it as a variable.
I know that if I compile from command line and do
./myawk.awk -v ID=4 text.sql
ID will be a variable set to 4. However, the input test cases I am given for my script are just
./myawk.awk ID=4 text.sql
The final goal of the script is to take an ID, find any line that begins with
-- ID
and print the following line. What I have so far is
#!/bin/awk -f
{
if ($1 ~/--/ && $2 ~/^ID/){
x = NR+1
}
while (NR <= x){
print $0
}
}
Can someone explain to me how I am able to read the variable ID without altering the line and adding -v before it, as well maybe give me advice on my current awk script.
awk command-line regular-expression variable arguments
asked 17 mins ago
Connor HaleConnor Hale
1
New contributor
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am trying to write an awk script that can read a users input from command line and store it as a variable.
I know that if I compile from command line and do
./myawk.awk -v ID=4 text.sql
ID will be a variable set to 4. However, the input test cases I am given for my script are just
./myawk.awk ID=4 text.sql
The final goal of the script is to take an ID, find any line that begins with
-- ID
and print the following line. What I have so far is
#!/bin/awk -f
{
if ($1 ~/--/ && $2 ~/^ID/){
x = NR+1
}
while (NR <= x){
print $0
}
}
Can someone explain to me how I am able to read the variable ID without altering the line and adding -v before it, as well maybe give me advice on my current awk script.
awk command-line regular-expression variable arguments
awk command-line regular-expression variable arguments
asked 17 mins ago
Connor HaleConnor Hale
1
New contributor
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 17 mins ago
Connor HaleConnor Hale
1
New contributor
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 17 mins ago
Connor HaleConnor Hale
1
New contributor
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 17 mins ago
Connor HaleConnor Hale
1
asked 17 mins ago
Connor HaleConnor Hale
1
1
New contributor
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Connor Hale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "106"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Connor Hale is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f503047%2fwriting-an-awk-script-that-reads-variable-from-cmmand-line%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Connor Hale is a new contributor. Be nice, and check out our Code of Conduct.
Connor Hale is a new contributor. Be nice, and check out our Code of Conduct.
Connor Hale is a new contributor. Be nice, and check out our Code of Conduct.
Connor Hale is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f503047%2fwriting-an-awk-script-that-reads-variable-from-cmmand-line%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
