Defining math functions
1
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult}
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
letz7pgfmathresult
z7 result is {z7}
%4. PLEASE point me to relevant documentation!
end{document}
pgfmathparse
edited 6 mins ago
marmot
101k4116224
asked 7 mins ago
user34241user34241
1362
add a comment |
1
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult}
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
letz7pgfmathresult
z7 result is {z7}
%4. PLEASE point me to relevant documentation!
end{document}
pgfmathparse
edited 6 mins ago
marmot
101k4116224
asked 7 mins ago
user34241user34241
1362
add a comment |
1
1
1
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult}
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
letz7pgfmathresult
z7 result is {z7}
%4. PLEASE point me to relevant documentation!
end{document}
pgfmathparse
edited 6 mins ago
marmot
101k4116224
asked 7 mins ago
user34241user34241
1362
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult}
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
letz7pgfmathresult
z7 result is {z7}
%4. PLEASE point me to relevant documentation!
end{document}
pgfmathparse
pgfmathparse
edited 6 mins ago
marmot
101k4116224
asked 7 mins ago
user34241user34241
1362
edited 6 mins ago
marmot
101k4116224
asked 7 mins ago
user34241user34241
1362
edited 6 mins ago
marmot
101k4116224
edited 6 mins ago
marmot
101k4116224
edited 6 mins ago
marmot
101k4116224
101k4116224
asked 7 mins ago
user34241user34241
1362
asked 7 mins ago
user34241user34241
1362
asked 7 mins ago
user34241user34241
1362
1362
add a comment |
add a comment |
1 Answer
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I am not sure I understand the question. However, if you want to call a macro z7 this does not work because macro names cannot contain numbers. And I had to remove a backslash to arrive at
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult} % <removed before #2
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
%pgfmathparse{z*7}
letzsevenpgfmathresult
z7 result is {zseven}
%4. PLEASE point me to relevant documentation!
end{document}
answered 1 min ago
marmotmarmot
101k4116224
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
I am not sure I understand the question. However, if you want to call a macro z7 this does not work because macro names cannot contain numbers. And I had to remove a backslash to arrive at
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult} % <removed before #2
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
%pgfmathparse{z*7}
letzsevenpgfmathresult
z7 result is {zseven}
%4. PLEASE point me to relevant documentation!
end{document}
answered 1 min ago
marmotmarmot
101k4116224
add a comment |
0
I am not sure I understand the question. However, if you want to call a macro z7 this does not work because macro names cannot contain numbers. And I had to remove a backslash to arrive at
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult} % <removed before #2
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
%pgfmathparse{z*7}
letzsevenpgfmathresult
z7 result is {zseven}
%4. PLEASE point me to relevant documentation!
end{document}
answered 1 min ago
marmotmarmot
101k4116224
add a comment |
0
0
0
I am not sure I understand the question. However, if you want to call a macro z7 this does not work because macro names cannot contain numbers. And I had to remove a backslash to arrive at
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult} % <removed before #2
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
%pgfmathparse{z*7}
letzsevenpgfmathresult
z7 result is {zseven}
%4. PLEASE point me to relevant documentation!
end{document}
answered 1 min ago
marmotmarmot
101k4116224
I am not sure I understand the question. However, if you want to call a macro z7 this does not work because macro names cannot contain numbers. And I had to remove a backslash to arrive at
documentclass[aspectratio=1610]{beamer}
usepackage{amsmath}
begin{document}
deffunction(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
pgfmathparse{3+function(1)}
letzpgfmathresult
z result is z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
defmyfp(#1,#2){pgfmathparse{#1} let#2pgfmathresult} % <removed before #2
myfp(3+ function(1),z)
% /This yields the right answer BUT z Result is z ..... Yields error
%3. Why does the following mess up%
%pgfmathparse{z*7}
letzsevenpgfmathresult
z7 result is {zseven}
%4. PLEASE point me to relevant documentation!
end{document}
answered 1 min ago
marmotmarmot
101k4116224
answered 1 min ago
marmotmarmot
101k4116224
answered 1 min ago
marmotmarmot
101k4116224
answered 1 min ago
marmotmarmot
101k4116224
101k4116224
add a comment |
add a comment |
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