How can i change phpmyadmin password. I tried it. But not work.?
0
First i login to my server using putty.
and this is my server data
uname -or
2.6.32-754.6.3.el6.x86_64 GNU/Linux
.
uname -a
Linux vps-xxx-xxx.example.com 2.6.32-754.6.3.el6.x86_64 #1 SMP Tue Oct 9 17:27:49 UTC 2018 x86_64 x86_64 x86_64 GNU/Linux
.
cat /etc/*elease`
CentOS release 6.10 (Final)
CentOS release 6.10 (Final)
CentOS release 6.10 (Final)
And this is my mysql version.
SELECT VERSION();
5.5.61
And this is mysql user.
select User,Host from mysql.user;
+----------------+-----------+
| User | Host |
+----------------+-----------+
| admin_test | % |
| admin_test | localhost |
| root | localhost |
| roundcube | localhost |
+----------------+-----------+
Then i tried to change mysql password.
1. service mysqld stop
Stopping mysqld: [OK]
.
2. mysqld_safe --skip-grant-tables &
[1] 713
[root@vps-xxx-xxx ~]# 190113 14:44:01 mysqld_safe Logging to '/var/log/mysqld.lo g'.
190113 14:44:01 mysqld_safe Starting mysqld daemon with databases from /var/lib/ mysql
.
3. mysql
Welcome to the MySQL monitor. Commands end with ; or g.
Your MySQL connection id is 1
Server version: 5.5.61 MySQL Community Server (GPL) by Remi
Copyright (c) 2000, 2018, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type 'help;' or 'h' for help. Type 'c' to clear the current input statement.
.
4. UPDATE mysql.user SET Password=PASSWORD('123456qwerty7890') WHERE User='admin_test';
Query OK, 0 rows affected (0.01 sec)
Rows matched: 2 Changed: 0 Warnings: 0
.
5. FLUSH PRIVILEGES;
Query OK, 0 rows affected (0.00 sec)
.
6. exit;
Bye
.
7. mysqladmin -u root -p shutdown
Enter password:
then i enter password = 123456qwerty7890 and it's show
190113 14:48:21 mysqld_safe mysqld from pid file /var/run/mysqld/mysqld.pid ende d
[1]+ Done mysqld_safe --skip-grant-tables
.
8. service mysqld start
Starting mysqld: [ OK ]
Then i tried to access to my phpmyadmin
xx.xxx.xxx.xxx/phpmyadmin
use username = admin_test and password = 123456qwerty7890
but can not login how can i do ?
centos ssh mysql phpmyadmin
asked 2 mins ago
user331368user331368
1
New contributor
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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0
First i login to my server using putty.
and this is my server data
uname -or
2.6.32-754.6.3.el6.x86_64 GNU/Linux
.
uname -a
Linux vps-xxx-xxx.example.com 2.6.32-754.6.3.el6.x86_64 #1 SMP Tue Oct 9 17:27:49 UTC 2018 x86_64 x86_64 x86_64 GNU/Linux
.
cat /etc/*elease`
CentOS release 6.10 (Final)
CentOS release 6.10 (Final)
CentOS release 6.10 (Final)
And this is my mysql version.
SELECT VERSION();
5.5.61
And this is mysql user.
select User,Host from mysql.user;
+----------------+-----------+
| User | Host |
+----------------+-----------+
| admin_test | % |
| admin_test | localhost |
| root | localhost |
| roundcube | localhost |
+----------------+-----------+
Then i tried to change mysql password.
1. service mysqld stop
Stopping mysqld: [OK]
.
2. mysqld_safe --skip-grant-tables &
[1] 713
[root@vps-xxx-xxx ~]# 190113 14:44:01 mysqld_safe Logging to '/var/log/mysqld.lo g'.
190113 14:44:01 mysqld_safe Starting mysqld daemon with databases from /var/lib/ mysql
.
3. mysql
Welcome to the MySQL monitor. Commands end with ; or g.
Your MySQL connection id is 1
Server version: 5.5.61 MySQL Community Server (GPL) by Remi
Copyright (c) 2000, 2018, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type 'help;' or 'h' for help. Type 'c' to clear the current input statement.
.
4. UPDATE mysql.user SET Password=PASSWORD('123456qwerty7890') WHERE User='admin_test';
Query OK, 0 rows affected (0.01 sec)
Rows matched: 2 Changed: 0 Warnings: 0
.
5. FLUSH PRIVILEGES;
Query OK, 0 rows affected (0.00 sec)
.
6. exit;
Bye
.
7. mysqladmin -u root -p shutdown
Enter password:
then i enter password = 123456qwerty7890 and it's show
190113 14:48:21 mysqld_safe mysqld from pid file /var/run/mysqld/mysqld.pid ende d
[1]+ Done mysqld_safe --skip-grant-tables
.
8. service mysqld start
Starting mysqld: [ OK ]
Then i tried to access to my phpmyadmin
xx.xxx.xxx.xxx/phpmyadmin
use username = admin_test and password = 123456qwerty7890
but can not login how can i do ?
centos ssh mysql phpmyadmin
asked 2 mins ago
user331368user331368
1
New contributor
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
0
0
0
First i login to my server using putty.
and this is my server data
uname -or
2.6.32-754.6.3.el6.x86_64 GNU/Linux
.
uname -a
Linux vps-xxx-xxx.example.com 2.6.32-754.6.3.el6.x86_64 #1 SMP Tue Oct 9 17:27:49 UTC 2018 x86_64 x86_64 x86_64 GNU/Linux
.
cat /etc/*elease`
CentOS release 6.10 (Final)
CentOS release 6.10 (Final)
CentOS release 6.10 (Final)
And this is my mysql version.
SELECT VERSION();
5.5.61
And this is mysql user.
select User,Host from mysql.user;
+----------------+-----------+
| User | Host |
+----------------+-----------+
| admin_test | % |
| admin_test | localhost |
| root | localhost |
| roundcube | localhost |
+----------------+-----------+
Then i tried to change mysql password.
1. service mysqld stop
Stopping mysqld: [OK]
.
2. mysqld_safe --skip-grant-tables &
[1] 713
[root@vps-xxx-xxx ~]# 190113 14:44:01 mysqld_safe Logging to '/var/log/mysqld.lo g'.
190113 14:44:01 mysqld_safe Starting mysqld daemon with databases from /var/lib/ mysql
.
3. mysql
Welcome to the MySQL monitor. Commands end with ; or g.
Your MySQL connection id is 1
Server version: 5.5.61 MySQL Community Server (GPL) by Remi
Copyright (c) 2000, 2018, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type 'help;' or 'h' for help. Type 'c' to clear the current input statement.
.
4. UPDATE mysql.user SET Password=PASSWORD('123456qwerty7890') WHERE User='admin_test';
Query OK, 0 rows affected (0.01 sec)
Rows matched: 2 Changed: 0 Warnings: 0
.
5. FLUSH PRIVILEGES;
Query OK, 0 rows affected (0.00 sec)
.
6. exit;
Bye
.
7. mysqladmin -u root -p shutdown
Enter password:
then i enter password = 123456qwerty7890 and it's show
190113 14:48:21 mysqld_safe mysqld from pid file /var/run/mysqld/mysqld.pid ende d
[1]+ Done mysqld_safe --skip-grant-tables
.
8. service mysqld start
Starting mysqld: [ OK ]
Then i tried to access to my phpmyadmin
xx.xxx.xxx.xxx/phpmyadmin
use username = admin_test and password = 123456qwerty7890
but can not login how can i do ?
centos ssh mysql phpmyadmin
asked 2 mins ago
user331368user331368
1
New contributor
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
First i login to my server using putty.
and this is my server data
uname -or
2.6.32-754.6.3.el6.x86_64 GNU/Linux
.
uname -a
Linux vps-xxx-xxx.example.com 2.6.32-754.6.3.el6.x86_64 #1 SMP Tue Oct 9 17:27:49 UTC 2018 x86_64 x86_64 x86_64 GNU/Linux
.
cat /etc/*elease`
CentOS release 6.10 (Final)
CentOS release 6.10 (Final)
CentOS release 6.10 (Final)
And this is my mysql version.
SELECT VERSION();
5.5.61
And this is mysql user.
select User,Host from mysql.user;
+----------------+-----------+
| User | Host |
+----------------+-----------+
| admin_test | % |
| admin_test | localhost |
| root | localhost |
| roundcube | localhost |
+----------------+-----------+
Then i tried to change mysql password.
1. service mysqld stop
Stopping mysqld: [OK]
.
2. mysqld_safe --skip-grant-tables &
[1] 713
[root@vps-xxx-xxx ~]# 190113 14:44:01 mysqld_safe Logging to '/var/log/mysqld.lo g'.
190113 14:44:01 mysqld_safe Starting mysqld daemon with databases from /var/lib/ mysql
.
3. mysql
Welcome to the MySQL monitor. Commands end with ; or g.
Your MySQL connection id is 1
Server version: 5.5.61 MySQL Community Server (GPL) by Remi
Copyright (c) 2000, 2018, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type 'help;' or 'h' for help. Type 'c' to clear the current input statement.
.
4. UPDATE mysql.user SET Password=PASSWORD('123456qwerty7890') WHERE User='admin_test';
Query OK, 0 rows affected (0.01 sec)
Rows matched: 2 Changed: 0 Warnings: 0
.
5. FLUSH PRIVILEGES;
Query OK, 0 rows affected (0.00 sec)
.
6. exit;
Bye
.
7. mysqladmin -u root -p shutdown
Enter password:
then i enter password = 123456qwerty7890 and it's show
190113 14:48:21 mysqld_safe mysqld from pid file /var/run/mysqld/mysqld.pid ende d
[1]+ Done mysqld_safe --skip-grant-tables
.
8. service mysqld start
Starting mysqld: [ OK ]
Then i tried to access to my phpmyadmin
xx.xxx.xxx.xxx/phpmyadmin
use username = admin_test and password = 123456qwerty7890
but can not login how can i do ?
centos ssh mysql phpmyadmin
centos ssh mysql phpmyadmin
asked 2 mins ago
user331368user331368
1
New contributor
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 mins ago
user331368user331368
1
New contributor
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 mins ago
user331368user331368
1
New contributor
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 mins ago
user331368user331368
1
asked 2 mins ago
user331368user331368
1
1
New contributor
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user331368 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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