Find array length in zsh script
1
Is there a way to find the length of the array *(files names) in zsh without using a for loop to increment some variable?
I naively tried echo ${#*[@]} but it didn't work. (bash syntax are welcome as well)
bash shell-script zsh bash-array
asked 46 mins ago
CristianoCristiano
63
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Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
1
Is there a way to find the length of the array *(files names) in zsh without using a for loop to increment some variable?
I naively tried echo ${#*[@]} but it didn't work. (bash syntax are welcome as well)
bash shell-script zsh bash-array
asked 46 mins ago
CristianoCristiano
63
New contributor
Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
By "length of the array" do you mean its number of elements? And do you want to get this without actually defining this array (*suggest you want to use shell globing mechanism here)?
– jimmij
37 mins ago
Oops, you're right i should have asked the other way around, I'll edit it.
– Cristiano
25 mins ago
@Cristiano: zsh doesn't have anything to do with it.*is not an array in the way you are using it, it is a shell glob. Arrays have nothing to do with your question unless you create an array as Jeff did in his answer. Your question is "How do I find how many files are in the current directory"
– Jesse_b
24 mins ago
@Jess_b But it acts like an array don't you think?echo *[0]in zsh prints the 1st file name...
– Cristiano
5 mins ago
add a comment |
1
1
1
Is there a way to find the length of the array *(files names) in zsh without using a for loop to increment some variable?
I naively tried echo ${#*[@]} but it didn't work. (bash syntax are welcome as well)
bash shell-script zsh bash-array
asked 46 mins ago
CristianoCristiano
63
New contributor
Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Is there a way to find the length of the array *(files names) in zsh without using a for loop to increment some variable?
I naively tried echo ${#*[@]} but it didn't work. (bash syntax are welcome as well)
bash shell-script zsh bash-array
bash shell-script zsh bash-array
asked 46 mins ago
CristianoCristiano
63
New contributor
Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 46 mins ago
CristianoCristiano
63
New contributor
Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 24 mins ago
Cristiano
asked 46 mins ago
CristianoCristiano
63
New contributor
Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 46 mins ago
CristianoCristiano
63
asked 46 mins ago
CristianoCristiano
63
63
New contributor
Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Cristiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
By "length of the array" do you mean its number of elements? And do you want to get this without actually defining this array (*suggest you want to use shell globing mechanism here)?
– jimmij
37 mins ago
Oops, you're right i should have asked the other way around, I'll edit it.
– Cristiano
25 mins ago
@Cristiano: zsh doesn't have anything to do with it.*is not an array in the way you are using it, it is a shell glob. Arrays have nothing to do with your question unless you create an array as Jeff did in his answer. Your question is "How do I find how many files are in the current directory"
– Jesse_b
24 mins ago
@Jess_b But it acts like an array don't you think?echo *[0]in zsh prints the 1st file name...
– Cristiano
5 mins ago
add a comment |
1
By "length of the array" do you mean its number of elements? And do you want to get this without actually defining this array (*suggest you want to use shell globing mechanism here)?
– jimmij
37 mins ago
Oops, you're right i should have asked the other way around, I'll edit it.
– Cristiano
25 mins ago
@Cristiano: zsh doesn't have anything to do with it.*is not an array in the way you are using it, it is a shell glob. Arrays have nothing to do with your question unless you create an array as Jeff did in his answer. Your question is "How do I find how many files are in the current directory"
– Jesse_b
24 mins ago
@Jess_b But it acts like an array don't you think?echo *[0]in zsh prints the 1st file name...
– Cristiano
5 mins ago
1
1
By "length of the array" do you mean its number of elements? And do you want to get this without actually defining this array (
* suggest you want to use shell globing mechanism here)?– jimmij
37 mins ago
By "length of the array" do you mean its number of elements? And do you want to get this without actually defining this array (
* suggest you want to use shell globing mechanism here)?– jimmij
37 mins ago
Oops, you're right i should have asked the other way around, I'll edit it.
– Cristiano
25 mins ago
Oops, you're right i should have asked the other way around, I'll edit it.
– Cristiano
25 mins ago
@Cristiano: zsh doesn't have anything to do with it.
* is not an array in the way you are using it, it is a shell glob. Arrays have nothing to do with your question unless you create an array as Jeff did in his answer. Your question is "How do I find how many files are in the current directory"– Jesse_b
24 mins ago
@Cristiano: zsh doesn't have anything to do with it.
* is not an array in the way you are using it, it is a shell glob. Arrays have nothing to do with your question unless you create an array as Jeff did in his answer. Your question is "How do I find how many files are in the current directory"– Jesse_b
24 mins ago
@Jess_b But it acts like an array don't you think?
echo *[0] in zsh prints the 1st file name...– Cristiano
5 mins ago
@Jess_b But it acts like an array don't you think?
echo *[0] in zsh prints the 1st file name...– Cristiano
5 mins ago
add a comment |
1 Answer
1
active
oldest
votes
1
files=(*)
printf 'There are %d filesn' "${#files[@]}"
or
set -- *
printf 'There are %d filesn' "$#"
You have to name the array first (as I did above with files) or use the built-in array $@ by populating it with the wildcard, as I did in the second example. In the former, the "length" (number of files) of the array is done with the ${#arrayname[@]} syntax. The number of elements inn the built-in array is in $#.
answered 30 mins ago
Jeff SchallerJeff Schaller
41.1k1056131
So the*acts as a regex expression? I thought that it was a special array... although surprise me that there is no such array...
– Cristiano
14 mins ago
wait, in zsh*[0] or *[1]gives me some file name... now I'm puzzled.
– Cristiano
11 mins ago
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
files=(*)
printf 'There are %d filesn' "${#files[@]}"
or
set -- *
printf 'There are %d filesn' "$#"
You have to name the array first (as I did above with files) or use the built-in array $@ by populating it with the wildcard, as I did in the second example. In the former, the "length" (number of files) of the array is done with the ${#arrayname[@]} syntax. The number of elements inn the built-in array is in $#.
answered 30 mins ago
Jeff SchallerJeff Schaller
41.1k1056131
So the*acts as a regex expression? I thought that it was a special array... although surprise me that there is no such array...
– Cristiano
14 mins ago
wait, in zsh*[0] or *[1]gives me some file name... now I'm puzzled.
– Cristiano
11 mins ago
add a comment |
1
files=(*)
printf 'There are %d filesn' "${#files[@]}"
or
set -- *
printf 'There are %d filesn' "$#"
You have to name the array first (as I did above with files) or use the built-in array $@ by populating it with the wildcard, as I did in the second example. In the former, the "length" (number of files) of the array is done with the ${#arrayname[@]} syntax. The number of elements inn the built-in array is in $#.
answered 30 mins ago
Jeff SchallerJeff Schaller
41.1k1056131
So the*acts as a regex expression? I thought that it was a special array... although surprise me that there is no such array...
– Cristiano
14 mins ago
wait, in zsh*[0] or *[1]gives me some file name... now I'm puzzled.
– Cristiano
11 mins ago
add a comment |
1
1
1
files=(*)
printf 'There are %d filesn' "${#files[@]}"
or
set -- *
printf 'There are %d filesn' "$#"
You have to name the array first (as I did above with files) or use the built-in array $@ by populating it with the wildcard, as I did in the second example. In the former, the "length" (number of files) of the array is done with the ${#arrayname[@]} syntax. The number of elements inn the built-in array is in $#.
answered 30 mins ago
Jeff SchallerJeff Schaller
41.1k1056131
files=(*)
printf 'There are %d filesn' "${#files[@]}"
or
set -- *
printf 'There are %d filesn' "$#"
You have to name the array first (as I did above with files) or use the built-in array $@ by populating it with the wildcard, as I did in the second example. In the former, the "length" (number of files) of the array is done with the ${#arrayname[@]} syntax. The number of elements inn the built-in array is in $#.
answered 30 mins ago
Jeff SchallerJeff Schaller
41.1k1056131
answered 30 mins ago
Jeff SchallerJeff Schaller
41.1k1056131
answered 30 mins ago
Jeff SchallerJeff Schaller
41.1k1056131
answered 30 mins ago
Jeff SchallerJeff Schaller
41.1k1056131
41.1k1056131
So the*acts as a regex expression? I thought that it was a special array... although surprise me that there is no such array...
– Cristiano
14 mins ago
wait, in zsh*[0] or *[1]gives me some file name... now I'm puzzled.
– Cristiano
11 mins ago
add a comment |
So the*acts as a regex expression? I thought that it was a special array... although surprise me that there is no such array...
– Cristiano
14 mins ago
wait, in zsh*[0] or *[1]gives me some file name... now I'm puzzled.
– Cristiano
11 mins ago
So the
* acts as a regex expression? I thought that it was a special array... although surprise me that there is no such array...– Cristiano
14 mins ago
So the
* acts as a regex expression? I thought that it was a special array... although surprise me that there is no such array...– Cristiano
14 mins ago
wait, in zsh
*[0] or *[1] gives me some file name... now I'm puzzled.– Cristiano
11 mins ago
wait, in zsh
*[0] or *[1] gives me some file name... now I'm puzzled.– Cristiano
11 mins ago
add a comment |
Cristiano is a new contributor. Be nice, and check out our Code of Conduct.
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1
By "length of the array" do you mean its number of elements? And do you want to get this without actually defining this array (
*suggest you want to use shell globing mechanism here)?– jimmij
37 mins ago
Oops, you're right i should have asked the other way around, I'll edit it.
– Cristiano
25 mins ago
@Cristiano: zsh doesn't have anything to do with it.
*is not an array in the way you are using it, it is a shell glob. Arrays have nothing to do with your question unless you create an array as Jeff did in his answer. Your question is "How do I find how many files are in the current directory"– Jesse_b
24 mins ago
@Jess_b But it acts like an array don't you think?
echo *[0]in zsh prints the 1st file name...– Cristiano
5 mins ago