Replacing a dynamic changing string with sed?
"Kerala",,"","[ ""ford aspire"" ]",,1,69
I have a line like this,I want to replace the value ""with "Not Detected" only when the value after two places is 1, if the value is 0 I have to replace with "Not Processed instead of Not Detected", Is there any way I could do that with sed??
"Kerala",,"",somevalue,somevalue,1,some value
linux bash sed
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"Kerala",,"","[ ""ford aspire"" ]",,1,69
I have a line like this,I want to replace the value ""with "Not Detected" only when the value after two places is 1, if the value is 0 I have to replace with "Not Processed instead of Not Detected", Is there any way I could do that with sed??
"Kerala",,"",somevalue,somevalue,1,some value
linux bash sed
New contributor
add a comment |
"Kerala",,"","[ ""ford aspire"" ]",,1,69
I have a line like this,I want to replace the value ""with "Not Detected" only when the value after two places is 1, if the value is 0 I have to replace with "Not Processed instead of Not Detected", Is there any way I could do that with sed??
"Kerala",,"",somevalue,somevalue,1,some value
linux bash sed
New contributor
"Kerala",,"","[ ""ford aspire"" ]",,1,69
I have a line like this,I want to replace the value ""with "Not Detected" only when the value after two places is 1, if the value is 0 I have to replace with "Not Processed instead of Not Detected", Is there any way I could do that with sed??
"Kerala",,"",somevalue,somevalue,1,some value
linux bash sed
linux bash sed
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New contributor
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asked 19 mins ago
Vijith VsVijith Vs
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Vijith Vs is a new contributor. Be nice, and check out our Code of Conduct.
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Vijith Vs is a new contributor. Be nice, and check out our Code of Conduct.
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