Why does regex `“.pdf”` match `/…/pdf…/…` in gawk, but not in mawk?












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From How can I extract only the pid column and only the pathname column in the lsof output?



awk '{ for (i=9; i<=NF; i++) {
if ($i ~ "string" && $1 != "wineserv" && $5 == "REG" && $NF ~ ".pdf") {
$1=$2=$3=$4=$5=$6=$7=$8=""
print
}
}}'


The regex ".pdf" matches /.../pdf.../... in gawk, but not in mawk. I wonder why?



Thanks.









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    0















    From How can I extract only the pid column and only the pathname column in the lsof output?



    awk '{ for (i=9; i<=NF; i++) {
    if ($i ~ "string" && $1 != "wineserv" && $5 == "REG" && $NF ~ ".pdf") {
    $1=$2=$3=$4=$5=$6=$7=$8=""
    print
    }
    }}'


    The regex ".pdf" matches /.../pdf.../... in gawk, but not in mawk. I wonder why?



    Thanks.









    share

























      0












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      0








      From How can I extract only the pid column and only the pathname column in the lsof output?



      awk '{ for (i=9; i<=NF; i++) {
      if ($i ~ "string" && $1 != "wineserv" && $5 == "REG" && $NF ~ ".pdf") {
      $1=$2=$3=$4=$5=$6=$7=$8=""
      print
      }
      }}'


      The regex ".pdf" matches /.../pdf.../... in gawk, but not in mawk. I wonder why?



      Thanks.









      share














      From How can I extract only the pid column and only the pathname column in the lsof output?



      awk '{ for (i=9; i<=NF; i++) {
      if ($i ~ "string" && $1 != "wineserv" && $5 == "REG" && $NF ~ ".pdf") {
      $1=$2=$3=$4=$5=$6=$7=$8=""
      print
      }
      }}'


      The regex ".pdf" matches /.../pdf.../... in gawk, but not in mawk. I wonder why?



      Thanks.







      awk gawk mawk





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      asked 3 mins ago









      TimTim

      27k78262472




      27k78262472






















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