LATEX Removing part of shaded area in polar plot
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I've been working on creating the following picture using TikZ.
The following code is as far as I've gotten.
documentclass[width=5cm, height=5cm, border=2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}[>=latex]
% cartesian coordinates
draw[-] (-2cm,0cm) -- (2cm,0cm) node[right,fill=white] {$x$};
draw[-] (0cm,-1cm) -- (0cm,3.1cm) node[above,fill=white] {$y$};
% sine graph with shading
draw [thick, domain=0:2*pi, samples=200, smooth] plot (xy polar cs:angle=x r,radius=
{1+1*sin(x r)});
filldraw [thick, even odd rule, fill=gray!50, fill opacity=0.3, domain=pi/6:5*pi/6,
samples=200, smooth] plot (xy polar cs:angle=x r,radius= {1+1*sin(x r)})
(0,1.5)circle(1.5cm);
end{tikzpicture}
end{document}
I was attempting with this code to first plot the sine graph(the one with a little dimple at the bottom) and then plot the shaded circle graph. The sine graph will only exist between pi/6 and 5pi/6, thus it'll "even odd rule" with the existing shaded circle and remove the shading within that region but as seen below it doesn't quite work out the way I was expecting. Pardon my limp explanation of the even odd rule, it's new to me and I'm still learning how to competently use it.
The above code produces the following polar plot.
How can I remove the obvious gray semicircle so it'll be like the sketch above?
Cheers in advance!
tikz-pgf texworks polarplot
asked 14 mins ago
salami_pirate
132
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up vote
0
down vote
favorite
I've been working on creating the following picture using TikZ.
The following code is as far as I've gotten.
documentclass[width=5cm, height=5cm, border=2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}[>=latex]
% cartesian coordinates
draw[-] (-2cm,0cm) -- (2cm,0cm) node[right,fill=white] {$x$};
draw[-] (0cm,-1cm) -- (0cm,3.1cm) node[above,fill=white] {$y$};
% sine graph with shading
draw [thick, domain=0:2*pi, samples=200, smooth] plot (xy polar cs:angle=x r,radius=
{1+1*sin(x r)});
filldraw [thick, even odd rule, fill=gray!50, fill opacity=0.3, domain=pi/6:5*pi/6,
samples=200, smooth] plot (xy polar cs:angle=x r,radius= {1+1*sin(x r)})
(0,1.5)circle(1.5cm);
end{tikzpicture}
end{document}
I was attempting with this code to first plot the sine graph(the one with a little dimple at the bottom) and then plot the shaded circle graph. The sine graph will only exist between pi/6 and 5pi/6, thus it'll "even odd rule" with the existing shaded circle and remove the shading within that region but as seen below it doesn't quite work out the way I was expecting. Pardon my limp explanation of the even odd rule, it's new to me and I'm still learning how to competently use it.
The above code produces the following polar plot.
How can I remove the obvious gray semicircle so it'll be like the sketch above?
Cheers in advance!
tikz-pgf texworks polarplot
asked 14 mins ago
salami_pirate
132
New contributor
salami_pirate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I've been working on creating the following picture using TikZ.
The following code is as far as I've gotten.
documentclass[width=5cm, height=5cm, border=2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}[>=latex]
% cartesian coordinates
draw[-] (-2cm,0cm) -- (2cm,0cm) node[right,fill=white] {$x$};
draw[-] (0cm,-1cm) -- (0cm,3.1cm) node[above,fill=white] {$y$};
% sine graph with shading
draw [thick, domain=0:2*pi, samples=200, smooth] plot (xy polar cs:angle=x r,radius=
{1+1*sin(x r)});
filldraw [thick, even odd rule, fill=gray!50, fill opacity=0.3, domain=pi/6:5*pi/6,
samples=200, smooth] plot (xy polar cs:angle=x r,radius= {1+1*sin(x r)})
(0,1.5)circle(1.5cm);
end{tikzpicture}
end{document}
I was attempting with this code to first plot the sine graph(the one with a little dimple at the bottom) and then plot the shaded circle graph. The sine graph will only exist between pi/6 and 5pi/6, thus it'll "even odd rule" with the existing shaded circle and remove the shading within that region but as seen below it doesn't quite work out the way I was expecting. Pardon my limp explanation of the even odd rule, it's new to me and I'm still learning how to competently use it.
The above code produces the following polar plot.
How can I remove the obvious gray semicircle so it'll be like the sketch above?
Cheers in advance!
tikz-pgf texworks polarplot
asked 14 mins ago
salami_pirate
132
New contributor
salami_pirate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I've been working on creating the following picture using TikZ.
The following code is as far as I've gotten.
documentclass[width=5cm, height=5cm, border=2mm]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}[>=latex]
% cartesian coordinates
draw[-] (-2cm,0cm) -- (2cm,0cm) node[right,fill=white] {$x$};
draw[-] (0cm,-1cm) -- (0cm,3.1cm) node[above,fill=white] {$y$};
% sine graph with shading
draw [thick, domain=0:2*pi, samples=200, smooth] plot (xy polar cs:angle=x r,radius=
{1+1*sin(x r)});
filldraw [thick, even odd rule, fill=gray!50, fill opacity=0.3, domain=pi/6:5*pi/6,
samples=200, smooth] plot (xy polar cs:angle=x r,radius= {1+1*sin(x r)})
(0,1.5)circle(1.5cm);
end{tikzpicture}
end{document}
I was attempting with this code to first plot the sine graph(the one with a little dimple at the bottom) and then plot the shaded circle graph. The sine graph will only exist between pi/6 and 5pi/6, thus it'll "even odd rule" with the existing shaded circle and remove the shading within that region but as seen below it doesn't quite work out the way I was expecting. Pardon my limp explanation of the even odd rule, it's new to me and I'm still learning how to competently use it.
The above code produces the following polar plot.
How can I remove the obvious gray semicircle so it'll be like the sketch above?
Cheers in advance!
tikz-pgf texworks polarplot
tikz-pgf texworks polarplot
asked 14 mins ago
salami_pirate
132
New contributor
salami_pirate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 14 mins ago
salami_pirate
132
New contributor
salami_pirate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 14 mins ago
salami_pirate
132
New contributor
salami_pirate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 14 mins ago
salami_pirate
132
asked 14 mins ago
salami_pirate
132
132
New contributor
salami_pirate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
salami_pirate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
salami_pirate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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