How to evaluate df(x)/dx at x=c rather than df(c)/dx?











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The following macros define f[#1] and its derivative fp[#1].



deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}

edeffp[#1]{Derive(1,f[#1])}


Question



How to evaluate fp[0.8] that means the value of df/dx at x=0.8 rather than df[0.8]/dx that always equals to zero?



MWE



documentclass[pstricks]{standalone}

usepackage{pstricks-add}



deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}

edeffp[#1]{Derive(1,f[#1])}

edefg[#1]#2{(fp[#2]*((#1)-(#2))+f[#2])}



psset{algebraic,plotpoints=200,unit=2cm}

begin{document}

begin{pspicture}(-.75,-2)(5.75,3)

    psplot[linecolor=red]{-.25}{5}{f[x]}

    psplot[linecolor=green]{-.25}{5}{g[x]{.8}}

end{pspicture}

end{document}


enter image description here






pstricks pst-plot pstricks-add







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    up vote
    0
    down vote

    favorite












    The following macros define f[#1] and its derivative fp[#1].



    deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
    
edeffp[#1]{Derive(1,f[#1])}


    Question



    How to evaluate fp[0.8] that means the value of df/dx at x=0.8 rather than df[0.8]/dx that always equals to zero?



    MWE



    documentclass[pstricks]{standalone}
    
usepackage{pstricks-add}
    

    
deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
    
edeffp[#1]{Derive(1,f[#1])}
    
edefg[#1]#2{(fp[#2]*((#1)-(#2))+f[#2])}
    

    
psset{algebraic,plotpoints=200,unit=2cm}
    
begin{document}
    
begin{pspicture}(-.75,-2)(5.75,3)
    
    psplot[linecolor=red]{-.25}{5}{f[x]}
    
    psplot[linecolor=green]{-.25}{5}{g[x]{.8}}
    
end{pspicture}
    
end{document}


    enter image description here






    pstricks pst-plot pstricks-add







    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      The following macros define f[#1] and its derivative fp[#1].



      deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
      
edeffp[#1]{Derive(1,f[#1])}


      Question



      How to evaluate fp[0.8] that means the value of df/dx at x=0.8 rather than df[0.8]/dx that always equals to zero?



      MWE



      documentclass[pstricks]{standalone}
      
usepackage{pstricks-add}
      

      
deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
      
edeffp[#1]{Derive(1,f[#1])}
      
edefg[#1]#2{(fp[#2]*((#1)-(#2))+f[#2])}
      

      
psset{algebraic,plotpoints=200,unit=2cm}
      
begin{document}
      
begin{pspicture}(-.75,-2)(5.75,3)
      
    psplot[linecolor=red]{-.25}{5}{f[x]}
      
    psplot[linecolor=green]{-.25}{5}{g[x]{.8}}
      
end{pspicture}
      
end{document}


      enter image description here






      pstricks pst-plot pstricks-add







      share|improve this question













      The following macros define f[#1] and its derivative fp[#1].



      deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
      
edeffp[#1]{Derive(1,f[#1])}


      Question



      How to evaluate fp[0.8] that means the value of df/dx at x=0.8 rather than df[0.8]/dx that always equals to zero?



      MWE



      documentclass[pstricks]{standalone}
      
usepackage{pstricks-add}
      

      
deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
      
edeffp[#1]{Derive(1,f[#1])}
      
edefg[#1]#2{(fp[#2]*((#1)-(#2))+f[#2])}
      

      
psset{algebraic,plotpoints=200,unit=2cm}
      
begin{document}
      
begin{pspicture}(-.75,-2)(5.75,3)
      
    psplot[linecolor=red]{-.25}{5}{f[x]}
      
    psplot[linecolor=green]{-.25}{5}{g[x]{.8}}
      
end{pspicture}
      
end{document}


      enter image description here






      pstricks pst-plot pstricks-add




      pstricks pst-plot pstricks-add






      share|improve this question













      share|improve this question











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      share|improve this question










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