How does bash coprocess achieve its pipelining?
Note this passage from man bash ( emphasis mine ):
Coprocesses
A coprocess is a shell command preceded by the coproc reserved word. A
coprocess is executed asynchronously in a subshell, as if the command
had been terminated with the & control operator, with a two-way pipe
established between the executing shell and the coprocess.
Now, as we know unlike other *nix systems, Linux pipes are unidirectional. So how does bash coproces achieve the "two-way pipe" without one existing on Linux ?
bash pipe coprocesses
asked 2 mins ago
Sergiy KolodyazhnyySergiy Kolodyazhnyy
8,51612254
add a comment |
Note this passage from man bash ( emphasis mine ):
Coprocesses
A coprocess is a shell command preceded by the coproc reserved word. A
coprocess is executed asynchronously in a subshell, as if the command
had been terminated with the & control operator, with a two-way pipe
established between the executing shell and the coprocess.
Now, as we know unlike other *nix systems, Linux pipes are unidirectional. So how does bash coproces achieve the "two-way pipe" without one existing on Linux ?
bash pipe coprocesses
asked 2 mins ago
Sergiy KolodyazhnyySergiy Kolodyazhnyy
8,51612254
add a comment |
Note this passage from man bash ( emphasis mine ):
Coprocesses
A coprocess is a shell command preceded by the coproc reserved word. A
coprocess is executed asynchronously in a subshell, as if the command
had been terminated with the & control operator, with a two-way pipe
established between the executing shell and the coprocess.
Now, as we know unlike other *nix systems, Linux pipes are unidirectional. So how does bash coproces achieve the "two-way pipe" without one existing on Linux ?
bash pipe coprocesses
asked 2 mins ago
Sergiy KolodyazhnyySergiy Kolodyazhnyy
8,51612254
Note this passage from man bash ( emphasis mine ):
Coprocesses
A coprocess is a shell command preceded by the coproc reserved word. A
coprocess is executed asynchronously in a subshell, as if the command
had been terminated with the & control operator, with a two-way pipe
established between the executing shell and the coprocess.
Now, as we know unlike other *nix systems, Linux pipes are unidirectional. So how does bash coproces achieve the "two-way pipe" without one existing on Linux ?
bash pipe coprocesses
bash pipe coprocesses
asked 2 mins ago
Sergiy KolodyazhnyySergiy Kolodyazhnyy
8,51612254
asked 2 mins ago
Sergiy KolodyazhnyySergiy Kolodyazhnyy
8,51612254
asked 2 mins ago
Sergiy KolodyazhnyySergiy Kolodyazhnyy
8,51612254
asked 2 mins ago
Sergiy KolodyazhnyySergiy Kolodyazhnyy
8,51612254
asked 2 mins ago
Sergiy KolodyazhnyySergiy Kolodyazhnyy
8,51612254
8,51612254
add a comment |
add a comment |
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