Linux - Checking if user has entered numbers and letters











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0
down vote

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The script I am trying to create should ask the user to enter a password. This password will then be checked if it contains a capital, characters and numbers



This is all I have so far before I got lost and started googling for ways of doing this



#!/bin/sh

echo "Please enter a password containing numbers and letters"

read password



if [[password =~ [0-9] ]]

then 

    echo "Successful"

else

    echo "Fail"

fi





linux shell-script







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ElonCode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • Is your intent for it to require a number, uppercase, lowercase, and special character?
    – Jesse_b
    yesterday










  • @Jesse_b yes this is what I intend
    – ElonCode
    yesterday















up vote
0
down vote

favorite












The script I am trying to create should ask the user to enter a password. This password will then be checked if it contains a capital, characters and numbers



This is all I have so far before I got lost and started googling for ways of doing this



#!/bin/sh

echo "Please enter a password containing numbers and letters"

read password



if [[password =~ [0-9] ]]

then 

    echo "Successful"

else

    echo "Fail"

fi





linux shell-script







share|improve this question









New contributor




ElonCode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Is your intent for it to require a number, uppercase, lowercase, and special character?
    – Jesse_b
    yesterday










  • @Jesse_b yes this is what I intend
    – ElonCode
    yesterday













up vote
0
down vote

favorite









up vote
0
down vote

favorite











The script I am trying to create should ask the user to enter a password. This password will then be checked if it contains a capital, characters and numbers



This is all I have so far before I got lost and started googling for ways of doing this



#!/bin/sh

echo "Please enter a password containing numbers and letters"

read password



if [[password =~ [0-9] ]]

then 

    echo "Successful"

else

    echo "Fail"

fi





linux shell-script







share|improve this question









New contributor




ElonCode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











The script I am trying to create should ask the user to enter a password. This password will then be checked if it contains a capital, characters and numbers



This is all I have so far before I got lost and started googling for ways of doing this



#!/bin/sh

echo "Please enter a password containing numbers and letters"

read password



if [[password =~ [0-9] ]]

then 

    echo "Successful"

else

    echo "Fail"

fi





linux shell-script




linux shell-script






share|improve this question









New contributor




ElonCode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




ElonCode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









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edited yesterday









SouravGhosh

371210




371210






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asked yesterday









ElonCode

84




84




New contributor




ElonCode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





ElonCode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






ElonCode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Is your intent for it to require a number, uppercase, lowercase, and special character?
    – Jesse_b
    yesterday










  • @Jesse_b yes this is what I intend
    – ElonCode
    yesterday


















  • Is your intent for it to require a number, uppercase, lowercase, and special character?
    – Jesse_b
    yesterday










  • @Jesse_b yes this is what I intend
    – ElonCode
    yesterday
















Is your intent for it to require a number, uppercase, lowercase, and special character?
– Jesse_b
yesterday




Is your intent for it to require a number, uppercase, lowercase, and special character?
– Jesse_b
yesterday












@Jesse_b yes this is what I intend
– ElonCode
yesterday




@Jesse_b yes this is what I intend
– ElonCode
yesterday










1 Answer
1






active

oldest

votes

















up vote
2
down vote













Some issues with your code:




  1. You need a space between [[ and password


  2. password will be a variable and therefore needs to be written as $password to expand

  3. You are using the #!/bin/sh hashbang and therefore the bash extended test ([[) may not be available

  4. You are only checking if the password contains numbers



I think a function would be best for checking if the password meets your requirements and have come up with the following:



#!/bin/sh



chk_pass () {

    local pass=$1

    # Check if password contains uppercase

    printf '%s' "$pass" | grep -q '[A-Z]' || return 1

    # Check if password contains lowercase

    printf '%s' "$pass" | grep -q '[a-z]' || return 1

    # Check if password contains numbers

    printf '%s' "$pass" | grep -q '[0-9]' || return 1

    # Check if password contains special characters

    printf '%s' "$pass" | grep -q '[^a-zA-Z0-9 t]' || return 1

    return 0

}



printf '%sn' 'Please enter a password containing at least one number, one uppercase letter, one lowercase letter, and one special character: '

read -rs 

if chk_pass "$REPLY"; then

    printf '%sn' 'Success'

else

    printf '%sn' 'Error: Password must contain one number, one uppercase letter, one lowercase letter, and one special character!' >&2

fi


Notes:



The last grep in the function actually only checks that the password contains characters other than alphanumeric or whitespace.

The -r option for read will preserve backslash characters

The -s option for read will hide user input (useful for password input)






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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

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    oldest

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    active

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    up vote
    2
    down vote













    Some issues with your code:




    1. You need a space between [[ and password


    2. password will be a variable and therefore needs to be written as $password to expand

    3. You are using the #!/bin/sh hashbang and therefore the bash extended test ([[) may not be available

    4. You are only checking if the password contains numbers



    I think a function would be best for checking if the password meets your requirements and have come up with the following:



    #!/bin/sh
    

    
chk_pass () {
    
    local pass=$1
    
    # Check if password contains uppercase
    
    printf '%s' "$pass" | grep -q '[A-Z]' || return 1
    
    # Check if password contains lowercase
    
    printf '%s' "$pass" | grep -q '[a-z]' || return 1
    
    # Check if password contains numbers
    
    printf '%s' "$pass" | grep -q '[0-9]' || return 1
    
    # Check if password contains special characters
    
    printf '%s' "$pass" | grep -q '[^a-zA-Z0-9 t]' || return 1
    
    return 0
    
}
    

    
printf '%sn' 'Please enter a password containing at least one number, one uppercase letter, one lowercase letter, and one special character: '
    
read -rs 
    
if chk_pass "$REPLY"; then
    
    printf '%sn' 'Success'
    
else
    
    printf '%sn' 'Error: Password must contain one number, one uppercase letter, one lowercase letter, and one special character!' >&2
    
fi


    Notes:



    The last grep in the function actually only checks that the password contains characters other than alphanumeric or whitespace.

    The -r option for read will preserve backslash characters

    The -s option for read will hide user input (useful for password input)






    share|improve this answer

























      up vote
      2
      down vote













      Some issues with your code:




      1. You need a space between [[ and password


      2. password will be a variable and therefore needs to be written as $password to expand

      3. You are using the #!/bin/sh hashbang and therefore the bash extended test ([[) may not be available

      4. You are only checking if the password contains numbers



      I think a function would be best for checking if the password meets your requirements and have come up with the following:



      #!/bin/sh
      

      
chk_pass () {
      
    local pass=$1
      
    # Check if password contains uppercase
      
    printf '%s' "$pass" | grep -q '[A-Z]' || return 1
      
    # Check if password contains lowercase
      
    printf '%s' "$pass" | grep -q '[a-z]' || return 1
      
    # Check if password contains numbers
      
    printf '%s' "$pass" | grep -q '[0-9]' || return 1
      
    # Check if password contains special characters
      
    printf '%s' "$pass" | grep -q '[^a-zA-Z0-9 t]' || return 1
      
    return 0
      
}
      

      
printf '%sn' 'Please enter a password containing at least one number, one uppercase letter, one lowercase letter, and one special character: '
      
read -rs 
      
if chk_pass "$REPLY"; then
      
    printf '%sn' 'Success'
      
else
      
    printf '%sn' 'Error: Password must contain one number, one uppercase letter, one lowercase letter, and one special character!' >&2
      
fi


      Notes:



      The last grep in the function actually only checks that the password contains characters other than alphanumeric or whitespace.

      The -r option for read will preserve backslash characters

      The -s option for read will hide user input (useful for password input)






      share|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        Some issues with your code:




        1. You need a space between [[ and password


        2. password will be a variable and therefore needs to be written as $password to expand

        3. You are using the #!/bin/sh hashbang and therefore the bash extended test ([[) may not be available

        4. You are only checking if the password contains numbers



        I think a function would be best for checking if the password meets your requirements and have come up with the following:



        #!/bin/sh
        

        
chk_pass () {
        
    local pass=$1
        
    # Check if password contains uppercase
        
    printf '%s' "$pass" | grep -q '[A-Z]' || return 1
        
    # Check if password contains lowercase
        
    printf '%s' "$pass" | grep -q '[a-z]' || return 1
        
    # Check if password contains numbers
        
    printf '%s' "$pass" | grep -q '[0-9]' || return 1
        
    # Check if password contains special characters
        
    printf '%s' "$pass" | grep -q '[^a-zA-Z0-9 t]' || return 1
        
    return 0
        
}
        

        
printf '%sn' 'Please enter a password containing at least one number, one uppercase letter, one lowercase letter, and one special character: '
        
read -rs 
        
if chk_pass "$REPLY"; then
        
    printf '%sn' 'Success'
        
else
        
    printf '%sn' 'Error: Password must contain one number, one uppercase letter, one lowercase letter, and one special character!' >&2
        
fi


        Notes:



        The last grep in the function actually only checks that the password contains characters other than alphanumeric or whitespace.

        The -r option for read will preserve backslash characters

        The -s option for read will hide user input (useful for password input)






        share|improve this answer












        Some issues with your code:




        1. You need a space between [[ and password


        2. password will be a variable and therefore needs to be written as $password to expand

        3. You are using the #!/bin/sh hashbang and therefore the bash extended test ([[) may not be available

        4. You are only checking if the password contains numbers



        I think a function would be best for checking if the password meets your requirements and have come up with the following:



        #!/bin/sh
        

        
chk_pass () {
        
    local pass=$1
        
    # Check if password contains uppercase
        
    printf '%s' "$pass" | grep -q '[A-Z]' || return 1
        
    # Check if password contains lowercase
        
    printf '%s' "$pass" | grep -q '[a-z]' || return 1
        
    # Check if password contains numbers
        
    printf '%s' "$pass" | grep -q '[0-9]' || return 1
        
    # Check if password contains special characters
        
    printf '%s' "$pass" | grep -q '[^a-zA-Z0-9 t]' || return 1
        
    return 0
        
}
        

        
printf '%sn' 'Please enter a password containing at least one number, one uppercase letter, one lowercase letter, and one special character: '
        
read -rs 
        
if chk_pass "$REPLY"; then
        
    printf '%sn' 'Success'
        
else
        
    printf '%sn' 'Error: Password must contain one number, one uppercase letter, one lowercase letter, and one special character!' >&2
        
fi


        Notes:



        The last grep in the function actually only checks that the password contains characters other than alphanumeric or whitespace.

        The -r option for read will preserve backslash characters

        The -s option for read will hide user input (useful for password input)







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered yesterday









        Jesse_b

        11.7k23063




        11.7k23063






















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