Sstrhsrtj

So, what I am trying to do is look for a set of files, and then have it echo which ones it has found. For example, this is what I have

    #!/bin/bash



    LaunchDaemon="LaunchDaemon.plist" 

    launchAgent="LaunchAgent"

    mobileLaunchDaemon="MobileDaemon.plist"

    mobileAgent="MobileAgent"



    if [ -f "$LaunchDaemon" ] || [ -f "$launchAgent" ] || [ -f "$mobileLaunchDaemon" ] || [ -f "$mobileAgent" ]

then

    echo "<result>Found</result>"

else

    echo "<result>Not Found</result>"

fi

So, this will tell me if it can find any of them, but it won't tell me which one it is finding. I created another with elif statements inside, which works sort of, but if it finds the first one, it stops there and won't tell me if the others are there as well. So, I hope this makes sense, I'm just trying to find a way to display which of the files have been found.

You need to split your if test into multiple

if [ -f "$LaunchDaemon" ]

then

  echo $LaunchDaemon found

elif [ -f "$launchAgent" ]

then

  echo $launchAgent found

elif [ ... 

  ...

else

  echo Not found

fi

type structure (fill in the blanks yourself.).

If you want to find all matches just do it as multiple tests, setting a variable to see if anything was found or not

found=0

if [ -f "$LaunchDaemon" ]

then

  echo $LaunchDaemon found

  found=1

fi

if [ -f "$launchAgent" ]

then

  echo $launchAgent found

  found=1

fi

...

if [ $found == 0 ]

then

  echo Not found

fi

Now sometimes we want to set a variable so we know which one was found. This is common when trying to find a matching program or file (eg in the old days we might have had /usr/lib/sendmail or /usr/sbin/sendmail depending on the OS distribution, so we'd need to search to find it).

found=

for f in "$LaunchDaemon" "$launchAgent" "$mobileLaunchDaemon" "$mobileAgent"

do

  [[ -f "$f" ]] && found="$f"

done

Now we have $found pointing to a found entry and can test on that.

if [ -n "$found" ]

then

  echo Found: $found

else

  echo Nothing found

fi

The second loop can also find all versions with a minor change:

found=

for f in "$LaunchDaemon" "$launchAgent" "$mobileLaunchDaemon" "$mobileAgent"

do

  [[ -f "$f" ]] && found="$found $f"

done

The downside of this is that there may be a leading space in front, so we should remove that:

found="${found# }"

An array would be the best approach here

#!/bin/bash

#Store the filenames in an array, also less management overhead

arry=( "LaunchDaemon.plist" "LaunchAgent" "MobileDaemon.plist" "MobileAgent" )

#Optioinally if you wish to add one more file to check you could

#uncomment the below line

#arry+=("$1") #One more file added from the command line

for i in "${arry[@]}" #Iterate through each element using a for loop

do

 if [ -f "$i" ]

 then

  echo "<result> $i Found</result>" 

 else

  echo "<result> $i Not Found</result>"

 fi

done

try this

#!/bin/bash

search_LaunchDaemon="LaunchDaemon.plist"

search_launchAgent="LaunchAgent"

search_mobileLaunchDaemon="MobileDaemon.plist"



for filex  in ${!search_*}

do

found=${!filex}

#echo  -e "${filex}=${!filex}"

#we remove the prefix "search_"

IFS="_" read part1 part2 <<< "${filex}"



if [[ -f $found ]];

then

echo "I have found ${part2}"

else

echo "${part2} not found!"

fi

done