strings -t d -n 4 /dev/sdb | grep LUKS
I tried to get the position of LUKS header from sdB:
# strings -t d -n 4 /dev/sdb | grep LUKS
...
1460823759 Extended_description-en_gb.utf-8: Encrypt this partition (LUKS)
1460823863 i tiun subdiskon (LUKS)
1460823939 n (LUKS)
1460823983 pti see kettajagu (LUKS)
1460824008 Extended_description-eu.utf-8: Zifratu partizio hau (LUKS)
1460824132 (LUKS)
1460824183 osio (LUKS)
15916083096 CRYPT-LUKS1-
15916085084 LUKS
15916199956 # luksformat - wrapper around LUKS-capable cryptsetup and mkfs for easy
15916200752 print gettext("luksformat - Create and format an encrypted LUKS device
...
Too many results printing on the output, how can I get the real one?
grep string luks
add a comment |
I tried to get the position of LUKS header from sdB:
# strings -t d -n 4 /dev/sdb | grep LUKS
...
1460823759 Extended_description-en_gb.utf-8: Encrypt this partition (LUKS)
1460823863 i tiun subdiskon (LUKS)
1460823939 n (LUKS)
1460823983 pti see kettajagu (LUKS)
1460824008 Extended_description-eu.utf-8: Zifratu partizio hau (LUKS)
1460824132 (LUKS)
1460824183 osio (LUKS)
15916083096 CRYPT-LUKS1-
15916085084 LUKS
15916199956 # luksformat - wrapper around LUKS-capable cryptsetup and mkfs for easy
15916200752 print gettext("luksformat - Create and format an encrypted LUKS device
...
Too many results printing on the output, how can I get the real one?
grep string luks
add a comment |
I tried to get the position of LUKS header from sdB:
# strings -t d -n 4 /dev/sdb | grep LUKS
...
1460823759 Extended_description-en_gb.utf-8: Encrypt this partition (LUKS)
1460823863 i tiun subdiskon (LUKS)
1460823939 n (LUKS)
1460823983 pti see kettajagu (LUKS)
1460824008 Extended_description-eu.utf-8: Zifratu partizio hau (LUKS)
1460824132 (LUKS)
1460824183 osio (LUKS)
15916083096 CRYPT-LUKS1-
15916085084 LUKS
15916199956 # luksformat - wrapper around LUKS-capable cryptsetup and mkfs for easy
15916200752 print gettext("luksformat - Create and format an encrypted LUKS device
...
Too many results printing on the output, how can I get the real one?
grep string luks
I tried to get the position of LUKS header from sdB:
# strings -t d -n 4 /dev/sdb | grep LUKS
...
1460823759 Extended_description-en_gb.utf-8: Encrypt this partition (LUKS)
1460823863 i tiun subdiskon (LUKS)
1460823939 n (LUKS)
1460823983 pti see kettajagu (LUKS)
1460824008 Extended_description-eu.utf-8: Zifratu partizio hau (LUKS)
1460824132 (LUKS)
1460824183 osio (LUKS)
15916083096 CRYPT-LUKS1-
15916085084 LUKS
15916199956 # luksformat - wrapper around LUKS-capable cryptsetup and mkfs for easy
15916200752 print gettext("luksformat - Create and format an encrypted LUKS device
...
Too many results printing on the output, how can I get the real one?
grep string luks
grep string luks
edited 2 mins ago
Olorin
3,9281723
3,9281723
asked 5 mins ago
MaggicmuojetMaggicmuojet
163
163
add a comment |
add a comment |
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