bash cannot correctly parse and shift path variable without slash in the end
my problem, I am using a script foo.sh
while [ -n "$1" ]
do
case $1 in
-p)
P=$2
shift 2
;;
-s)
S=$2
shift 2
;;
esac
done
to parse 2 expected variables: s and p, where p will be a path of dir and s will be a path to file.
For ./foo.sh -p /aa/bb/cc -s dd/ee.tar.gz
I am expecting P to be /aa/bb/cc and S to be dd/ee.tar.gz.
But I found above will give me a P=/aa/bb/cc, as expected, BUT the S is empty!
If I add a slash to the end of path or quote the path, for example
./foo.sh -p /aa/bb/cc/ -s dd/ee.tar.gz
./foo.sh -p "/aa/bb/cc" -s dd/ee.tar.gz
Then it works as expected again.
I read through the similar questions
bash
asked 2 hours ago
PsyduckPsyduck
11
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my problem, I am using a script foo.sh
while [ -n "$1" ]
do
case $1 in
-p)
P=$2
shift 2
;;
-s)
S=$2
shift 2
;;
esac
done
to parse 2 expected variables: s and p, where p will be a path of dir and s will be a path to file.
For ./foo.sh -p /aa/bb/cc -s dd/ee.tar.gz
I am expecting P to be /aa/bb/cc and S to be dd/ee.tar.gz.
But I found above will give me a P=/aa/bb/cc, as expected, BUT the S is empty!
If I add a slash to the end of path or quote the path, for example
./foo.sh -p /aa/bb/cc/ -s dd/ee.tar.gz
./foo.sh -p "/aa/bb/cc" -s dd/ee.tar.gz
Then it works as expected again.
I read through the similar questions
bash
asked 2 hours ago
PsyduckPsyduck
11
New contributor
Psyduck is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
I can not reproduce your issue. The code behaves as expected. One may have wanted to implement it with a while loop overgetopts, but your code works for the examples you show (including the first ones). Please mention what happens before and after this code snippet and where you test the value of the variables.
– Kusalananda
2 hours ago
Same. The code works for me as expected with the options you have provided
– Jesse_b
2 hours ago
1
Especially the quoting shouldn't possibly matter at all:-p /aa/bb/ccis exactly the same thing as-p "/aa/bb/cc". Of course, if you're actually using something else than a static string there, things might be different.
– ilkkachu
2 hours ago
add a comment |
my problem, I am using a script foo.sh
while [ -n "$1" ]
do
case $1 in
-p)
P=$2
shift 2
;;
-s)
S=$2
shift 2
;;
esac
done
to parse 2 expected variables: s and p, where p will be a path of dir and s will be a path to file.
For ./foo.sh -p /aa/bb/cc -s dd/ee.tar.gz
I am expecting P to be /aa/bb/cc and S to be dd/ee.tar.gz.
But I found above will give me a P=/aa/bb/cc, as expected, BUT the S is empty!
If I add a slash to the end of path or quote the path, for example
./foo.sh -p /aa/bb/cc/ -s dd/ee.tar.gz
./foo.sh -p "/aa/bb/cc" -s dd/ee.tar.gz
Then it works as expected again.
I read through the similar questions
bash
asked 2 hours ago
PsyduckPsyduck
11
New contributor
Psyduck is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
my problem, I am using a script foo.sh
while [ -n "$1" ]
do
case $1 in
-p)
P=$2
shift 2
;;
-s)
S=$2
shift 2
;;
esac
done
to parse 2 expected variables: s and p, where p will be a path of dir and s will be a path to file.
For ./foo.sh -p /aa/bb/cc -s dd/ee.tar.gz
I am expecting P to be /aa/bb/cc and S to be dd/ee.tar.gz.
But I found above will give me a P=/aa/bb/cc, as expected, BUT the S is empty!
If I add a slash to the end of path or quote the path, for example
./foo.sh -p /aa/bb/cc/ -s dd/ee.tar.gz
./foo.sh -p "/aa/bb/cc" -s dd/ee.tar.gz
Then it works as expected again.
I read through the similar questions
bash
bash
asked 2 hours ago
PsyduckPsyduck
11
New contributor
Psyduck is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
PsyduckPsyduck
11
New contributor
Psyduck is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
PsyduckPsyduck
11
New contributor
Psyduck is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 2 hours ago
PsyduckPsyduck
11
asked 2 hours ago
PsyduckPsyduck
11
11
New contributor
Psyduck is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
Psyduck is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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3
I can not reproduce your issue. The code behaves as expected. One may have wanted to implement it with a while loop overgetopts, but your code works for the examples you show (including the first ones). Please mention what happens before and after this code snippet and where you test the value of the variables.
– Kusalananda
2 hours ago
Same. The code works for me as expected with the options you have provided
– Jesse_b
2 hours ago
1
Especially the quoting shouldn't possibly matter at all:-p /aa/bb/ccis exactly the same thing as-p "/aa/bb/cc". Of course, if you're actually using something else than a static string there, things might be different.
– ilkkachu
2 hours ago
add a comment |
3
I can not reproduce your issue. The code behaves as expected. One may have wanted to implement it with a while loop overgetopts, but your code works for the examples you show (including the first ones). Please mention what happens before and after this code snippet and where you test the value of the variables.
– Kusalananda
2 hours ago
Same. The code works for me as expected with the options you have provided
– Jesse_b
2 hours ago
1
Especially the quoting shouldn't possibly matter at all:-p /aa/bb/ccis exactly the same thing as-p "/aa/bb/cc". Of course, if you're actually using something else than a static string there, things might be different.
– ilkkachu
2 hours ago
3
3
I can not reproduce your issue. The code behaves as expected. One may have wanted to implement it with a while loop over
getopts, but your code works for the examples you show (including the first ones). Please mention what happens before and after this code snippet and where you test the value of the variables.– Kusalananda
2 hours ago
I can not reproduce your issue. The code behaves as expected. One may have wanted to implement it with a while loop over
getopts, but your code works for the examples you show (including the first ones). Please mention what happens before and after this code snippet and where you test the value of the variables.– Kusalananda
2 hours ago
Same. The code works for me as expected with the options you have provided
– Jesse_b
2 hours ago
Same. The code works for me as expected with the options you have provided
– Jesse_b
2 hours ago
1
1
Especially the quoting shouldn't possibly matter at all:
-p /aa/bb/cc is exactly the same thing as -p "/aa/bb/cc". Of course, if you're actually using something else than a static string there, things might be different.– ilkkachu
2 hours ago
Especially the quoting shouldn't possibly matter at all:
-p /aa/bb/cc is exactly the same thing as -p "/aa/bb/cc". Of course, if you're actually using something else than a static string there, things might be different.– ilkkachu
2 hours ago
add a comment |
1 Answer
1
active
oldest
votes
In order to implement your code using getopts
while getopts p:s: opt; do
case $opt in
p) p=$OPTARG;;
s) s=$OPTARG;;
esac
done
The : after the option indicates it requires an argument which will be set to the OPTARG variable.
answered 2 hours ago
Jesse_bJesse_b
13.4k23370
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
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active
oldest
votes
In order to implement your code using getopts
while getopts p:s: opt; do
case $opt in
p) p=$OPTARG;;
s) s=$OPTARG;;
esac
done
The : after the option indicates it requires an argument which will be set to the OPTARG variable.
answered 2 hours ago
Jesse_bJesse_b
13.4k23370
add a comment |
In order to implement your code using getopts
while getopts p:s: opt; do
case $opt in
p) p=$OPTARG;;
s) s=$OPTARG;;
esac
done
The : after the option indicates it requires an argument which will be set to the OPTARG variable.
answered 2 hours ago
Jesse_bJesse_b
13.4k23370
add a comment |
In order to implement your code using getopts
while getopts p:s: opt; do
case $opt in
p) p=$OPTARG;;
s) s=$OPTARG;;
esac
done
The : after the option indicates it requires an argument which will be set to the OPTARG variable.
answered 2 hours ago
Jesse_bJesse_b
13.4k23370
In order to implement your code using getopts
while getopts p:s: opt; do
case $opt in
p) p=$OPTARG;;
s) s=$OPTARG;;
esac
done
The : after the option indicates it requires an argument which will be set to the OPTARG variable.
answered 2 hours ago
Jesse_bJesse_b
13.4k23370
answered 2 hours ago
Jesse_bJesse_b
13.4k23370
answered 2 hours ago
Jesse_bJesse_b
13.4k23370
answered 2 hours ago
Jesse_bJesse_b
13.4k23370
13.4k23370
add a comment |
add a comment |
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3
I can not reproduce your issue. The code behaves as expected. One may have wanted to implement it with a while loop over
getopts, but your code works for the examples you show (including the first ones). Please mention what happens before and after this code snippet and where you test the value of the variables.– Kusalananda
2 hours ago
Same. The code works for me as expected with the options you have provided
– Jesse_b
2 hours ago
1
Especially the quoting shouldn't possibly matter at all:
-p /aa/bb/ccis exactly the same thing as-p "/aa/bb/cc". Of course, if you're actually using something else than a static string there, things might be different.– ilkkachu
2 hours ago