How to store values in an array?
How to store a calculated value in array?
zz(1) = ( xx(1) + yy(1) )/2
fpevalzz(counter){(xx(counter)+yy(counter))/2} NOT working
documentclass{beamer}
usepackage{siunitx,amsmath}
usepackage{xparse,xfp}
ExplSyntaxOn
NewDocumentCommand{newarray}{m}
{
seq_new:c { l_hafid_array_#1_seq }
cs_new:cpn { #1 } ##1
{
seq_item:cn { l_hafid_array_#1_seq } { ##1 }
}
}
NewDocumentCommand{readarray}{mm}
{
seq_set_split:cnn { l_hafid_array_#1_seq } { & } { #2 }
}
cs_generate_variant:Nn seq_set_split:Nnn { c }
NewExpandableDocumentCommand{sumarray}{O{15}m}
{
fp_eval:n { round( seq_use:cn { l_hafid_array_#2_seq } { + }, #1 ) }
}
ExplSyntaxOff
begin{document}
newarray{xx}
readarray{xx}{1&2&3&4&5}
newarray{yy}
readarray{yy}{6&7&8&9&10}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & xx{1} & yy{1} & fpeval{(xx{1}+yy{1})/2} \
2 & xx{2} & yy{2} & fpeval{(xx{2}+yy{2})/2} \
3 & xx{3} & yy{3} & \
4 & xx{4} & yy{4} & \
5 & xx{5} & yy{5} & \ hline
end{tabular}
end{table}
end{frame}
%newarray{zz}
%readarray{xx}{0&0&0&0&0}
newcountcounter
counter=5
loop
fpevalzz(counter){(xx(counter)+yy(counter))/2}
advance counter by -1
unlessifnum counter<1
repeat
end{document}
fp
add a comment |
How to store a calculated value in array?
zz(1) = ( xx(1) + yy(1) )/2
fpevalzz(counter){(xx(counter)+yy(counter))/2} NOT working
documentclass{beamer}
usepackage{siunitx,amsmath}
usepackage{xparse,xfp}
ExplSyntaxOn
NewDocumentCommand{newarray}{m}
{
seq_new:c { l_hafid_array_#1_seq }
cs_new:cpn { #1 } ##1
{
seq_item:cn { l_hafid_array_#1_seq } { ##1 }
}
}
NewDocumentCommand{readarray}{mm}
{
seq_set_split:cnn { l_hafid_array_#1_seq } { & } { #2 }
}
cs_generate_variant:Nn seq_set_split:Nnn { c }
NewExpandableDocumentCommand{sumarray}{O{15}m}
{
fp_eval:n { round( seq_use:cn { l_hafid_array_#2_seq } { + }, #1 ) }
}
ExplSyntaxOff
begin{document}
newarray{xx}
readarray{xx}{1&2&3&4&5}
newarray{yy}
readarray{yy}{6&7&8&9&10}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & xx{1} & yy{1} & fpeval{(xx{1}+yy{1})/2} \
2 & xx{2} & yy{2} & fpeval{(xx{2}+yy{2})/2} \
3 & xx{3} & yy{3} & \
4 & xx{4} & yy{4} & \
5 & xx{5} & yy{5} & \ hline
end{tabular}
end{table}
end{frame}
%newarray{zz}
%readarray{xx}{0&0&0&0&0}
newcountcounter
counter=5
loop
fpevalzz(counter){(xx(counter)+yy(counter))/2}
advance counter by -1
unlessifnum counter<1
repeat
end{document}
fp
add a comment |
How to store a calculated value in array?
zz(1) = ( xx(1) + yy(1) )/2
fpevalzz(counter){(xx(counter)+yy(counter))/2} NOT working
documentclass{beamer}
usepackage{siunitx,amsmath}
usepackage{xparse,xfp}
ExplSyntaxOn
NewDocumentCommand{newarray}{m}
{
seq_new:c { l_hafid_array_#1_seq }
cs_new:cpn { #1 } ##1
{
seq_item:cn { l_hafid_array_#1_seq } { ##1 }
}
}
NewDocumentCommand{readarray}{mm}
{
seq_set_split:cnn { l_hafid_array_#1_seq } { & } { #2 }
}
cs_generate_variant:Nn seq_set_split:Nnn { c }
NewExpandableDocumentCommand{sumarray}{O{15}m}
{
fp_eval:n { round( seq_use:cn { l_hafid_array_#2_seq } { + }, #1 ) }
}
ExplSyntaxOff
begin{document}
newarray{xx}
readarray{xx}{1&2&3&4&5}
newarray{yy}
readarray{yy}{6&7&8&9&10}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & xx{1} & yy{1} & fpeval{(xx{1}+yy{1})/2} \
2 & xx{2} & yy{2} & fpeval{(xx{2}+yy{2})/2} \
3 & xx{3} & yy{3} & \
4 & xx{4} & yy{4} & \
5 & xx{5} & yy{5} & \ hline
end{tabular}
end{table}
end{frame}
%newarray{zz}
%readarray{xx}{0&0&0&0&0}
newcountcounter
counter=5
loop
fpevalzz(counter){(xx(counter)+yy(counter))/2}
advance counter by -1
unlessifnum counter<1
repeat
end{document}
fp
How to store a calculated value in array?
zz(1) = ( xx(1) + yy(1) )/2
fpevalzz(counter){(xx(counter)+yy(counter))/2} NOT working
documentclass{beamer}
usepackage{siunitx,amsmath}
usepackage{xparse,xfp}
ExplSyntaxOn
NewDocumentCommand{newarray}{m}
{
seq_new:c { l_hafid_array_#1_seq }
cs_new:cpn { #1 } ##1
{
seq_item:cn { l_hafid_array_#1_seq } { ##1 }
}
}
NewDocumentCommand{readarray}{mm}
{
seq_set_split:cnn { l_hafid_array_#1_seq } { & } { #2 }
}
cs_generate_variant:Nn seq_set_split:Nnn { c }
NewExpandableDocumentCommand{sumarray}{O{15}m}
{
fp_eval:n { round( seq_use:cn { l_hafid_array_#2_seq } { + }, #1 ) }
}
ExplSyntaxOff
begin{document}
newarray{xx}
readarray{xx}{1&2&3&4&5}
newarray{yy}
readarray{yy}{6&7&8&9&10}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & xx{1} & yy{1} & fpeval{(xx{1}+yy{1})/2} \
2 & xx{2} & yy{2} & fpeval{(xx{2}+yy{2})/2} \
3 & xx{3} & yy{3} & \
4 & xx{4} & yy{4} & \
5 & xx{5} & yy{5} & \ hline
end{tabular}
end{table}
end{frame}
%newarray{zz}
%readarray{xx}{0&0&0&0&0}
newcountcounter
counter=5
loop
fpevalzz(counter){(xx(counter)+yy(counter))/2}
advance counter by -1
unlessifnum counter<1
repeat
end{document}
fp
fp
asked 20 mins ago
sandusandu
3,68442856
3,68442856
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I did not really try to make your example work but would like to propose an alternative way of doing what I think you want to do.
documentclass{beamer}
usepackage{pgfmath}
begin{document}
defxx{{1,2,3,4,5}}
defyy{{6,7,8,9,10}}
newcommand{Parse}[1]{pgfmathparse{#1}pgfmathresult}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & Parse{xx[0]} & Parse{yy[0]} & Parse{xx[0]/2+yy[0]/2}\
2 & Parse{xx[1]} & Parse{yy[1]} & Parse{xx[1]/2+yy[1]/2}\
3 & Parse{xx[2]} & Parse{yy[2]} & Parse{xx[2]/2+yy[2]/2}\
4 & Parse{xx[3]} & Parse{yy[3]} & Parse{xx[3]/2+yy[3]/2}\
5 & Parse{xx[4]} & Parse{yy[4]} & Parse{xx[4]/2+yy[4]/2}\
hline
end{tabular}
end{table}
newcounter{counter}
setcounter{counter}{4}
loop
Parse{xx[numbervalue{counter}]/2+yy[numbervalue{counter}]/2}
addtocounter{counter}{-1}
unlessifnumnumbervalue{counter}=-1
repeat
end{frame}
end{document}
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I did not really try to make your example work but would like to propose an alternative way of doing what I think you want to do.
documentclass{beamer}
usepackage{pgfmath}
begin{document}
defxx{{1,2,3,4,5}}
defyy{{6,7,8,9,10}}
newcommand{Parse}[1]{pgfmathparse{#1}pgfmathresult}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & Parse{xx[0]} & Parse{yy[0]} & Parse{xx[0]/2+yy[0]/2}\
2 & Parse{xx[1]} & Parse{yy[1]} & Parse{xx[1]/2+yy[1]/2}\
3 & Parse{xx[2]} & Parse{yy[2]} & Parse{xx[2]/2+yy[2]/2}\
4 & Parse{xx[3]} & Parse{yy[3]} & Parse{xx[3]/2+yy[3]/2}\
5 & Parse{xx[4]} & Parse{yy[4]} & Parse{xx[4]/2+yy[4]/2}\
hline
end{tabular}
end{table}
newcounter{counter}
setcounter{counter}{4}
loop
Parse{xx[numbervalue{counter}]/2+yy[numbervalue{counter}]/2}
addtocounter{counter}{-1}
unlessifnumnumbervalue{counter}=-1
repeat
end{frame}
end{document}
add a comment |
I did not really try to make your example work but would like to propose an alternative way of doing what I think you want to do.
documentclass{beamer}
usepackage{pgfmath}
begin{document}
defxx{{1,2,3,4,5}}
defyy{{6,7,8,9,10}}
newcommand{Parse}[1]{pgfmathparse{#1}pgfmathresult}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & Parse{xx[0]} & Parse{yy[0]} & Parse{xx[0]/2+yy[0]/2}\
2 & Parse{xx[1]} & Parse{yy[1]} & Parse{xx[1]/2+yy[1]/2}\
3 & Parse{xx[2]} & Parse{yy[2]} & Parse{xx[2]/2+yy[2]/2}\
4 & Parse{xx[3]} & Parse{yy[3]} & Parse{xx[3]/2+yy[3]/2}\
5 & Parse{xx[4]} & Parse{yy[4]} & Parse{xx[4]/2+yy[4]/2}\
hline
end{tabular}
end{table}
newcounter{counter}
setcounter{counter}{4}
loop
Parse{xx[numbervalue{counter}]/2+yy[numbervalue{counter}]/2}
addtocounter{counter}{-1}
unlessifnumnumbervalue{counter}=-1
repeat
end{frame}
end{document}
add a comment |
I did not really try to make your example work but would like to propose an alternative way of doing what I think you want to do.
documentclass{beamer}
usepackage{pgfmath}
begin{document}
defxx{{1,2,3,4,5}}
defyy{{6,7,8,9,10}}
newcommand{Parse}[1]{pgfmathparse{#1}pgfmathresult}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & Parse{xx[0]} & Parse{yy[0]} & Parse{xx[0]/2+yy[0]/2}\
2 & Parse{xx[1]} & Parse{yy[1]} & Parse{xx[1]/2+yy[1]/2}\
3 & Parse{xx[2]} & Parse{yy[2]} & Parse{xx[2]/2+yy[2]/2}\
4 & Parse{xx[3]} & Parse{yy[3]} & Parse{xx[3]/2+yy[3]/2}\
5 & Parse{xx[4]} & Parse{yy[4]} & Parse{xx[4]/2+yy[4]/2}\
hline
end{tabular}
end{table}
newcounter{counter}
setcounter{counter}{4}
loop
Parse{xx[numbervalue{counter}]/2+yy[numbervalue{counter}]/2}
addtocounter{counter}{-1}
unlessifnumnumbervalue{counter}=-1
repeat
end{frame}
end{document}
I did not really try to make your example work but would like to propose an alternative way of doing what I think you want to do.
documentclass{beamer}
usepackage{pgfmath}
begin{document}
defxx{{1,2,3,4,5}}
defyy{{6,7,8,9,10}}
newcommand{Parse}[1]{pgfmathparse{#1}pgfmathresult}
begin{frame}
begin{table}
begin{tabular}{cccc}
No & xx & yy & zz \ hline
1 & Parse{xx[0]} & Parse{yy[0]} & Parse{xx[0]/2+yy[0]/2}\
2 & Parse{xx[1]} & Parse{yy[1]} & Parse{xx[1]/2+yy[1]/2}\
3 & Parse{xx[2]} & Parse{yy[2]} & Parse{xx[2]/2+yy[2]/2}\
4 & Parse{xx[3]} & Parse{yy[3]} & Parse{xx[3]/2+yy[3]/2}\
5 & Parse{xx[4]} & Parse{yy[4]} & Parse{xx[4]/2+yy[4]/2}\
hline
end{tabular}
end{table}
newcounter{counter}
setcounter{counter}{4}
loop
Parse{xx[numbervalue{counter}]/2+yy[numbervalue{counter}]/2}
addtocounter{counter}{-1}
unlessifnumnumbervalue{counter}=-1
repeat
end{frame}
end{document}
answered 2 mins ago
marmotmarmot
110k5137256
110k5137256
add a comment |
add a comment |
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