What is the difference between iptables -S and iptables -L











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The help information doesn't seem to be very informative:



--list    -L [chain [rulenum]]
List the rules in a chain or all chains
--list-rules -S [chain [rulenum]]
Print the rules in a chain or all chains


The only difference is in the choice of word: "list" vs. "print".



THe manual is a bit more detailed but still doesn't help:



   -L, --list [chain]
List all rules in the selected chain. If no chain is selected, all chains are listed. Like every other iptables command, it applies to the specified table (filter is the default), so NAT
rules get listed by
iptables -t nat -n -L
Please note that it is often used with the -n option, in order to avoid long reverse DNS lookups. It is legal to specify the -Z (zero) option as well, in which case the chain(s) will be atom‐
ically listed and zeroed. The exact output is affected by the other arguments given. The exact rules are suppressed until you use
iptables -L -v

-S, --list-rules [chain]
Print all rules in the selected chain. If no chain is selected, all chains are printed like iptables-save. Like every other iptables command, it applies to the specified table (filter is the
default).


Seems to me that -S is actually more detailed and printed out the exact ports that I allowed with a --dports argument. But why is that the case? I don't think the word "print" automatically suggests a higher level of details than "list"?










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    up vote
    0
    down vote

    favorite












    The help information doesn't seem to be very informative:



    --list    -L [chain [rulenum]]
    List the rules in a chain or all chains
    --list-rules -S [chain [rulenum]]
    Print the rules in a chain or all chains


    The only difference is in the choice of word: "list" vs. "print".



    THe manual is a bit more detailed but still doesn't help:



       -L, --list [chain]
    List all rules in the selected chain. If no chain is selected, all chains are listed. Like every other iptables command, it applies to the specified table (filter is the default), so NAT
    rules get listed by
    iptables -t nat -n -L
    Please note that it is often used with the -n option, in order to avoid long reverse DNS lookups. It is legal to specify the -Z (zero) option as well, in which case the chain(s) will be atom‐
    ically listed and zeroed. The exact output is affected by the other arguments given. The exact rules are suppressed until you use
    iptables -L -v

    -S, --list-rules [chain]
    Print all rules in the selected chain. If no chain is selected, all chains are printed like iptables-save. Like every other iptables command, it applies to the specified table (filter is the
    default).


    Seems to me that -S is actually more detailed and printed out the exact ports that I allowed with a --dports argument. But why is that the case? I don't think the word "print" automatically suggests a higher level of details than "list"?










    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      The help information doesn't seem to be very informative:



      --list    -L [chain [rulenum]]
      List the rules in a chain or all chains
      --list-rules -S [chain [rulenum]]
      Print the rules in a chain or all chains


      The only difference is in the choice of word: "list" vs. "print".



      THe manual is a bit more detailed but still doesn't help:



         -L, --list [chain]
      List all rules in the selected chain. If no chain is selected, all chains are listed. Like every other iptables command, it applies to the specified table (filter is the default), so NAT
      rules get listed by
      iptables -t nat -n -L
      Please note that it is often used with the -n option, in order to avoid long reverse DNS lookups. It is legal to specify the -Z (zero) option as well, in which case the chain(s) will be atom‐
      ically listed and zeroed. The exact output is affected by the other arguments given. The exact rules are suppressed until you use
      iptables -L -v

      -S, --list-rules [chain]
      Print all rules in the selected chain. If no chain is selected, all chains are printed like iptables-save. Like every other iptables command, it applies to the specified table (filter is the
      default).


      Seems to me that -S is actually more detailed and printed out the exact ports that I allowed with a --dports argument. But why is that the case? I don't think the word "print" automatically suggests a higher level of details than "list"?










      share|improve this question













      The help information doesn't seem to be very informative:



      --list    -L [chain [rulenum]]
      List the rules in a chain or all chains
      --list-rules -S [chain [rulenum]]
      Print the rules in a chain or all chains


      The only difference is in the choice of word: "list" vs. "print".



      THe manual is a bit more detailed but still doesn't help:



         -L, --list [chain]
      List all rules in the selected chain. If no chain is selected, all chains are listed. Like every other iptables command, it applies to the specified table (filter is the default), so NAT
      rules get listed by
      iptables -t nat -n -L
      Please note that it is often used with the -n option, in order to avoid long reverse DNS lookups. It is legal to specify the -Z (zero) option as well, in which case the chain(s) will be atom‐
      ically listed and zeroed. The exact output is affected by the other arguments given. The exact rules are suppressed until you use
      iptables -L -v

      -S, --list-rules [chain]
      Print all rules in the selected chain. If no chain is selected, all chains are printed like iptables-save. Like every other iptables command, it applies to the specified table (filter is the
      default).


      Seems to me that -S is actually more detailed and printed out the exact ports that I allowed with a --dports argument. But why is that the case? I don't think the word "print" automatically suggests a higher level of details than "list"?







      networking iptables firewall






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      asked 2 days ago









      xji

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          The difference is the output format. The -S option produces in the the fashion of iptables-save. And this can be reused with iptables-apply,iptables-restore. (Check their man pages entries for details.) So you can think of the difference as:





          • -L is for reference, to get a clue of what's there


          • -S is for reusable output, which is for machine parsing


          If you think the -S option gives more details, then you should learn other iptables parameters that provide more details in combination with -L.






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            1 Answer
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            1 Answer
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            active

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            up vote
            4
            down vote



            accepted










            The difference is the output format. The -S option produces in the the fashion of iptables-save. And this can be reused with iptables-apply,iptables-restore. (Check their man pages entries for details.) So you can think of the difference as:





            • -L is for reference, to get a clue of what's there


            • -S is for reusable output, which is for machine parsing


            If you think the -S option gives more details, then you should learn other iptables parameters that provide more details in combination with -L.






            share|improve this answer

























              up vote
              4
              down vote



              accepted










              The difference is the output format. The -S option produces in the the fashion of iptables-save. And this can be reused with iptables-apply,iptables-restore. (Check their man pages entries for details.) So you can think of the difference as:





              • -L is for reference, to get a clue of what's there


              • -S is for reusable output, which is for machine parsing


              If you think the -S option gives more details, then you should learn other iptables parameters that provide more details in combination with -L.






              share|improve this answer























                up vote
                4
                down vote



                accepted







                up vote
                4
                down vote



                accepted






                The difference is the output format. The -S option produces in the the fashion of iptables-save. And this can be reused with iptables-apply,iptables-restore. (Check their man pages entries for details.) So you can think of the difference as:





                • -L is for reference, to get a clue of what's there


                • -S is for reusable output, which is for machine parsing


                If you think the -S option gives more details, then you should learn other iptables parameters that provide more details in combination with -L.






                share|improve this answer












                The difference is the output format. The -S option produces in the the fashion of iptables-save. And this can be reused with iptables-apply,iptables-restore. (Check their man pages entries for details.) So you can think of the difference as:





                • -L is for reference, to get a clue of what's there


                • -S is for reusable output, which is for machine parsing


                If you think the -S option gives more details, then you should learn other iptables parameters that provide more details in combination with -L.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 2 days ago









                Tomasz

                9,13052964




                9,13052964






























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