Sstrhsrtj

I need to get the list of files(.log/.lst) present in a directory($logfolder) whose creation date is in a specific $year and $month

stat  --format='%y %n'  $logfolder/* |

  grep "$year-$month-"|

  awk -F' ' '{print $4}'|

  grep 'log$|lst$' > $archivepath/filesToArchive

This doesn't work when I query the command to a folder where there are too many files. I get the following error:

-bash: /usr/bin/stat: Argument list too long

For a funny possibility, if your find handles -newerXY, use it! For example to get the files from year 1977 and month October:

find "$logfolder" ( -name '*.log' -o -name '*.lst' ) -newermt "1977-10-01" ! -newermt "1977-10-01 +1 month"

Done!

As you already have the variables year and month it's straightforward to write as:

find "$logfolder" ( -name '*.log' -o -name '*.lst' ) -newermt "$year-$month-01" ! -newermt "$year-$month-01 +1 month"

Only one find command! amazing!

I would do it like this:

find "$logfolder" ( -name '*.log' -o -name '*lst' ) -printf "%TBt%TYt%pn" |

     awk '$1==m && $2==y' m="$month" y="$year" | cut -f 3- 

Explanation

By grouping the two -name calls in parentheses, you can combine them with the -o (or) flag. This will make find look for either .log or .lst files. The -printf (a GNU extension) prints the file's modification month (%TB), then its modification year (%TY) and then its path (%p), with a tab (t) between each field.

The awk simply checks that the 1st field (the month) is the same as $month and the second is the same as $year.

The cut removes the first two fields (the month and year) and prints everything from the 3rd field on.

I tested the above by creating files modified in December 2012 (and set $month to "December" and $year to 2012):

$ touch -d "December 13 2012" {a,b,c}{.lst,.log}

$ touch c.lst a.log ## c.lst and a.log now have today's modification date.

$ find $logfolder ( -name '*.log' -o -name '*lst' ) -printf "%TBt%TYt%pn" |

  awk '$1==m && $2==y' m="$month" y="$year" | cut -f 3-

./b.log

./c.log

./b.lst

./a.lst

(note that it assumes file and directory names don't contain newline characters).

Try this:

find $logfolder -type f -exec stat --format='%y %n' "{}" + |

  grep "$year-$month-"|

  awk -F' ' '{print $4}'|

  grep 'log$|lst$' > $archivepath/filesToArchive

ls -lh *.log *.lst logfolder | grep year | grep month