How can I prepend filenames with ascending numbers like 1_ 2_?











up vote
2
down vote

favorite












How can I add numbers to the files in one directory?



In one directory I have files like below:



fileA
fileB
fileC
fileD


I want to prepend ascending numbers to them, like this:



1_fileA
2_fileB
3_fileC
4_fileD


Thank you in advance.










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  • So you want to rename the files?
    – PerlDuck
    yesterday










  • @PerlDuck Yes, I have to enumarte them changing their name.
    – paweljvn
    yesterday










  • Related: askubuntu.com/q/839959
    – Justin
    22 hours ago















up vote
2
down vote

favorite












How can I add numbers to the files in one directory?



In one directory I have files like below:



fileA
fileB
fileC
fileD


I want to prepend ascending numbers to them, like this:



1_fileA
2_fileB
3_fileC
4_fileD


Thank you in advance.










share|improve this question









New contributor




paweljvn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • So you want to rename the files?
    – PerlDuck
    yesterday










  • @PerlDuck Yes, I have to enumarte them changing their name.
    – paweljvn
    yesterday










  • Related: askubuntu.com/q/839959
    – Justin
    22 hours ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











How can I add numbers to the files in one directory?



In one directory I have files like below:



fileA
fileB
fileC
fileD


I want to prepend ascending numbers to them, like this:



1_fileA
2_fileB
3_fileC
4_fileD


Thank you in advance.










share|improve this question









New contributor




paweljvn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











How can I add numbers to the files in one directory?



In one directory I have files like below:



fileA
fileB
fileC
fileD


I want to prepend ascending numbers to them, like this:



1_fileA
2_fileB
3_fileC
4_fileD


Thank you in advance.







command-line bash batch-rename






share|improve this question









New contributor




paweljvn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




paweljvn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited yesterday









Zanna

49k13123234




49k13123234






New contributor




paweljvn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









paweljvn

185




185




New contributor




paweljvn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





paweljvn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






paweljvn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • So you want to rename the files?
    – PerlDuck
    yesterday










  • @PerlDuck Yes, I have to enumarte them changing their name.
    – paweljvn
    yesterday










  • Related: askubuntu.com/q/839959
    – Justin
    22 hours ago


















  • So you want to rename the files?
    – PerlDuck
    yesterday










  • @PerlDuck Yes, I have to enumarte them changing their name.
    – paweljvn
    yesterday










  • Related: askubuntu.com/q/839959
    – Justin
    22 hours ago
















So you want to rename the files?
– PerlDuck
yesterday




So you want to rename the files?
– PerlDuck
yesterday












@PerlDuck Yes, I have to enumarte them changing their name.
– paweljvn
yesterday




@PerlDuck Yes, I have to enumarte them changing their name.
– paweljvn
yesterday












Related: askubuntu.com/q/839959
– Justin
22 hours ago




Related: askubuntu.com/q/839959
– Justin
22 hours ago










4 Answers
4






active

oldest

votes

















up vote
4
down vote



accepted










One of the solutions:



cd <your dir> then run in bash (copy and paste in command-line):



n=1; for f in *; do mv "$f" "$((n++))_$f"; done


Bash script case:



#!/bin/bash
n=1
for f in *
do
if [ "$f" = "rename.sh" ]
then
continue
fi
mv "$f" "$((n++))_$f"
done


save it as rename.sh to dir with files to rename, chmod +x rename.sh then run it ./rename.sh






share|improve this answer























  • but can I also run this from vim? I mean to put your code in vim as #!/bin/bash and the run it from the command line?
    – paweljvn
    yesterday










  • Sure. But you need add this simple command to bash file. Then You need to solve self-renaming of this rename.sh file.
    – S_Flash
    yesterday






  • 1




    Added example with bash file. If you need something like bash command to run it in any file system place, you need use first example saved in bash file and add this bash file to PATH with alias.
    – S_Flash
    yesterday


















up vote
4
down vote













If there are more than 9 files, I would use printf to pad the number to get the expected sort order, like this



n=0
for f in *
do printf -v new "%2d$((++n))_$f"
echo mv -v -- "$f" "$new"
done


Remove echo when you see the correct result.



Explanation



In this line, do printf -v new "%2d$((++n))_$f" we create a format for the new filenames and put it into the variable new.



%2d is a 2 digit decimal number. Instead of 2d, you can use 3d etc to get another leading 0 (if you have more than 99 files).



((++n)) increments the variable n (which we set to 0 at the start of the script. Since it is iterated once each time the loop is run, files get incremented name prefixes.



-v makes mv print what will be changed.



-- in the mv statement is to prevent filenames that start with - being interpreted as options.






share|improve this answer




























    up vote
    2
    down vote















    That’s a job for rename:



    rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *


    This defines a variable, increases it if it’s not set (else it would start with 0 instead of 1) and replaces the beginning of the filename with the number increasing it every time. You can change the format easily, e.g. to make it three-digit (001, 002, …) use "%03d_". Running it with -n only prints the changes, to actually perform the renaming remove this flag.



    Example run



    $ ls -1
    fileA
    fileB
    fileC
    fileD
    $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
    rename(fileA, 1_fileA)
    rename(fileB, 2_fileB)
    rename(fileC, 3_fileC)
    rename(fileD, 4_fileD)
    $ rename 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
    $ ls -1
    1_fileA
    2_fileB
    3_fileC
    4_fileD





    share|improve this answer




























      up vote
      0
      down vote













      One option is



      cd /path/to/folder/
      ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'



      • This works fine, except with the file names with new line "n". Switch '-1v'takes care of spaces and tabs,


      • Other commands posted here change the order of files with numbers e.g. 10a comes before 1a.


      • Whichever suits in a situation.



      I had some time to test all these commands. Here are the results.



      $ ls
      001abc.txt '10a bc.txt' 1abc.txt '2ab c.txt' 'a'$'t''bc.txt'

      $ ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'
      Reading filenames from file handle (GLOB(0x55cb57991b28))
      rename(001abc.txt, 01_001abc.txt)
      rename(1abc.txt, 02_1abc.txt)
      rename(2ab c.txt, 03_2ab c.txt)
      rename(10a bc.txt, 04_10a bc.txt)
      rename(a bc.txt, 05_a bc.txt)

      $ n=1; for f in *; do echo mv "$f" "$((n++))_$f"; done
      mv 001abc.txt 1_001abc.txt
      mv 10a bc.txt 2_10a bc.txt
      mv 1abc.txt 3_1abc.txt
      mv 2ab c.txt 4_2ab c.txt
      mv a bc.txt 5_a bc.txt

      $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
      mv -v -- 001abc.txt 09_001abc.txt
      mv -v -- 10a bc.txt 010_10a bc.txt
      mv -v -- 1abc.txt 011_1abc.txt
      mv -v -- 2ab c.txt 012_2ab c.txt
      mv -v -- a bc.txt 013_a bc.txt

      $ ./rename.sh
      mv 001abc.txt 1_001abc.txt
      mv 10a bc.txt 2_10a bc.txt
      mv 1abc.txt 3_1abc.txt
      mv 2ab c.txt 4_2ab c.txt
      mv a bc.txt 5_a bc.txt

      $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
      rename(001abc.txt, 1_001abc.txt)
      rename(10a bc.txt, 2_10a bc.txt)
      rename(1abc.txt, 3_1abc.txt)
      rename(2ab c.txt, 4_2ab c.txt)
      rename(a bc.txt, 5_a bc.txt)
      rename(rename.sh, 6_rename.sh)

      $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
      mv -v -- 001abc.txt 01_001abc.txt
      mv -v -- 10a bc.txt 02_10a bc.txt
      mv -v -- 1abc.txt 03_1abc.txt
      mv -v -- 2ab c.txt 04_2ab c.txt
      mv -v -- a bc.txt 05_a bc.txt
      mv -v -- rename.sh 06_rename.sh





      share|improve this answer























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        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes








        up vote
        4
        down vote



        accepted










        One of the solutions:



        cd <your dir> then run in bash (copy and paste in command-line):



        n=1; for f in *; do mv "$f" "$((n++))_$f"; done


        Bash script case:



        #!/bin/bash
        n=1
        for f in *
        do
        if [ "$f" = "rename.sh" ]
        then
        continue
        fi
        mv "$f" "$((n++))_$f"
        done


        save it as rename.sh to dir with files to rename, chmod +x rename.sh then run it ./rename.sh






        share|improve this answer























        • but can I also run this from vim? I mean to put your code in vim as #!/bin/bash and the run it from the command line?
          – paweljvn
          yesterday










        • Sure. But you need add this simple command to bash file. Then You need to solve self-renaming of this rename.sh file.
          – S_Flash
          yesterday






        • 1




          Added example with bash file. If you need something like bash command to run it in any file system place, you need use first example saved in bash file and add this bash file to PATH with alias.
          – S_Flash
          yesterday















        up vote
        4
        down vote



        accepted










        One of the solutions:



        cd <your dir> then run in bash (copy and paste in command-line):



        n=1; for f in *; do mv "$f" "$((n++))_$f"; done


        Bash script case:



        #!/bin/bash
        n=1
        for f in *
        do
        if [ "$f" = "rename.sh" ]
        then
        continue
        fi
        mv "$f" "$((n++))_$f"
        done


        save it as rename.sh to dir with files to rename, chmod +x rename.sh then run it ./rename.sh






        share|improve this answer























        • but can I also run this from vim? I mean to put your code in vim as #!/bin/bash and the run it from the command line?
          – paweljvn
          yesterday










        • Sure. But you need add this simple command to bash file. Then You need to solve self-renaming of this rename.sh file.
          – S_Flash
          yesterday






        • 1




          Added example with bash file. If you need something like bash command to run it in any file system place, you need use first example saved in bash file and add this bash file to PATH with alias.
          – S_Flash
          yesterday













        up vote
        4
        down vote



        accepted







        up vote
        4
        down vote



        accepted






        One of the solutions:



        cd <your dir> then run in bash (copy and paste in command-line):



        n=1; for f in *; do mv "$f" "$((n++))_$f"; done


        Bash script case:



        #!/bin/bash
        n=1
        for f in *
        do
        if [ "$f" = "rename.sh" ]
        then
        continue
        fi
        mv "$f" "$((n++))_$f"
        done


        save it as rename.sh to dir with files to rename, chmod +x rename.sh then run it ./rename.sh






        share|improve this answer














        One of the solutions:



        cd <your dir> then run in bash (copy and paste in command-line):



        n=1; for f in *; do mv "$f" "$((n++))_$f"; done


        Bash script case:



        #!/bin/bash
        n=1
        for f in *
        do
        if [ "$f" = "rename.sh" ]
        then
        continue
        fi
        mv "$f" "$((n++))_$f"
        done


        save it as rename.sh to dir with files to rename, chmod +x rename.sh then run it ./rename.sh







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited yesterday

























        answered yesterday









        S_Flash

        1,007117




        1,007117












        • but can I also run this from vim? I mean to put your code in vim as #!/bin/bash and the run it from the command line?
          – paweljvn
          yesterday










        • Sure. But you need add this simple command to bash file. Then You need to solve self-renaming of this rename.sh file.
          – S_Flash
          yesterday






        • 1




          Added example with bash file. If you need something like bash command to run it in any file system place, you need use first example saved in bash file and add this bash file to PATH with alias.
          – S_Flash
          yesterday


















        • but can I also run this from vim? I mean to put your code in vim as #!/bin/bash and the run it from the command line?
          – paweljvn
          yesterday










        • Sure. But you need add this simple command to bash file. Then You need to solve self-renaming of this rename.sh file.
          – S_Flash
          yesterday






        • 1




          Added example with bash file. If you need something like bash command to run it in any file system place, you need use first example saved in bash file and add this bash file to PATH with alias.
          – S_Flash
          yesterday
















        but can I also run this from vim? I mean to put your code in vim as #!/bin/bash and the run it from the command line?
        – paweljvn
        yesterday




        but can I also run this from vim? I mean to put your code in vim as #!/bin/bash and the run it from the command line?
        – paweljvn
        yesterday












        Sure. But you need add this simple command to bash file. Then You need to solve self-renaming of this rename.sh file.
        – S_Flash
        yesterday




        Sure. But you need add this simple command to bash file. Then You need to solve self-renaming of this rename.sh file.
        – S_Flash
        yesterday




        1




        1




        Added example with bash file. If you need something like bash command to run it in any file system place, you need use first example saved in bash file and add this bash file to PATH with alias.
        – S_Flash
        yesterday




        Added example with bash file. If you need something like bash command to run it in any file system place, you need use first example saved in bash file and add this bash file to PATH with alias.
        – S_Flash
        yesterday












        up vote
        4
        down vote













        If there are more than 9 files, I would use printf to pad the number to get the expected sort order, like this



        n=0
        for f in *
        do printf -v new "%2d$((++n))_$f"
        echo mv -v -- "$f" "$new"
        done


        Remove echo when you see the correct result.



        Explanation



        In this line, do printf -v new "%2d$((++n))_$f" we create a format for the new filenames and put it into the variable new.



        %2d is a 2 digit decimal number. Instead of 2d, you can use 3d etc to get another leading 0 (if you have more than 99 files).



        ((++n)) increments the variable n (which we set to 0 at the start of the script. Since it is iterated once each time the loop is run, files get incremented name prefixes.



        -v makes mv print what will be changed.



        -- in the mv statement is to prevent filenames that start with - being interpreted as options.






        share|improve this answer

























          up vote
          4
          down vote













          If there are more than 9 files, I would use printf to pad the number to get the expected sort order, like this



          n=0
          for f in *
          do printf -v new "%2d$((++n))_$f"
          echo mv -v -- "$f" "$new"
          done


          Remove echo when you see the correct result.



          Explanation



          In this line, do printf -v new "%2d$((++n))_$f" we create a format for the new filenames and put it into the variable new.



          %2d is a 2 digit decimal number. Instead of 2d, you can use 3d etc to get another leading 0 (if you have more than 99 files).



          ((++n)) increments the variable n (which we set to 0 at the start of the script. Since it is iterated once each time the loop is run, files get incremented name prefixes.



          -v makes mv print what will be changed.



          -- in the mv statement is to prevent filenames that start with - being interpreted as options.






          share|improve this answer























            up vote
            4
            down vote










            up vote
            4
            down vote









            If there are more than 9 files, I would use printf to pad the number to get the expected sort order, like this



            n=0
            for f in *
            do printf -v new "%2d$((++n))_$f"
            echo mv -v -- "$f" "$new"
            done


            Remove echo when you see the correct result.



            Explanation



            In this line, do printf -v new "%2d$((++n))_$f" we create a format for the new filenames and put it into the variable new.



            %2d is a 2 digit decimal number. Instead of 2d, you can use 3d etc to get another leading 0 (if you have more than 99 files).



            ((++n)) increments the variable n (which we set to 0 at the start of the script. Since it is iterated once each time the loop is run, files get incremented name prefixes.



            -v makes mv print what will be changed.



            -- in the mv statement is to prevent filenames that start with - being interpreted as options.






            share|improve this answer












            If there are more than 9 files, I would use printf to pad the number to get the expected sort order, like this



            n=0
            for f in *
            do printf -v new "%2d$((++n))_$f"
            echo mv -v -- "$f" "$new"
            done


            Remove echo when you see the correct result.



            Explanation



            In this line, do printf -v new "%2d$((++n))_$f" we create a format for the new filenames and put it into the variable new.



            %2d is a 2 digit decimal number. Instead of 2d, you can use 3d etc to get another leading 0 (if you have more than 99 files).



            ((++n)) increments the variable n (which we set to 0 at the start of the script. Since it is iterated once each time the loop is run, files get incremented name prefixes.



            -v makes mv print what will be changed.



            -- in the mv statement is to prevent filenames that start with - being interpreted as options.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered yesterday









            Zanna

            49k13123234




            49k13123234






















                up vote
                2
                down vote















                That’s a job for rename:



                rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *


                This defines a variable, increases it if it’s not set (else it would start with 0 instead of 1) and replaces the beginning of the filename with the number increasing it every time. You can change the format easily, e.g. to make it three-digit (001, 002, …) use "%03d_". Running it with -n only prints the changes, to actually perform the renaming remove this flag.



                Example run



                $ ls -1
                fileA
                fileB
                fileC
                fileD
                $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                rename(fileA, 1_fileA)
                rename(fileB, 2_fileB)
                rename(fileC, 3_fileC)
                rename(fileD, 4_fileD)
                $ rename 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                $ ls -1
                1_fileA
                2_fileB
                3_fileC
                4_fileD





                share|improve this answer

























                  up vote
                  2
                  down vote















                  That’s a job for rename:



                  rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *


                  This defines a variable, increases it if it’s not set (else it would start with 0 instead of 1) and replaces the beginning of the filename with the number increasing it every time. You can change the format easily, e.g. to make it three-digit (001, 002, …) use "%03d_". Running it with -n only prints the changes, to actually perform the renaming remove this flag.



                  Example run



                  $ ls -1
                  fileA
                  fileB
                  fileC
                  fileD
                  $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                  rename(fileA, 1_fileA)
                  rename(fileB, 2_fileB)
                  rename(fileC, 3_fileC)
                  rename(fileD, 4_fileD)
                  $ rename 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                  $ ls -1
                  1_fileA
                  2_fileB
                  3_fileC
                  4_fileD





                  share|improve this answer























                    up vote
                    2
                    down vote










                    up vote
                    2
                    down vote











                    That’s a job for rename:



                    rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *


                    This defines a variable, increases it if it’s not set (else it would start with 0 instead of 1) and replaces the beginning of the filename with the number increasing it every time. You can change the format easily, e.g. to make it three-digit (001, 002, …) use "%03d_". Running it with -n only prints the changes, to actually perform the renaming remove this flag.



                    Example run



                    $ ls -1
                    fileA
                    fileB
                    fileC
                    fileD
                    $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                    rename(fileA, 1_fileA)
                    rename(fileB, 2_fileB)
                    rename(fileC, 3_fileC)
                    rename(fileD, 4_fileD)
                    $ rename 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                    $ ls -1
                    1_fileA
                    2_fileB
                    3_fileC
                    4_fileD





                    share|improve this answer














                    That’s a job for rename:



                    rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *


                    This defines a variable, increases it if it’s not set (else it would start with 0 instead of 1) and replaces the beginning of the filename with the number increasing it every time. You can change the format easily, e.g. to make it three-digit (001, 002, …) use "%03d_". Running it with -n only prints the changes, to actually perform the renaming remove this flag.



                    Example run



                    $ ls -1
                    fileA
                    fileB
                    fileC
                    fileD
                    $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                    rename(fileA, 1_fileA)
                    rename(fileB, 2_fileB)
                    rename(fileC, 3_fileC)
                    rename(fileD, 4_fileD)
                    $ rename 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                    $ ls -1
                    1_fileA
                    2_fileB
                    3_fileC
                    4_fileD






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered yesterday









                    dessert

                    21.2k55896




                    21.2k55896






















                        up vote
                        0
                        down vote













                        One option is



                        cd /path/to/folder/
                        ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'



                        • This works fine, except with the file names with new line "n". Switch '-1v'takes care of spaces and tabs,


                        • Other commands posted here change the order of files with numbers e.g. 10a comes before 1a.


                        • Whichever suits in a situation.



                        I had some time to test all these commands. Here are the results.



                        $ ls
                        001abc.txt '10a bc.txt' 1abc.txt '2ab c.txt' 'a'$'t''bc.txt'

                        $ ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'
                        Reading filenames from file handle (GLOB(0x55cb57991b28))
                        rename(001abc.txt, 01_001abc.txt)
                        rename(1abc.txt, 02_1abc.txt)
                        rename(2ab c.txt, 03_2ab c.txt)
                        rename(10a bc.txt, 04_10a bc.txt)
                        rename(a bc.txt, 05_a bc.txt)

                        $ n=1; for f in *; do echo mv "$f" "$((n++))_$f"; done
                        mv 001abc.txt 1_001abc.txt
                        mv 10a bc.txt 2_10a bc.txt
                        mv 1abc.txt 3_1abc.txt
                        mv 2ab c.txt 4_2ab c.txt
                        mv a bc.txt 5_a bc.txt

                        $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
                        mv -v -- 001abc.txt 09_001abc.txt
                        mv -v -- 10a bc.txt 010_10a bc.txt
                        mv -v -- 1abc.txt 011_1abc.txt
                        mv -v -- 2ab c.txt 012_2ab c.txt
                        mv -v -- a bc.txt 013_a bc.txt

                        $ ./rename.sh
                        mv 001abc.txt 1_001abc.txt
                        mv 10a bc.txt 2_10a bc.txt
                        mv 1abc.txt 3_1abc.txt
                        mv 2ab c.txt 4_2ab c.txt
                        mv a bc.txt 5_a bc.txt

                        $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                        rename(001abc.txt, 1_001abc.txt)
                        rename(10a bc.txt, 2_10a bc.txt)
                        rename(1abc.txt, 3_1abc.txt)
                        rename(2ab c.txt, 4_2ab c.txt)
                        rename(a bc.txt, 5_a bc.txt)
                        rename(rename.sh, 6_rename.sh)

                        $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
                        mv -v -- 001abc.txt 01_001abc.txt
                        mv -v -- 10a bc.txt 02_10a bc.txt
                        mv -v -- 1abc.txt 03_1abc.txt
                        mv -v -- 2ab c.txt 04_2ab c.txt
                        mv -v -- a bc.txt 05_a bc.txt
                        mv -v -- rename.sh 06_rename.sh





                        share|improve this answer



























                          up vote
                          0
                          down vote













                          One option is



                          cd /path/to/folder/
                          ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'



                          • This works fine, except with the file names with new line "n". Switch '-1v'takes care of spaces and tabs,


                          • Other commands posted here change the order of files with numbers e.g. 10a comes before 1a.


                          • Whichever suits in a situation.



                          I had some time to test all these commands. Here are the results.



                          $ ls
                          001abc.txt '10a bc.txt' 1abc.txt '2ab c.txt' 'a'$'t''bc.txt'

                          $ ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'
                          Reading filenames from file handle (GLOB(0x55cb57991b28))
                          rename(001abc.txt, 01_001abc.txt)
                          rename(1abc.txt, 02_1abc.txt)
                          rename(2ab c.txt, 03_2ab c.txt)
                          rename(10a bc.txt, 04_10a bc.txt)
                          rename(a bc.txt, 05_a bc.txt)

                          $ n=1; for f in *; do echo mv "$f" "$((n++))_$f"; done
                          mv 001abc.txt 1_001abc.txt
                          mv 10a bc.txt 2_10a bc.txt
                          mv 1abc.txt 3_1abc.txt
                          mv 2ab c.txt 4_2ab c.txt
                          mv a bc.txt 5_a bc.txt

                          $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
                          mv -v -- 001abc.txt 09_001abc.txt
                          mv -v -- 10a bc.txt 010_10a bc.txt
                          mv -v -- 1abc.txt 011_1abc.txt
                          mv -v -- 2ab c.txt 012_2ab c.txt
                          mv -v -- a bc.txt 013_a bc.txt

                          $ ./rename.sh
                          mv 001abc.txt 1_001abc.txt
                          mv 10a bc.txt 2_10a bc.txt
                          mv 1abc.txt 3_1abc.txt
                          mv 2ab c.txt 4_2ab c.txt
                          mv a bc.txt 5_a bc.txt

                          $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                          rename(001abc.txt, 1_001abc.txt)
                          rename(10a bc.txt, 2_10a bc.txt)
                          rename(1abc.txt, 3_1abc.txt)
                          rename(2ab c.txt, 4_2ab c.txt)
                          rename(a bc.txt, 5_a bc.txt)
                          rename(rename.sh, 6_rename.sh)

                          $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
                          mv -v -- 001abc.txt 01_001abc.txt
                          mv -v -- 10a bc.txt 02_10a bc.txt
                          mv -v -- 1abc.txt 03_1abc.txt
                          mv -v -- 2ab c.txt 04_2ab c.txt
                          mv -v -- a bc.txt 05_a bc.txt
                          mv -v -- rename.sh 06_rename.sh





                          share|improve this answer

























                            up vote
                            0
                            down vote










                            up vote
                            0
                            down vote









                            One option is



                            cd /path/to/folder/
                            ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'



                            • This works fine, except with the file names with new line "n". Switch '-1v'takes care of spaces and tabs,


                            • Other commands posted here change the order of files with numbers e.g. 10a comes before 1a.


                            • Whichever suits in a situation.



                            I had some time to test all these commands. Here are the results.



                            $ ls
                            001abc.txt '10a bc.txt' 1abc.txt '2ab c.txt' 'a'$'t''bc.txt'

                            $ ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'
                            Reading filenames from file handle (GLOB(0x55cb57991b28))
                            rename(001abc.txt, 01_001abc.txt)
                            rename(1abc.txt, 02_1abc.txt)
                            rename(2ab c.txt, 03_2ab c.txt)
                            rename(10a bc.txt, 04_10a bc.txt)
                            rename(a bc.txt, 05_a bc.txt)

                            $ n=1; for f in *; do echo mv "$f" "$((n++))_$f"; done
                            mv 001abc.txt 1_001abc.txt
                            mv 10a bc.txt 2_10a bc.txt
                            mv 1abc.txt 3_1abc.txt
                            mv 2ab c.txt 4_2ab c.txt
                            mv a bc.txt 5_a bc.txt

                            $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
                            mv -v -- 001abc.txt 09_001abc.txt
                            mv -v -- 10a bc.txt 010_10a bc.txt
                            mv -v -- 1abc.txt 011_1abc.txt
                            mv -v -- 2ab c.txt 012_2ab c.txt
                            mv -v -- a bc.txt 013_a bc.txt

                            $ ./rename.sh
                            mv 001abc.txt 1_001abc.txt
                            mv 10a bc.txt 2_10a bc.txt
                            mv 1abc.txt 3_1abc.txt
                            mv 2ab c.txt 4_2ab c.txt
                            mv a bc.txt 5_a bc.txt

                            $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                            rename(001abc.txt, 1_001abc.txt)
                            rename(10a bc.txt, 2_10a bc.txt)
                            rename(1abc.txt, 3_1abc.txt)
                            rename(2ab c.txt, 4_2ab c.txt)
                            rename(a bc.txt, 5_a bc.txt)
                            rename(rename.sh, 6_rename.sh)

                            $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
                            mv -v -- 001abc.txt 01_001abc.txt
                            mv -v -- 10a bc.txt 02_10a bc.txt
                            mv -v -- 1abc.txt 03_1abc.txt
                            mv -v -- 2ab c.txt 04_2ab c.txt
                            mv -v -- a bc.txt 05_a bc.txt
                            mv -v -- rename.sh 06_rename.sh





                            share|improve this answer














                            One option is



                            cd /path/to/folder/
                            ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'



                            • This works fine, except with the file names with new line "n". Switch '-1v'takes care of spaces and tabs,


                            • Other commands posted here change the order of files with numbers e.g. 10a comes before 1a.


                            • Whichever suits in a situation.



                            I had some time to test all these commands. Here are the results.



                            $ ls
                            001abc.txt '10a bc.txt' 1abc.txt '2ab c.txt' 'a'$'t''bc.txt'

                            $ ls -1v | rename -n -v 's/^/sprintf("%02d_", ++our$i)/e'
                            Reading filenames from file handle (GLOB(0x55cb57991b28))
                            rename(001abc.txt, 01_001abc.txt)
                            rename(1abc.txt, 02_1abc.txt)
                            rename(2ab c.txt, 03_2ab c.txt)
                            rename(10a bc.txt, 04_10a bc.txt)
                            rename(a bc.txt, 05_a bc.txt)

                            $ n=1; for f in *; do echo mv "$f" "$((n++))_$f"; done
                            mv 001abc.txt 1_001abc.txt
                            mv 10a bc.txt 2_10a bc.txt
                            mv 1abc.txt 3_1abc.txt
                            mv 2ab c.txt 4_2ab c.txt
                            mv a bc.txt 5_a bc.txt

                            $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
                            mv -v -- 001abc.txt 09_001abc.txt
                            mv -v -- 10a bc.txt 010_10a bc.txt
                            mv -v -- 1abc.txt 011_1abc.txt
                            mv -v -- 2ab c.txt 012_2ab c.txt
                            mv -v -- a bc.txt 013_a bc.txt

                            $ ./rename.sh
                            mv 001abc.txt 1_001abc.txt
                            mv 10a bc.txt 2_10a bc.txt
                            mv 1abc.txt 3_1abc.txt
                            mv 2ab c.txt 4_2ab c.txt
                            mv a bc.txt 5_a bc.txt

                            $ rename -n 'our $i; if (!$i) {$i++}; s/^/sprintf("%d_", $i++)/e' *
                            rename(001abc.txt, 1_001abc.txt)
                            rename(10a bc.txt, 2_10a bc.txt)
                            rename(1abc.txt, 3_1abc.txt)
                            rename(2ab c.txt, 4_2ab c.txt)
                            rename(a bc.txt, 5_a bc.txt)
                            rename(rename.sh, 6_rename.sh)

                            $ for f in *; do printf -v new "%2d$((++n))_$f"; echo mv -v -- "$f" "$new"; done
                            mv -v -- 001abc.txt 01_001abc.txt
                            mv -v -- 10a bc.txt 02_10a bc.txt
                            mv -v -- 1abc.txt 03_1abc.txt
                            mv -v -- 2ab c.txt 04_2ab c.txt
                            mv -v -- a bc.txt 05_a bc.txt
                            mv -v -- rename.sh 06_rename.sh






                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited 13 hours ago

























                            answered 14 hours ago









                            Hobbyist

                            989617




                            989617






















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