Central alignment of text or numbers in `Table` Environment











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I want to know how to centre-align a text or a number while using multicolumn in Table environment. I need to prepare a table as shown in the image below. Table for my paper



The MWE for the above table is as follows:



documentclass{article}

%%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
usepackage{multirow}
usepackage{calc}
usepackage{array}
newcolumntype{L}[1]{>
{raggedrightletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{C}[1]{>
{centeringletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{R}[1]{>
{raggedleftletnewline\arraybackslashhspace{0pt}}m{#1}}
newcommand{mc}[3]{multicolumn{#1}{#2}{#3}}
newcommand{mr}[3]{multirow{#1}{#2}{#3}}
usepackage{booktabs}
begin{document}

begin{table}[ht!]
begin{center}
begin{tabular}{cccccccccccccc}hline
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{C{3cm}|}{1} & mc{3}{C{3cm}|}{2} & mc{3}{C{3cm}|}{3}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is bounded } & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is unbounded } & mc{3}{C{3cm}|}{$T_{alpha}^{-1}$ does not exists}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|L{0.75cm}|}{$I$} & mc{3}{C{2.5cm}|}{$R(T-alpha I)=X$} & mc{3}{p{3cm}|}{$alpha in rho (T,X)$} & mc{3}{C{3cm}|}{$-$} & mc{3}{p{3cm}|}{centering$alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$}\ hline
end{tabular}
end{center}
end{table}
%
end{document}


The output of the MWE looks similar to the one in the image. The only issue is the alignment of the text or numbers.



Please help or provide suggestions?










share|improve this question






















  • What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
    – Bernard
    yesterday










  • @Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
    – Tanvir
    yesterday










  • The solutions provided below solved the problem I had with the alignment.
    – Tanvir
    yesterday















up vote
3
down vote

favorite
1












I want to know how to centre-align a text or a number while using multicolumn in Table environment. I need to prepare a table as shown in the image below. Table for my paper



The MWE for the above table is as follows:



documentclass{article}

%%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
usepackage{multirow}
usepackage{calc}
usepackage{array}
newcolumntype{L}[1]{>
{raggedrightletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{C}[1]{>
{centeringletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{R}[1]{>
{raggedleftletnewline\arraybackslashhspace{0pt}}m{#1}}
newcommand{mc}[3]{multicolumn{#1}{#2}{#3}}
newcommand{mr}[3]{multirow{#1}{#2}{#3}}
usepackage{booktabs}
begin{document}

begin{table}[ht!]
begin{center}
begin{tabular}{cccccccccccccc}hline
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{C{3cm}|}{1} & mc{3}{C{3cm}|}{2} & mc{3}{C{3cm}|}{3}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is bounded } & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is unbounded } & mc{3}{C{3cm}|}{$T_{alpha}^{-1}$ does not exists}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|L{0.75cm}|}{$I$} & mc{3}{C{2.5cm}|}{$R(T-alpha I)=X$} & mc{3}{p{3cm}|}{$alpha in rho (T,X)$} & mc{3}{C{3cm}|}{$-$} & mc{3}{p{3cm}|}{centering$alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$}\ hline
end{tabular}
end{center}
end{table}
%
end{document}


The output of the MWE looks similar to the one in the image. The only issue is the alignment of the text or numbers.



Please help or provide suggestions?










share|improve this question






















  • What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
    – Bernard
    yesterday










  • @Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
    – Tanvir
    yesterday










  • The solutions provided below solved the problem I had with the alignment.
    – Tanvir
    yesterday













up vote
3
down vote

favorite
1









up vote
3
down vote

favorite
1






1





I want to know how to centre-align a text or a number while using multicolumn in Table environment. I need to prepare a table as shown in the image below. Table for my paper



The MWE for the above table is as follows:



documentclass{article}

%%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
usepackage{multirow}
usepackage{calc}
usepackage{array}
newcolumntype{L}[1]{>
{raggedrightletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{C}[1]{>
{centeringletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{R}[1]{>
{raggedleftletnewline\arraybackslashhspace{0pt}}m{#1}}
newcommand{mc}[3]{multicolumn{#1}{#2}{#3}}
newcommand{mr}[3]{multirow{#1}{#2}{#3}}
usepackage{booktabs}
begin{document}

begin{table}[ht!]
begin{center}
begin{tabular}{cccccccccccccc}hline
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{C{3cm}|}{1} & mc{3}{C{3cm}|}{2} & mc{3}{C{3cm}|}{3}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is bounded } & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is unbounded } & mc{3}{C{3cm}|}{$T_{alpha}^{-1}$ does not exists}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|L{0.75cm}|}{$I$} & mc{3}{C{2.5cm}|}{$R(T-alpha I)=X$} & mc{3}{p{3cm}|}{$alpha in rho (T,X)$} & mc{3}{C{3cm}|}{$-$} & mc{3}{p{3cm}|}{centering$alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$}\ hline
end{tabular}
end{center}
end{table}
%
end{document}


The output of the MWE looks similar to the one in the image. The only issue is the alignment of the text or numbers.



Please help or provide suggestions?










share|improve this question













I want to know how to centre-align a text or a number while using multicolumn in Table environment. I need to prepare a table as shown in the image below. Table for my paper



The MWE for the above table is as follows:



documentclass{article}

%%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
usepackage{multirow}
usepackage{calc}
usepackage{array}
newcolumntype{L}[1]{>
{raggedrightletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{C}[1]{>
{centeringletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{R}[1]{>
{raggedleftletnewline\arraybackslashhspace{0pt}}m{#1}}
newcommand{mc}[3]{multicolumn{#1}{#2}{#3}}
newcommand{mr}[3]{multirow{#1}{#2}{#3}}
usepackage{booktabs}
begin{document}

begin{table}[ht!]
begin{center}
begin{tabular}{cccccccccccccc}hline
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{C{3cm}|}{1} & mc{3}{C{3cm}|}{2} & mc{3}{C{3cm}|}{3}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is bounded } & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is unbounded } & mc{3}{C{3cm}|}{$T_{alpha}^{-1}$ does not exists}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|L{0.75cm}|}{$I$} & mc{3}{C{2.5cm}|}{$R(T-alpha I)=X$} & mc{3}{p{3cm}|}{$alpha in rho (T,X)$} & mc{3}{C{3cm}|}{$-$} & mc{3}{p{3cm}|}{centering$alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$}\ hline
end{tabular}
end{center}
end{table}
%
end{document}


The output of the MWE looks similar to the one in the image. The only issue is the alignment of the text or numbers.



Please help or provide suggestions?







tables multicolumn






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked yesterday









Tanvir

173214




173214












  • What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
    – Bernard
    yesterday










  • @Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
    – Tanvir
    yesterday










  • The solutions provided below solved the problem I had with the alignment.
    – Tanvir
    yesterday


















  • What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
    – Bernard
    yesterday










  • @Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
    – Tanvir
    yesterday










  • The solutions provided below solved the problem I had with the alignment.
    – Tanvir
    yesterday
















What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
– Bernard
yesterday




What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
– Bernard
yesterday












@Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
– Tanvir
yesterday




@Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
– Tanvir
yesterday












The solutions provided below solved the problem I had with the alignment.
– Tanvir
yesterday




The solutions provided below solved the problem I had with the alignment.
– Tanvir
yesterday










3 Answers
3






active

oldest

votes

















up vote
3
down vote



accepted










I think you were almost there.



documentclass{article}
usepackage{array}
usepackage{amsmath}
usepackage{bbm}
begin{document}

newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

begin{table}
renewcommand{arraystretch}{1.3}
begin{tabular}{|l|l|C|C|C|}
hline
& & 1 &2 & multicolumn{1}{c|}{3} \ hline
& & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
$mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
$begin{array}{r@{}l}
alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
end{array}$ \ hline
end{tabular}
end{table}
end{document}


enter image description here






share|improve this answer




























    up vote
    2
    down vote













    Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



    documentclass{article}
    usepackage{array,tabularx}
    begin{document}

    newcolumntype{L}{>{raggedrightarraybackslash}X}

    begin{table}
    renewcommand{arraystretch}{1.3}
    begin{tabularx}{textwidth}{|l|l|L|L|L|}
    hline
    & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
    & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
    $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
    end{tabularx}
    end{table}

    end{document}


    enter image description here



    You may also want to improve the whole design using booktabs as follows:



    documentclass{article}
    usepackage{array,tabularx,booktabs}
    begin{document}

    newcolumntype{L}{>{raggedrightarraybackslash}X}

    begin{table}
    %renewcommand{arraystretch}{1.3}
    begin{tabularx}{textwidth}{@{}llLLL@{}}
    toprule
    & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
    & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
    textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
    end{tabularx}
    end{table}

    end{document}


    enter image description here






    share|improve this answer























    • +1. Please replace textit{$I$} with $I$, though.
      – Mico
      yesterday










    • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
      – Tanvir
      yesterday


















    up vote
    1
    down vote













    Avoid jailed tables:



    documentclass{article}

    %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
    usepackage{array}
    usepackage{booktabs}
    usepackage{tabularx}

    newcolumntype{C}{>{centering}X}

    begin{document}

    begin{table}[ht!]
    centering
    renewcommand{tabularxcolumn}{m}

    begin{tabularx}{textwidth}{@{}ccCCC@{}}
    toprule
    && 1 & 2 & 3 tabularnewline
    cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
    && $T_{alpha}^{-1}$ exists and \ is bounded &
    $T_{alpha}^{-1}$ exists and \ is unbounded &
    $T_{alpha}^{-1}$ does not exist tabularnewline
    midrule
    $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
    $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
    bottomrule
    end{tabularx}

    end{table}

    end{document}


    Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



    Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



    enter image description here



    It's easy to make it jailed, though.



    begin{tabularx}{textwidth}{|c|c|C|C|C|}
    hline
    && 1 & 2 & 3 tabularnewline
    hline
    && $T_{alpha}^{-1}$ exists and \ is bounded &
    $T_{alpha}^{-1}$ exists and \ is unbounded &
    $T_{alpha}^{-1}$ does not exist tabularnewline
    hline
    $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
    $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
    hline
    end{tabularx}


    enter image description here






    share|improve this answer





















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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote



      accepted










      I think you were almost there.



      documentclass{article}
      usepackage{array}
      usepackage{amsmath}
      usepackage{bbm}
      begin{document}

      newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

      begin{table}
      renewcommand{arraystretch}{1.3}
      begin{tabular}{|l|l|C|C|C|}
      hline
      & & 1 &2 & multicolumn{1}{c|}{3} \ hline
      & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
      $mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
      $begin{array}{r@{}l}
      alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
      end{array}$ \ hline
      end{tabular}
      end{table}
      end{document}


      enter image description here






      share|improve this answer

























        up vote
        3
        down vote



        accepted










        I think you were almost there.



        documentclass{article}
        usepackage{array}
        usepackage{amsmath}
        usepackage{bbm}
        begin{document}

        newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

        begin{table}
        renewcommand{arraystretch}{1.3}
        begin{tabular}{|l|l|C|C|C|}
        hline
        & & 1 &2 & multicolumn{1}{c|}{3} \ hline
        & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
        $mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
        $begin{array}{r@{}l}
        alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
        end{array}$ \ hline
        end{tabular}
        end{table}
        end{document}


        enter image description here






        share|improve this answer























          up vote
          3
          down vote



          accepted







          up vote
          3
          down vote



          accepted






          I think you were almost there.



          documentclass{article}
          usepackage{array}
          usepackage{amsmath}
          usepackage{bbm}
          begin{document}

          newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

          begin{table}
          renewcommand{arraystretch}{1.3}
          begin{tabular}{|l|l|C|C|C|}
          hline
          & & 1 &2 & multicolumn{1}{c|}{3} \ hline
          & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
          $mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
          $begin{array}{r@{}l}
          alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
          end{array}$ \ hline
          end{tabular}
          end{table}
          end{document}


          enter image description here






          share|improve this answer












          I think you were almost there.



          documentclass{article}
          usepackage{array}
          usepackage{amsmath}
          usepackage{bbm}
          begin{document}

          newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

          begin{table}
          renewcommand{arraystretch}{1.3}
          begin{tabular}{|l|l|C|C|C|}
          hline
          & & 1 &2 & multicolumn{1}{c|}{3} \ hline
          & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
          $mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
          $begin{array}{r@{}l}
          alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
          end{array}$ \ hline
          end{tabular}
          end{table}
          end{document}


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered yesterday









          marmot

          77.7k487166




          77.7k487166






















              up vote
              2
              down vote













              Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



              documentclass{article}
              usepackage{array,tabularx}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{|l|l|L|L|L|}
              hline
              & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
              end{tabularx}
              end{table}

              end{document}


              enter image description here



              You may also want to improve the whole design using booktabs as follows:



              documentclass{article}
              usepackage{array,tabularx,booktabs}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              %renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{@{}llLLL@{}}
              toprule
              & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
              textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
              end{tabularx}
              end{table}

              end{document}


              enter image description here






              share|improve this answer























              • +1. Please replace textit{$I$} with $I$, though.
                – Mico
                yesterday










              • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
                – Tanvir
                yesterday















              up vote
              2
              down vote













              Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



              documentclass{article}
              usepackage{array,tabularx}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{|l|l|L|L|L|}
              hline
              & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
              end{tabularx}
              end{table}

              end{document}


              enter image description here



              You may also want to improve the whole design using booktabs as follows:



              documentclass{article}
              usepackage{array,tabularx,booktabs}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              %renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{@{}llLLL@{}}
              toprule
              & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
              textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
              end{tabularx}
              end{table}

              end{document}


              enter image description here






              share|improve this answer























              • +1. Please replace textit{$I$} with $I$, though.
                – Mico
                yesterday










              • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
                – Tanvir
                yesterday













              up vote
              2
              down vote










              up vote
              2
              down vote









              Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



              documentclass{article}
              usepackage{array,tabularx}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{|l|l|L|L|L|}
              hline
              & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
              end{tabularx}
              end{table}

              end{document}


              enter image description here



              You may also want to improve the whole design using booktabs as follows:



              documentclass{article}
              usepackage{array,tabularx,booktabs}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              %renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{@{}llLLL@{}}
              toprule
              & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
              textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
              end{tabularx}
              end{table}

              end{document}


              enter image description here






              share|improve this answer














              Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



              documentclass{article}
              usepackage{array,tabularx}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{|l|l|L|L|L|}
              hline
              & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
              end{tabularx}
              end{table}

              end{document}


              enter image description here



              You may also want to improve the whole design using booktabs as follows:



              documentclass{article}
              usepackage{array,tabularx,booktabs}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              %renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{@{}llLLL@{}}
              toprule
              & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
              textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
              end{tabularx}
              end{table}

              end{document}


              enter image description here







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited yesterday

























              answered yesterday









              AboAmmar

              31.1k22780




              31.1k22780












              • +1. Please replace textit{$I$} with $I$, though.
                – Mico
                yesterday










              • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
                – Tanvir
                yesterday


















              • +1. Please replace textit{$I$} with $I$, though.
                – Mico
                yesterday










              • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
                – Tanvir
                yesterday
















              +1. Please replace textit{$I$} with $I$, though.
              – Mico
              yesterday




              +1. Please replace textit{$I$} with $I$, though.
              – Mico
              yesterday












              The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
              – Tanvir
              yesterday




              The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
              – Tanvir
              yesterday










              up vote
              1
              down vote













              Avoid jailed tables:



              documentclass{article}

              %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
              usepackage{array}
              usepackage{booktabs}
              usepackage{tabularx}

              newcolumntype{C}{>{centering}X}

              begin{document}

              begin{table}[ht!]
              centering
              renewcommand{tabularxcolumn}{m}

              begin{tabularx}{textwidth}{@{}ccCCC@{}}
              toprule
              && 1 & 2 & 3 tabularnewline
              cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
              && $T_{alpha}^{-1}$ exists and \ is bounded &
              $T_{alpha}^{-1}$ exists and \ is unbounded &
              $T_{alpha}^{-1}$ does not exist tabularnewline
              midrule
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
              $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
              bottomrule
              end{tabularx}

              end{table}

              end{document}


              Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



              Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



              enter image description here



              It's easy to make it jailed, though.



              begin{tabularx}{textwidth}{|c|c|C|C|C|}
              hline
              && 1 & 2 & 3 tabularnewline
              hline
              && $T_{alpha}^{-1}$ exists and \ is bounded &
              $T_{alpha}^{-1}$ exists and \ is unbounded &
              $T_{alpha}^{-1}$ does not exist tabularnewline
              hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
              $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
              hline
              end{tabularx}


              enter image description here






              share|improve this answer

























                up vote
                1
                down vote













                Avoid jailed tables:



                documentclass{article}

                %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
                usepackage{array}
                usepackage{booktabs}
                usepackage{tabularx}

                newcolumntype{C}{>{centering}X}

                begin{document}

                begin{table}[ht!]
                centering
                renewcommand{tabularxcolumn}{m}

                begin{tabularx}{textwidth}{@{}ccCCC@{}}
                toprule
                && 1 & 2 & 3 tabularnewline
                cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
                && $T_{alpha}^{-1}$ exists and \ is bounded &
                $T_{alpha}^{-1}$ exists and \ is unbounded &
                $T_{alpha}^{-1}$ does not exist tabularnewline
                midrule
                $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                bottomrule
                end{tabularx}

                end{table}

                end{document}


                Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



                Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



                enter image description here



                It's easy to make it jailed, though.



                begin{tabularx}{textwidth}{|c|c|C|C|C|}
                hline
                && 1 & 2 & 3 tabularnewline
                hline
                && $T_{alpha}^{-1}$ exists and \ is bounded &
                $T_{alpha}^{-1}$ exists and \ is unbounded &
                $T_{alpha}^{-1}$ does not exist tabularnewline
                hline
                $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                hline
                end{tabularx}


                enter image description here






                share|improve this answer























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  Avoid jailed tables:



                  documentclass{article}

                  %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
                  usepackage{array}
                  usepackage{booktabs}
                  usepackage{tabularx}

                  newcolumntype{C}{>{centering}X}

                  begin{document}

                  begin{table}[ht!]
                  centering
                  renewcommand{tabularxcolumn}{m}

                  begin{tabularx}{textwidth}{@{}ccCCC@{}}
                  toprule
                  && 1 & 2 & 3 tabularnewline
                  cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
                  && $T_{alpha}^{-1}$ exists and \ is bounded &
                  $T_{alpha}^{-1}$ exists and \ is unbounded &
                  $T_{alpha}^{-1}$ does not exist tabularnewline
                  midrule
                  $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                  $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                  bottomrule
                  end{tabularx}

                  end{table}

                  end{document}


                  Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



                  Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



                  enter image description here



                  It's easy to make it jailed, though.



                  begin{tabularx}{textwidth}{|c|c|C|C|C|}
                  hline
                  && 1 & 2 & 3 tabularnewline
                  hline
                  && $T_{alpha}^{-1}$ exists and \ is bounded &
                  $T_{alpha}^{-1}$ exists and \ is unbounded &
                  $T_{alpha}^{-1}$ does not exist tabularnewline
                  hline
                  $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                  $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                  hline
                  end{tabularx}


                  enter image description here






                  share|improve this answer












                  Avoid jailed tables:



                  documentclass{article}

                  %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
                  usepackage{array}
                  usepackage{booktabs}
                  usepackage{tabularx}

                  newcolumntype{C}{>{centering}X}

                  begin{document}

                  begin{table}[ht!]
                  centering
                  renewcommand{tabularxcolumn}{m}

                  begin{tabularx}{textwidth}{@{}ccCCC@{}}
                  toprule
                  && 1 & 2 & 3 tabularnewline
                  cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
                  && $T_{alpha}^{-1}$ exists and \ is bounded &
                  $T_{alpha}^{-1}$ exists and \ is unbounded &
                  $T_{alpha}^{-1}$ does not exist tabularnewline
                  midrule
                  $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                  $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                  bottomrule
                  end{tabularx}

                  end{table}

                  end{document}


                  Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



                  Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



                  enter image description here



                  It's easy to make it jailed, though.



                  begin{tabularx}{textwidth}{|c|c|C|C|C|}
                  hline
                  && 1 & 2 & 3 tabularnewline
                  hline
                  && $T_{alpha}^{-1}$ exists and \ is bounded &
                  $T_{alpha}^{-1}$ exists and \ is unbounded &
                  $T_{alpha}^{-1}$ does not exist tabularnewline
                  hline
                  $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                  $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                  hline
                  end{tabularx}


                  enter image description here







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered yesterday









                  egreg

                  699k8518613132




                  699k8518613132






























                       

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