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In Young's double slit experiment, can we get an even number of maxima in the central envelope maximum? If so how and why the regular modelling of the double split interfaces is with an odd number like in the picture

Source of the pic: Hyperphysics

In order for two maximum interference fringes to appear, it is necessary to break the reflection symmetry between the two slits. If this symmetry remains unbroken, the phases associated with paths through the top and bottom slits always match, and the amplitudes interfere constructively as mentioned by Tausif Hossain. There are many ways to break this symmetry, most of which involve doing so at a classical level (this is the case, for example, in Pieter's answer pertaining to double slit interference of photons.)

In the case of double slit interference of electrons, it is possible to break the symmetry in a way that is intrinsically quantum mechanical (preserving the reflection symmetry at a classical level) using the Aharonov Bohm effect. If you insert a thin magnetic flux through and perpendicular to the electron beam and tune it to just the right value, you should be able to obtain an even number of maxima. (Whether you can get more than two maxima is another story, and probably depends more sensitively on how the magnetic flux is distributed.)

One can get an even number of fringes by covering the pair of slits with a wedge of glass or plastic that gives half a wavelength more delay at one slit than at the other.

Notice that if it is strictly a double slit experiment with a coherent light source then there will always be a central bright fringe where the path difference between the waves is zero(which is that, there is a point in the screen which is equidistant from the slits which lies on the perpendicular bisector of the slits). Hence the constructive interference at the center and the bright fringe.

Thus, as long as that center fringe exists and also as there is symmetry ofcourse between the path differences on both sides of the central bright fringe. So the other bright fringes occur in pairs (like staring from 1 wavelength path difference from each side and so on).So, the number of fringes is always $1+2n$ (Where 1 is for the central bright fringe). Hence an odd number of bright fringes.