Display elementary math without evaluating











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Given a list of operators and integers, for instance 



oper = {Subtract, Times, Plus}

{a, b, c, d} = {3, 5, 4, 9}


I would like to print



oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


as $(3-5)times (4+9)$ (set aside the $LaTeX$ formatting, I just mean the numbers and the operators in a classical way). Whenever I use Hold, Unevaluate or Inactivate, the oper[[2]] and similar are not evaluated. Also the operator names are not replaced with their symbols.



Any hints?






hold display







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  • For the purpose of displaying, consider strings.
    – Αλέξανδρος Ζεγγ
    6 hours ago

















up vote
3
down vote

favorite
1












Given a list of operators and integers, for instance 



oper = {Subtract, Times, Plus}

{a, b, c, d} = {3, 5, 4, 9}


I would like to print



oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


as $(3-5)times (4+9)$ (set aside the $LaTeX$ formatting, I just mean the numbers and the operators in a classical way). Whenever I use Hold, Unevaluate or Inactivate, the oper[[2]] and similar are not evaluated. Also the operator names are not replaced with their symbols.



Any hints?






hold display







share|improve this question






















  • For the purpose of displaying, consider strings.
    – Αλέξανδρος Ζεγγ
    6 hours ago















up vote
3
down vote

favorite
1









up vote
3
down vote

favorite
1






1





Given a list of operators and integers, for instance 



oper = {Subtract, Times, Plus}

{a, b, c, d} = {3, 5, 4, 9}


I would like to print



oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


as $(3-5)times (4+9)$ (set aside the $LaTeX$ formatting, I just mean the numbers and the operators in a classical way). Whenever I use Hold, Unevaluate or Inactivate, the oper[[2]] and similar are not evaluated. Also the operator names are not replaced with their symbols.



Any hints?






hold display







share|improve this question













Given a list of operators and integers, for instance 



oper = {Subtract, Times, Plus}

{a, b, c, d} = {3, 5, 4, 9}


I would like to print



oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


as $(3-5)times (4+9)$ (set aside the $LaTeX$ formatting, I just mean the numbers and the operators in a classical way). Whenever I use Hold, Unevaluate or Inactivate, the oper[[2]] and similar are not evaluated. Also the operator names are not replaced with their symbols.



Any hints?






hold display




hold display






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asked 9 hours ago









anderstood

7,7391858




7,7391858












  • For the purpose of displaying, consider strings.
    – Αλέξανδρος Ζεγγ
    6 hours ago




















  • For the purpose of displaying, consider strings.
    – Αλέξανδρος Ζεγγ
    6 hours ago


















For the purpose of displaying, consider strings.
– Αλέξανδρος Ζεγγ
6 hours ago






For the purpose of displaying, consider strings.
– Αλέξανδρος Ζεγγ
6 hours ago












1 Answer
1






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5
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ClearAll[a, b, c, d, oper]

oper = {Subtract, Inactive@Times, Inactive@Plus} /.

   Subtract -> (HoldForm[Plus[#, -#2]] &);

{a, b, c, d} = {3, 5, 4, 9};

oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


enter image description here






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    ClearAll[a, b, c, d, oper]
    
oper = {Subtract, Inactive@Times, Inactive@Plus} /.
    
   Subtract -> (HoldForm[Plus[#, -#2]] &);
    
{a, b, c, d} = {3, 5, 4, 9};
    
oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


    enter image description here






    share|improve this answer

























      up vote
      5
      down vote













      ClearAll[a, b, c, d, oper]
      
oper = {Subtract, Inactive@Times, Inactive@Plus} /.
      
   Subtract -> (HoldForm[Plus[#, -#2]] &);
      
{a, b, c, d} = {3, 5, 4, 9};
      
oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


      enter image description here






      share|improve this answer























        up vote
        5
        down vote










        up vote
        5
        down vote









        ClearAll[a, b, c, d, oper]
        
oper = {Subtract, Inactive@Times, Inactive@Plus} /.
        
   Subtract -> (HoldForm[Plus[#, -#2]] &);
        
{a, b, c, d} = {3, 5, 4, 9};
        
oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


        enter image description here






        share|improve this answer












        ClearAll[a, b, c, d, oper]
        
oper = {Subtract, Inactive@Times, Inactive@Plus} /.
        
   Subtract -> (HoldForm[Plus[#, -#2]] &);
        
{a, b, c, d} = {3, 5, 4, 9};
        
oper[[2]][oper[[1]] @@ {a, b}, oper[[3]] @@ {c, d}]


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 9 hours ago









        kglr

        173k8195400




        173k8195400






























             

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