Use sed replace with line number from variable












0















This is my sed command:



while ...;

do sed -r "${counter}s/^S+ /$line /g" $in > $out;

..

..

done


Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:



do echo ´sed -r "${counter}s/^S+/$line/g" $in > $out´;


which printed this to the console:



sed -r <line number>/^S+/<replace pattern>/g <infile> > <outfile>


When executing this very command (without the ´) from the console, I get this:



sed: -e expression #1, char 8: unterminated s' command


I guess this is because the ' are missing around the pattern.



So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?






bash sed







share|improve this question
















bumped to the homepage by Community♦ 20 mins ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
















  • how could it possibly work? i dont see any input at all, and it looks like youre calling sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off.

    – mikeserv
    Oct 28 '15 at 9:46











  • $counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.

    – entenbein
    Oct 28 '15 at 9:57













  • awk or perl are better tools for doing that.

    – cas
    Oct 28 '15 at 10:02






  • 1





    Is there / or n in $line variable? Any way try to execute sed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants?

    – Costas
    Oct 28 '15 at 10:16













  • Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.

    – entenbein
    Oct 28 '15 at 10:25
















0















This is my sed command:



while ...;

do sed -r "${counter}s/^S+ /$line /g" $in > $out;

..

..

done


Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:



do echo ´sed -r "${counter}s/^S+/$line/g" $in > $out´;


which printed this to the console:



sed -r <line number>/^S+/<replace pattern>/g <infile> > <outfile>


When executing this very command (without the ´) from the console, I get this:



sed: -e expression #1, char 8: unterminated s' command


I guess this is because the ' are missing around the pattern.



So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?






bash sed







share|improve this question
















bumped to the homepage by Community♦ 20 mins ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
















  • how could it possibly work? i dont see any input at all, and it looks like youre calling sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off.

    – mikeserv
    Oct 28 '15 at 9:46











  • $counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.

    – entenbein
    Oct 28 '15 at 9:57













  • awk or perl are better tools for doing that.

    – cas
    Oct 28 '15 at 10:02






  • 1





    Is there / or n in $line variable? Any way try to execute sed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants?

    – Costas
    Oct 28 '15 at 10:16













  • Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.

    – entenbein
    Oct 28 '15 at 10:25














0












0








0








This is my sed command:



while ...;

do sed -r "${counter}s/^S+ /$line /g" $in > $out;

..

..

done


Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:



do echo ´sed -r "${counter}s/^S+/$line/g" $in > $out´;


which printed this to the console:



sed -r <line number>/^S+/<replace pattern>/g <infile> > <outfile>


When executing this very command (without the ´) from the console, I get this:



sed: -e expression #1, char 8: unterminated s' command


I guess this is because the ' are missing around the pattern.



So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?






bash sed







share|improve this question
















This is my sed command:



while ...;

do sed -r "${counter}s/^S+ /$line /g" $in > $out;

..

..

done


Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:



do echo ´sed -r "${counter}s/^S+/$line/g" $in > $out´;


which printed this to the console:



sed -r <line number>/^S+/<replace pattern>/g <infile> > <outfile>


When executing this very command (without the ´) from the console, I get this:



sed: -e expression #1, char 8: unterminated s' command


I guess this is because the ' are missing around the pattern.



So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?






bash sed




bash sed






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Oct 28 '15 at 10:16









serenesat

9341519




9341519










asked Oct 28 '15 at 9:42









entenbeinentenbein

12




12





bumped to the homepage by Community♦ 20 mins ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.







bumped to the homepage by Community♦ 20 mins ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.















  • how could it possibly work? i dont see any input at all, and it looks like youre calling sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off.

    – mikeserv
    Oct 28 '15 at 9:46











  • $counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.

    – entenbein
    Oct 28 '15 at 9:57













  • awk or perl are better tools for doing that.

    – cas
    Oct 28 '15 at 10:02






  • 1





    Is there / or n in $line variable? Any way try to execute sed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants?

    – Costas
    Oct 28 '15 at 10:16













  • Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.

    – entenbein
    Oct 28 '15 at 10:25



















  • how could it possibly work? i dont see any input at all, and it looks like youre calling sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off.

    – mikeserv
    Oct 28 '15 at 9:46











  • $counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.

    – entenbein
    Oct 28 '15 at 9:57













  • awk or perl are better tools for doing that.

    – cas
    Oct 28 '15 at 10:02






  • 1





    Is there / or n in $line variable? Any way try to execute sed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants?

    – Costas
    Oct 28 '15 at 10:16













  • Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.

    – entenbein
    Oct 28 '15 at 10:25

















how could it possibly work? i dont see any input at all, and it looks like youre calling sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off.

– mikeserv
Oct 28 '15 at 9:46





how could it possibly work? i dont see any input at all, and it looks like youre calling sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off.

– mikeserv
Oct 28 '15 at 9:46













$counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.

– entenbein
Oct 28 '15 at 9:57







$counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.

– entenbein
Oct 28 '15 at 9:57















awk or perl are better tools for doing that.

– cas
Oct 28 '15 at 10:02





awk or perl are better tools for doing that.

– cas
Oct 28 '15 at 10:02




1




1





Is there / or n in $line variable? Any way try to execute sed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants?

– Costas
Oct 28 '15 at 10:16







Is there / or n in $line variable? Any way try to execute sed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants?

– Costas
Oct 28 '15 at 10:16















Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.

– entenbein
Oct 28 '15 at 10:25





Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.

– entenbein
Oct 28 '15 at 10:25










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Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....



Thanks for your help!






share|improve this answer























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    Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....



    Thanks for your help!






    share|improve this answer




























      0














      Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....



      Thanks for your help!






      share|improve this answer


























        0












        0








        0







        Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....



        Thanks for your help!






        share|improve this answer













        Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....



        Thanks for your help!







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Oct 28 '15 at 10:57









        entenbeinentenbein

        12




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