AWK: Print first field of every line as identifier for every following field in the corresponding line












0














I have a input file like this with a blank as field seperator



AAABBB: 243.234.12.2 123.3.2 231.5.12 451.192.29.9

BBXDS: 324.22.32.5 235.235.283 234.239. 234.23.23.1 

DDF: 23.12.59.09 98.39.239.29 394.293.2.2


The output should look like this:



AAABBB: 243.234.12.2

AAABBB: 123.3.2

AAABBB: 231.5.12

AAABBB: 451.192.29.9

BBXDS: 324.22.32.5

BBXDS: 235.235.283

BBXDS: 234.239.

.....


The first field of every line is a identifier and should be printed as a new line in front of every column in the corresponding line until the end of the line.






awk







share|improve this question






















  • Really close to a duplicate: unix.stackexchange.com/q/456907/117549
    – Jeff Schaller
    48 mins ago
















0














I have a input file like this with a blank as field seperator



AAABBB: 243.234.12.2 123.3.2 231.5.12 451.192.29.9

BBXDS: 324.22.32.5 235.235.283 234.239. 234.23.23.1 

DDF: 23.12.59.09 98.39.239.29 394.293.2.2


The output should look like this:



AAABBB: 243.234.12.2

AAABBB: 123.3.2

AAABBB: 231.5.12

AAABBB: 451.192.29.9

BBXDS: 324.22.32.5

BBXDS: 235.235.283

BBXDS: 234.239.

.....


The first field of every line is a identifier and should be printed as a new line in front of every column in the corresponding line until the end of the line.






awk







share|improve this question






















  • Really close to a duplicate: unix.stackexchange.com/q/456907/117549
    – Jeff Schaller
    48 mins ago














0












0








0







I have a input file like this with a blank as field seperator



AAABBB: 243.234.12.2 123.3.2 231.5.12 451.192.29.9

BBXDS: 324.22.32.5 235.235.283 234.239. 234.23.23.1 

DDF: 23.12.59.09 98.39.239.29 394.293.2.2


The output should look like this:



AAABBB: 243.234.12.2

AAABBB: 123.3.2

AAABBB: 231.5.12

AAABBB: 451.192.29.9

BBXDS: 324.22.32.5

BBXDS: 235.235.283

BBXDS: 234.239.

.....


The first field of every line is a identifier and should be printed as a new line in front of every column in the corresponding line until the end of the line.






awk







share|improve this question













I have a input file like this with a blank as field seperator



AAABBB: 243.234.12.2 123.3.2 231.5.12 451.192.29.9

BBXDS: 324.22.32.5 235.235.283 234.239. 234.23.23.1 

DDF: 23.12.59.09 98.39.239.29 394.293.2.2


The output should look like this:



AAABBB: 243.234.12.2

AAABBB: 123.3.2

AAABBB: 231.5.12

AAABBB: 451.192.29.9

BBXDS: 324.22.32.5

BBXDS: 235.235.283

BBXDS: 234.239.

.....


The first field of every line is a identifier and should be printed as a new line in front of every column in the corresponding line until the end of the line.






awk




awk






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 56 mins ago









T-One

586




586












  • Really close to a duplicate: unix.stackexchange.com/q/456907/117549
    – Jeff Schaller
    48 mins ago


















  • Really close to a duplicate: unix.stackexchange.com/q/456907/117549
    – Jeff Schaller
    48 mins ago
















Really close to a duplicate: unix.stackexchange.com/q/456907/117549
– Jeff Schaller
48 mins ago




Really close to a duplicate: unix.stackexchange.com/q/456907/117549
– Jeff Schaller
48 mins ago










1 Answer
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4














Fairly straightforwardly:



awk '{ for(i=2; i <= NF; i++) print $1, $i}' < input


On every line, oop from 2 until the last field (Number of Fields), printing field 1 and the looped field.






share|improve this answer





















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    1 Answer
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    active

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    Fairly straightforwardly:



    awk '{ for(i=2; i <= NF; i++) print $1, $i}' < input


    On every line, oop from 2 until the last field (Number of Fields), printing field 1 and the looped field.






    share|improve this answer


























      4














      Fairly straightforwardly:



      awk '{ for(i=2; i <= NF; i++) print $1, $i}' < input


      On every line, oop from 2 until the last field (Number of Fields), printing field 1 and the looped field.






      share|improve this answer
























        4












        4








        4






        Fairly straightforwardly:



        awk '{ for(i=2; i <= NF; i++) print $1, $i}' < input


        On every line, oop from 2 until the last field (Number of Fields), printing field 1 and the looped field.






        share|improve this answer












        Fairly straightforwardly:



        awk '{ for(i=2; i <= NF; i++) print $1, $i}' < input


        On every line, oop from 2 until the last field (Number of Fields), printing field 1 and the looped field.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 50 mins ago









        Jeff Schaller

        38.7k1053125




        38.7k1053125






























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