How to shuffle a Rubik's cube?












5















documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
usepackage{arrayjob}
begin{document}

newarraycolors
readarray{colors}{red&red&red&red&red&red&red&red&yellow&yellow&yellow&yellow&yellow&yellow&yellow&yellow&yellow&orange&orange&orange&orange&orange&orange&orange&orange&orange&green&green&green&green&green&green&green&green&green&blue&blue&blue&blue&blue&blue&blue&blue&blue}

edefcolorfaces{}%
multido{i=0+1}{57}{%
checkcolors(i)
xdefcolorfaces{colorfacesispace(cachedata)space}}
%
deffigure#1#2{%
psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=colorfaces%
,Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



Question:




  1. Is there an another way without using the package arrayjob?


  2. How to get the random color for it?



Thanks.










share|improve this question




















  • 1





    As for 2.: you are already loading pgf, so you have already a built in way to get a random item. Just add pgfmathdeclarerandomlist{colors}{{red}{red}{red}{red}{red}{red}{red}{red}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{green}{green}{green}{green}{green}{green}{green}{green}{green}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}} pgfmathrandomitem{c}{colors} typeout{c} to your code.

    – marmot
    12 hours ago











  • It occurred to me that random colors may not be a good idea. There are six colors, eight corners and eight edges. Each edge has a unique combination of 2 colors, and each corner has a unique combination of 3 colors, of which each color is used in precisely 4 corners and 4 edges. And each of 6 centers has a different color. What you really need is a random sort of the different components.

    – John Kormylo
    3 hours ago













  • Because the colors are not freely randomized but they must follow some rules, I think I need to change the title to be more specific.

    – Artificial Stupidity
    11 mins ago
















5















documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
usepackage{arrayjob}
begin{document}

newarraycolors
readarray{colors}{red&red&red&red&red&red&red&red&yellow&yellow&yellow&yellow&yellow&yellow&yellow&yellow&yellow&orange&orange&orange&orange&orange&orange&orange&orange&orange&green&green&green&green&green&green&green&green&green&blue&blue&blue&blue&blue&blue&blue&blue&blue}

edefcolorfaces{}%
multido{i=0+1}{57}{%
checkcolors(i)
xdefcolorfaces{colorfacesispace(cachedata)space}}
%
deffigure#1#2{%
psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=colorfaces%
,Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



Question:




  1. Is there an another way without using the package arrayjob?


  2. How to get the random color for it?



Thanks.










share|improve this question




















  • 1





    As for 2.: you are already loading pgf, so you have already a built in way to get a random item. Just add pgfmathdeclarerandomlist{colors}{{red}{red}{red}{red}{red}{red}{red}{red}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{green}{green}{green}{green}{green}{green}{green}{green}{green}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}} pgfmathrandomitem{c}{colors} typeout{c} to your code.

    – marmot
    12 hours ago











  • It occurred to me that random colors may not be a good idea. There are six colors, eight corners and eight edges. Each edge has a unique combination of 2 colors, and each corner has a unique combination of 3 colors, of which each color is used in precisely 4 corners and 4 edges. And each of 6 centers has a different color. What you really need is a random sort of the different components.

    – John Kormylo
    3 hours ago













  • Because the colors are not freely randomized but they must follow some rules, I think I need to change the title to be more specific.

    – Artificial Stupidity
    11 mins ago














5












5








5








documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
usepackage{arrayjob}
begin{document}

newarraycolors
readarray{colors}{red&red&red&red&red&red&red&red&yellow&yellow&yellow&yellow&yellow&yellow&yellow&yellow&yellow&orange&orange&orange&orange&orange&orange&orange&orange&orange&green&green&green&green&green&green&green&green&green&blue&blue&blue&blue&blue&blue&blue&blue&blue}

edefcolorfaces{}%
multido{i=0+1}{57}{%
checkcolors(i)
xdefcolorfaces{colorfacesispace(cachedata)space}}
%
deffigure#1#2{%
psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=colorfaces%
,Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



Question:




  1. Is there an another way without using the package arrayjob?


  2. How to get the random color for it?



Thanks.










share|improve this question
















documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
usepackage{arrayjob}
begin{document}

newarraycolors
readarray{colors}{red&red&red&red&red&red&red&red&yellow&yellow&yellow&yellow&yellow&yellow&yellow&yellow&yellow&orange&orange&orange&orange&orange&orange&orange&orange&orange&green&green&green&green&green&green&green&green&green&blue&blue&blue&blue&blue&blue&blue&blue&blue}

edefcolorfaces{}%
multido{i=0+1}{57}{%
checkcolors(i)
xdefcolorfaces{colorfacesispace(cachedata)space}}
%
deffigure#1#2{%
psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=colorfaces%
,Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



Question:




  1. Is there an another way without using the package arrayjob?


  2. How to get the random color for it?



Thanks.







pstricks pst-solides3d






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 13 mins ago









Artificial Stupidity

5,35711041




5,35711041










asked 14 hours ago









chishimutojichishimutoji

7141320




7141320








  • 1





    As for 2.: you are already loading pgf, so you have already a built in way to get a random item. Just add pgfmathdeclarerandomlist{colors}{{red}{red}{red}{red}{red}{red}{red}{red}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{green}{green}{green}{green}{green}{green}{green}{green}{green}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}} pgfmathrandomitem{c}{colors} typeout{c} to your code.

    – marmot
    12 hours ago











  • It occurred to me that random colors may not be a good idea. There are six colors, eight corners and eight edges. Each edge has a unique combination of 2 colors, and each corner has a unique combination of 3 colors, of which each color is used in precisely 4 corners and 4 edges. And each of 6 centers has a different color. What you really need is a random sort of the different components.

    – John Kormylo
    3 hours ago













  • Because the colors are not freely randomized but they must follow some rules, I think I need to change the title to be more specific.

    – Artificial Stupidity
    11 mins ago














  • 1





    As for 2.: you are already loading pgf, so you have already a built in way to get a random item. Just add pgfmathdeclarerandomlist{colors}{{red}{red}{red}{red}{red}{red}{red}{red}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{green}{green}{green}{green}{green}{green}{green}{green}{green}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}} pgfmathrandomitem{c}{colors} typeout{c} to your code.

    – marmot
    12 hours ago











  • It occurred to me that random colors may not be a good idea. There are six colors, eight corners and eight edges. Each edge has a unique combination of 2 colors, and each corner has a unique combination of 3 colors, of which each color is used in precisely 4 corners and 4 edges. And each of 6 centers has a different color. What you really need is a random sort of the different components.

    – John Kormylo
    3 hours ago













  • Because the colors are not freely randomized but they must follow some rules, I think I need to change the title to be more specific.

    – Artificial Stupidity
    11 mins ago








1




1





As for 2.: you are already loading pgf, so you have already a built in way to get a random item. Just add pgfmathdeclarerandomlist{colors}{{red}{red}{red}{red}{red}{red}{red}{red}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{green}{green}{green}{green}{green}{green}{green}{green}{green}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}} pgfmathrandomitem{c}{colors} typeout{c} to your code.

– marmot
12 hours ago





As for 2.: you are already loading pgf, so you have already a built in way to get a random item. Just add pgfmathdeclarerandomlist{colors}{{red}{red}{red}{red}{red}{red}{red}{red}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{yellow}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{orange}{green}{green}{green}{green}{green}{green}{green}{green}{green}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}{blue}} pgfmathrandomitem{c}{colors} typeout{c} to your code.

– marmot
12 hours ago













It occurred to me that random colors may not be a good idea. There are six colors, eight corners and eight edges. Each edge has a unique combination of 2 colors, and each corner has a unique combination of 3 colors, of which each color is used in precisely 4 corners and 4 edges. And each of 6 centers has a different color. What you really need is a random sort of the different components.

– John Kormylo
3 hours ago







It occurred to me that random colors may not be a good idea. There are six colors, eight corners and eight edges. Each edge has a unique combination of 2 colors, and each corner has a unique combination of 3 colors, of which each color is used in precisely 4 corners and 4 edges. And each of 6 centers has a different color. What you really need is a random sort of the different components.

– John Kormylo
3 hours ago















Because the colors are not freely randomized but they must follow some rules, I think I need to change the title to be more specific.

– Artificial Stupidity
11 mins ago





Because the colors are not freely randomized but they must follow some rules, I think I need to change the title to be more specific.

– Artificial Stupidity
11 mins ago










1 Answer
1






active

oldest

votes


















4














documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { Colors Rand 4.5 mul cvi get } for
9 1 17 { Colors Rand 4.5 mul cvi get } for
18 1 26 { Colors Rand 4.5 mul cvi get } for
27 1 35 { Colors Rand 4.5 mul cvi get } for
36 1 44 { Colors Rand 4.5 mul cvi get } for
45 1 53 { Colors Rand 4.5 mul cvi get } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



 0 1 8 {      from 0 to 8 with step 1 do
put the loop variable on the stack
Colors. Load Color array
Rand get a random number between 0 and 1
4.5 mul between 0 and 4.5
cvi between 0 and 4
get load color with random number
} for. end of for loop


Every square has a corresponding number 0 .. 53 which can be used
for color setting: 0 (red) 1 (green) ... and so on. see pages 38 ff of
the documentation.



The same for complete faces:



documentclass[pstricks,border=10pt]{standalone}

usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { (red) } for
9 1 17 { (green) } for
18 1 26 { (blue) } for
27 1 35 { (orange) } for
36 1 44 { (yellow) } for
45 1 53 { (cyan) } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here






share|improve this answer


























  • Please to answer the first question. Your code(PostScript language) is new with me...

    – chishimutoji
    10 hours ago













  • see edited answer ...

    – Herbert
    10 hours ago











  • Oh, you misunderstood me. I mean that you can rewrite my code as the smart way.( my figure only 6 colors). The second question is not important. :-) And of course thanks for your expansion..

    – chishimutoji
    10 hours ago













  • And I just check pages 38 of the documentation BUT there is no anything as you can see. :-)

    – chishimutoji
    10 hours ago











  • I see only 5 colors. pages 38ff show anything about colors.

    – Herbert
    10 hours ago











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1 Answer
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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { Colors Rand 4.5 mul cvi get } for
9 1 17 { Colors Rand 4.5 mul cvi get } for
18 1 26 { Colors Rand 4.5 mul cvi get } for
27 1 35 { Colors Rand 4.5 mul cvi get } for
36 1 44 { Colors Rand 4.5 mul cvi get } for
45 1 53 { Colors Rand 4.5 mul cvi get } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



 0 1 8 {      from 0 to 8 with step 1 do
put the loop variable on the stack
Colors. Load Color array
Rand get a random number between 0 and 1
4.5 mul between 0 and 4.5
cvi between 0 and 4
get load color with random number
} for. end of for loop


Every square has a corresponding number 0 .. 53 which can be used
for color setting: 0 (red) 1 (green) ... and so on. see pages 38 ff of
the documentation.



The same for complete faces:



documentclass[pstricks,border=10pt]{standalone}

usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { (red) } for
9 1 17 { (green) } for
18 1 26 { (blue) } for
27 1 35 { (orange) } for
36 1 44 { (yellow) } for
45 1 53 { (cyan) } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here






share|improve this answer


























  • Please to answer the first question. Your code(PostScript language) is new with me...

    – chishimutoji
    10 hours ago













  • see edited answer ...

    – Herbert
    10 hours ago











  • Oh, you misunderstood me. I mean that you can rewrite my code as the smart way.( my figure only 6 colors). The second question is not important. :-) And of course thanks for your expansion..

    – chishimutoji
    10 hours ago













  • And I just check pages 38 of the documentation BUT there is no anything as you can see. :-)

    – chishimutoji
    10 hours ago











  • I see only 5 colors. pages 38ff show anything about colors.

    – Herbert
    10 hours ago
















4














documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { Colors Rand 4.5 mul cvi get } for
9 1 17 { Colors Rand 4.5 mul cvi get } for
18 1 26 { Colors Rand 4.5 mul cvi get } for
27 1 35 { Colors Rand 4.5 mul cvi get } for
36 1 44 { Colors Rand 4.5 mul cvi get } for
45 1 53 { Colors Rand 4.5 mul cvi get } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



 0 1 8 {      from 0 to 8 with step 1 do
put the loop variable on the stack
Colors. Load Color array
Rand get a random number between 0 and 1
4.5 mul between 0 and 4.5
cvi between 0 and 4
get load color with random number
} for. end of for loop


Every square has a corresponding number 0 .. 53 which can be used
for color setting: 0 (red) 1 (green) ... and so on. see pages 38 ff of
the documentation.



The same for complete faces:



documentclass[pstricks,border=10pt]{standalone}

usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { (red) } for
9 1 17 { (green) } for
18 1 26 { (blue) } for
27 1 35 { (orange) } for
36 1 44 { (yellow) } for
45 1 53 { (cyan) } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here






share|improve this answer


























  • Please to answer the first question. Your code(PostScript language) is new with me...

    – chishimutoji
    10 hours ago













  • see edited answer ...

    – Herbert
    10 hours ago











  • Oh, you misunderstood me. I mean that you can rewrite my code as the smart way.( my figure only 6 colors). The second question is not important. :-) And of course thanks for your expansion..

    – chishimutoji
    10 hours ago













  • And I just check pages 38 of the documentation BUT there is no anything as you can see. :-)

    – chishimutoji
    10 hours ago











  • I see only 5 colors. pages 38ff show anything about colors.

    – Herbert
    10 hours ago














4












4








4







documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { Colors Rand 4.5 mul cvi get } for
9 1 17 { Colors Rand 4.5 mul cvi get } for
18 1 26 { Colors Rand 4.5 mul cvi get } for
27 1 35 { Colors Rand 4.5 mul cvi get } for
36 1 44 { Colors Rand 4.5 mul cvi get } for
45 1 53 { Colors Rand 4.5 mul cvi get } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



 0 1 8 {      from 0 to 8 with step 1 do
put the loop variable on the stack
Colors. Load Color array
Rand get a random number between 0 and 1
4.5 mul between 0 and 4.5
cvi between 0 and 4
get load color with random number
} for. end of for loop


Every square has a corresponding number 0 .. 53 which can be used
for color setting: 0 (red) 1 (green) ... and so on. see pages 38 ff of
the documentation.



The same for complete faces:



documentclass[pstricks,border=10pt]{standalone}

usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { (red) } for
9 1 17 { (green) } for
18 1 26 { (blue) } for
27 1 35 { (orange) } for
36 1 44 { (yellow) } for
45 1 53 { (cyan) } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here






share|improve this answer















documentclass[pstricks,border=10pt]{standalone}
usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { Colors Rand 4.5 mul cvi get } for
9 1 17 { Colors Rand 4.5 mul cvi get } for
18 1 26 { Colors Rand 4.5 mul cvi get } for
27 1 35 { Colors Rand 4.5 mul cvi get } for
36 1 44 { Colors Rand 4.5 mul cvi get } for
45 1 53 { Colors Rand 4.5 mul cvi get } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here



 0 1 8 {      from 0 to 8 with step 1 do
put the loop variable on the stack
Colors. Load Color array
Rand get a random number between 0 and 1
4.5 mul between 0 and 4.5
cvi between 0 and 4
get load color with random number
} for. end of for loop


Every square has a corresponding number 0 .. 53 which can be used
for color setting: 0 (red) 1 (green) ... and so on. see pages 38 ff of
the documentation.



The same for complete faces:



documentclass[pstricks,border=10pt]{standalone}

usepackage{pst-solides3d}
begin{document}

psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
deffigure#1#2{%
begin{pspicture}(-3,-3)(3,3)
psSolid[a=8,object=cube,ngrid=3,%
fcol=
0 1 8 { (red) } for
9 1 17 { (green) } for
18 1 26 { (blue) } for
27 1 35 { (orange) } for
36 1 44 { (yellow) } for
45 1 53 { (cyan) } for,
Rot#2=-#1space]%
end{pspicture}
}
multido{iA=0+10}{36}{figure{iA}{X}}
multido{iA=0+10}{36}{figure{iA}{Y}}
multido{iA=0+10}{36}{figure{iA}{Z}}
end{document}


enter image description here







share|improve this answer














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edited 10 hours ago

























answered 11 hours ago









HerbertHerbert

274k24417730




274k24417730













  • Please to answer the first question. Your code(PostScript language) is new with me...

    – chishimutoji
    10 hours ago













  • see edited answer ...

    – Herbert
    10 hours ago











  • Oh, you misunderstood me. I mean that you can rewrite my code as the smart way.( my figure only 6 colors). The second question is not important. :-) And of course thanks for your expansion..

    – chishimutoji
    10 hours ago













  • And I just check pages 38 of the documentation BUT there is no anything as you can see. :-)

    – chishimutoji
    10 hours ago











  • I see only 5 colors. pages 38ff show anything about colors.

    – Herbert
    10 hours ago



















  • Please to answer the first question. Your code(PostScript language) is new with me...

    – chishimutoji
    10 hours ago













  • see edited answer ...

    – Herbert
    10 hours ago











  • Oh, you misunderstood me. I mean that you can rewrite my code as the smart way.( my figure only 6 colors). The second question is not important. :-) And of course thanks for your expansion..

    – chishimutoji
    10 hours ago













  • And I just check pages 38 of the documentation BUT there is no anything as you can see. :-)

    – chishimutoji
    10 hours ago











  • I see only 5 colors. pages 38ff show anything about colors.

    – Herbert
    10 hours ago

















Please to answer the first question. Your code(PostScript language) is new with me...

– chishimutoji
10 hours ago







Please to answer the first question. Your code(PostScript language) is new with me...

– chishimutoji
10 hours ago















see edited answer ...

– Herbert
10 hours ago





see edited answer ...

– Herbert
10 hours ago













Oh, you misunderstood me. I mean that you can rewrite my code as the smart way.( my figure only 6 colors). The second question is not important. :-) And of course thanks for your expansion..

– chishimutoji
10 hours ago







Oh, you misunderstood me. I mean that you can rewrite my code as the smart way.( my figure only 6 colors). The second question is not important. :-) And of course thanks for your expansion..

– chishimutoji
10 hours ago















And I just check pages 38 of the documentation BUT there is no anything as you can see. :-)

– chishimutoji
10 hours ago





And I just check pages 38 of the documentation BUT there is no anything as you can see. :-)

– chishimutoji
10 hours ago













I see only 5 colors. pages 38ff show anything about colors.

– Herbert
10 hours ago





I see only 5 colors. pages 38ff show anything about colors.

– Herbert
10 hours ago


















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