Figuring out the remaining seconds left until a certain time with bash?
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0
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I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.
I want to use this as an argument for the 'shutdown' command for example.
how do I do this?
bash shell-script scripting
edited 2 days ago
Rui F Ribeiro
38.5k1479128
asked 2 days ago
dudawe
31
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dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
0
down vote
favorite
I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.
I want to use this as an argument for the 'shutdown' command for example.
how do I do this?
bash shell-script scripting
edited 2 days ago
Rui F Ribeiro
38.5k1479128
asked 2 days ago
dudawe
31
New contributor
dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.
I want to use this as an argument for the 'shutdown' command for example.
how do I do this?
bash shell-script scripting
edited 2 days ago
Rui F Ribeiro
38.5k1479128
asked 2 days ago
dudawe
31
New contributor
dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.
I want to use this as an argument for the 'shutdown' command for example.
how do I do this?
bash shell-script scripting
bash shell-script scripting
edited 2 days ago
Rui F Ribeiro
38.5k1479128
asked 2 days ago
dudawe
31
New contributor
dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Rui F Ribeiro
38.5k1479128
asked 2 days ago
dudawe
31
New contributor
dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Rui F Ribeiro
38.5k1479128
edited 2 days ago
Rui F Ribeiro
38.5k1479128
edited 2 days ago
Rui F Ribeiro
38.5k1479128
38.5k1479128
asked 2 days ago
dudawe
31
New contributor
dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
dudawe
31
asked 2 days ago
dudawe
31
31
New contributor
dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered 2 days ago
tink
4,07511218
Great! Thank you, foot man
– dudawe
2 days ago
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
2 days ago
how do I divide by 60? in the same command?
– dudawe
2 days ago
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
2 days ago
1
Awesome! I tried without the additional brackets (noob)
– dudawe
2 days ago
add a comment |
up vote
0
down vote
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered 2 days ago
Isaac
10.8k11447
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered 2 days ago
tink
4,07511218
Great! Thank you, foot man
– dudawe
2 days ago
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
2 days ago
how do I divide by 60? in the same command?
– dudawe
2 days ago
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
2 days ago
1
Awesome! I tried without the additional brackets (noob)
– dudawe
2 days ago
add a comment |
up vote
1
down vote
accepted
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered 2 days ago
tink
4,07511218
Great! Thank you, foot man
– dudawe
2 days ago
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
2 days ago
how do I divide by 60? in the same command?
– dudawe
2 days ago
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
2 days ago
1
Awesome! I tried without the additional brackets (noob)
– dudawe
2 days ago
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered 2 days ago
tink
4,07511218
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered 2 days ago
tink
4,07511218
answered 2 days ago
tink
4,07511218
answered 2 days ago
tink
4,07511218
answered 2 days ago
tink
4,07511218
4,07511218
Great! Thank you, foot man
– dudawe
2 days ago
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
2 days ago
how do I divide by 60? in the same command?
– dudawe
2 days ago
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
2 days ago
1
Awesome! I tried without the additional brackets (noob)
– dudawe
2 days ago
add a comment |
Great! Thank you, foot man
– dudawe
2 days ago
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
2 days ago
how do I divide by 60? in the same command?
– dudawe
2 days ago
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
2 days ago
1
Awesome! I tried without the additional brackets (noob)
– dudawe
2 days ago
Great! Thank you, foot man
– dudawe
2 days ago
Great! Thank you, foot man
– dudawe
2 days ago
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
2 days ago
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
2 days ago
how do I divide by 60? in the same command?
– dudawe
2 days ago
how do I divide by 60? in the same command?
– dudawe
2 days ago
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
2 days ago
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
2 days ago
1
1
Awesome! I tried without the additional brackets (noob)
– dudawe
2 days ago
Awesome! I tried without the additional brackets (noob)
– dudawe
2 days ago
add a comment |
up vote
0
down vote
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered 2 days ago
Isaac
10.8k11447
add a comment |
up vote
0
down vote
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered 2 days ago
Isaac
10.8k11447
add a comment |
up vote
0
down vote
up vote
0
down vote
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered 2 days ago
Isaac
10.8k11447
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered 2 days ago
Isaac
10.8k11447
edited 2 days ago
answered 2 days ago
Isaac
10.8k11447
answered 2 days ago
Isaac
10.8k11447
answered 2 days ago
Isaac
10.8k11447
10.8k11447
add a comment |
add a comment |
dudawe is a new contributor. Be nice, and check out our Code of Conduct.
dudawe is a new contributor. Be nice, and check out our Code of Conduct.
dudawe is a new contributor. Be nice, and check out our Code of Conduct.
dudawe is a new contributor. Be nice, and check out our Code of Conduct.
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