Figuring out the remaining seconds left until a certain time with bash?











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I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.



I want to use this as an argument for the 'shutdown' command for example.



how do I do this?






bash shell-script scripting







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    up vote
    0
    down vote

    favorite












    I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.



    I want to use this as an argument for the 'shutdown' command for example.



    how do I do this?






    bash shell-script scripting







    share|improve this question









    New contributor




    dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.



      I want to use this as an argument for the 'shutdown' command for example.



      how do I do this?






      bash shell-script scripting







      share|improve this question









      New contributor




      dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.



      I want to use this as an argument for the 'shutdown' command for example.



      how do I do this?






      bash shell-script scripting




      bash shell-script scripting






      share|improve this question









      New contributor




      dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 2 days ago









      Rui F Ribeiro

      38.5k1479128




      38.5k1479128






      New contributor




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      asked 2 days ago









      dudawe

      31




      31




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      New contributor





      dudawe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      Check out our Code of Conduct.






















          2 Answers
          2






          active

          oldest

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          up vote
          1
          down vote



          accepted










          Something like this?



          echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
          
59856





          share|improve this answer





















          • Great! Thank you, foot man
            – dudawe
            2 days ago










          • You're welcome ;) Feel free to up-vote or accept :D the answer.
            – tink
            2 days ago










          • how do I divide by 60? in the same command?
            – dudawe
            2 days ago










          • ` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
            – tink
            2 days ago






          • 1




            Awesome! I tried without the additional brackets (noob)
            – dudawe
            2 days ago


















          up vote
          0
          down vote













          The conversion to a time string could be done directly in bash (less than 24 hours):



           $ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
          
 00:02:03


          The time difference could be found with simple math:



           $ now=$(printf '%(%s)T')
          
 $ future=$(date -d '+10 hours' '+%s')
          
 $ tdiff=$(( future - now ))
          
 $ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
          
 10:00:00


          To get up to 364 days use this:



           now=$(printf '%(%s)T')
          
 future=$(date -d '+10 hour' '+%s')
          
 tdiff=$(( future - now ))
          
 j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
          
 TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
          

          
 0 days 10:00:00





          share|improve this answer























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            1
            down vote



            accepted










            Something like this?



            echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
            
59856





            share|improve this answer





















            • Great! Thank you, foot man
              – dudawe
              2 days ago










            • You're welcome ;) Feel free to up-vote or accept :D the answer.
              – tink
              2 days ago










            • how do I divide by 60? in the same command?
              – dudawe
              2 days ago










            • ` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
              – tink
              2 days ago






            • 1




              Awesome! I tried without the additional brackets (noob)
              – dudawe
              2 days ago















            up vote
            1
            down vote



            accepted










            Something like this?



            echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
            
59856





            share|improve this answer





















            • Great! Thank you, foot man
              – dudawe
              2 days ago










            • You're welcome ;) Feel free to up-vote or accept :D the answer.
              – tink
              2 days ago










            • how do I divide by 60? in the same command?
              – dudawe
              2 days ago










            • ` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
              – tink
              2 days ago






            • 1




              Awesome! I tried without the additional brackets (noob)
              – dudawe
              2 days ago













            up vote
            1
            down vote



            accepted







            up vote
            1
            down vote



            accepted






            Something like this?



            echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
            
59856





            share|improve this answer












            Something like this?



            echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
            
59856






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 2 days ago









            tink

            4,07511218




            4,07511218












            • Great! Thank you, foot man
              – dudawe
              2 days ago










            • You're welcome ;) Feel free to up-vote or accept :D the answer.
              – tink
              2 days ago










            • how do I divide by 60? in the same command?
              – dudawe
              2 days ago










            • ` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
              – tink
              2 days ago






            • 1




              Awesome! I tried without the additional brackets (noob)
              – dudawe
              2 days ago


















            • Great! Thank you, foot man
              – dudawe
              2 days ago










            • You're welcome ;) Feel free to up-vote or accept :D the answer.
              – tink
              2 days ago










            • how do I divide by 60? in the same command?
              – dudawe
              2 days ago










            • ` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
              – tink
              2 days ago






            • 1




              Awesome! I tried without the additional brackets (noob)
              – dudawe
              2 days ago
















            Great! Thank you, foot man
            – dudawe
            2 days ago




            Great! Thank you, foot man
            – dudawe
            2 days ago












            You're welcome ;) Feel free to up-vote or accept :D the answer.
            – tink
            2 days ago




            You're welcome ;) Feel free to up-vote or accept :D the answer.
            – tink
            2 days ago












            how do I divide by 60? in the same command?
            – dudawe
            2 days ago




            how do I divide by 60? in the same command?
            – dudawe
            2 days ago












            ` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
            – tink
            2 days ago




            ` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
            – tink
            2 days ago




            1




            1




            Awesome! I tried without the additional brackets (noob)
            – dudawe
            2 days ago




            Awesome! I tried without the additional brackets (noob)
            – dudawe
            2 days ago












            up vote
            0
            down vote













            The conversion to a time string could be done directly in bash (less than 24 hours):



             $ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
            
 00:02:03


            The time difference could be found with simple math:



             $ now=$(printf '%(%s)T')
            
 $ future=$(date -d '+10 hours' '+%s')
            
 $ tdiff=$(( future - now ))
            
 $ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
            
 10:00:00


            To get up to 364 days use this:



             now=$(printf '%(%s)T')
            
 future=$(date -d '+10 hour' '+%s')
            
 tdiff=$(( future - now ))
            
 j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
            
 TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
            

            
 0 days 10:00:00





            share|improve this answer



























              up vote
              0
              down vote













              The conversion to a time string could be done directly in bash (less than 24 hours):



               $ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
              
 00:02:03


              The time difference could be found with simple math:



               $ now=$(printf '%(%s)T')
              
 $ future=$(date -d '+10 hours' '+%s')
              
 $ tdiff=$(( future - now ))
              
 $ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
              
 10:00:00


              To get up to 364 days use this:



               now=$(printf '%(%s)T')
              
 future=$(date -d '+10 hour' '+%s')
              
 tdiff=$(( future - now ))
              
 j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
              
 TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
              

              
 0 days 10:00:00





              share|improve this answer

























                up vote
                0
                down vote










                up vote
                0
                down vote









                The conversion to a time string could be done directly in bash (less than 24 hours):



                 $ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
                
 00:02:03


                The time difference could be found with simple math:



                 $ now=$(printf '%(%s)T')
                
 $ future=$(date -d '+10 hours' '+%s')
                
 $ tdiff=$(( future - now ))
                
 $ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
                
 10:00:00


                To get up to 364 days use this:



                 now=$(printf '%(%s)T')
                
 future=$(date -d '+10 hour' '+%s')
                
 tdiff=$(( future - now ))
                
 j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
                
 TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
                

                
 0 days 10:00:00





                share|improve this answer














                The conversion to a time string could be done directly in bash (less than 24 hours):



                 $ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
                
 00:02:03


                The time difference could be found with simple math:



                 $ now=$(printf '%(%s)T')
                
 $ future=$(date -d '+10 hours' '+%s')
                
 $ tdiff=$(( future - now ))
                
 $ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
                
 10:00:00


                To get up to 364 days use this:



                 now=$(printf '%(%s)T')
                
 future=$(date -d '+10 hour' '+%s')
                
 tdiff=$(( future - now ))
                
 j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
                
 TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
                

                
 0 days 10:00:00






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 2 days ago

























                answered 2 days ago









                Isaac

                10.8k11447




                10.8k11447






















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