How do I make multiple directories at once in a directory?











up vote
25
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I know with mkdir I can do mkdir A B C D E F to create each directory. How do I create directories A-Z or 1-100 with out typing in each letter or number?










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    up vote
    25
    down vote

    favorite
    7












    I know with mkdir I can do mkdir A B C D E F to create each directory. How do I create directories A-Z or 1-100 with out typing in each letter or number?










    share|improve this question
























      up vote
      25
      down vote

      favorite
      7









      up vote
      25
      down vote

      favorite
      7






      7





      I know with mkdir I can do mkdir A B C D E F to create each directory. How do I create directories A-Z or 1-100 with out typing in each letter or number?










      share|improve this question













      I know with mkdir I can do mkdir A B C D E F to create each directory. How do I create directories A-Z or 1-100 with out typing in each letter or number?







      linux command-line






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Aug 18 '10 at 1:33









      Steve Burdine

      3,44651919




      3,44651919






















          6 Answers
          6






          active

          oldest

          votes

















          up vote
          17
          down vote



          accepted










          It's probably easiest to just use a for loop:



          for char in {A..Z}; do
          mkdir $char
          done

          for num in {1..100}; do
          mkdir $num
          done


          You need at least bash 3.0 though; otherwise you have to use something like seq






          share|improve this answer

















          • 1




            Michael thanks! being curious I also tried it adding test in front of $char for char in {A..Z}; do mkdir test$char done which gave me directories test[A-Z], always good to learn
            – Steve Burdine
            Aug 18 '10 at 1:48












          • One thing to keep in mind is how your file names will be sorted when you list them or use them with wildcards like *. '11' will sort before '2'. This can be avoided if you arrange for all the numbers to be the same length with leading zeros. Dennis Williams shows how to do that in bash 4, but you can code your script to do it if you don't have bash 4.
            – Joe
            Dec 11 '11 at 6:45


















          up vote
          69
          down vote













          The {} syntax is Bash syntax not tied to the for construct.



          mkdir {A..Z}


          is sufficient all by itself.



          http://www.gnu.org/software/bash/manual/bashref.html#Brace-Expansion






          share|improve this answer



















          • 4




            Oh, that's spectacular. This is a much better answer
            – Michael Mrozek
            Aug 18 '10 at 1:58






          • 1




            I didn't know this, great tip!
            – invert
            Aug 18 '10 at 9:34






          • 5




            +1 for beauty, +1 for style, +1 for rcrowley
            – Stefan
            Sep 16 '10 at 10:02










          • +500 bounty from me.
            – George Chalhoub
            Dec 24 '15 at 17:41










          • This is awesome! just used it: mkdir -p ./logs-{1..5}
            – Pranav 웃
            Jan 17 '16 at 6:22


















          up vote
          8
          down vote













          You can also do more complex combinations (try these with echo instead of mkdir so there's no cleanup afterwards):



          Compare



          $ echo pre-{{F..G},{3..4},{m..n}}-post
          pre-F-post pre-G-post pre-3-post pre-4-post pre-m-post pre-n-post


          to



          $ echo pre-{F..G}{3..4}{m..n}-post
          pre-F3m-post pre-F3n-post pre-F4m-post pre-F4n-post pre-G3m-post pre-G3n-post
          pre-G4m-post pre-G4n-post


          If you have Bash 4, try



          $ echo file{0001..10}
          file0001 file0002 file0003 file0004 file0005 file0006 file0007 file0008 file0009
          file0010


          and



          $ echo file{0001..10..2}
          file0001 file0003 file0005 file0007 file0009





          share|improve this answer






























            up vote
            7
            down vote













            On Linux you can generate sequences of digits with the "seq" command, but this doesn't exist on all Unix systems. For example to generate directories from 1 to 100:



            mkdir `seq 1 100`


            While you can certainly make directories A to Z with shell utils:



            seq 65 90 
            | while read foo; do printf "%bn" `printf '\\x%xn' $foo`; done
            | xargs mkdir


            It's probably a lot less ugly to just use Perl:



            perl -e 'foreach (ord "A"..ord "Z") { mkdir chr $_ }'





            share|improve this answer




























              up vote
              -1
              down vote













              mkdir direct{1..3} will result in mkdir direct1 direct2 direct3 and so on . Same for {a..z}






              share|improve this answer










              New contributor




              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.














              • 2




                this is a reiteration of three existing answers and the one that I already commented on
                – Jeff Schaller
                yesterday


















              up vote
              -2
              down vote













              mkdir {A..Z}
              mkdir {0..100}
              mkdir test_{A..Z}
              and so on.






              share|improve this answer








              New contributor




              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.


















              • I do not get it
                – Pierre.Vriens
                2 days ago






              • 1




                this has already been covered
                – Jeff Schaller
                2 days ago











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              6 Answers
              6






              active

              oldest

              votes








              6 Answers
              6






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              17
              down vote



              accepted










              It's probably easiest to just use a for loop:



              for char in {A..Z}; do
              mkdir $char
              done

              for num in {1..100}; do
              mkdir $num
              done


              You need at least bash 3.0 though; otherwise you have to use something like seq






              share|improve this answer

















              • 1




                Michael thanks! being curious I also tried it adding test in front of $char for char in {A..Z}; do mkdir test$char done which gave me directories test[A-Z], always good to learn
                – Steve Burdine
                Aug 18 '10 at 1:48












              • One thing to keep in mind is how your file names will be sorted when you list them or use them with wildcards like *. '11' will sort before '2'. This can be avoided if you arrange for all the numbers to be the same length with leading zeros. Dennis Williams shows how to do that in bash 4, but you can code your script to do it if you don't have bash 4.
                – Joe
                Dec 11 '11 at 6:45















              up vote
              17
              down vote



              accepted










              It's probably easiest to just use a for loop:



              for char in {A..Z}; do
              mkdir $char
              done

              for num in {1..100}; do
              mkdir $num
              done


              You need at least bash 3.0 though; otherwise you have to use something like seq






              share|improve this answer

















              • 1




                Michael thanks! being curious I also tried it adding test in front of $char for char in {A..Z}; do mkdir test$char done which gave me directories test[A-Z], always good to learn
                – Steve Burdine
                Aug 18 '10 at 1:48












              • One thing to keep in mind is how your file names will be sorted when you list them or use them with wildcards like *. '11' will sort before '2'. This can be avoided if you arrange for all the numbers to be the same length with leading zeros. Dennis Williams shows how to do that in bash 4, but you can code your script to do it if you don't have bash 4.
                – Joe
                Dec 11 '11 at 6:45













              up vote
              17
              down vote



              accepted







              up vote
              17
              down vote



              accepted






              It's probably easiest to just use a for loop:



              for char in {A..Z}; do
              mkdir $char
              done

              for num in {1..100}; do
              mkdir $num
              done


              You need at least bash 3.0 though; otherwise you have to use something like seq






              share|improve this answer












              It's probably easiest to just use a for loop:



              for char in {A..Z}; do
              mkdir $char
              done

              for num in {1..100}; do
              mkdir $num
              done


              You need at least bash 3.0 though; otherwise you have to use something like seq







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Aug 18 '10 at 1:37









              Michael Mrozek

              59.9k28187208




              59.9k28187208








              • 1




                Michael thanks! being curious I also tried it adding test in front of $char for char in {A..Z}; do mkdir test$char done which gave me directories test[A-Z], always good to learn
                – Steve Burdine
                Aug 18 '10 at 1:48












              • One thing to keep in mind is how your file names will be sorted when you list them or use them with wildcards like *. '11' will sort before '2'. This can be avoided if you arrange for all the numbers to be the same length with leading zeros. Dennis Williams shows how to do that in bash 4, but you can code your script to do it if you don't have bash 4.
                – Joe
                Dec 11 '11 at 6:45














              • 1




                Michael thanks! being curious I also tried it adding test in front of $char for char in {A..Z}; do mkdir test$char done which gave me directories test[A-Z], always good to learn
                – Steve Burdine
                Aug 18 '10 at 1:48












              • One thing to keep in mind is how your file names will be sorted when you list them or use them with wildcards like *. '11' will sort before '2'. This can be avoided if you arrange for all the numbers to be the same length with leading zeros. Dennis Williams shows how to do that in bash 4, but you can code your script to do it if you don't have bash 4.
                – Joe
                Dec 11 '11 at 6:45








              1




              1




              Michael thanks! being curious I also tried it adding test in front of $char for char in {A..Z}; do mkdir test$char done which gave me directories test[A-Z], always good to learn
              – Steve Burdine
              Aug 18 '10 at 1:48






              Michael thanks! being curious I also tried it adding test in front of $char for char in {A..Z}; do mkdir test$char done which gave me directories test[A-Z], always good to learn
              – Steve Burdine
              Aug 18 '10 at 1:48














              One thing to keep in mind is how your file names will be sorted when you list them or use them with wildcards like *. '11' will sort before '2'. This can be avoided if you arrange for all the numbers to be the same length with leading zeros. Dennis Williams shows how to do that in bash 4, but you can code your script to do it if you don't have bash 4.
              – Joe
              Dec 11 '11 at 6:45




              One thing to keep in mind is how your file names will be sorted when you list them or use them with wildcards like *. '11' will sort before '2'. This can be avoided if you arrange for all the numbers to be the same length with leading zeros. Dennis Williams shows how to do that in bash 4, but you can code your script to do it if you don't have bash 4.
              – Joe
              Dec 11 '11 at 6:45












              up vote
              69
              down vote













              The {} syntax is Bash syntax not tied to the for construct.



              mkdir {A..Z}


              is sufficient all by itself.



              http://www.gnu.org/software/bash/manual/bashref.html#Brace-Expansion






              share|improve this answer



















              • 4




                Oh, that's spectacular. This is a much better answer
                – Michael Mrozek
                Aug 18 '10 at 1:58






              • 1




                I didn't know this, great tip!
                – invert
                Aug 18 '10 at 9:34






              • 5




                +1 for beauty, +1 for style, +1 for rcrowley
                – Stefan
                Sep 16 '10 at 10:02










              • +500 bounty from me.
                – George Chalhoub
                Dec 24 '15 at 17:41










              • This is awesome! just used it: mkdir -p ./logs-{1..5}
                – Pranav 웃
                Jan 17 '16 at 6:22















              up vote
              69
              down vote













              The {} syntax is Bash syntax not tied to the for construct.



              mkdir {A..Z}


              is sufficient all by itself.



              http://www.gnu.org/software/bash/manual/bashref.html#Brace-Expansion






              share|improve this answer



















              • 4




                Oh, that's spectacular. This is a much better answer
                – Michael Mrozek
                Aug 18 '10 at 1:58






              • 1




                I didn't know this, great tip!
                – invert
                Aug 18 '10 at 9:34






              • 5




                +1 for beauty, +1 for style, +1 for rcrowley
                – Stefan
                Sep 16 '10 at 10:02










              • +500 bounty from me.
                – George Chalhoub
                Dec 24 '15 at 17:41










              • This is awesome! just used it: mkdir -p ./logs-{1..5}
                – Pranav 웃
                Jan 17 '16 at 6:22













              up vote
              69
              down vote










              up vote
              69
              down vote









              The {} syntax is Bash syntax not tied to the for construct.



              mkdir {A..Z}


              is sufficient all by itself.



              http://www.gnu.org/software/bash/manual/bashref.html#Brace-Expansion






              share|improve this answer














              The {} syntax is Bash syntax not tied to the for construct.



              mkdir {A..Z}


              is sufficient all by itself.



              http://www.gnu.org/software/bash/manual/bashref.html#Brace-Expansion







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Aug 18 '10 at 1:58

























              answered Aug 18 '10 at 1:49









              rcrowley

              997166




              997166








              • 4




                Oh, that's spectacular. This is a much better answer
                – Michael Mrozek
                Aug 18 '10 at 1:58






              • 1




                I didn't know this, great tip!
                – invert
                Aug 18 '10 at 9:34






              • 5




                +1 for beauty, +1 for style, +1 for rcrowley
                – Stefan
                Sep 16 '10 at 10:02










              • +500 bounty from me.
                – George Chalhoub
                Dec 24 '15 at 17:41










              • This is awesome! just used it: mkdir -p ./logs-{1..5}
                – Pranav 웃
                Jan 17 '16 at 6:22














              • 4




                Oh, that's spectacular. This is a much better answer
                – Michael Mrozek
                Aug 18 '10 at 1:58






              • 1




                I didn't know this, great tip!
                – invert
                Aug 18 '10 at 9:34






              • 5




                +1 for beauty, +1 for style, +1 for rcrowley
                – Stefan
                Sep 16 '10 at 10:02










              • +500 bounty from me.
                – George Chalhoub
                Dec 24 '15 at 17:41










              • This is awesome! just used it: mkdir -p ./logs-{1..5}
                – Pranav 웃
                Jan 17 '16 at 6:22








              4




              4




              Oh, that's spectacular. This is a much better answer
              – Michael Mrozek
              Aug 18 '10 at 1:58




              Oh, that's spectacular. This is a much better answer
              – Michael Mrozek
              Aug 18 '10 at 1:58




              1




              1




              I didn't know this, great tip!
              – invert
              Aug 18 '10 at 9:34




              I didn't know this, great tip!
              – invert
              Aug 18 '10 at 9:34




              5




              5




              +1 for beauty, +1 for style, +1 for rcrowley
              – Stefan
              Sep 16 '10 at 10:02




              +1 for beauty, +1 for style, +1 for rcrowley
              – Stefan
              Sep 16 '10 at 10:02












              +500 bounty from me.
              – George Chalhoub
              Dec 24 '15 at 17:41




              +500 bounty from me.
              – George Chalhoub
              Dec 24 '15 at 17:41












              This is awesome! just used it: mkdir -p ./logs-{1..5}
              – Pranav 웃
              Jan 17 '16 at 6:22




              This is awesome! just used it: mkdir -p ./logs-{1..5}
              – Pranav 웃
              Jan 17 '16 at 6:22










              up vote
              8
              down vote













              You can also do more complex combinations (try these with echo instead of mkdir so there's no cleanup afterwards):



              Compare



              $ echo pre-{{F..G},{3..4},{m..n}}-post
              pre-F-post pre-G-post pre-3-post pre-4-post pre-m-post pre-n-post


              to



              $ echo pre-{F..G}{3..4}{m..n}-post
              pre-F3m-post pre-F3n-post pre-F4m-post pre-F4n-post pre-G3m-post pre-G3n-post
              pre-G4m-post pre-G4n-post


              If you have Bash 4, try



              $ echo file{0001..10}
              file0001 file0002 file0003 file0004 file0005 file0006 file0007 file0008 file0009
              file0010


              and



              $ echo file{0001..10..2}
              file0001 file0003 file0005 file0007 file0009





              share|improve this answer



























                up vote
                8
                down vote













                You can also do more complex combinations (try these with echo instead of mkdir so there's no cleanup afterwards):



                Compare



                $ echo pre-{{F..G},{3..4},{m..n}}-post
                pre-F-post pre-G-post pre-3-post pre-4-post pre-m-post pre-n-post


                to



                $ echo pre-{F..G}{3..4}{m..n}-post
                pre-F3m-post pre-F3n-post pre-F4m-post pre-F4n-post pre-G3m-post pre-G3n-post
                pre-G4m-post pre-G4n-post


                If you have Bash 4, try



                $ echo file{0001..10}
                file0001 file0002 file0003 file0004 file0005 file0006 file0007 file0008 file0009
                file0010


                and



                $ echo file{0001..10..2}
                file0001 file0003 file0005 file0007 file0009





                share|improve this answer

























                  up vote
                  8
                  down vote










                  up vote
                  8
                  down vote









                  You can also do more complex combinations (try these with echo instead of mkdir so there's no cleanup afterwards):



                  Compare



                  $ echo pre-{{F..G},{3..4},{m..n}}-post
                  pre-F-post pre-G-post pre-3-post pre-4-post pre-m-post pre-n-post


                  to



                  $ echo pre-{F..G}{3..4}{m..n}-post
                  pre-F3m-post pre-F3n-post pre-F4m-post pre-F4n-post pre-G3m-post pre-G3n-post
                  pre-G4m-post pre-G4n-post


                  If you have Bash 4, try



                  $ echo file{0001..10}
                  file0001 file0002 file0003 file0004 file0005 file0006 file0007 file0008 file0009
                  file0010


                  and



                  $ echo file{0001..10..2}
                  file0001 file0003 file0005 file0007 file0009





                  share|improve this answer














                  You can also do more complex combinations (try these with echo instead of mkdir so there's no cleanup afterwards):



                  Compare



                  $ echo pre-{{F..G},{3..4},{m..n}}-post
                  pre-F-post pre-G-post pre-3-post pre-4-post pre-m-post pre-n-post


                  to



                  $ echo pre-{F..G}{3..4}{m..n}-post
                  pre-F3m-post pre-F3n-post pre-F4m-post pre-F4n-post pre-G3m-post pre-G3n-post
                  pre-G4m-post pre-G4n-post


                  If you have Bash 4, try



                  $ echo file{0001..10}
                  file0001 file0002 file0003 file0004 file0005 file0006 file0007 file0008 file0009
                  file0010


                  and



                  $ echo file{0001..10..2}
                  file0001 file0003 file0005 file0007 file0009






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Aug 19 '10 at 23:30

























                  answered Aug 19 '10 at 0:44









                  Dennis Williamson

                  5,32812232




                  5,32812232






















                      up vote
                      7
                      down vote













                      On Linux you can generate sequences of digits with the "seq" command, but this doesn't exist on all Unix systems. For example to generate directories from 1 to 100:



                      mkdir `seq 1 100`


                      While you can certainly make directories A to Z with shell utils:



                      seq 65 90 
                      | while read foo; do printf "%bn" `printf '\\x%xn' $foo`; done
                      | xargs mkdir


                      It's probably a lot less ugly to just use Perl:



                      perl -e 'foreach (ord "A"..ord "Z") { mkdir chr $_ }'





                      share|improve this answer

























                        up vote
                        7
                        down vote













                        On Linux you can generate sequences of digits with the "seq" command, but this doesn't exist on all Unix systems. For example to generate directories from 1 to 100:



                        mkdir `seq 1 100`


                        While you can certainly make directories A to Z with shell utils:



                        seq 65 90 
                        | while read foo; do printf "%bn" `printf '\\x%xn' $foo`; done
                        | xargs mkdir


                        It's probably a lot less ugly to just use Perl:



                        perl -e 'foreach (ord "A"..ord "Z") { mkdir chr $_ }'





                        share|improve this answer























                          up vote
                          7
                          down vote










                          up vote
                          7
                          down vote









                          On Linux you can generate sequences of digits with the "seq" command, but this doesn't exist on all Unix systems. For example to generate directories from 1 to 100:



                          mkdir `seq 1 100`


                          While you can certainly make directories A to Z with shell utils:



                          seq 65 90 
                          | while read foo; do printf "%bn" `printf '\\x%xn' $foo`; done
                          | xargs mkdir


                          It's probably a lot less ugly to just use Perl:



                          perl -e 'foreach (ord "A"..ord "Z") { mkdir chr $_ }'





                          share|improve this answer












                          On Linux you can generate sequences of digits with the "seq" command, but this doesn't exist on all Unix systems. For example to generate directories from 1 to 100:



                          mkdir `seq 1 100`


                          While you can certainly make directories A to Z with shell utils:



                          seq 65 90 
                          | while read foo; do printf "%bn" `printf '\\x%xn' $foo`; done
                          | xargs mkdir


                          It's probably a lot less ugly to just use Perl:



                          perl -e 'foreach (ord "A"..ord "Z") { mkdir chr $_ }'






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Aug 18 '10 at 1:46









                          dhd

                          1211




                          1211






















                              up vote
                              -1
                              down vote













                              mkdir direct{1..3} will result in mkdir direct1 direct2 direct3 and so on . Same for {a..z}






                              share|improve this answer










                              New contributor




                              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.














                              • 2




                                this is a reiteration of three existing answers and the one that I already commented on
                                – Jeff Schaller
                                yesterday















                              up vote
                              -1
                              down vote













                              mkdir direct{1..3} will result in mkdir direct1 direct2 direct3 and so on . Same for {a..z}






                              share|improve this answer










                              New contributor




                              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.














                              • 2




                                this is a reiteration of three existing answers and the one that I already commented on
                                – Jeff Schaller
                                yesterday













                              up vote
                              -1
                              down vote










                              up vote
                              -1
                              down vote









                              mkdir direct{1..3} will result in mkdir direct1 direct2 direct3 and so on . Same for {a..z}






                              share|improve this answer










                              New contributor




                              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              mkdir direct{1..3} will result in mkdir direct1 direct2 direct3 and so on . Same for {a..z}







                              share|improve this answer










                              New contributor




                              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              share|improve this answer



                              share|improve this answer








                              edited yesterday









                              Jesse_b

                              11.4k23063




                              11.4k23063






                              New contributor




                              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              answered yesterday









                              Lionel AVOGNON

                              9




                              9




                              New contributor




                              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.





                              New contributor





                              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                              Lionel AVOGNON is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                              • 2




                                this is a reiteration of three existing answers and the one that I already commented on
                                – Jeff Schaller
                                yesterday














                              • 2




                                this is a reiteration of three existing answers and the one that I already commented on
                                – Jeff Schaller
                                yesterday








                              2




                              2




                              this is a reiteration of three existing answers and the one that I already commented on
                              – Jeff Schaller
                              yesterday




                              this is a reiteration of three existing answers and the one that I already commented on
                              – Jeff Schaller
                              yesterday










                              up vote
                              -2
                              down vote













                              mkdir {A..Z}
                              mkdir {0..100}
                              mkdir test_{A..Z}
                              and so on.






                              share|improve this answer








                              New contributor




                              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.


















                              • I do not get it
                                – Pierre.Vriens
                                2 days ago






                              • 1




                                this has already been covered
                                – Jeff Schaller
                                2 days ago















                              up vote
                              -2
                              down vote













                              mkdir {A..Z}
                              mkdir {0..100}
                              mkdir test_{A..Z}
                              and so on.






                              share|improve this answer








                              New contributor




                              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.


















                              • I do not get it
                                – Pierre.Vriens
                                2 days ago






                              • 1




                                this has already been covered
                                – Jeff Schaller
                                2 days ago













                              up vote
                              -2
                              down vote










                              up vote
                              -2
                              down vote









                              mkdir {A..Z}
                              mkdir {0..100}
                              mkdir test_{A..Z}
                              and so on.






                              share|improve this answer








                              New contributor




                              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              mkdir {A..Z}
                              mkdir {0..100}
                              mkdir test_{A..Z}
                              and so on.







                              share|improve this answer








                              New contributor




                              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              share|improve this answer



                              share|improve this answer






                              New contributor




                              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              answered 2 days ago









                              Avognon Lionel

                              1




                              1




                              New contributor




                              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.





                              New contributor





                              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.






                              Avognon Lionel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.












                              • I do not get it
                                – Pierre.Vriens
                                2 days ago






                              • 1




                                this has already been covered
                                – Jeff Schaller
                                2 days ago


















                              • I do not get it
                                – Pierre.Vriens
                                2 days ago






                              • 1




                                this has already been covered
                                – Jeff Schaller
                                2 days ago
















                              I do not get it
                              – Pierre.Vriens
                              2 days ago




                              I do not get it
                              – Pierre.Vriens
                              2 days ago




                              1




                              1




                              this has already been covered
                              – Jeff Schaller
                              2 days ago




                              this has already been covered
                              – Jeff Schaller
                              2 days ago


















                               

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