Argument list too long when zipping large list of certain files in a folder












0















I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command by met with "Argument list too long" error.



declare -a arr=()       

fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("${i}_${j}.xxx")
done
done

new_arr=$(printf ",%s" "${arr[@]}")
new_arr=${new_arr:1}

zip all_data.zip {$new_arr}


Please advice









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    0















    I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command by met with "Argument list too long" error.



    declare -a arr=()       

    fixed=5
    for i in `seq 10 1 200`; do
    for j in `seq $((i+fixed)) 1 200`; do
    arr+=("${i}_${j}.xxx")
    done
    done

    new_arr=$(printf ",%s" "${arr[@]}")
    new_arr=${new_arr:1}

    zip all_data.zip {$new_arr}


    Please advice









    share







    New contributor




    Zack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























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      0








      I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command by met with "Argument list too long" error.



      declare -a arr=()       

      fixed=5
      for i in `seq 10 1 200`; do
      for j in `seq $((i+fixed)) 1 200`; do
      arr+=("${i}_${j}.xxx")
      done
      done

      new_arr=$(printf ",%s" "${arr[@]}")
      new_arr=${new_arr:1}

      zip all_data.zip {$new_arr}


      Please advice









      share







      New contributor




      Zack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command by met with "Argument list too long" error.



      declare -a arr=()       

      fixed=5
      for i in `seq 10 1 200`; do
      for j in `seq $((i+fixed)) 1 200`; do
      arr+=("${i}_${j}.xxx")
      done
      done

      new_arr=$(printf ",%s" "${arr[@]}")
      new_arr=${new_arr:1}

      zip all_data.zip {$new_arr}


      Please advice







      bash





      share







      New contributor




      Zack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Zack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      Zack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked 1 min ago









      ZackZack

      11




      11




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      Zack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      New contributor





      Zack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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