Argument list too long when zipping large list of certain files in a folder
I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command by met with "Argument list too long" error.
declare -a arr=()
fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("${i}_${j}.xxx")
done
done
new_arr=$(printf ",%s" "${arr[@]}")
new_arr=${new_arr:1}
zip all_data.zip {$new_arr}
Please advice
bash
New contributor
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I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command by met with "Argument list too long" error.
declare -a arr=()
fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("${i}_${j}.xxx")
done
done
new_arr=$(printf ",%s" "${arr[@]}")
new_arr=${new_arr:1}
zip all_data.zip {$new_arr}
Please advice
bash
New contributor
add a comment |
I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command by met with "Argument list too long" error.
declare -a arr=()
fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("${i}_${j}.xxx")
done
done
new_arr=$(printf ",%s" "${arr[@]}")
new_arr=${new_arr:1}
zip all_data.zip {$new_arr}
Please advice
bash
New contributor
I'm trying to zip a certain large number of files by creating an array of them. Then I tried to run the zip command by met with "Argument list too long" error.
declare -a arr=()
fixed=5
for i in `seq 10 1 200`; do
for j in `seq $((i+fixed)) 1 200`; do
arr+=("${i}_${j}.xxx")
done
done
new_arr=$(printf ",%s" "${arr[@]}")
new_arr=${new_arr:1}
zip all_data.zip {$new_arr}
Please advice
bash
bash
New contributor
New contributor
New contributor
asked 1 min ago
ZackZack
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Zack is a new contributor. Be nice, and check out our Code of Conduct.
Zack is a new contributor. Be nice, and check out our Code of Conduct.
Zack is a new contributor. Be nice, and check out our Code of Conduct.
Zack is a new contributor. Be nice, and check out our Code of Conduct.
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