DOS command to Bash command conversion












1















I need to make Bash take DOS commands in with arguments and then convert the main command to a Bash command and still use the arguments if there are any arguments.



The part I am lost on is how to pass arguments to the individual cases and not getting stuck by the *) Command Not Found!



For example a user inputs:



copy file1.txt file2.txt


Use case: copy then should run the Linux cp command and use the two arguments passed copy to finish the command.



#!/bin/bash



while :

do

read INPUT_STRING

case $INPUT_STRING in

        chdir|CHDIR)

        cd $arg1

        bash myscript.sh

;;

        cls|CLS)

        clear

        bash myscript.sh

;;

        copy|COPY)

        cp $arg1 $arg2

        bash myscript.sh

;;

        createdir|CREATEDIR)

        mkdir $arg1

        bash myscript.sh

;;

        delete|DELETE)

        rm $arg1

        bash myscript.sh

;;

        dir|DIR)

        ls

        bash myscript.sh

;;

        move|MOVE)

        mv $arg1 $arg2

        bash myscript.sh

;;

        print|PRINT)

        echo $arg1

        bash myscript.sh

;;

        quit|QUIT)

        break

        PS1="n01396736@cisvm-cop4640-2:~$ "

;;

        rename|RENAME)

        mv $arg1 $arg2

        bash myscript.sh

;;

        type|TYPE)

        cat $arg1

        bash myscript.sh

;;

        *)

        echo "Command Not Found!!"

        bash myscript.sh

;;

esac

break

done





linux bash arguments case







share|improve this question









New contributor




Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1





    What are you expecting bash myscript.sh at the end of each case branch to do? I think you're trying to loop, but you're actually calling the script from itself over and over again. Remove the break at the end and strip out all these bash myscript.sh statements.

    – roaima
    1 hour ago








  • 1





    Quote those variables. Quote those variables. Quote those variables. (For example mv $arg1 $arg2 should be rewritten as mv "$arg1" "$arg2")

    – roaima
    1 hour ago













  • I need it to continue to loop until user types quit or QUIT. with a single break in the quit|QUIT) case it didn't send the user back the terminal/command prompt out of the bash. As far as the bash myscript.sh I had issues where it would run dir and then drop the user to back to the terminal/command prompt out of the bash.

    – Trinity Zamrzla
    1 hour ago











  • I added the quotes around all the $arg1 and $arg2. I am still getting the same error that when I input copy file1.txt file2.txt my catch all *) responds with Command Not Found!! which is a good thing that it is working, however, I need the arguments to be sued inside the case. In java or C I could separate the input by white space and then store them into an array and then increment through the array to read each section separately.

    – Trinity Zamrzla
    1 hour ago











  • Thank you for the hit about the quotes I got it working now. read command arg1 arg2 arg3 case "$command" in then I am using "$arg1" to "$arg3" as needed

    – Trinity Zamrzla
    9 mins ago


















1















I need to make Bash take DOS commands in with arguments and then convert the main command to a Bash command and still use the arguments if there are any arguments.



The part I am lost on is how to pass arguments to the individual cases and not getting stuck by the *) Command Not Found!



For example a user inputs:



copy file1.txt file2.txt


Use case: copy then should run the Linux cp command and use the two arguments passed copy to finish the command.



#!/bin/bash



while :

do

read INPUT_STRING

case $INPUT_STRING in

        chdir|CHDIR)

        cd $arg1

        bash myscript.sh

;;

        cls|CLS)

        clear

        bash myscript.sh

;;

        copy|COPY)

        cp $arg1 $arg2

        bash myscript.sh

;;

        createdir|CREATEDIR)

        mkdir $arg1

        bash myscript.sh

;;

        delete|DELETE)

        rm $arg1

        bash myscript.sh

;;

        dir|DIR)

        ls

        bash myscript.sh

;;

        move|MOVE)

        mv $arg1 $arg2

        bash myscript.sh

;;

        print|PRINT)

        echo $arg1

        bash myscript.sh

;;

        quit|QUIT)

        break

        PS1="n01396736@cisvm-cop4640-2:~$ "

;;

        rename|RENAME)

        mv $arg1 $arg2

        bash myscript.sh

;;

        type|TYPE)

        cat $arg1

        bash myscript.sh

;;

        *)

        echo "Command Not Found!!"

        bash myscript.sh

;;

esac

break

done





linux bash arguments case







share|improve this question









New contributor




Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1





    What are you expecting bash myscript.sh at the end of each case branch to do? I think you're trying to loop, but you're actually calling the script from itself over and over again. Remove the break at the end and strip out all these bash myscript.sh statements.

    – roaima
    1 hour ago








  • 1





    Quote those variables. Quote those variables. Quote those variables. (For example mv $arg1 $arg2 should be rewritten as mv "$arg1" "$arg2")

    – roaima
    1 hour ago













  • I need it to continue to loop until user types quit or QUIT. with a single break in the quit|QUIT) case it didn't send the user back the terminal/command prompt out of the bash. As far as the bash myscript.sh I had issues where it would run dir and then drop the user to back to the terminal/command prompt out of the bash.

    – Trinity Zamrzla
    1 hour ago











  • I added the quotes around all the $arg1 and $arg2. I am still getting the same error that when I input copy file1.txt file2.txt my catch all *) responds with Command Not Found!! which is a good thing that it is working, however, I need the arguments to be sued inside the case. In java or C I could separate the input by white space and then store them into an array and then increment through the array to read each section separately.

    – Trinity Zamrzla
    1 hour ago











  • Thank you for the hit about the quotes I got it working now. read command arg1 arg2 arg3 case "$command" in then I am using "$arg1" to "$arg3" as needed

    – Trinity Zamrzla
    9 mins ago
















1












1








1








I need to make Bash take DOS commands in with arguments and then convert the main command to a Bash command and still use the arguments if there are any arguments.



The part I am lost on is how to pass arguments to the individual cases and not getting stuck by the *) Command Not Found!



For example a user inputs:



copy file1.txt file2.txt


Use case: copy then should run the Linux cp command and use the two arguments passed copy to finish the command.



#!/bin/bash



while :

do

read INPUT_STRING

case $INPUT_STRING in

        chdir|CHDIR)

        cd $arg1

        bash myscript.sh

;;

        cls|CLS)

        clear

        bash myscript.sh

;;

        copy|COPY)

        cp $arg1 $arg2

        bash myscript.sh

;;

        createdir|CREATEDIR)

        mkdir $arg1

        bash myscript.sh

;;

        delete|DELETE)

        rm $arg1

        bash myscript.sh

;;

        dir|DIR)

        ls

        bash myscript.sh

;;

        move|MOVE)

        mv $arg1 $arg2

        bash myscript.sh

;;

        print|PRINT)

        echo $arg1

        bash myscript.sh

;;

        quit|QUIT)

        break

        PS1="n01396736@cisvm-cop4640-2:~$ "

;;

        rename|RENAME)

        mv $arg1 $arg2

        bash myscript.sh

;;

        type|TYPE)

        cat $arg1

        bash myscript.sh

;;

        *)

        echo "Command Not Found!!"

        bash myscript.sh

;;

esac

break

done





linux bash arguments case







share|improve this question









New contributor




Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I need to make Bash take DOS commands in with arguments and then convert the main command to a Bash command and still use the arguments if there are any arguments.



The part I am lost on is how to pass arguments to the individual cases and not getting stuck by the *) Command Not Found!



For example a user inputs:



copy file1.txt file2.txt


Use case: copy then should run the Linux cp command and use the two arguments passed copy to finish the command.



#!/bin/bash



while :

do

read INPUT_STRING

case $INPUT_STRING in

        chdir|CHDIR)

        cd $arg1

        bash myscript.sh

;;

        cls|CLS)

        clear

        bash myscript.sh

;;

        copy|COPY)

        cp $arg1 $arg2

        bash myscript.sh

;;

        createdir|CREATEDIR)

        mkdir $arg1

        bash myscript.sh

;;

        delete|DELETE)

        rm $arg1

        bash myscript.sh

;;

        dir|DIR)

        ls

        bash myscript.sh

;;

        move|MOVE)

        mv $arg1 $arg2

        bash myscript.sh

;;

        print|PRINT)

        echo $arg1

        bash myscript.sh

;;

        quit|QUIT)

        break

        PS1="n01396736@cisvm-cop4640-2:~$ "

;;

        rename|RENAME)

        mv $arg1 $arg2

        bash myscript.sh

;;

        type|TYPE)

        cat $arg1

        bash myscript.sh

;;

        *)

        echo "Command Not Found!!"

        bash myscript.sh

;;

esac

break

done





linux bash arguments case




linux bash arguments case






share|improve this question









New contributor




Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 5 mins ago









Michael Prokopec

1,458218




1,458218






New contributor




Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 1 hour ago









Trinity ZamrzlaTrinity Zamrzla

64




64




New contributor




Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Trinity Zamrzla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1





    What are you expecting bash myscript.sh at the end of each case branch to do? I think you're trying to loop, but you're actually calling the script from itself over and over again. Remove the break at the end and strip out all these bash myscript.sh statements.

    – roaima
    1 hour ago








  • 1





    Quote those variables. Quote those variables. Quote those variables. (For example mv $arg1 $arg2 should be rewritten as mv "$arg1" "$arg2")

    – roaima
    1 hour ago













  • I need it to continue to loop until user types quit or QUIT. with a single break in the quit|QUIT) case it didn't send the user back the terminal/command prompt out of the bash. As far as the bash myscript.sh I had issues where it would run dir and then drop the user to back to the terminal/command prompt out of the bash.

    – Trinity Zamrzla
    1 hour ago











  • I added the quotes around all the $arg1 and $arg2. I am still getting the same error that when I input copy file1.txt file2.txt my catch all *) responds with Command Not Found!! which is a good thing that it is working, however, I need the arguments to be sued inside the case. In java or C I could separate the input by white space and then store them into an array and then increment through the array to read each section separately.

    – Trinity Zamrzla
    1 hour ago











  • Thank you for the hit about the quotes I got it working now. read command arg1 arg2 arg3 case "$command" in then I am using "$arg1" to "$arg3" as needed

    – Trinity Zamrzla
    9 mins ago
















  • 1





    What are you expecting bash myscript.sh at the end of each case branch to do? I think you're trying to loop, but you're actually calling the script from itself over and over again. Remove the break at the end and strip out all these bash myscript.sh statements.

    – roaima
    1 hour ago








  • 1





    Quote those variables. Quote those variables. Quote those variables. (For example mv $arg1 $arg2 should be rewritten as mv "$arg1" "$arg2")

    – roaima
    1 hour ago













  • I need it to continue to loop until user types quit or QUIT. with a single break in the quit|QUIT) case it didn't send the user back the terminal/command prompt out of the bash. As far as the bash myscript.sh I had issues where it would run dir and then drop the user to back to the terminal/command prompt out of the bash.

    – Trinity Zamrzla
    1 hour ago











  • I added the quotes around all the $arg1 and $arg2. I am still getting the same error that when I input copy file1.txt file2.txt my catch all *) responds with Command Not Found!! which is a good thing that it is working, however, I need the arguments to be sued inside the case. In java or C I could separate the input by white space and then store them into an array and then increment through the array to read each section separately.

    – Trinity Zamrzla
    1 hour ago











  • Thank you for the hit about the quotes I got it working now. read command arg1 arg2 arg3 case "$command" in then I am using "$arg1" to "$arg3" as needed

    – Trinity Zamrzla
    9 mins ago










1




1





What are you expecting bash myscript.sh at the end of each case branch to do? I think you're trying to loop, but you're actually calling the script from itself over and over again. Remove the break at the end and strip out all these bash myscript.sh statements.

– roaima
1 hour ago







What are you expecting bash myscript.sh at the end of each case branch to do? I think you're trying to loop, but you're actually calling the script from itself over and over again. Remove the break at the end and strip out all these bash myscript.sh statements.

– roaima
1 hour ago






1




1





Quote those variables. Quote those variables. Quote those variables. (For example mv $arg1 $arg2 should be rewritten as mv "$arg1" "$arg2")

– roaima
1 hour ago







Quote those variables. Quote those variables. Quote those variables. (For example mv $arg1 $arg2 should be rewritten as mv "$arg1" "$arg2")

– roaima
1 hour ago















I need it to continue to loop until user types quit or QUIT. with a single break in the quit|QUIT) case it didn't send the user back the terminal/command prompt out of the bash. As far as the bash myscript.sh I had issues where it would run dir and then drop the user to back to the terminal/command prompt out of the bash.

– Trinity Zamrzla
1 hour ago





I need it to continue to loop until user types quit or QUIT. with a single break in the quit|QUIT) case it didn't send the user back the terminal/command prompt out of the bash. As far as the bash myscript.sh I had issues where it would run dir and then drop the user to back to the terminal/command prompt out of the bash.

– Trinity Zamrzla
1 hour ago













I added the quotes around all the $arg1 and $arg2. I am still getting the same error that when I input copy file1.txt file2.txt my catch all *) responds with Command Not Found!! which is a good thing that it is working, however, I need the arguments to be sued inside the case. In java or C I could separate the input by white space and then store them into an array and then increment through the array to read each section separately.

– Trinity Zamrzla
1 hour ago





I added the quotes around all the $arg1 and $arg2. I am still getting the same error that when I input copy file1.txt file2.txt my catch all *) responds with Command Not Found!! which is a good thing that it is working, however, I need the arguments to be sued inside the case. In java or C I could separate the input by white space and then store them into an array and then increment through the array to read each section separately.

– Trinity Zamrzla
1 hour ago













Thank you for the hit about the quotes I got it working now. read command arg1 arg2 arg3 case "$command" in then I am using "$arg1" to "$arg3" as needed

– Trinity Zamrzla
9 mins ago







Thank you for the hit about the quotes I got it working now. read command arg1 arg2 arg3 case "$command" in then I am using "$arg1" to "$arg3" as needed

– Trinity Zamrzla
9 mins ago












0






active

oldest

votes











Your Answer








StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "106"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});






Trinity Zamrzla is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f500747%2fdos-command-to-bash-command-conversion%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes








Trinity Zamrzla is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

draft discarded


















Trinity Zamrzla is a new contributor. Be nice, and check out our Code of Conduct.













Trinity Zamrzla is a new contributor. Be nice, and check out our Code of Conduct.












Trinity Zamrzla is a new contributor. Be nice, and check out our Code of Conduct.
















Thanks for contributing an answer to Unix & Linux Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid …



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f500747%2fdos-command-to-bash-command-conversion%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







-

Popular posts from this blog

Entries order in /etc/network/interfaces

Image
4 I have a device with two interfaces, eth0 and eth1. One should get its IP from a DHCP server and the other should get its IP statically. If my /etc/network/interfaces file is configured as follows: auto lo iface lo inet loopback auto eth1 iface eth1 inet dhcp iface eth1 inet6 auto auto eth0 iface eth0 inet static address 10.10.10.10 netmask 255.255.255.0 Everything works great, eth1 gets its IP from the DHCP server, eth0 sets its IP statically from the information given, but if I try to change the order in the file, such as auto lo iface lo inet loopback auto eth0 iface eth0 inet static address 10.10.10.10 netmask 255.255.255.0 auto eth1 iface eth1 inet dhcp iface eth1 inet6 auto In this case, eth1 fails to get an IP. Does the /etc/network/interface care about th...
Read more

新発田市

Image
しばたし 新発田市 市のシンボル・新発田城（二の丸隅櫓） 新発田市旗 1934年7月9日制定 新発田市章 1934年7月9日制定 国 日本 地方 中部地方、北陸地方 甲信越地方、信越地方 都道府県 新潟県 団体コード 15206-4 法人番号 5000020152064 面積 533.10 km 2 総人口 96,267 人 [編集] （推計人口、2018年10月1日） 人口密度 181 人/km 2 隣接自治体 新潟市、阿賀野市、胎内市、北蒲原郡聖籠町、東蒲原郡阿賀町 福島県喜多方市 山形県西置賜郡小国町 市の木 サクラ 市の花 アヤメ 市のシンボル 新発田城 新発田市役所 市長 [編集] 二階堂馨 所在地 〒 957-8686 新潟県新発田市中央町3丁目3番3号 北緯37度56分52.5秒東経139度19分38.2秒 外部リンク 公式ウェブサイト ■ ― 政令指定都市 / ■ ― 市 / ■ ― 町 / ■ ― 村 地理院地図 Google Bing GeoHack MapFan Mapion Yahoo! NAVITIME ゼンリン   表示   ウィキプロジェクト 新発田市中心部周辺の空中写真。 1975年撮影の8枚を合成作成。国土交通省 国土画像情報（カラー空中写真）を基に作成。 新発田市 （しばたし）は、新潟県下越地方にある市である。新潟市への通勤率は16.6%（平成22年国勢調査）。 目次 1 概要 2 地理 2.1 隣接している自治体・行政区 3 地域・市街地構成 4 歴史 4.1 市名の由来 4.2 沿革 5 人口 6 行政 6.1 市長 7 経済 7.1 産業 7.1.1 市内の主な企業 7.1.2 漁業 8 姉妹都市・提携都市 8.1 国内 8.2 海外 9 施設・...
Read more

Grub takes very long (several minutes) to open Menu (in Multi-Boot-System)

Image
0 I have a Multi-Boot-System with 4 different installations of Linux. (1 Manjaro, 3 Mint) spread over 2 hard drives (2 on each). After doing grub-install /dev/sdX and update-grub several times within each installation ... the Grub-menu needs more and more time to open. It started with a few more seconds, now it takes several minutes. I tried to purge and reinstall Grub but this made the problem even worse: apt-get purge grub grub-pc grub-common apt-get install grub-common grub-pc os-prober update-grub What could be causing this problem? linux grub2 multiboot share | improve this question edited 4 mins ago ...
Read more