Speeding up object name check by record ID
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I have been able to piece together some code that determines object name based on record ID without any hard-coding or SOQL. It works with both custom and standard objects but it is very slow, I'm guessing due to loading so much schema data and a lot of looping.
I am looking for a way to speed this function up, potentially by limiting the object names searched or the amount of data being sorted through.
Here is the entire (working, but slow) function:
// Get sObject type by record ID
public static String getObjName(String recordId) {
// Get record prefix
String recordPrefix = recordId.substring(0, 3);
// Get global "describe"
Map<String, Schema.SObjectType> gd = Schema.getGlobalDescribe();
// Loop through all objects to find match for record ID prefix
for (Schema.SObjectType otype : gd.values()) {
Schema.DescribeSObjectResult r = otype.getDescribe();
String prefix = r.getKeyPrefix();
// Found match!
if (prefix != null && prefix.equals(recordPrefix)) return r.getName();
}
return '';
}
Any ideas?
apex
New contributor
add a comment |
up vote
2
down vote
favorite
I have been able to piece together some code that determines object name based on record ID without any hard-coding or SOQL. It works with both custom and standard objects but it is very slow, I'm guessing due to loading so much schema data and a lot of looping.
I am looking for a way to speed this function up, potentially by limiting the object names searched or the amount of data being sorted through.
Here is the entire (working, but slow) function:
// Get sObject type by record ID
public static String getObjName(String recordId) {
// Get record prefix
String recordPrefix = recordId.substring(0, 3);
// Get global "describe"
Map<String, Schema.SObjectType> gd = Schema.getGlobalDescribe();
// Loop through all objects to find match for record ID prefix
for (Schema.SObjectType otype : gd.values()) {
Schema.DescribeSObjectResult r = otype.getDescribe();
String prefix = r.getKeyPrefix();
// Found match!
if (prefix != null && prefix.equals(recordPrefix)) return r.getName();
}
return '';
}
Any ideas?
apex
New contributor
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have been able to piece together some code that determines object name based on record ID without any hard-coding or SOQL. It works with both custom and standard objects but it is very slow, I'm guessing due to loading so much schema data and a lot of looping.
I am looking for a way to speed this function up, potentially by limiting the object names searched or the amount of data being sorted through.
Here is the entire (working, but slow) function:
// Get sObject type by record ID
public static String getObjName(String recordId) {
// Get record prefix
String recordPrefix = recordId.substring(0, 3);
// Get global "describe"
Map<String, Schema.SObjectType> gd = Schema.getGlobalDescribe();
// Loop through all objects to find match for record ID prefix
for (Schema.SObjectType otype : gd.values()) {
Schema.DescribeSObjectResult r = otype.getDescribe();
String prefix = r.getKeyPrefix();
// Found match!
if (prefix != null && prefix.equals(recordPrefix)) return r.getName();
}
return '';
}
Any ideas?
apex
New contributor
I have been able to piece together some code that determines object name based on record ID without any hard-coding or SOQL. It works with both custom and standard objects but it is very slow, I'm guessing due to loading so much schema data and a lot of looping.
I am looking for a way to speed this function up, potentially by limiting the object names searched or the amount of data being sorted through.
Here is the entire (working, but slow) function:
// Get sObject type by record ID
public static String getObjName(String recordId) {
// Get record prefix
String recordPrefix = recordId.substring(0, 3);
// Get global "describe"
Map<String, Schema.SObjectType> gd = Schema.getGlobalDescribe();
// Loop through all objects to find match for record ID prefix
for (Schema.SObjectType otype : gd.values()) {
Schema.DescribeSObjectResult r = otype.getDescribe();
String prefix = r.getKeyPrefix();
// Found match!
if (prefix != null && prefix.equals(recordPrefix)) return r.getName();
}
return '';
}
Any ideas?
apex
apex
New contributor
New contributor
New contributor
asked 7 hours ago
Ixalmida
1113
1113
New contributor
New contributor
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add a comment |
1 Answer
1
active
oldest
votes
up vote
6
down vote
The Id
class already contains an instance method to do exactly what you wish, named getSObjectType
. The entire body of your method can be simplified to the below:
return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());
Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
– Ixalmida
7 hours ago
1
You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
– Sebastian Kessel
7 hours ago
1
First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually:return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName();
I will accept the answer when it is corrected.
– Ixalmida
7 hours ago
1
You can just useString.valueOf
, which should be much faster. Depending on your use case, it would actually be much better to just change your return type toSObjectType
. Static types are preferable toString
where they fit.
– Adrian Larson♦
7 hours ago
1
@AdrianLarson you can also justreturn recordId == null? '': ''+recordId.getSobjectType()
; the string + operator takes care of the String.valueOf for you.
– sfdcfox
3 hours ago
|
show 2 more comments
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
The Id
class already contains an instance method to do exactly what you wish, named getSObjectType
. The entire body of your method can be simplified to the below:
return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());
Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
– Ixalmida
7 hours ago
1
You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
– Sebastian Kessel
7 hours ago
1
First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually:return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName();
I will accept the answer when it is corrected.
– Ixalmida
7 hours ago
1
You can just useString.valueOf
, which should be much faster. Depending on your use case, it would actually be much better to just change your return type toSObjectType
. Static types are preferable toString
where they fit.
– Adrian Larson♦
7 hours ago
1
@AdrianLarson you can also justreturn recordId == null? '': ''+recordId.getSobjectType()
; the string + operator takes care of the String.valueOf for you.
– sfdcfox
3 hours ago
|
show 2 more comments
up vote
6
down vote
The Id
class already contains an instance method to do exactly what you wish, named getSObjectType
. The entire body of your method can be simplified to the below:
return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());
Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
– Ixalmida
7 hours ago
1
You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
– Sebastian Kessel
7 hours ago
1
First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually:return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName();
I will accept the answer when it is corrected.
– Ixalmida
7 hours ago
1
You can just useString.valueOf
, which should be much faster. Depending on your use case, it would actually be much better to just change your return type toSObjectType
. Static types are preferable toString
where they fit.
– Adrian Larson♦
7 hours ago
1
@AdrianLarson you can also justreturn recordId == null? '': ''+recordId.getSobjectType()
; the string + operator takes care of the String.valueOf for you.
– sfdcfox
3 hours ago
|
show 2 more comments
up vote
6
down vote
up vote
6
down vote
The Id
class already contains an instance method to do exactly what you wish, named getSObjectType
. The entire body of your method can be simplified to the below:
return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());
The Id
class already contains an instance method to do exactly what you wish, named getSObjectType
. The entire body of your method can be simplified to the below:
return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());
edited 7 hours ago
answered 7 hours ago
Adrian Larson♦
103k19110233
103k19110233
Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
– Ixalmida
7 hours ago
1
You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
– Sebastian Kessel
7 hours ago
1
First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually:return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName();
I will accept the answer when it is corrected.
– Ixalmida
7 hours ago
1
You can just useString.valueOf
, which should be much faster. Depending on your use case, it would actually be much better to just change your return type toSObjectType
. Static types are preferable toString
where they fit.
– Adrian Larson♦
7 hours ago
1
@AdrianLarson you can also justreturn recordId == null? '': ''+recordId.getSobjectType()
; the string + operator takes care of the String.valueOf for you.
– sfdcfox
3 hours ago
|
show 2 more comments
Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
– Ixalmida
7 hours ago
1
You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
– Sebastian Kessel
7 hours ago
1
First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually:return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName();
I will accept the answer when it is corrected.
– Ixalmida
7 hours ago
1
You can just useString.valueOf
, which should be much faster. Depending on your use case, it would actually be much better to just change your return type toSObjectType
. Static types are preferable toString
where they fit.
– Adrian Larson♦
7 hours ago
1
@AdrianLarson you can also justreturn recordId == null? '': ''+recordId.getSobjectType()
; the string + operator takes care of the String.valueOf for you.
– sfdcfox
3 hours ago
Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
– Ixalmida
7 hours ago
Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
– Ixalmida
7 hours ago
1
1
You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
– Sebastian Kessel
7 hours ago
You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
– Sebastian Kessel
7 hours ago
1
1
First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually:
return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName();
I will accept the answer when it is corrected.– Ixalmida
7 hours ago
First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually:
return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName();
I will accept the answer when it is corrected.– Ixalmida
7 hours ago
1
1
You can just use
String.valueOf
, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType
. Static types are preferable to String
where they fit.– Adrian Larson♦
7 hours ago
You can just use
String.valueOf
, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType
. Static types are preferable to String
where they fit.– Adrian Larson♦
7 hours ago
1
1
@AdrianLarson you can also just
return recordId == null? '': ''+recordId.getSobjectType()
; the string + operator takes care of the String.valueOf for you.– sfdcfox
3 hours ago
@AdrianLarson you can also just
return recordId == null? '': ''+recordId.getSobjectType()
; the string + operator takes care of the String.valueOf for you.– sfdcfox
3 hours ago
|
show 2 more comments
Ixalmida is a new contributor. Be nice, and check out our Code of Conduct.
Ixalmida is a new contributor. Be nice, and check out our Code of Conduct.
Ixalmida is a new contributor. Be nice, and check out our Code of Conduct.
Ixalmida is a new contributor. Be nice, and check out our Code of Conduct.
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