sed: replace part of text in previous line if match is found [duplicate]

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This question already has an answer here:

Replace a string before a certain line

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I want to replace create_test in the file with #create_test if the next line contains psfxxx_16_pi. How can I do it with sed for the whole file containing this?

Input file content:

create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }

Output file:

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }

edited yesterday

Mr Shunz

2,99311822

asked yesterday

mandrake00

243

New contributor

marked as duplicate by don_crissti, Jeff Schaller, Isaac, RalfFriedl, Romeo Ninov 6 hours ago

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
yesterday

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
yesterday

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
18 hours ago

add a comment |

up vote
0
down vote

favorite

This question already has an answer here:

Replace a string before a certain line

5 answers

I want to replace create_test in the file with #create_test if the next line contains psfxxx_16_pi. How can I do it with sed for the whole file containing this?

Input file content:

create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }

Output file:

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }

edited yesterday

Mr Shunz

2,99311822

asked yesterday

mandrake00

243

New contributor

marked as duplicate by don_crissti, Jeff Schaller, Isaac, RalfFriedl, Romeo Ninov 6 hours ago

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
yesterday

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
yesterday

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
18 hours ago

add a comment |

up vote
0
down vote

favorite

This question already has an answer here:

Replace a string before a certain line

5 answers

I want to replace create_test in the file with #create_test if the next line contains psfxxx_16_pi. How can I do it with sed for the whole file containing this?

Input file content:

create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }

Output file:

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }

edited yesterday

Mr Shunz

2,99311822

asked yesterday

mandrake00

243

New contributor

This question already has an answer here:

Replace a string before a certain line

5 answers

I want to replace create_test in the file with #create_test if the next line contains psfxxx_16_pi. How can I do it with sed for the whole file containing this?

Input file content:

create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }

Output file:

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }

This question already has an answer here:

Replace a string before a certain line

5 answers

sed

edited yesterday

Mr Shunz

2,99311822

asked yesterday

mandrake00

243

New contributor

edited yesterday

Mr Shunz

2,99311822

asked yesterday

mandrake00

243

New contributor

edited yesterday

Mr Shunz

2,99311822

edited yesterday

Mr Shunz

2,99311822

edited yesterday

Mr Shunz

2,99311822

asked yesterday

mandrake00

243

New contributor

asked yesterday

mandrake00

243

asked yesterday

mandrake00

243

New contributor

mandrake00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

marked as duplicate by don_crissti, Jeff Schaller, Isaac, RalfFriedl, Romeo Ninov 6 hours ago

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by don_crissti, Jeff Schaller, Isaac, RalfFriedl, Romeo Ninov 6 hours ago

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
yesterday

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
yesterday

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
18 hours ago

add a comment |

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
yesterday

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
yesterday

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
18 hours ago

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
yesterday

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
yesterday

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
18 hours ago

add a comment |

3 Answers
3

active

oldest

votes

up vote
2
down vote

Try

sed '/^create_test/ {N; /psfxxx/ s/^/#/}' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }



create_test -type hard -outer { 1.0000 } { 

    vsfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    vsfxxx_16_pi/psfop/deadline_south_re_1 }

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered yesterday

RudiC

3,0411211

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer { 1.0000 } { psfxxx_16_pi/psfop/deadline_north_re_0 } create_ test -type hard -outer { 0.0000 } { psfxxx_16_pi/psfop/deadline_south_re_1 }
– mandrake00
yesterday

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
yesterday

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
yesterday

Thank you RudiC. It works well.
– mandrake00
yesterday

add a comment |

up vote
0
down vote

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1

answered yesterday

fpmurphy1

2,336915

add a comment |

up vote
0
down vote

If awk will do:

awk '/psfxxx_16_pi/{prev = "#" prev} {print prev} {prev = $0} END {print}'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered yesterday

JohnDoea

211

New contributor

add a comment |

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
2
down vote

Try

sed '/^create_test/ {N; /psfxxx/ s/^/#/}' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }



create_test -type hard -outer { 1.0000 } { 

    vsfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    vsfxxx_16_pi/psfop/deadline_south_re_1 }

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered yesterday

RudiC

3,0411211

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer { 1.0000 } { psfxxx_16_pi/psfop/deadline_north_re_0 } create_ test -type hard -outer { 0.0000 } { psfxxx_16_pi/psfop/deadline_south_re_1 }
– mandrake00
yesterday

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
yesterday

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
yesterday

Thank you RudiC. It works well.
– mandrake00
yesterday

add a comment |

up vote
2
down vote

Try

sed '/^create_test/ {N; /psfxxx/ s/^/#/}' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }



create_test -type hard -outer { 1.0000 } { 

    vsfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    vsfxxx_16_pi/psfop/deadline_south_re_1 }

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered yesterday

RudiC

3,0411211

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer { 1.0000 } { psfxxx_16_pi/psfop/deadline_north_re_0 } create_ test -type hard -outer { 0.0000 } { psfxxx_16_pi/psfop/deadline_south_re_1 }
– mandrake00
yesterday

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
yesterday

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
yesterday

Thank you RudiC. It works well.
– mandrake00
yesterday

add a comment |

up vote
2
down vote

Try

sed '/^create_test/ {N; /psfxxx/ s/^/#/}' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }



create_test -type hard -outer { 1.0000 } { 

    vsfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    vsfxxx_16_pi/psfop/deadline_south_re_1 }

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered yesterday

RudiC

3,0411211

Try

sed '/^create_test/ {N; /psfxxx/ s/^/#/}' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1 }



create_test -type hard -outer { 1.0000 } { 

    vsfxxx_16_pi/psfop/deadline_north_re_0 }



create_test -type hard -outer { 0.0000 } { 

    vsfxxx_16_pi/psfop/deadline_south_re_1 }

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered yesterday

RudiC

3,0411211

answered yesterday

RudiC

3,0411211

answered yesterday

RudiC

3,0411211

answered yesterday

RudiC

3,0411211

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer { 1.0000 } { psfxxx_16_pi/psfop/deadline_north_re_0 } create_ test -type hard -outer { 0.0000 } { psfxxx_16_pi/psfop/deadline_south_re_1 }
– mandrake00
yesterday

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
yesterday

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
yesterday

Thank you RudiC. It works well.
– mandrake00
yesterday

add a comment |

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer { 1.0000 } { psfxxx_16_pi/psfop/deadline_north_re_0 } create_ test -type hard -outer { 0.0000 } { psfxxx_16_pi/psfop/deadline_south_re_1 }
– mandrake00
yesterday

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
yesterday

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
yesterday

Thank you RudiC. It works well.
– mandrake00
yesterday

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer { 1.0000 } { psfxxx_16_pi/psfop/deadline_north_re_0 } create_ test -type hard -outer { 0.0000 } { psfxxx_16_pi/psfop/deadline_south_re_1 }
– mandrake00
yesterday

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
yesterday

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
yesterday

Thank you RudiC. It works well.
– mandrake00
yesterday

add a comment |

up vote
0
down vote

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1

answered yesterday

fpmurphy1

2,336915

add a comment |

up vote
0
down vote

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1

answered yesterday

fpmurphy1

2,336915

add a comment |

up vote
0
down vote

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1

answered yesterday

fpmurphy1

2,336915

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file

#create_test -type hard -outer { 1.0000 } { 

    psfxxx_16_pi/psfop/deadline_north_re_0 }



#create_test -type hard -outer { 0.0000 } { 

    psfxxx_16_pi/psfop/deadline_south_re_1

answered yesterday

fpmurphy1

2,336915

answered yesterday

fpmurphy1

2,336915

answered yesterday

fpmurphy1

2,336915

answered yesterday

fpmurphy1

2,336915

add a comment |

up vote
0
down vote

If awk will do:

awk '/psfxxx_16_pi/{prev = "#" prev} {print prev} {prev = $0} END {print}'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered yesterday

JohnDoea

211

New contributor

add a comment |

up vote
0
down vote

If awk will do:

awk '/psfxxx_16_pi/{prev = "#" prev} {print prev} {prev = $0} END {print}'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered yesterday

JohnDoea

211

New contributor

add a comment |

up vote
0
down vote

If awk will do:

awk '/psfxxx_16_pi/{prev = "#" prev} {print prev} {prev = $0} END {print}'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered yesterday

JohnDoea

211

New contributor

If awk will do:

awk '/psfxxx_16_pi/{prev = "#" prev} {print prev} {prev = $0} END {print}'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered yesterday

JohnDoea

211

New contributor

answered yesterday

JohnDoea

211

New contributor

answered yesterday

JohnDoea

211

answered yesterday

JohnDoea

211

New contributor

JohnDoea is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment |

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