How to find the rectangle with those text
In this image:
I want to find this rectangle with all contents(without those grid's lines)
I think the total of the pixels can help a little like:
img = Import["http://i.stack.imgur.com/lnd5w.png"];
data = Total[ImageData[ImageRotate[ColorNegate[img]]]];
Show[ImageRotate[img],
ListLinePlot[data, PlotRange -> All, PlotStyle -> Red]]
And I have such images:
image2
image3
image4
I have no idea to do this thing. Does anyone have an idea?
image-processing signal-processing
asked 1 hour ago
yode
10.1k233100
add a comment |
In this image:
I want to find this rectangle with all contents(without those grid's lines)
I think the total of the pixels can help a little like:
img = Import["http://i.stack.imgur.com/lnd5w.png"];
data = Total[ImageData[ImageRotate[ColorNegate[img]]]];
Show[ImageRotate[img],
ListLinePlot[data, PlotRange -> All, PlotStyle -> Red]]
And I have such images:
image2
image3
image4
I have no idea to do this thing. Does anyone have an idea?
image-processing signal-processing
asked 1 hour ago
yode
10.1k233100
1
Have you asked this question before? It seems very familiar to me...
– Carl Lange
1 hour ago
Ah, I was thinking of this and this. Just for context purposes :)
– Carl Lange
1 hour ago
@CarlLange It's not very similar...
– yode
1 hour ago
The question isn't but the images are, so I wanted to make sure it wasn't a duplicate somehow. That's all!
– Carl Lange
43 mins ago
add a comment |
In this image:
I want to find this rectangle with all contents(without those grid's lines)
I think the total of the pixels can help a little like:
img = Import["http://i.stack.imgur.com/lnd5w.png"];
data = Total[ImageData[ImageRotate[ColorNegate[img]]]];
Show[ImageRotate[img],
ListLinePlot[data, PlotRange -> All, PlotStyle -> Red]]
And I have such images:
image2
image3
image4
I have no idea to do this thing. Does anyone have an idea?
image-processing signal-processing
asked 1 hour ago
yode
10.1k233100
In this image:
I want to find this rectangle with all contents(without those grid's lines)
I think the total of the pixels can help a little like:
img = Import["http://i.stack.imgur.com/lnd5w.png"];
data = Total[ImageData[ImageRotate[ColorNegate[img]]]];
Show[ImageRotate[img],
ListLinePlot[data, PlotRange -> All, PlotStyle -> Red]]
And I have such images:
image2
image3
image4
I have no idea to do this thing. Does anyone have an idea?
image-processing signal-processing
image-processing signal-processing
asked 1 hour ago
yode
10.1k233100
asked 1 hour ago
yode
10.1k233100
asked 1 hour ago
yode
10.1k233100
asked 1 hour ago
yode
10.1k233100
asked 1 hour ago
yode
10.1k233100
10.1k233100
1
Have you asked this question before? It seems very familiar to me...
– Carl Lange
1 hour ago
Ah, I was thinking of this and this. Just for context purposes :)
– Carl Lange
1 hour ago
@CarlLange It's not very similar...
– yode
1 hour ago
The question isn't but the images are, so I wanted to make sure it wasn't a duplicate somehow. That's all!
– Carl Lange
43 mins ago
add a comment |
1
Have you asked this question before? It seems very familiar to me...
– Carl Lange
1 hour ago
Ah, I was thinking of this and this. Just for context purposes :)
– Carl Lange
1 hour ago
@CarlLange It's not very similar...
– yode
1 hour ago
The question isn't but the images are, so I wanted to make sure it wasn't a duplicate somehow. That's all!
– Carl Lange
43 mins ago
1
1
Have you asked this question before? It seems very familiar to me...
– Carl Lange
1 hour ago
Have you asked this question before? It seems very familiar to me...
– Carl Lange
1 hour ago
Ah, I was thinking of this and this. Just for context purposes :)
– Carl Lange
1 hour ago
Ah, I was thinking of this and this. Just for context purposes :)
– Carl Lange
1 hour ago
@CarlLange It's not very similar...
– yode
1 hour ago
@CarlLange It's not very similar...
– yode
1 hour ago
The question isn't but the images are, so I wanted to make sure it wasn't a duplicate somehow. That's all!
– Carl Lange
43 mins ago
The question isn't but the images are, so I wanted to make sure it wasn't a duplicate somehow. That's all!
– Carl Lange
43 mins ago
add a comment |
2 Answers
2
active
oldest
votes
This works quite well:
findRegion[img_] := TextRecognize[img, "BoundingBox", RecognitionPrior -> "SparseText"]
HighlightImage[#, findRegion@#] & /@ imgs
As you can see, the result for the first image is not perfect unfortunately, but hopefully this gives you some ideas.
answered 1 hour ago
Lukas Lang
5,6131626
Yes, as your try, the Tesseract not very stable..
– yode
1 hour ago
add a comment |
Binarization and ComponentMeasurements seems the straightforward solution:
img = Import["https://i.stack.imgur.com/lnd5w.png"];
Selct all components that are less than half as long as the image:
comp = ComponentMeasurements[MorphologicalBinarize[ColorNegate@img],
"BoundingBox", #CaliperLength < Min[ImageDimensions[img]]*0.5 &];
This selects all digits and boxes, but not the grid lines, because they are longer than height/2:
HighlightImage[img, Rectangle @@@ comp[[All, 2]]]
Then combine the individual bounding boxes to one big bounding box:
HighlightImage[img,
Rectangle @@
Transpose[MinMax /@ Transpose[Flatten[comp[[All, 2]], 1]]]]
You might have to adjust binarization and the criteria in ComponentMeasurements, but for me, it worked on all the images you posted on the first try.
answered 41 mins ago
Niki Estner
30.5k374132
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
This works quite well:
findRegion[img_] := TextRecognize[img, "BoundingBox", RecognitionPrior -> "SparseText"]
HighlightImage[#, findRegion@#] & /@ imgs
As you can see, the result for the first image is not perfect unfortunately, but hopefully this gives you some ideas.
answered 1 hour ago
Lukas Lang
5,6131626
Yes, as your try, the Tesseract not very stable..
– yode
1 hour ago
add a comment |
This works quite well:
findRegion[img_] := TextRecognize[img, "BoundingBox", RecognitionPrior -> "SparseText"]
HighlightImage[#, findRegion@#] & /@ imgs
As you can see, the result for the first image is not perfect unfortunately, but hopefully this gives you some ideas.
answered 1 hour ago
Lukas Lang
5,6131626
Yes, as your try, the Tesseract not very stable..
– yode
1 hour ago
add a comment |
This works quite well:
findRegion[img_] := TextRecognize[img, "BoundingBox", RecognitionPrior -> "SparseText"]
HighlightImage[#, findRegion@#] & /@ imgs
As you can see, the result for the first image is not perfect unfortunately, but hopefully this gives you some ideas.
answered 1 hour ago
Lukas Lang
5,6131626
This works quite well:
findRegion[img_] := TextRecognize[img, "BoundingBox", RecognitionPrior -> "SparseText"]
HighlightImage[#, findRegion@#] & /@ imgs
As you can see, the result for the first image is not perfect unfortunately, but hopefully this gives you some ideas.
answered 1 hour ago
Lukas Lang
5,6131626
answered 1 hour ago
Lukas Lang
5,6131626
answered 1 hour ago
Lukas Lang
5,6131626
answered 1 hour ago
Lukas Lang
5,6131626
5,6131626
Yes, as your try, the Tesseract not very stable..
– yode
1 hour ago
add a comment |
Yes, as your try, the Tesseract not very stable..
– yode
1 hour ago
Yes, as your try, the Tesseract not very stable..
– yode
1 hour ago
Yes, as your try, the Tesseract not very stable..
– yode
1 hour ago
add a comment |
Binarization and ComponentMeasurements seems the straightforward solution:
img = Import["https://i.stack.imgur.com/lnd5w.png"];
Selct all components that are less than half as long as the image:
comp = ComponentMeasurements[MorphologicalBinarize[ColorNegate@img],
"BoundingBox", #CaliperLength < Min[ImageDimensions[img]]*0.5 &];
This selects all digits and boxes, but not the grid lines, because they are longer than height/2:
HighlightImage[img, Rectangle @@@ comp[[All, 2]]]
Then combine the individual bounding boxes to one big bounding box:
HighlightImage[img,
Rectangle @@
Transpose[MinMax /@ Transpose[Flatten[comp[[All, 2]], 1]]]]
You might have to adjust binarization and the criteria in ComponentMeasurements, but for me, it worked on all the images you posted on the first try.
answered 41 mins ago
Niki Estner
30.5k374132
add a comment |
Binarization and ComponentMeasurements seems the straightforward solution:
img = Import["https://i.stack.imgur.com/lnd5w.png"];
Selct all components that are less than half as long as the image:
comp = ComponentMeasurements[MorphologicalBinarize[ColorNegate@img],
"BoundingBox", #CaliperLength < Min[ImageDimensions[img]]*0.5 &];
This selects all digits and boxes, but not the grid lines, because they are longer than height/2:
HighlightImage[img, Rectangle @@@ comp[[All, 2]]]
Then combine the individual bounding boxes to one big bounding box:
HighlightImage[img,
Rectangle @@
Transpose[MinMax /@ Transpose[Flatten[comp[[All, 2]], 1]]]]
You might have to adjust binarization and the criteria in ComponentMeasurements, but for me, it worked on all the images you posted on the first try.
answered 41 mins ago
Niki Estner
30.5k374132
add a comment |
Binarization and ComponentMeasurements seems the straightforward solution:
img = Import["https://i.stack.imgur.com/lnd5w.png"];
Selct all components that are less than half as long as the image:
comp = ComponentMeasurements[MorphologicalBinarize[ColorNegate@img],
"BoundingBox", #CaliperLength < Min[ImageDimensions[img]]*0.5 &];
This selects all digits and boxes, but not the grid lines, because they are longer than height/2:
HighlightImage[img, Rectangle @@@ comp[[All, 2]]]
Then combine the individual bounding boxes to one big bounding box:
HighlightImage[img,
Rectangle @@
Transpose[MinMax /@ Transpose[Flatten[comp[[All, 2]], 1]]]]
You might have to adjust binarization and the criteria in ComponentMeasurements, but for me, it worked on all the images you posted on the first try.
answered 41 mins ago
Niki Estner
30.5k374132
Binarization and ComponentMeasurements seems the straightforward solution:
img = Import["https://i.stack.imgur.com/lnd5w.png"];
Selct all components that are less than half as long as the image:
comp = ComponentMeasurements[MorphologicalBinarize[ColorNegate@img],
"BoundingBox", #CaliperLength < Min[ImageDimensions[img]]*0.5 &];
This selects all digits and boxes, but not the grid lines, because they are longer than height/2:
HighlightImage[img, Rectangle @@@ comp[[All, 2]]]
Then combine the individual bounding boxes to one big bounding box:
HighlightImage[img,
Rectangle @@
Transpose[MinMax /@ Transpose[Flatten[comp[[All, 2]], 1]]]]
You might have to adjust binarization and the criteria in ComponentMeasurements, but for me, it worked on all the images you posted on the first try.
answered 41 mins ago
Niki Estner
30.5k374132
answered 41 mins ago
Niki Estner
30.5k374132
answered 41 mins ago
Niki Estner
30.5k374132
answered 41 mins ago
Niki Estner
30.5k374132
30.5k374132
add a comment |
add a comment |
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1
Have you asked this question before? It seems very familiar to me...
– Carl Lange
1 hour ago
Ah, I was thinking of this and this. Just for context purposes :)
– Carl Lange
1 hour ago
@CarlLange It's not very similar...
– yode
1 hour ago
The question isn't but the images are, so I wanted to make sure it wasn't a duplicate somehow. That's all!
– Carl Lange
43 mins ago