How to draw a hyperbolic triangle?
Any ideas about how to draw this with TikZ? I tried several things, but nothing satisfactory. What I tried was to doing in the simplest way, that is,
begin{tikzpicture}
draw (point) arc (angle contitions);
end{tikzpicture}
What I need is something like the image:
I tried to use this code also (from Use tikz (for example) to draw pictures in hyperbolic geometry)
begin{document}
newcommand{hgline}[2]{
pgfmathsetmacro{thetaone}{#1}
pgfmathsetmacro{thetatwo}{#2}
pgfmathsetmacro{theta}{(thetaone+thetatwo)/2}
pgfmathsetmacro{phi}{abs(thetaone-thetatwo)/2}
pgfmathsetmacro{close}{less(abs(phi-90),0.0001)}
ifdim close pt = 1pt
draw[blue] (theta+180:1) -- (theta:1);
else
pgfmathsetmacro{R}{tan(phi)}
pgfmathsetmacro{distance}{sqrt(1+R^2)}
draw[blue] (theta:distance) circle (R);
fi
}
begin{tikzpicture}
draw (0,0) circle (1);
clip (0,0) circle (1);
hgline{30}{-30}
hgline{180}{270}
hgline{30}{120}
hgline{0}{180}
end{tikzpicture}
But this allow me to draw lines embedded on the disk, and when I try to remove the circle, the code is unuseful.
Thank you.
tikz-pgf tikz-styles
New contributor
|
show 1 more comment
Any ideas about how to draw this with TikZ? I tried several things, but nothing satisfactory. What I tried was to doing in the simplest way, that is,
begin{tikzpicture}
draw (point) arc (angle contitions);
end{tikzpicture}
What I need is something like the image:
I tried to use this code also (from Use tikz (for example) to draw pictures in hyperbolic geometry)
begin{document}
newcommand{hgline}[2]{
pgfmathsetmacro{thetaone}{#1}
pgfmathsetmacro{thetatwo}{#2}
pgfmathsetmacro{theta}{(thetaone+thetatwo)/2}
pgfmathsetmacro{phi}{abs(thetaone-thetatwo)/2}
pgfmathsetmacro{close}{less(abs(phi-90),0.0001)}
ifdim close pt = 1pt
draw[blue] (theta+180:1) -- (theta:1);
else
pgfmathsetmacro{R}{tan(phi)}
pgfmathsetmacro{distance}{sqrt(1+R^2)}
draw[blue] (theta:distance) circle (R);
fi
}
begin{tikzpicture}
draw (0,0) circle (1);
clip (0,0) circle (1);
hgline{30}{-30}
hgline{180}{270}
hgline{30}{120}
hgline{0}{180}
end{tikzpicture}
But this allow me to draw lines embedded on the disk, and when I try to remove the circle, the code is unuseful.
Thank you.
tikz-pgf tikz-styles
New contributor
A hyperbolic triangle. The first I tried was to use the most simple thing using draw (point) arc (angle). However, I could not control the lines so I searched here: tex.stackexchange.com/questions/16617/… I tried everything they put, but their solutions were about drawing hyperbolic lines on the disk, and when I tried to remove the disk the code began to do strange things.
– Rubén Fernández Fuertes
27 mins ago
2
Check out tex.stackexchange.com/q/446325/172926
– Pippip19
26 mins ago
I did it, and it was too much complicated for what I need, I need just a code for drawing a simple hyperbolic triangle...
– Rubén Fernández Fuertes
25 mins ago
2
@RubénFernándezFuertes We need to know what your simple hyperbolic triangle looks like. Please make your question in some formats like this: I want to draw this <picture> Here is what I have tried <code>.
– JouleV
23 mins ago
In the simplest possible case, you only have to draw three curves joining three points.
– JouleV
23 mins ago
|
show 1 more comment
Any ideas about how to draw this with TikZ? I tried several things, but nothing satisfactory. What I tried was to doing in the simplest way, that is,
begin{tikzpicture}
draw (point) arc (angle contitions);
end{tikzpicture}
What I need is something like the image:
I tried to use this code also (from Use tikz (for example) to draw pictures in hyperbolic geometry)
begin{document}
newcommand{hgline}[2]{
pgfmathsetmacro{thetaone}{#1}
pgfmathsetmacro{thetatwo}{#2}
pgfmathsetmacro{theta}{(thetaone+thetatwo)/2}
pgfmathsetmacro{phi}{abs(thetaone-thetatwo)/2}
pgfmathsetmacro{close}{less(abs(phi-90),0.0001)}
ifdim close pt = 1pt
draw[blue] (theta+180:1) -- (theta:1);
else
pgfmathsetmacro{R}{tan(phi)}
pgfmathsetmacro{distance}{sqrt(1+R^2)}
draw[blue] (theta:distance) circle (R);
fi
}
begin{tikzpicture}
draw (0,0) circle (1);
clip (0,0) circle (1);
hgline{30}{-30}
hgline{180}{270}
hgline{30}{120}
hgline{0}{180}
end{tikzpicture}
But this allow me to draw lines embedded on the disk, and when I try to remove the circle, the code is unuseful.
Thank you.
tikz-pgf tikz-styles
New contributor
Any ideas about how to draw this with TikZ? I tried several things, but nothing satisfactory. What I tried was to doing in the simplest way, that is,
begin{tikzpicture}
draw (point) arc (angle contitions);
end{tikzpicture}
What I need is something like the image:
I tried to use this code also (from Use tikz (for example) to draw pictures in hyperbolic geometry)
begin{document}
newcommand{hgline}[2]{
pgfmathsetmacro{thetaone}{#1}
pgfmathsetmacro{thetatwo}{#2}
pgfmathsetmacro{theta}{(thetaone+thetatwo)/2}
pgfmathsetmacro{phi}{abs(thetaone-thetatwo)/2}
pgfmathsetmacro{close}{less(abs(phi-90),0.0001)}
ifdim close pt = 1pt
draw[blue] (theta+180:1) -- (theta:1);
else
pgfmathsetmacro{R}{tan(phi)}
pgfmathsetmacro{distance}{sqrt(1+R^2)}
draw[blue] (theta:distance) circle (R);
fi
}
begin{tikzpicture}
draw (0,0) circle (1);
clip (0,0) circle (1);
hgline{30}{-30}
hgline{180}{270}
hgline{30}{120}
hgline{0}{180}
end{tikzpicture}
But this allow me to draw lines embedded on the disk, and when I try to remove the circle, the code is unuseful.
Thank you.
tikz-pgf tikz-styles
tikz-pgf tikz-styles
New contributor
New contributor
edited 13 mins ago
Rubén Fernández Fuertes
New contributor
asked 35 mins ago
Rubén Fernández FuertesRubén Fernández Fuertes
11
11
New contributor
New contributor
A hyperbolic triangle. The first I tried was to use the most simple thing using draw (point) arc (angle). However, I could not control the lines so I searched here: tex.stackexchange.com/questions/16617/… I tried everything they put, but their solutions were about drawing hyperbolic lines on the disk, and when I tried to remove the disk the code began to do strange things.
– Rubén Fernández Fuertes
27 mins ago
2
Check out tex.stackexchange.com/q/446325/172926
– Pippip19
26 mins ago
I did it, and it was too much complicated for what I need, I need just a code for drawing a simple hyperbolic triangle...
– Rubén Fernández Fuertes
25 mins ago
2
@RubénFernándezFuertes We need to know what your simple hyperbolic triangle looks like. Please make your question in some formats like this: I want to draw this <picture> Here is what I have tried <code>.
– JouleV
23 mins ago
In the simplest possible case, you only have to draw three curves joining three points.
– JouleV
23 mins ago
|
show 1 more comment
A hyperbolic triangle. The first I tried was to use the most simple thing using draw (point) arc (angle). However, I could not control the lines so I searched here: tex.stackexchange.com/questions/16617/… I tried everything they put, but their solutions were about drawing hyperbolic lines on the disk, and when I tried to remove the disk the code began to do strange things.
– Rubén Fernández Fuertes
27 mins ago
2
Check out tex.stackexchange.com/q/446325/172926
– Pippip19
26 mins ago
I did it, and it was too much complicated for what I need, I need just a code for drawing a simple hyperbolic triangle...
– Rubén Fernández Fuertes
25 mins ago
2
@RubénFernándezFuertes We need to know what your simple hyperbolic triangle looks like. Please make your question in some formats like this: I want to draw this <picture> Here is what I have tried <code>.
– JouleV
23 mins ago
In the simplest possible case, you only have to draw three curves joining three points.
– JouleV
23 mins ago
A hyperbolic triangle. The first I tried was to use the most simple thing using draw (point) arc (angle). However, I could not control the lines so I searched here: tex.stackexchange.com/questions/16617/… I tried everything they put, but their solutions were about drawing hyperbolic lines on the disk, and when I tried to remove the disk the code began to do strange things.
– Rubén Fernández Fuertes
27 mins ago
A hyperbolic triangle. The first I tried was to use the most simple thing using draw (point) arc (angle). However, I could not control the lines so I searched here: tex.stackexchange.com/questions/16617/… I tried everything they put, but their solutions were about drawing hyperbolic lines on the disk, and when I tried to remove the disk the code began to do strange things.
– Rubén Fernández Fuertes
27 mins ago
2
2
Check out tex.stackexchange.com/q/446325/172926
– Pippip19
26 mins ago
Check out tex.stackexchange.com/q/446325/172926
– Pippip19
26 mins ago
I did it, and it was too much complicated for what I need, I need just a code for drawing a simple hyperbolic triangle...
– Rubén Fernández Fuertes
25 mins ago
I did it, and it was too much complicated for what I need, I need just a code for drawing a simple hyperbolic triangle...
– Rubén Fernández Fuertes
25 mins ago
2
2
@RubénFernándezFuertes We need to know what your simple hyperbolic triangle looks like. Please make your question in some formats like this: I want to draw this <picture> Here is what I have tried <code>.
– JouleV
23 mins ago
@RubénFernándezFuertes We need to know what your simple hyperbolic triangle looks like. Please make your question in some formats like this: I want to draw this <picture> Here is what I have tried <code>.
– JouleV
23 mins ago
In the simplest possible case, you only have to draw three curves joining three points.
– JouleV
23 mins ago
In the simplest possible case, you only have to draw three curves joining three points.
– JouleV
23 mins ago
|
show 1 more comment
1 Answer
1
active
oldest
votes
Something like this?
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[font=sffamily]
path (0,0) coordinate (A) (4,1) coordinate (B) (2,-2) coordinate (C);
draw[thick,path picture={
foreach X in {A,B,C}
{draw (X) circle (1);}}] (A) node[left]{$O$} to[bend right=12]
(B) node[above right]{$g_2^{-1}cdot O$} to[bend right=15]
(C) node[below]{$g_1^{-1}cdot O$} to[bend right=20] cycle;
end{tikzpicture}
end{document}
I have a small request: How can I add the angles?
– JouleV
7 mins ago
@JouleV Added. (Withpath picture
it is very easy.)
– marmot
3 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Something like this?
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[font=sffamily]
path (0,0) coordinate (A) (4,1) coordinate (B) (2,-2) coordinate (C);
draw[thick,path picture={
foreach X in {A,B,C}
{draw (X) circle (1);}}] (A) node[left]{$O$} to[bend right=12]
(B) node[above right]{$g_2^{-1}cdot O$} to[bend right=15]
(C) node[below]{$g_1^{-1}cdot O$} to[bend right=20] cycle;
end{tikzpicture}
end{document}
I have a small request: How can I add the angles?
– JouleV
7 mins ago
@JouleV Added. (Withpath picture
it is very easy.)
– marmot
3 mins ago
add a comment |
Something like this?
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[font=sffamily]
path (0,0) coordinate (A) (4,1) coordinate (B) (2,-2) coordinate (C);
draw[thick,path picture={
foreach X in {A,B,C}
{draw (X) circle (1);}}] (A) node[left]{$O$} to[bend right=12]
(B) node[above right]{$g_2^{-1}cdot O$} to[bend right=15]
(C) node[below]{$g_1^{-1}cdot O$} to[bend right=20] cycle;
end{tikzpicture}
end{document}
I have a small request: How can I add the angles?
– JouleV
7 mins ago
@JouleV Added. (Withpath picture
it is very easy.)
– marmot
3 mins ago
add a comment |
Something like this?
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[font=sffamily]
path (0,0) coordinate (A) (4,1) coordinate (B) (2,-2) coordinate (C);
draw[thick,path picture={
foreach X in {A,B,C}
{draw (X) circle (1);}}] (A) node[left]{$O$} to[bend right=12]
(B) node[above right]{$g_2^{-1}cdot O$} to[bend right=15]
(C) node[below]{$g_1^{-1}cdot O$} to[bend right=20] cycle;
end{tikzpicture}
end{document}
Something like this?
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[font=sffamily]
path (0,0) coordinate (A) (4,1) coordinate (B) (2,-2) coordinate (C);
draw[thick,path picture={
foreach X in {A,B,C}
{draw (X) circle (1);}}] (A) node[left]{$O$} to[bend right=12]
(B) node[above right]{$g_2^{-1}cdot O$} to[bend right=15]
(C) node[below]{$g_1^{-1}cdot O$} to[bend right=20] cycle;
end{tikzpicture}
end{document}
edited 4 mins ago
answered 9 mins ago
marmotmarmot
101k4116224
101k4116224
I have a small request: How can I add the angles?
– JouleV
7 mins ago
@JouleV Added. (Withpath picture
it is very easy.)
– marmot
3 mins ago
add a comment |
I have a small request: How can I add the angles?
– JouleV
7 mins ago
@JouleV Added. (Withpath picture
it is very easy.)
– marmot
3 mins ago
I have a small request: How can I add the angles?
– JouleV
7 mins ago
I have a small request: How can I add the angles?
– JouleV
7 mins ago
@JouleV Added. (With
path picture
it is very easy.)– marmot
3 mins ago
@JouleV Added. (With
path picture
it is very easy.)– marmot
3 mins ago
add a comment |
Rubén Fernández Fuertes is a new contributor. Be nice, and check out our Code of Conduct.
Rubén Fernández Fuertes is a new contributor. Be nice, and check out our Code of Conduct.
Rubén Fernández Fuertes is a new contributor. Be nice, and check out our Code of Conduct.
Rubén Fernández Fuertes is a new contributor. Be nice, and check out our Code of Conduct.
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A hyperbolic triangle. The first I tried was to use the most simple thing using draw (point) arc (angle). However, I could not control the lines so I searched here: tex.stackexchange.com/questions/16617/… I tried everything they put, but their solutions were about drawing hyperbolic lines on the disk, and when I tried to remove the disk the code began to do strange things.
– Rubén Fernández Fuertes
27 mins ago
2
Check out tex.stackexchange.com/q/446325/172926
– Pippip19
26 mins ago
I did it, and it was too much complicated for what I need, I need just a code for drawing a simple hyperbolic triangle...
– Rubén Fernández Fuertes
25 mins ago
2
@RubénFernándezFuertes We need to know what your simple hyperbolic triangle looks like. Please make your question in some formats like this: I want to draw this <picture> Here is what I have tried <code>.
– JouleV
23 mins ago
In the simplest possible case, you only have to draw three curves joining three points.
– JouleV
23 mins ago