What's the purpose of 1> in exec 1> >(logger -s -t tagname) 2>&1?
I just stumbled over
exec 1> >(logger -s -t $(basename $0)) 2>&1
which is used to redirect the output of the current script to the system logger (in case you've never seen this, but are interested check out https://stackoverflow.com/questions/8888251/understanding-bash-exec-12-command to broaden your shell knowledge).
I am wondering why the 1> is necessary. It seems necessary because exec >(logger -s -t test) 2>&1 fails due to
bash: /dev/fd/63: Permission denied
bash: exec: /dev/fd/63: cannot execute: Permission denied
Omitting 1> is however what I'd do intuitively because exec >[some redirection target] already should be sufficient for the redirection according to the question linked above. 2>&1 then redirects the stderr to stdout as usual.
I'm using bash 4.4.19.
bash shell io-redirection exec
asked 41 mins ago
Karl Richter
7521823
add a comment |
I just stumbled over
exec 1> >(logger -s -t $(basename $0)) 2>&1
which is used to redirect the output of the current script to the system logger (in case you've never seen this, but are interested check out https://stackoverflow.com/questions/8888251/understanding-bash-exec-12-command to broaden your shell knowledge).
I am wondering why the 1> is necessary. It seems necessary because exec >(logger -s -t test) 2>&1 fails due to
bash: /dev/fd/63: Permission denied
bash: exec: /dev/fd/63: cannot execute: Permission denied
Omitting 1> is however what I'd do intuitively because exec >[some redirection target] already should be sufficient for the redirection according to the question linked above. 2>&1 then redirects the stderr to stdout as usual.
I'm using bash 4.4.19.
bash shell io-redirection exec
asked 41 mins ago
Karl Richter
7521823
It is necessary (the extra>, not the1,1>could be simply written>). The>(...)process substitution will expand to something like/dev/fd/13(a file name), and then>will redirect the standard output into it. Thence> >(...).
– mosvy
38 mins ago
@mosvy I see, thank you. I just learned about process substitution, i.e. didn't know that>(...)means that. I'd accept that as an answer.
– Karl Richter
30 mins ago
add a comment |
I just stumbled over
exec 1> >(logger -s -t $(basename $0)) 2>&1
which is used to redirect the output of the current script to the system logger (in case you've never seen this, but are interested check out https://stackoverflow.com/questions/8888251/understanding-bash-exec-12-command to broaden your shell knowledge).
I am wondering why the 1> is necessary. It seems necessary because exec >(logger -s -t test) 2>&1 fails due to
bash: /dev/fd/63: Permission denied
bash: exec: /dev/fd/63: cannot execute: Permission denied
Omitting 1> is however what I'd do intuitively because exec >[some redirection target] already should be sufficient for the redirection according to the question linked above. 2>&1 then redirects the stderr to stdout as usual.
I'm using bash 4.4.19.
bash shell io-redirection exec
asked 41 mins ago
Karl Richter
7521823
I just stumbled over
exec 1> >(logger -s -t $(basename $0)) 2>&1
which is used to redirect the output of the current script to the system logger (in case you've never seen this, but are interested check out https://stackoverflow.com/questions/8888251/understanding-bash-exec-12-command to broaden your shell knowledge).
I am wondering why the 1> is necessary. It seems necessary because exec >(logger -s -t test) 2>&1 fails due to
bash: /dev/fd/63: Permission denied
bash: exec: /dev/fd/63: cannot execute: Permission denied
Omitting 1> is however what I'd do intuitively because exec >[some redirection target] already should be sufficient for the redirection according to the question linked above. 2>&1 then redirects the stderr to stdout as usual.
I'm using bash 4.4.19.
bash shell io-redirection exec
bash shell io-redirection exec
asked 41 mins ago
Karl Richter
7521823
asked 41 mins ago
Karl Richter
7521823
asked 41 mins ago
Karl Richter
7521823
asked 41 mins ago
Karl Richter
7521823
asked 41 mins ago
Karl Richter
7521823
7521823
It is necessary (the extra>, not the1,1>could be simply written>). The>(...)process substitution will expand to something like/dev/fd/13(a file name), and then>will redirect the standard output into it. Thence> >(...).
– mosvy
38 mins ago
@mosvy I see, thank you. I just learned about process substitution, i.e. didn't know that>(...)means that. I'd accept that as an answer.
– Karl Richter
30 mins ago
add a comment |
It is necessary (the extra>, not the1,1>could be simply written>). The>(...)process substitution will expand to something like/dev/fd/13(a file name), and then>will redirect the standard output into it. Thence> >(...).
– mosvy
38 mins ago
@mosvy I see, thank you. I just learned about process substitution, i.e. didn't know that>(...)means that. I'd accept that as an answer.
– Karl Richter
30 mins ago
It is necessary (the extra
>, not the 1, 1> could be simply written >). The >(...) process substitution will expand to something like /dev/fd/13 (a file name), and then > will redirect the standard output into it. Thence > >(...).– mosvy
38 mins ago
It is necessary (the extra
>, not the 1, 1> could be simply written >). The >(...) process substitution will expand to something like /dev/fd/13 (a file name), and then > will redirect the standard output into it. Thence > >(...).– mosvy
38 mins ago
@mosvy I see, thank you. I just learned about process substitution, i.e. didn't know that
>(...) means that. I'd accept that as an answer.– Karl Richter
30 mins ago
@mosvy I see, thank you. I just learned about process substitution, i.e. didn't know that
>(...) means that. I'd accept that as an answer.– Karl Richter
30 mins ago
add a comment |
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It is necessary (the extra
>, not the1,1>could be simply written>). The>(...)process substitution will expand to something like/dev/fd/13(a file name), and then>will redirect the standard output into it. Thence> >(...).– mosvy
38 mins ago
@mosvy I see, thank you. I just learned about process substitution, i.e. didn't know that
>(...)means that. I'd accept that as an answer.– Karl Richter
30 mins ago