How can I get the count of how many times a string appears in my list?












1












$begingroup$


I have a list of strings, like so:



{"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss", "kk mm"}


I know WordCounts will return the numbers of every single word, but I want to the word group numbers, i.e., "aa bb" 3 times, and "cc dd" 2 times. How can I do this?






string-manipulation counting







share|improve this question











$endgroup$

















    1












    $begingroup$


    I have a list of strings, like so:



    {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss", "kk mm"}


    I know WordCounts will return the numbers of every single word, but I want to the word group numbers, i.e., "aa bb" 3 times, and "cc dd" 2 times. How can I do this?






    string-manipulation counting







    share|improve this question











    $endgroup$















      1












      1








      1





      $begingroup$


      I have a list of strings, like so:



      {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss", "kk mm"}


      I know WordCounts will return the numbers of every single word, but I want to the word group numbers, i.e., "aa bb" 3 times, and "cc dd" 2 times. How can I do this?






      string-manipulation counting







      share|improve this question











      $endgroup$




      I have a list of strings, like so:



      {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss", "kk mm"}


      I know WordCounts will return the numbers of every single word, but I want to the word group numbers, i.e., "aa bb" 3 times, and "cc dd" 2 times. How can I do this?






      string-manipulation counting




      string-manipulation counting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 24 mins ago









      m_goldberg

      87k872197




      87k872197










      asked 3 hours ago









      zongxianzongxian

      1074




      1074






















          1 Answer
          1






          active

          oldest

          votes


















          3












          $begingroup$

          You can try Tally



          lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};
          
Tally[lst]


          Mathematica graphics



          Edit by m_goldberg



          As J.M. says in his comment below, Counts will give the same information as an association.



          Counts[data]



          <|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>




          This is equivalent to 



          Rule @@@ Tally[data] // Association





          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Counts should also work.
            $endgroup$
            – J. M. is computer-less♦
            1 hour ago











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "387"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f192562%2fhow-can-i-get-the-count-of-how-many-times-a-string-appears-in-my-list%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3












          $begingroup$

          You can try Tally



          lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};
          
Tally[lst]


          Mathematica graphics



          Edit by m_goldberg



          As J.M. says in his comment below, Counts will give the same information as an association.



          Counts[data]



          <|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>




          This is equivalent to 



          Rule @@@ Tally[data] // Association





          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Counts should also work.
            $endgroup$
            – J. M. is computer-less♦
            1 hour ago
















          3












          $begingroup$

          You can try Tally



          lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};
          
Tally[lst]


          Mathematica graphics



          Edit by m_goldberg



          As J.M. says in his comment below, Counts will give the same information as an association.



          Counts[data]



          <|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>




          This is equivalent to 



          Rule @@@ Tally[data] // Association





          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Counts should also work.
            $endgroup$
            – J. M. is computer-less♦
            1 hour ago














          3












          3








          3





          $begingroup$

          You can try Tally



          lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};
          
Tally[lst]


          Mathematica graphics



          Edit by m_goldberg



          As J.M. says in his comment below, Counts will give the same information as an association.



          Counts[data]



          <|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>




          This is equivalent to 



          Rule @@@ Tally[data] // Association





          share|improve this answer











          $endgroup$



          You can try Tally



          lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};
          
Tally[lst]


          Mathematica graphics



          Edit by m_goldberg



          As J.M. says in his comment below, Counts will give the same information as an association.



          Counts[data]



          <|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>




          This is equivalent to 



          Rule @@@ Tally[data] // Association






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 12 mins ago









          m_goldberg

          87k872197




          87k872197










          answered 2 hours ago









          NasserNasser

          58k489206




          58k489206








          • 1




            $begingroup$
            Counts should also work.
            $endgroup$
            – J. M. is computer-less♦
            1 hour ago














          • 1




            $begingroup$
            Counts should also work.
            $endgroup$
            – J. M. is computer-less♦
            1 hour ago








          1




          1




          $begingroup$
          Counts should also work.
          $endgroup$
          – J. M. is computer-less♦
          1 hour ago




          $begingroup$
          Counts should also work.
          $endgroup$
          – J. M. is computer-less♦
          1 hour ago


















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Mathematica Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid …



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f192562%2fhow-can-i-get-the-count-of-how-many-times-a-string-appears-in-my-list%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          -

          Popular posts from this blog

          Accessing regular linux commands in Huawei's Dopra Linux

          Image
          4 Backstory: I have a Huawei HG8245 router in my house and I want to change the default username/password. I've tried following this guide but the config file always gets reset. My ISP isn't helping either so I'm looking for other ways to accomplish this. The router has telnet access so this seems like a way to change the credentials. The first shell I gain access to looks like this: WAP> Pressing "?" gives me a list of available commands which I've pasted here, the two interesting ones are "su" and "shell". I can't seem to get su access, even after logging in as root (challenge password prompt, and then nothing happens), but shell gives me a proper linux shell. WAP>shell BusyBox v1.18.4 (2017-12-26 17:06:34 CST) built-in shell (ash) Enter 'hel...
          Read more

          Can't connect RFCOMM socket: Host is down

          Image
          up vote 3 down vote favorite I have bluez 5.4.3 and I am attempting to communicate with a ble device through minicom. These two deceives (my computer and a bluno nano) are alreadt paired and this has been my method so far. #bluetoothctl # pair xx:xx:xx:xx:xx:xx # exit Everything is working well so far then... #sudo rfcomm connect /dev/rfcomm0 xx:xx:xx:xx:xx:xx 1 & [1] 3665 Can't connect RFCOMM socket: Host is down Does anyone know how to resolve this issue? Any help would be very much appreciated. bluetooth bluez share | improve this question asked Feb 9 '17 at 18:46 Brandon Knape 46 2 ...
          Read more

          Kernel panic - not syncing: Fatal Exception in Interrupt

          Image
          0 Every day this error occured on my pc, kernel panic error on interrupt, what will be the problem? linux-mint share asked 6 mins ago Vinod Selvin Vinod Selvin 1 1 New contributor Vinod Selvin is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct. add a comment ...
          Read more