use search result in replace statement with vim substitute
up vote
1
down vote
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I've got a file with a whole heap of words of the form 'foo' and i want to change them to Literal('foo'). The following :s command :%s/'.*'/Literal('.*')/gci finds the things i want to change but then it replaces them all with Literal('.*') rather than Literal('foo')
Examples:
I get:
'_' -> Literal('.*')
'dog' -> Literal('.*')
I want:
'_' -> Literal('_')
'dog' -> Literal('dog')
vim regular-expression
edited yesterday
Rui F Ribeiro
38.6k1479128
asked Dec 28 '13 at 4:31
user191304
255
add a comment |
up vote
1
down vote
favorite
I've got a file with a whole heap of words of the form 'foo' and i want to change them to Literal('foo'). The following :s command :%s/'.*'/Literal('.*')/gci finds the things i want to change but then it replaces them all with Literal('.*') rather than Literal('foo')
Examples:
I get:
'_' -> Literal('.*')
'dog' -> Literal('.*')
I want:
'_' -> Literal('_')
'dog' -> Literal('dog')
vim regular-expression
edited yesterday
Rui F Ribeiro
38.6k1479128
asked Dec 28 '13 at 4:31
user191304
255
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I've got a file with a whole heap of words of the form 'foo' and i want to change them to Literal('foo'). The following :s command :%s/'.*'/Literal('.*')/gci finds the things i want to change but then it replaces them all with Literal('.*') rather than Literal('foo')
Examples:
I get:
'_' -> Literal('.*')
'dog' -> Literal('.*')
I want:
'_' -> Literal('_')
'dog' -> Literal('dog')
vim regular-expression
edited yesterday
Rui F Ribeiro
38.6k1479128
asked Dec 28 '13 at 4:31
user191304
255
I've got a file with a whole heap of words of the form 'foo' and i want to change them to Literal('foo'). The following :s command :%s/'.*'/Literal('.*')/gci finds the things i want to change but then it replaces them all with Literal('.*') rather than Literal('foo')
Examples:
I get:
'_' -> Literal('.*')
'dog' -> Literal('.*')
I want:
'_' -> Literal('_')
'dog' -> Literal('dog')
vim regular-expression
vim regular-expression
edited yesterday
Rui F Ribeiro
38.6k1479128
asked Dec 28 '13 at 4:31
user191304
255
edited yesterday
Rui F Ribeiro
38.6k1479128
asked Dec 28 '13 at 4:31
user191304
255
edited yesterday
Rui F Ribeiro
38.6k1479128
edited yesterday
Rui F Ribeiro
38.6k1479128
edited yesterday
Rui F Ribeiro
38.6k1479128
38.6k1479128
asked Dec 28 '13 at 4:31
user191304
255
asked Dec 28 '13 at 4:31
user191304
255
asked Dec 28 '13 at 4:31
user191304
255
255
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
4
down vote
accepted
You almost have it
:%s/('.*')/Literal(1)/gci
You need to save the match and reference it in the replace. You were inserting a literal (no pun) .* in the replace.
answered Dec 28 '13 at 4:41
casey
11.4k33457
Wonderful. Thanks so much.
– user191304
Dec 28 '13 at 4:59
add a comment |
up vote
1
down vote
An alternative to casey's answer with explicit capturing is to restrict the match with zs (start) and ze (end), to assert that the single quotes are there, but don't include them. Then, you can just refer to the match in the replacement part with &:
:%s/'zs.*ze'/Literal(&)/gci
answered Dec 28 '13 at 20:31
Ingo Karkat
8,53911832
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
You almost have it
:%s/('.*')/Literal(1)/gci
You need to save the match and reference it in the replace. You were inserting a literal (no pun) .* in the replace.
answered Dec 28 '13 at 4:41
casey
11.4k33457
Wonderful. Thanks so much.
– user191304
Dec 28 '13 at 4:59
add a comment |
up vote
4
down vote
accepted
You almost have it
:%s/('.*')/Literal(1)/gci
You need to save the match and reference it in the replace. You were inserting a literal (no pun) .* in the replace.
answered Dec 28 '13 at 4:41
casey
11.4k33457
Wonderful. Thanks so much.
– user191304
Dec 28 '13 at 4:59
add a comment |
up vote
4
down vote
accepted
up vote
4
down vote
accepted
You almost have it
:%s/('.*')/Literal(1)/gci
You need to save the match and reference it in the replace. You were inserting a literal (no pun) .* in the replace.
answered Dec 28 '13 at 4:41
casey
11.4k33457
You almost have it
:%s/('.*')/Literal(1)/gci
You need to save the match and reference it in the replace. You were inserting a literal (no pun) .* in the replace.
answered Dec 28 '13 at 4:41
casey
11.4k33457
answered Dec 28 '13 at 4:41
casey
11.4k33457
answered Dec 28 '13 at 4:41
casey
11.4k33457
answered Dec 28 '13 at 4:41
casey
11.4k33457
11.4k33457
Wonderful. Thanks so much.
– user191304
Dec 28 '13 at 4:59
add a comment |
Wonderful. Thanks so much.
– user191304
Dec 28 '13 at 4:59
Wonderful. Thanks so much.
– user191304
Dec 28 '13 at 4:59
Wonderful. Thanks so much.
– user191304
Dec 28 '13 at 4:59
add a comment |
up vote
1
down vote
An alternative to casey's answer with explicit capturing is to restrict the match with zs (start) and ze (end), to assert that the single quotes are there, but don't include them. Then, you can just refer to the match in the replacement part with &:
:%s/'zs.*ze'/Literal(&)/gci
answered Dec 28 '13 at 20:31
Ingo Karkat
8,53911832
add a comment |
up vote
1
down vote
An alternative to casey's answer with explicit capturing is to restrict the match with zs (start) and ze (end), to assert that the single quotes are there, but don't include them. Then, you can just refer to the match in the replacement part with &:
:%s/'zs.*ze'/Literal(&)/gci
answered Dec 28 '13 at 20:31
Ingo Karkat
8,53911832
add a comment |
up vote
1
down vote
up vote
1
down vote
An alternative to casey's answer with explicit capturing is to restrict the match with zs (start) and ze (end), to assert that the single quotes are there, but don't include them. Then, you can just refer to the match in the replacement part with &:
:%s/'zs.*ze'/Literal(&)/gci
answered Dec 28 '13 at 20:31
Ingo Karkat
8,53911832
An alternative to casey's answer with explicit capturing is to restrict the match with zs (start) and ze (end), to assert that the single quotes are there, but don't include them. Then, you can just refer to the match in the replacement part with &:
:%s/'zs.*ze'/Literal(&)/gci
answered Dec 28 '13 at 20:31
Ingo Karkat
8,53911832
answered Dec 28 '13 at 20:31
Ingo Karkat
8,53911832
answered Dec 28 '13 at 20:31
Ingo Karkat
8,53911832
answered Dec 28 '13 at 20:31
Ingo Karkat
8,53911832
8,53911832
add a comment |
add a comment |
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