Finding the Percentage from a grep variable
0
I want to display the calculation of the CPU load in percentage.
num2=$(uptime | grep "average:" | tr -d " " | cut -d ':' -f 5 | cut -d ',' -f 2)
percent=$((num2(*100)))
echo 'CPU percentage' $percent
Am I missing something?
shell-script variable uptime
edited 1 hour ago
Jeff Schaller
38.7k1053125
asked 1 hour ago
User101
1
New contributor
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0
I want to display the calculation of the CPU load in percentage.
num2=$(uptime | grep "average:" | tr -d " " | cut -d ':' -f 5 | cut -d ',' -f 2)
percent=$((num2(*100)))
echo 'CPU percentage' $percent
Am I missing something?
shell-script variable uptime
edited 1 hour ago
Jeff Schaller
38.7k1053125
asked 1 hour ago
User101
1
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Is that an actual typo of(*100)or a copy/paste typo?
– Jeff Schaller
1 hour ago
Nope that's what I think how it should be.
– User101
1 hour ago
1
bash arithmetic uses infix notation, so you'd need$((num2 * 100)), if that's all that's stopping you
– Jeff Schaller
1 hour ago
it always shows up a syntax error: invalid arithmetic operator (error token is ".01")
– User101
1 hour ago
That seems like an awfully long pipeline - at least on Linux, you might want to look at reading the value more directly from/proc/loadavge.g.awk '{print "CPU percentage " $2*100}' < /proc/loadavg
– steeldriver
1 hour ago
|
show 1 more comment
0
0
0
I want to display the calculation of the CPU load in percentage.
num2=$(uptime | grep "average:" | tr -d " " | cut -d ':' -f 5 | cut -d ',' -f 2)
percent=$((num2(*100)))
echo 'CPU percentage' $percent
Am I missing something?
shell-script variable uptime
edited 1 hour ago
Jeff Schaller
38.7k1053125
asked 1 hour ago
User101
1
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I want to display the calculation of the CPU load in percentage.
num2=$(uptime | grep "average:" | tr -d " " | cut -d ':' -f 5 | cut -d ',' -f 2)
percent=$((num2(*100)))
echo 'CPU percentage' $percent
Am I missing something?
shell-script variable uptime
shell-script variable uptime
edited 1 hour ago
Jeff Schaller
38.7k1053125
asked 1 hour ago
User101
1
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Jeff Schaller
38.7k1053125
asked 1 hour ago
User101
1
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Jeff Schaller
38.7k1053125
edited 1 hour ago
Jeff Schaller
38.7k1053125
edited 1 hour ago
Jeff Schaller
38.7k1053125
38.7k1053125
asked 1 hour ago
User101
1
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
User101
1
asked 1 hour ago
User101
1
1
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Is that an actual typo of(*100)or a copy/paste typo?
– Jeff Schaller
1 hour ago
Nope that's what I think how it should be.
– User101
1 hour ago
1
bash arithmetic uses infix notation, so you'd need$((num2 * 100)), if that's all that's stopping you
– Jeff Schaller
1 hour ago
it always shows up a syntax error: invalid arithmetic operator (error token is ".01")
– User101
1 hour ago
That seems like an awfully long pipeline - at least on Linux, you might want to look at reading the value more directly from/proc/loadavge.g.awk '{print "CPU percentage " $2*100}' < /proc/loadavg
– steeldriver
1 hour ago
|
show 1 more comment
Is that an actual typo of(*100)or a copy/paste typo?
– Jeff Schaller
1 hour ago
Nope that's what I think how it should be.
– User101
1 hour ago
1
bash arithmetic uses infix notation, so you'd need$((num2 * 100)), if that's all that's stopping you
– Jeff Schaller
1 hour ago
it always shows up a syntax error: invalid arithmetic operator (error token is ".01")
– User101
1 hour ago
That seems like an awfully long pipeline - at least on Linux, you might want to look at reading the value more directly from/proc/loadavge.g.awk '{print "CPU percentage " $2*100}' < /proc/loadavg
– steeldriver
1 hour ago
Is that an actual typo of
(*100) or a copy/paste typo?– Jeff Schaller
1 hour ago
Is that an actual typo of
(*100) or a copy/paste typo?– Jeff Schaller
1 hour ago
Nope that's what I think how it should be.
– User101
1 hour ago
Nope that's what I think how it should be.
– User101
1 hour ago
1
1
bash arithmetic uses infix notation, so you'd need
$((num2 * 100)), if that's all that's stopping you– Jeff Schaller
1 hour ago
bash arithmetic uses infix notation, so you'd need
$((num2 * 100)), if that's all that's stopping you– Jeff Schaller
1 hour ago
it always shows up a syntax error: invalid arithmetic operator (error token is ".01")
– User101
1 hour ago
it always shows up a syntax error: invalid arithmetic operator (error token is ".01")
– User101
1 hour ago
That seems like an awfully long pipeline - at least on Linux, you might want to look at reading the value more directly from
/proc/loadavg e.g. awk '{print "CPU percentage " $2*100}' < /proc/loadavg– steeldriver
1 hour ago
That seems like an awfully long pipeline - at least on Linux, you might want to look at reading the value more directly from
/proc/loadavg e.g. awk '{print "CPU percentage " $2*100}' < /proc/loadavg– steeldriver
1 hour ago
|
show 1 more comment
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Is that an actual typo of
(*100)or a copy/paste typo?– Jeff Schaller
1 hour ago
Nope that's what I think how it should be.
– User101
1 hour ago
1
bash arithmetic uses infix notation, so you'd need
$((num2 * 100)), if that's all that's stopping you– Jeff Schaller
1 hour ago
it always shows up a syntax error: invalid arithmetic operator (error token is ".01")
– User101
1 hour ago
That seems like an awfully long pipeline - at least on Linux, you might want to look at reading the value more directly from
/proc/loadavge.g.awk '{print "CPU percentage " $2*100}' < /proc/loadavg– steeldriver
1 hour ago