Create text files from each link in a list?












0














I have a file with links like this:



http://domain.com/file_name1.mkv

http://domain.com/file_name2.mkv

http://domain.com/file_name3.mkv


... and so on.



I want to create a file for each link with extension .strm and each file to have the name of the file name and to contain the link for that file. So, for the first link the first file name will be file_name1.strm and contain the first link, for the second link the file name will be file_name2.strm and will contain the second link, and so on. How can i do that?



I have a command that is doing something close but it creates only files with the names from words in a file:



sed -e 's/$/.strm/' file | xargs -d 'n' touch





files







share|improve this question



























    0














    I have a file with links like this:



    http://domain.com/file_name1.mkv
    
http://domain.com/file_name2.mkv
    
http://domain.com/file_name3.mkv


    ... and so on.



    I want to create a file for each link with extension .strm and each file to have the name of the file name and to contain the link for that file. So, for the first link the first file name will be file_name1.strm and contain the first link, for the second link the file name will be file_name2.strm and will contain the second link, and so on. How can i do that?



    I have a command that is doing something close but it creates only files with the names from words in a file:



    sed -e 's/$/.strm/' file | xargs -d 'n' touch





    files







    share|improve this question

























      0












      0








      0







      I have a file with links like this:



      http://domain.com/file_name1.mkv
      
http://domain.com/file_name2.mkv
      
http://domain.com/file_name3.mkv


      ... and so on.



      I want to create a file for each link with extension .strm and each file to have the name of the file name and to contain the link for that file. So, for the first link the first file name will be file_name1.strm and contain the first link, for the second link the file name will be file_name2.strm and will contain the second link, and so on. How can i do that?



      I have a command that is doing something close but it creates only files with the names from words in a file:



      sed -e 's/$/.strm/' file | xargs -d 'n' touch





      files







      share|improve this question













      I have a file with links like this:



      http://domain.com/file_name1.mkv
      
http://domain.com/file_name2.mkv
      
http://domain.com/file_name3.mkv


      ... and so on.



      I want to create a file for each link with extension .strm and each file to have the name of the file name and to contain the link for that file. So, for the first link the first file name will be file_name1.strm and contain the first link, for the second link the file name will be file_name2.strm and will contain the second link, and so on. How can i do that?



      I have a command that is doing something close but it creates only files with the names from words in a file:



      sed -e 's/$/.strm/' file | xargs -d 'n' touch





      files




      files






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 1 hour ago









      user1800997

      163




      163






















          3 Answers
          3






          active

          oldest

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          0














          You could parse the file with awk and ask it to print the various lines to filenames based on the last element of the URL. The -F/ tells awk to split the lines into fields using / as a delimiter; $0 is the entire line, and $NF is the value of the last field. The print statement executes for every line of the file.



          awk -F/ '{print $0 > $NF}' < input





          share|improve this answer





























            0














            To elaborate your xargs attempt



            xargs -L1 sh -c 'f="${0##*/}"; printf "%sn" "$0" > "${f%.*}.strm"' < file


            The first substitution f="${0##*/}" removes the path components of the URL, while the second "${f%.*}.strm" removes and replaces the extension.



            Ex.



            $ xargs -L1 sh -c 'f=${0##*/}; printf "%sn" "$0" > "${f%.*}.strm"' < file
            
$ head *.strm
            
==> file_name1.strm <==
            
http://domain.com/file_name1.mkv
            

            
==> file_name2.strm <==
            
http://domain.com/file_name2.mkv
            

            
==> file_name3.strm <==
            
http://domain.com/file_name3.mkv





            share|improve this answer





























              -1














              while read link; do
              
   echo $link >$link.strm
              
done





              share|improve this answer





















              • Issues: The links contain /, so the shell will interpret them as files in weirdly named subdirectories. The variables are unquoted, which may possibly be problematic if any link contains a filename globbing character. No input data is given to the loop. No explanation given in the answer.
                – Kusalananda
                37 mins ago











              Your Answer








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              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

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              active

              oldest

              votes









              0














              You could parse the file with awk and ask it to print the various lines to filenames based on the last element of the URL. The -F/ tells awk to split the lines into fields using / as a delimiter; $0 is the entire line, and $NF is the value of the last field. The print statement executes for every line of the file.



              awk -F/ '{print $0 > $NF}' < input





              share|improve this answer


























                0














                You could parse the file with awk and ask it to print the various lines to filenames based on the last element of the URL. The -F/ tells awk to split the lines into fields using / as a delimiter; $0 is the entire line, and $NF is the value of the last field. The print statement executes for every line of the file.



                awk -F/ '{print $0 > $NF}' < input





                share|improve this answer
























                  0












                  0








                  0






                  You could parse the file with awk and ask it to print the various lines to filenames based on the last element of the URL. The -F/ tells awk to split the lines into fields using / as a delimiter; $0 is the entire line, and $NF is the value of the last field. The print statement executes for every line of the file.



                  awk -F/ '{print $0 > $NF}' < input





                  share|improve this answer












                  You could parse the file with awk and ask it to print the various lines to filenames based on the last element of the URL. The -F/ tells awk to split the lines into fields using / as a delimiter; $0 is the entire line, and $NF is the value of the last field. The print statement executes for every line of the file.



                  awk -F/ '{print $0 > $NF}' < input






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 30 mins ago









                  Jeff Schaller

                  38.7k1053125




                  38.7k1053125

























                      0














                      To elaborate your xargs attempt



                      xargs -L1 sh -c 'f="${0##*/}"; printf "%sn" "$0" > "${f%.*}.strm"' < file


                      The first substitution f="${0##*/}" removes the path components of the URL, while the second "${f%.*}.strm" removes and replaces the extension.



                      Ex.



                      $ xargs -L1 sh -c 'f=${0##*/}; printf "%sn" "$0" > "${f%.*}.strm"' < file
                      
$ head *.strm
                      
==> file_name1.strm <==
                      
http://domain.com/file_name1.mkv
                      

                      
==> file_name2.strm <==
                      
http://domain.com/file_name2.mkv
                      

                      
==> file_name3.strm <==
                      
http://domain.com/file_name3.mkv





                      share|improve this answer


























                        0














                        To elaborate your xargs attempt



                        xargs -L1 sh -c 'f="${0##*/}"; printf "%sn" "$0" > "${f%.*}.strm"' < file


                        The first substitution f="${0##*/}" removes the path components of the URL, while the second "${f%.*}.strm" removes and replaces the extension.



                        Ex.



                        $ xargs -L1 sh -c 'f=${0##*/}; printf "%sn" "$0" > "${f%.*}.strm"' < file
                        
$ head *.strm
                        
==> file_name1.strm <==
                        
http://domain.com/file_name1.mkv
                        

                        
==> file_name2.strm <==
                        
http://domain.com/file_name2.mkv
                        

                        
==> file_name3.strm <==
                        
http://domain.com/file_name3.mkv





                        share|improve this answer
























                          0












                          0








                          0






                          To elaborate your xargs attempt



                          xargs -L1 sh -c 'f="${0##*/}"; printf "%sn" "$0" > "${f%.*}.strm"' < file


                          The first substitution f="${0##*/}" removes the path components of the URL, while the second "${f%.*}.strm" removes and replaces the extension.



                          Ex.



                          $ xargs -L1 sh -c 'f=${0##*/}; printf "%sn" "$0" > "${f%.*}.strm"' < file
                          
$ head *.strm
                          
==> file_name1.strm <==
                          
http://domain.com/file_name1.mkv
                          

                          
==> file_name2.strm <==
                          
http://domain.com/file_name2.mkv
                          

                          
==> file_name3.strm <==
                          
http://domain.com/file_name3.mkv





                          share|improve this answer












                          To elaborate your xargs attempt



                          xargs -L1 sh -c 'f="${0##*/}"; printf "%sn" "$0" > "${f%.*}.strm"' < file


                          The first substitution f="${0##*/}" removes the path components of the URL, while the second "${f%.*}.strm" removes and replaces the extension.



                          Ex.



                          $ xargs -L1 sh -c 'f=${0##*/}; printf "%sn" "$0" > "${f%.*}.strm"' < file
                          
$ head *.strm
                          
==> file_name1.strm <==
                          
http://domain.com/file_name1.mkv
                          

                          
==> file_name2.strm <==
                          
http://domain.com/file_name2.mkv
                          

                          
==> file_name3.strm <==
                          
http://domain.com/file_name3.mkv






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 26 mins ago









                          steeldriver

                          34.2k35083




                          34.2k35083























                              -1














                              while read link; do
                              
   echo $link >$link.strm
                              
done





                              share|improve this answer





















                              • Issues: The links contain /, so the shell will interpret them as files in weirdly named subdirectories. The variables are unquoted, which may possibly be problematic if any link contains a filename globbing character. No input data is given to the loop. No explanation given in the answer.
                                – Kusalananda
                                37 mins ago
















                              -1














                              while read link; do
                              
   echo $link >$link.strm
                              
done





                              share|improve this answer





















                              • Issues: The links contain /, so the shell will interpret them as files in weirdly named subdirectories. The variables are unquoted, which may possibly be problematic if any link contains a filename globbing character. No input data is given to the loop. No explanation given in the answer.
                                – Kusalananda
                                37 mins ago














                              -1












                              -1








                              -1






                              while read link; do
                              
   echo $link >$link.strm
                              
done





                              share|improve this answer












                              while read link; do
                              
   echo $link >$link.strm
                              
done






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered 40 mins ago









                              Erwan

                              1994




                              1994












                              • Issues: The links contain /, so the shell will interpret them as files in weirdly named subdirectories. The variables are unquoted, which may possibly be problematic if any link contains a filename globbing character. No input data is given to the loop. No explanation given in the answer.
                                – Kusalananda
                                37 mins ago


















                              • Issues: The links contain /, so the shell will interpret them as files in weirdly named subdirectories. The variables are unquoted, which may possibly be problematic if any link contains a filename globbing character. No input data is given to the loop. No explanation given in the answer.
                                – Kusalananda
                                37 mins ago
















                              Issues: The links contain /, so the shell will interpret them as files in weirdly named subdirectories. The variables are unquoted, which may possibly be problematic if any link contains a filename globbing character. No input data is given to the loop. No explanation given in the answer.
                              – Kusalananda
                              37 mins ago




                              Issues: The links contain /, so the shell will interpret them as files in weirdly named subdirectories. The variables are unquoted, which may possibly be problematic if any link contains a filename globbing character. No input data is given to the loop. No explanation given in the answer.
                              – Kusalananda
                              37 mins ago


















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