Read string block as multiple variables ubuntu











up vote
1
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I have a script to copy permissions which works fine, being the interesting line this one:



...
bash commands.sh $PAM_USER "medium" /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed} /usr/bin/{vim,touch,java,python,gcc,awk,make}
...


commands.sh has a loop which reads through all permissions listed and copies them to a specified directory.
Problem comes when I try to do the same thing reading the permissions from a config file.



My config file contains the following:



MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
MEDIUM_PERMISSIONS_USR_BIN=/usr/bin/{vim,touch,java,python,gcc,awk,make}
MEDIUM_ENVIROMENT_LIFESPAN=midnight
MEDIUM_PERSISTENT_HOME=true


Note: the last two configurations are for something different, for now I'm trying to read the first two lines properly.



I add the config file to the previous script and try to execute the following:



source /etc/users/config.cfg
...
bash commands.sh $PAM_USER "medium" $MEDIUM_PERMISSIONS_BIN $MEDIUM_PERMISSIONS_USR_BIN
...


The problem is that the loop reads it as such:



loop: /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
loop: /usr/bin/{vim,touch,java,python,gcc,awk,make}


when previously it used to read it as /bin/ls, /bin/rm, /bin/rm and so on, hence the loop working with the first version as it is able to find those commands, but not on the second version sisnce the output specified previously is incorrect.



I've read through the sed and awk commands but I'm quite new to this and can't get them to work.



How can I read the permissions from my config file as if I was introducing them directly like in the first version?



Thanks



edit: commands.sh code:



#!/bin/bash

CHROOT="/users/$2/$1"
if [ ! -d "$CHROOT/home/$1" ]; then
mkdir -p "$CHROOT/home/$1"
fi

for i in $( ldd $* | grep -v dynamic | cut -d " " -f 3 | sed 's/://' | sort | uniq )
do
cp -v --parents $i $CHROOT
done

#ARCH amd64
if [ -f /lib64/ld-linux-x86-64.so.2 ]; then
cp --parents /lib64/ld-linux-x86-64.so.2 /$CHROOT
fi

#ARCH i386
if [ -f /lib/ld-linux.so.2 ]; then
cp --parents /lib/ld-linux.so.2 /$CHROOT
fi

clear
cd


Comment: I removed all the debugging echoes. This code is pretty much a copy from a code you can find here: https://linuxconfig.org/how-to-automatically-chroot-jail-selected-ssh-user-logins










share|improve this question









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  • 1




    Please edit your question and show us the commands.sh script. We need to see the code to understand how it reads whatever it reads.
    – terdon
    Dec 3 at 11:22










  • @terdon done. I should have included it in my original post, sorry. Anyways, your post seems to work perfectly and also explaining how it works. Much appreciated :)
    – sartox
    Dec 3 at 13:55










  • Yeah, I guessed how you were reading it after leaving the comment :)
    – terdon
    Dec 3 at 13:57















up vote
1
down vote

favorite












I have a script to copy permissions which works fine, being the interesting line this one:



...
bash commands.sh $PAM_USER "medium" /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed} /usr/bin/{vim,touch,java,python,gcc,awk,make}
...


commands.sh has a loop which reads through all permissions listed and copies them to a specified directory.
Problem comes when I try to do the same thing reading the permissions from a config file.



My config file contains the following:



MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
MEDIUM_PERMISSIONS_USR_BIN=/usr/bin/{vim,touch,java,python,gcc,awk,make}
MEDIUM_ENVIROMENT_LIFESPAN=midnight
MEDIUM_PERSISTENT_HOME=true


Note: the last two configurations are for something different, for now I'm trying to read the first two lines properly.



I add the config file to the previous script and try to execute the following:



source /etc/users/config.cfg
...
bash commands.sh $PAM_USER "medium" $MEDIUM_PERMISSIONS_BIN $MEDIUM_PERMISSIONS_USR_BIN
...


The problem is that the loop reads it as such:



loop: /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
loop: /usr/bin/{vim,touch,java,python,gcc,awk,make}


when previously it used to read it as /bin/ls, /bin/rm, /bin/rm and so on, hence the loop working with the first version as it is able to find those commands, but not on the second version sisnce the output specified previously is incorrect.



I've read through the sed and awk commands but I'm quite new to this and can't get them to work.



How can I read the permissions from my config file as if I was introducing them directly like in the first version?



Thanks



edit: commands.sh code:



#!/bin/bash

CHROOT="/users/$2/$1"
if [ ! -d "$CHROOT/home/$1" ]; then
mkdir -p "$CHROOT/home/$1"
fi

for i in $( ldd $* | grep -v dynamic | cut -d " " -f 3 | sed 's/://' | sort | uniq )
do
cp -v --parents $i $CHROOT
done

#ARCH amd64
if [ -f /lib64/ld-linux-x86-64.so.2 ]; then
cp --parents /lib64/ld-linux-x86-64.so.2 /$CHROOT
fi

#ARCH i386
if [ -f /lib/ld-linux.so.2 ]; then
cp --parents /lib/ld-linux.so.2 /$CHROOT
fi

clear
cd


Comment: I removed all the debugging echoes. This code is pretty much a copy from a code you can find here: https://linuxconfig.org/how-to-automatically-chroot-jail-selected-ssh-user-logins










share|improve this question









New contributor




sartox is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1




    Please edit your question and show us the commands.sh script. We need to see the code to understand how it reads whatever it reads.
    – terdon
    Dec 3 at 11:22










  • @terdon done. I should have included it in my original post, sorry. Anyways, your post seems to work perfectly and also explaining how it works. Much appreciated :)
    – sartox
    Dec 3 at 13:55










  • Yeah, I guessed how you were reading it after leaving the comment :)
    – terdon
    Dec 3 at 13:57













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I have a script to copy permissions which works fine, being the interesting line this one:



...
bash commands.sh $PAM_USER "medium" /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed} /usr/bin/{vim,touch,java,python,gcc,awk,make}
...


commands.sh has a loop which reads through all permissions listed and copies them to a specified directory.
Problem comes when I try to do the same thing reading the permissions from a config file.



My config file contains the following:



MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
MEDIUM_PERMISSIONS_USR_BIN=/usr/bin/{vim,touch,java,python,gcc,awk,make}
MEDIUM_ENVIROMENT_LIFESPAN=midnight
MEDIUM_PERSISTENT_HOME=true


Note: the last two configurations are for something different, for now I'm trying to read the first two lines properly.



I add the config file to the previous script and try to execute the following:



source /etc/users/config.cfg
...
bash commands.sh $PAM_USER "medium" $MEDIUM_PERMISSIONS_BIN $MEDIUM_PERMISSIONS_USR_BIN
...


The problem is that the loop reads it as such:



loop: /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
loop: /usr/bin/{vim,touch,java,python,gcc,awk,make}


when previously it used to read it as /bin/ls, /bin/rm, /bin/rm and so on, hence the loop working with the first version as it is able to find those commands, but not on the second version sisnce the output specified previously is incorrect.



I've read through the sed and awk commands but I'm quite new to this and can't get them to work.



How can I read the permissions from my config file as if I was introducing them directly like in the first version?



Thanks



edit: commands.sh code:



#!/bin/bash

CHROOT="/users/$2/$1"
if [ ! -d "$CHROOT/home/$1" ]; then
mkdir -p "$CHROOT/home/$1"
fi

for i in $( ldd $* | grep -v dynamic | cut -d " " -f 3 | sed 's/://' | sort | uniq )
do
cp -v --parents $i $CHROOT
done

#ARCH amd64
if [ -f /lib64/ld-linux-x86-64.so.2 ]; then
cp --parents /lib64/ld-linux-x86-64.so.2 /$CHROOT
fi

#ARCH i386
if [ -f /lib/ld-linux.so.2 ]; then
cp --parents /lib/ld-linux.so.2 /$CHROOT
fi

clear
cd


Comment: I removed all the debugging echoes. This code is pretty much a copy from a code you can find here: https://linuxconfig.org/how-to-automatically-chroot-jail-selected-ssh-user-logins










share|improve this question









New contributor




sartox is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I have a script to copy permissions which works fine, being the interesting line this one:



...
bash commands.sh $PAM_USER "medium" /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed} /usr/bin/{vim,touch,java,python,gcc,awk,make}
...


commands.sh has a loop which reads through all permissions listed and copies them to a specified directory.
Problem comes when I try to do the same thing reading the permissions from a config file.



My config file contains the following:



MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
MEDIUM_PERMISSIONS_USR_BIN=/usr/bin/{vim,touch,java,python,gcc,awk,make}
MEDIUM_ENVIROMENT_LIFESPAN=midnight
MEDIUM_PERSISTENT_HOME=true


Note: the last two configurations are for something different, for now I'm trying to read the first two lines properly.



I add the config file to the previous script and try to execute the following:



source /etc/users/config.cfg
...
bash commands.sh $PAM_USER "medium" $MEDIUM_PERMISSIONS_BIN $MEDIUM_PERMISSIONS_USR_BIN
...


The problem is that the loop reads it as such:



loop: /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
loop: /usr/bin/{vim,touch,java,python,gcc,awk,make}


when previously it used to read it as /bin/ls, /bin/rm, /bin/rm and so on, hence the loop working with the first version as it is able to find those commands, but not on the second version sisnce the output specified previously is incorrect.



I've read through the sed and awk commands but I'm quite new to this and can't get them to work.



How can I read the permissions from my config file as if I was introducing them directly like in the first version?



Thanks



edit: commands.sh code:



#!/bin/bash

CHROOT="/users/$2/$1"
if [ ! -d "$CHROOT/home/$1" ]; then
mkdir -p "$CHROOT/home/$1"
fi

for i in $( ldd $* | grep -v dynamic | cut -d " " -f 3 | sed 's/://' | sort | uniq )
do
cp -v --parents $i $CHROOT
done

#ARCH amd64
if [ -f /lib64/ld-linux-x86-64.so.2 ]; then
cp --parents /lib64/ld-linux-x86-64.so.2 /$CHROOT
fi

#ARCH i386
if [ -f /lib/ld-linux.so.2 ]; then
cp --parents /lib/ld-linux.so.2 /$CHROOT
fi

clear
cd


Comment: I removed all the debugging echoes. This code is pretty much a copy from a code you can find here: https://linuxconfig.org/how-to-automatically-chroot-jail-selected-ssh-user-logins







bash scripting






share|improve this question









New contributor




sartox is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




sartox is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited Dec 3 at 13:56





















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asked Dec 3 at 11:13









sartox

83




83




New contributor




sartox is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





sartox is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






sartox is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    Please edit your question and show us the commands.sh script. We need to see the code to understand how it reads whatever it reads.
    – terdon
    Dec 3 at 11:22










  • @terdon done. I should have included it in my original post, sorry. Anyways, your post seems to work perfectly and also explaining how it works. Much appreciated :)
    – sartox
    Dec 3 at 13:55










  • Yeah, I guessed how you were reading it after leaving the comment :)
    – terdon
    Dec 3 at 13:57














  • 1




    Please edit your question and show us the commands.sh script. We need to see the code to understand how it reads whatever it reads.
    – terdon
    Dec 3 at 11:22










  • @terdon done. I should have included it in my original post, sorry. Anyways, your post seems to work perfectly and also explaining how it works. Much appreciated :)
    – sartox
    Dec 3 at 13:55










  • Yeah, I guessed how you were reading it after leaving the comment :)
    – terdon
    Dec 3 at 13:57








1




1




Please edit your question and show us the commands.sh script. We need to see the code to understand how it reads whatever it reads.
– terdon
Dec 3 at 11:22




Please edit your question and show us the commands.sh script. We need to see the code to understand how it reads whatever it reads.
– terdon
Dec 3 at 11:22












@terdon done. I should have included it in my original post, sorry. Anyways, your post seems to work perfectly and also explaining how it works. Much appreciated :)
– sartox
Dec 3 at 13:55




@terdon done. I should have included it in my original post, sorry. Anyways, your post seems to work perfectly and also explaining how it works. Much appreciated :)
– sartox
Dec 3 at 13:55












Yeah, I guessed how you were reading it after leaving the comment :)
– terdon
Dec 3 at 13:57




Yeah, I guessed how you were reading it after leaving the comment :)
– terdon
Dec 3 at 13:57










1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










You are trying to define an array variable but are using the format for a string:



## This will define a string variable
$ MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
$ echo $MEDIUM_PERMISSIONS_BIN
/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}

## The parentheses tell the shell this is an array
$ MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
$ echo $MEDIUM_PERMISSIONS_BIN ## the 1st element of the array
/bin/ls
$ echo ${MEDIUM_PERMISSIONS_BIN[@]} ## the entire array
/bin/ls /bin/rm /bin/bash /bin/nano /bin/mkdir /bin/kill /bin/ln /bin/ps /bin/grep /bin/sed


So just change your config file to:



MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
MEDIUM_PERMISSIONS_USR_BIN=(/usr/bin/{vim,touch,java,python,gcc,awk,make})
MEDIUM_ENVIROMENT_LIFESPAN=midnight
MEDIUM_PERSISTENT_HOME=true


And then, in your script, use "${MEDIUM_PERMISSIONS_BIN[@]}".






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    1 Answer
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    active

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    up vote
    1
    down vote



    accepted










    You are trying to define an array variable but are using the format for a string:



    ## This will define a string variable
    $ MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
    $ echo $MEDIUM_PERMISSIONS_BIN
    /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}

    ## The parentheses tell the shell this is an array
    $ MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
    $ echo $MEDIUM_PERMISSIONS_BIN ## the 1st element of the array
    /bin/ls
    $ echo ${MEDIUM_PERMISSIONS_BIN[@]} ## the entire array
    /bin/ls /bin/rm /bin/bash /bin/nano /bin/mkdir /bin/kill /bin/ln /bin/ps /bin/grep /bin/sed


    So just change your config file to:



    MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
    MEDIUM_PERMISSIONS_USR_BIN=(/usr/bin/{vim,touch,java,python,gcc,awk,make})
    MEDIUM_ENVIROMENT_LIFESPAN=midnight
    MEDIUM_PERSISTENT_HOME=true


    And then, in your script, use "${MEDIUM_PERMISSIONS_BIN[@]}".






    share|improve this answer

























      up vote
      1
      down vote



      accepted










      You are trying to define an array variable but are using the format for a string:



      ## This will define a string variable
      $ MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
      $ echo $MEDIUM_PERMISSIONS_BIN
      /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}

      ## The parentheses tell the shell this is an array
      $ MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
      $ echo $MEDIUM_PERMISSIONS_BIN ## the 1st element of the array
      /bin/ls
      $ echo ${MEDIUM_PERMISSIONS_BIN[@]} ## the entire array
      /bin/ls /bin/rm /bin/bash /bin/nano /bin/mkdir /bin/kill /bin/ln /bin/ps /bin/grep /bin/sed


      So just change your config file to:



      MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
      MEDIUM_PERMISSIONS_USR_BIN=(/usr/bin/{vim,touch,java,python,gcc,awk,make})
      MEDIUM_ENVIROMENT_LIFESPAN=midnight
      MEDIUM_PERSISTENT_HOME=true


      And then, in your script, use "${MEDIUM_PERMISSIONS_BIN[@]}".






      share|improve this answer























        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        You are trying to define an array variable but are using the format for a string:



        ## This will define a string variable
        $ MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
        $ echo $MEDIUM_PERMISSIONS_BIN
        /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}

        ## The parentheses tell the shell this is an array
        $ MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
        $ echo $MEDIUM_PERMISSIONS_BIN ## the 1st element of the array
        /bin/ls
        $ echo ${MEDIUM_PERMISSIONS_BIN[@]} ## the entire array
        /bin/ls /bin/rm /bin/bash /bin/nano /bin/mkdir /bin/kill /bin/ln /bin/ps /bin/grep /bin/sed


        So just change your config file to:



        MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
        MEDIUM_PERMISSIONS_USR_BIN=(/usr/bin/{vim,touch,java,python,gcc,awk,make})
        MEDIUM_ENVIROMENT_LIFESPAN=midnight
        MEDIUM_PERSISTENT_HOME=true


        And then, in your script, use "${MEDIUM_PERMISSIONS_BIN[@]}".






        share|improve this answer












        You are trying to define an array variable but are using the format for a string:



        ## This will define a string variable
        $ MEDIUM_PERMISSIONS_BIN=/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}
        $ echo $MEDIUM_PERMISSIONS_BIN
        /bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed}

        ## The parentheses tell the shell this is an array
        $ MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
        $ echo $MEDIUM_PERMISSIONS_BIN ## the 1st element of the array
        /bin/ls
        $ echo ${MEDIUM_PERMISSIONS_BIN[@]} ## the entire array
        /bin/ls /bin/rm /bin/bash /bin/nano /bin/mkdir /bin/kill /bin/ln /bin/ps /bin/grep /bin/sed


        So just change your config file to:



        MEDIUM_PERMISSIONS_BIN=(/bin/{ls,rm,bash,nano,mkdir,kill,ln,ps,grep,sed})
        MEDIUM_PERMISSIONS_USR_BIN=(/usr/bin/{vim,touch,java,python,gcc,awk,make})
        MEDIUM_ENVIROMENT_LIFESPAN=midnight
        MEDIUM_PERSISTENT_HOME=true


        And then, in your script, use "${MEDIUM_PERMISSIONS_BIN[@]}".







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 3 at 11:27









        terdon

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