Starting index at zero












4












$begingroup$


In order to start an index at zero, I found N. Abbasi is quite convenient. For instance,



enter image description here



(Note that in the original code by Abbasi, one of under scores _ in Notation was missing.)



However, with this method, we need to define these notations for each symbol.
I'd like to use any symbols with subscripts, like "a" in the above pic. with the same definition.



Any help is appreciated! Thanks in advance.






list-manipulation







share|improve this question







New contributor




Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$

















    4












    $begingroup$


    In order to start an index at zero, I found N. Abbasi is quite convenient. For instance,



    enter image description here



    (Note that in the original code by Abbasi, one of under scores _ in Notation was missing.)



    However, with this method, we need to define these notations for each symbol.
    I'd like to use any symbols with subscripts, like "a" in the above pic. with the same definition.



    Any help is appreciated! Thanks in advance.






    list-manipulation







    share|improve this question







    New contributor




    Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      4












      4








      4





      $begingroup$


      In order to start an index at zero, I found N. Abbasi is quite convenient. For instance,



      enter image description here



      (Note that in the original code by Abbasi, one of under scores _ in Notation was missing.)



      However, with this method, we need to define these notations for each symbol.
      I'd like to use any symbols with subscripts, like "a" in the above pic. with the same definition.



      Any help is appreciated! Thanks in advance.






      list-manipulation







      share|improve this question







      New contributor




      Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      In order to start an index at zero, I found N. Abbasi is quite convenient. For instance,



      enter image description here



      (Note that in the original code by Abbasi, one of under scores _ in Notation was missing.)



      However, with this method, we need to define these notations for each symbol.
      I'd like to use any symbols with subscripts, like "a" in the above pic. with the same definition.



      Any help is appreciated! Thanks in advance.






      list-manipulation




      list-manipulation






      share|improve this question







      New contributor




      Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked 3 hours ago









      Like TinaLike Tina

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      212




      New contributor




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      New contributor





      Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          1 Answer
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          $begingroup$

          There's no need to use the Notation package to achieve the same behavior. For example:



          SetAttributes[Subscript, HoldFirst];
          
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]


          Then:



          a = {"Alice", "Bob"};
          
Subscript[a, 0]
          
Subscript[a, 1]



          "Alice"



          "Bob"




          or an image:



          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
            $endgroup$
            – Like Tina
            2 hours ago











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          active

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          5












          $begingroup$

          There's no need to use the Notation package to achieve the same behavior. For example:



          SetAttributes[Subscript, HoldFirst];
          
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]


          Then:



          a = {"Alice", "Bob"};
          
Subscript[a, 0]
          
Subscript[a, 1]



          "Alice"



          "Bob"




          or an image:



          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
            $endgroup$
            – Like Tina
            2 hours ago
















          5












          $begingroup$

          There's no need to use the Notation package to achieve the same behavior. For example:



          SetAttributes[Subscript, HoldFirst];
          
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]


          Then:



          a = {"Alice", "Bob"};
          
Subscript[a, 0]
          
Subscript[a, 1]



          "Alice"



          "Bob"




          or an image:



          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
            $endgroup$
            – Like Tina
            2 hours ago














          5












          5








          5





          $begingroup$

          There's no need to use the Notation package to achieve the same behavior. For example:



          SetAttributes[Subscript, HoldFirst];
          
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]


          Then:



          a = {"Alice", "Bob"};
          
Subscript[a, 0]
          
Subscript[a, 1]



          "Alice"



          "Bob"




          or an image:



          enter image description here






          share|improve this answer









          $endgroup$



          There's no need to use the Notation package to achieve the same behavior. For example:



          SetAttributes[Subscript, HoldFirst];
          
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]


          Then:



          a = {"Alice", "Bob"};
          
Subscript[a, 0]
          
Subscript[a, 1]



          "Alice"



          "Bob"




          or an image:



          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 3 hours ago









          Carl WollCarl Woll

          69.1k392178




          69.1k392178












          • $begingroup$
            Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
            $endgroup$
            – Like Tina
            2 hours ago


















          • $begingroup$
            Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
            $endgroup$
            – Like Tina
            2 hours ago
















          $begingroup$
          Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
          $endgroup$
          – Like Tina
          2 hours ago




          $begingroup$
          Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
          $endgroup$
          – Like Tina
          2 hours ago










          Like Tina is a new contributor. Be nice, and check out our Code of Conduct.










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