Is integer division always equal to the floor of regular division?












6














For large quotients, integer division (//) doesn't seem to be necessarily equal to the floor of regular division (math.floor(a/b)).



According to Python docs (https://docs.python.org/3/reference/expressions.html - 6.7),




floor division of integers results in an integer; the result is that of mathematical division with the ‘floor’ function applied to the result.




However,



math.floor(648705536316023400 / 7) = 92672219473717632

648705536316023400 // 7 = 92672219473717628


'{0:.10f}'.format(648705536316023400 / 7) yields '92672219473717632.0000000000', but the last two digits of the decimal part should be 28 and not 32.










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    6














    For large quotients, integer division (//) doesn't seem to be necessarily equal to the floor of regular division (math.floor(a/b)).



    According to Python docs (https://docs.python.org/3/reference/expressions.html - 6.7),




    floor division of integers results in an integer; the result is that of mathematical division with the ‘floor’ function applied to the result.




    However,



    math.floor(648705536316023400 / 7) = 92672219473717632

    648705536316023400 // 7 = 92672219473717628


    '{0:.10f}'.format(648705536316023400 / 7) yields '92672219473717632.0000000000', but the last two digits of the decimal part should be 28 and not 32.










    share|improve this question









    New contributor




    Aditya Chanana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      6












      6








      6


      1





      For large quotients, integer division (//) doesn't seem to be necessarily equal to the floor of regular division (math.floor(a/b)).



      According to Python docs (https://docs.python.org/3/reference/expressions.html - 6.7),




      floor division of integers results in an integer; the result is that of mathematical division with the ‘floor’ function applied to the result.




      However,



      math.floor(648705536316023400 / 7) = 92672219473717632

      648705536316023400 // 7 = 92672219473717628


      '{0:.10f}'.format(648705536316023400 / 7) yields '92672219473717632.0000000000', but the last two digits of the decimal part should be 28 and not 32.










      share|improve this question









      New contributor




      Aditya Chanana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      For large quotients, integer division (//) doesn't seem to be necessarily equal to the floor of regular division (math.floor(a/b)).



      According to Python docs (https://docs.python.org/3/reference/expressions.html - 6.7),




      floor division of integers results in an integer; the result is that of mathematical division with the ‘floor’ function applied to the result.




      However,



      math.floor(648705536316023400 / 7) = 92672219473717632

      648705536316023400 // 7 = 92672219473717628


      '{0:.10f}'.format(648705536316023400 / 7) yields '92672219473717632.0000000000', but the last two digits of the decimal part should be 28 and not 32.







      python integer division floating-accuracy integer-division






      share|improve this question









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      edited 3 hours ago









      dan04

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      asked 3 hours ago









      Aditya Chanana

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          7














          The reason the quotients in your test case are not equal is that in the math.floor(a/b) case, the result is calculated with floating point arithmetic (IEEE-754 64-bit), which means there is a maximum precision. The quotient you have there is larger than the 253 limit above which floating point is no longer accurate up to the unit.



          With the integer division however, Python uses its unlimited integer range, and so that result is correct.






          share|improve this answer





























            2














            You may be dealing with integral values that are too large to express exactly as floats. Your number is significantly larger than 2^53, which is where the gaps between adjacent floating point doubles start to get bigger than 1. So you lose some precision when doing the floating point division.



            The integer division, on the other hand, is computed exactly.






            share|improve this answer





















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              7














              The reason the quotients in your test case are not equal is that in the math.floor(a/b) case, the result is calculated with floating point arithmetic (IEEE-754 64-bit), which means there is a maximum precision. The quotient you have there is larger than the 253 limit above which floating point is no longer accurate up to the unit.



              With the integer division however, Python uses its unlimited integer range, and so that result is correct.






              share|improve this answer


























                7














                The reason the quotients in your test case are not equal is that in the math.floor(a/b) case, the result is calculated with floating point arithmetic (IEEE-754 64-bit), which means there is a maximum precision. The quotient you have there is larger than the 253 limit above which floating point is no longer accurate up to the unit.



                With the integer division however, Python uses its unlimited integer range, and so that result is correct.






                share|improve this answer
























                  7












                  7








                  7






                  The reason the quotients in your test case are not equal is that in the math.floor(a/b) case, the result is calculated with floating point arithmetic (IEEE-754 64-bit), which means there is a maximum precision. The quotient you have there is larger than the 253 limit above which floating point is no longer accurate up to the unit.



                  With the integer division however, Python uses its unlimited integer range, and so that result is correct.






                  share|improve this answer












                  The reason the quotients in your test case are not equal is that in the math.floor(a/b) case, the result is calculated with floating point arithmetic (IEEE-754 64-bit), which means there is a maximum precision. The quotient you have there is larger than the 253 limit above which floating point is no longer accurate up to the unit.



                  With the integer division however, Python uses its unlimited integer range, and so that result is correct.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 3 hours ago









                  trincot

                  116k1478109




                  116k1478109

























                      2














                      You may be dealing with integral values that are too large to express exactly as floats. Your number is significantly larger than 2^53, which is where the gaps between adjacent floating point doubles start to get bigger than 1. So you lose some precision when doing the floating point division.



                      The integer division, on the other hand, is computed exactly.






                      share|improve this answer


























                        2














                        You may be dealing with integral values that are too large to express exactly as floats. Your number is significantly larger than 2^53, which is where the gaps between adjacent floating point doubles start to get bigger than 1. So you lose some precision when doing the floating point division.



                        The integer division, on the other hand, is computed exactly.






                        share|improve this answer
























                          2












                          2








                          2






                          You may be dealing with integral values that are too large to express exactly as floats. Your number is significantly larger than 2^53, which is where the gaps between adjacent floating point doubles start to get bigger than 1. So you lose some precision when doing the floating point division.



                          The integer division, on the other hand, is computed exactly.






                          share|improve this answer












                          You may be dealing with integral values that are too large to express exactly as floats. Your number is significantly larger than 2^53, which is where the gaps between adjacent floating point doubles start to get bigger than 1. So you lose some precision when doing the floating point division.



                          The integer division, on the other hand, is computed exactly.







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 3 hours ago









                          interfect

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