How to split a string argument in a bash over multiple lines without adding space
Imagine I'm running the following command:
some_command --flag "foo
bar
quux" arg2
This causes the string to be passed as footbartquux.
I'm looking for a way to have this argument passed without being tab characters (or other whitespace characters added) while keeping the indentation (to make my script readable).
What would help me achieve this cleanly?
bash
asked 8 mins ago
Ahmet Alp BalkanAhmet Alp Balkan
1666
add a comment |
Imagine I'm running the following command:
some_command --flag "foo
bar
quux" arg2
This causes the string to be passed as footbartquux.
I'm looking for a way to have this argument passed without being tab characters (or other whitespace characters added) while keeping the indentation (to make my script readable).
What would help me achieve this cleanly?
bash
asked 8 mins ago
Ahmet Alp BalkanAhmet Alp Balkan
1666
add a comment |
Imagine I'm running the following command:
some_command --flag "foo
bar
quux" arg2
This causes the string to be passed as footbartquux.
I'm looking for a way to have this argument passed without being tab characters (or other whitespace characters added) while keeping the indentation (to make my script readable).
What would help me achieve this cleanly?
bash
asked 8 mins ago
Ahmet Alp BalkanAhmet Alp Balkan
1666
Imagine I'm running the following command:
some_command --flag "foo
bar
quux" arg2
This causes the string to be passed as footbartquux.
I'm looking for a way to have this argument passed without being tab characters (or other whitespace characters added) while keeping the indentation (to make my script readable).
What would help me achieve this cleanly?
bash
bash
asked 8 mins ago
Ahmet Alp BalkanAhmet Alp Balkan
1666
asked 8 mins ago
Ahmet Alp BalkanAhmet Alp Balkan
1666
asked 8 mins ago
Ahmet Alp BalkanAhmet Alp Balkan
1666
asked 8 mins ago
Ahmet Alp BalkanAhmet Alp Balkan
1666
asked 8 mins ago
Ahmet Alp BalkanAhmet Alp Balkan
1666
1666
add a comment |
add a comment |
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