How to grep for a particular string?












0















I am trying to get a string that matches the following pattern: starts with foo and finishes with bar.



grep -e "^foo*bar$"









share|improve this question


















  • 2





    o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

    – steeldriver
    2 hours ago











  • Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

    – Bionix1441
    2 hours ago











  • But you missed the point!

    – A.B
    2 hours ago











  • Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

    – Bionix1441
    2 hours ago











  • Well the point is actually a dot. A wild guess? Should I tell it before?

    – A.B
    2 hours ago
















0















I am trying to get a string that matches the following pattern: starts with foo and finishes with bar.



grep -e "^foo*bar$"









share|improve this question


















  • 2





    o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

    – steeldriver
    2 hours ago











  • Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

    – Bionix1441
    2 hours ago











  • But you missed the point!

    – A.B
    2 hours ago











  • Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

    – Bionix1441
    2 hours ago











  • Well the point is actually a dot. A wild guess? Should I tell it before?

    – A.B
    2 hours ago














0












0








0








I am trying to get a string that matches the following pattern: starts with foo and finishes with bar.



grep -e "^foo*bar$"









share|improve this question














I am trying to get a string that matches the following pattern: starts with foo and finishes with bar.



grep -e "^foo*bar$"






grep regular-expression






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 2 hours ago









Bionix1441Bionix1441

17113




17113








  • 2





    o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

    – steeldriver
    2 hours ago











  • Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

    – Bionix1441
    2 hours ago











  • But you missed the point!

    – A.B
    2 hours ago











  • Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

    – Bionix1441
    2 hours ago











  • Well the point is actually a dot. A wild guess? Should I tell it before?

    – A.B
    2 hours ago














  • 2





    o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

    – steeldriver
    2 hours ago











  • Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

    – Bionix1441
    2 hours ago











  • But you missed the point!

    – A.B
    2 hours ago











  • Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

    – Bionix1441
    2 hours ago











  • Well the point is actually a dot. A wild guess? Should I tell it before?

    – A.B
    2 hours ago








2




2





o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

– steeldriver
2 hours ago





o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

– steeldriver
2 hours ago













Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

– Bionix1441
2 hours ago





Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

– Bionix1441
2 hours ago













But you missed the point!

– A.B
2 hours ago





But you missed the point!

– A.B
2 hours ago













Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

– Bionix1441
2 hours ago





Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

– Bionix1441
2 hours ago













Well the point is actually a dot. A wild guess? Should I tell it before?

– A.B
2 hours ago





Well the point is actually a dot. A wild guess? Should I tell it before?

– A.B
2 hours ago










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