difference between echo ($x) and a=“($x)”; echo $a












0















When I execute the following in terminal:



x=1
a=($x)

echo $a #output: 1
echo ($x) #output: -bash: syntax error near unexpected token `$x'


Why are above outputs different?
Also why are the following 2 outputs different:



$(echo foo) #output: -bash: foo: command not found
(echo foo) #output: foo


P.S.: I am new to shell scripting and trying to understand command substitution: $(command)









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    0















    When I execute the following in terminal:



    x=1
    a=($x)

    echo $a #output: 1
    echo ($x) #output: -bash: syntax error near unexpected token `$x'


    Why are above outputs different?
    Also why are the following 2 outputs different:



    $(echo foo) #output: -bash: foo: command not found
    (echo foo) #output: foo


    P.S.: I am new to shell scripting and trying to understand command substitution: $(command)









    share







    New contributor




    Sunny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0








      When I execute the following in terminal:



      x=1
      a=($x)

      echo $a #output: 1
      echo ($x) #output: -bash: syntax error near unexpected token `$x'


      Why are above outputs different?
      Also why are the following 2 outputs different:



      $(echo foo) #output: -bash: foo: command not found
      (echo foo) #output: foo


      P.S.: I am new to shell scripting and trying to understand command substitution: $(command)









      share







      New contributor




      Sunny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      When I execute the following in terminal:



      x=1
      a=($x)

      echo $a #output: 1
      echo ($x) #output: -bash: syntax error near unexpected token `$x'


      Why are above outputs different?
      Also why are the following 2 outputs different:



      $(echo foo) #output: -bash: foo: command not found
      (echo foo) #output: foo


      P.S.: I am new to shell scripting and trying to understand command substitution: $(command)







      bash shell scripting command-substitution





      share







      New contributor




      Sunny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Sunny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






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      Sunny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 5 mins ago









      SunnySunny

      1




      1




      New contributor




      Sunny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      New contributor





      Sunny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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