Just Twice Is Nice












3














Let's have string multiplication to take a string and a positive number and concatenate that string that many times. In Haskell:



0 * s = ""

n * s = s ++ ((n - 1) * s)


Your task is to write a program that outputs a number $n > 0$. When you double your program (with the described procedure) the new program should output $2n$. When your program is tripled or quadrupled it should once again output the original $n$.



This is code-golf so your answers will be scored in bytes with fewer bytes being better.




Related, Related.






code-golf source-layout







share|improve this question


















  • 4




    All the solutions so far are trivial modifications of solutions to existing challenges so I wouldn't be surprised to see this dupe-hammered by someone.
    – Shaggy
    4 hours ago
















3














Let's have string multiplication to take a string and a positive number and concatenate that string that many times. In Haskell:



0 * s = ""

n * s = s ++ ((n - 1) * s)


Your task is to write a program that outputs a number $n > 0$. When you double your program (with the described procedure) the new program should output $2n$. When your program is tripled or quadrupled it should once again output the original $n$.



This is code-golf so your answers will be scored in bytes with fewer bytes being better.




Related, Related.






code-golf source-layout







share|improve this question


















  • 4




    All the solutions so far are trivial modifications of solutions to existing challenges so I wouldn't be surprised to see this dupe-hammered by someone.
    – Shaggy
    4 hours ago














3












3








3







Let's have string multiplication to take a string and a positive number and concatenate that string that many times. In Haskell:



0 * s = ""

n * s = s ++ ((n - 1) * s)


Your task is to write a program that outputs a number $n > 0$. When you double your program (with the described procedure) the new program should output $2n$. When your program is tripled or quadrupled it should once again output the original $n$.



This is code-golf so your answers will be scored in bytes with fewer bytes being better.




Related, Related.






code-golf source-layout







share|improve this question













Let's have string multiplication to take a string and a positive number and concatenate that string that many times. In Haskell:



0 * s = ""

n * s = s ++ ((n - 1) * s)


Your task is to write a program that outputs a number $n > 0$. When you double your program (with the described procedure) the new program should output $2n$. When your program is tripled or quadrupled it should once again output the original $n$.



This is code-golf so your answers will be scored in bytes with fewer bytes being better.




Related, Related.






code-golf source-layout




code-golf source-layout






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 6 hours ago









Post Left Garf Hunter

33.9k10156365




33.9k10156365








  • 4




    All the solutions so far are trivial modifications of solutions to existing challenges so I wouldn't be surprised to see this dupe-hammered by someone.
    – Shaggy
    4 hours ago














  • 4




    All the solutions so far are trivial modifications of solutions to existing challenges so I wouldn't be surprised to see this dupe-hammered by someone.
    – Shaggy
    4 hours ago








4




4




All the solutions so far are trivial modifications of solutions to existing challenges so I wouldn't be surprised to see this dupe-hammered by someone.
– Shaggy
4 hours ago




All the solutions so far are trivial modifications of solutions to existing challenges so I wouldn't be surprised to see this dupe-hammered by someone.
– Shaggy
4 hours ago










5 Answers
5






active

oldest

votes


















2















R, 27 25 bytes





1+!1-length(readLines())


Try it online!



Inspired by rturnbull's answer to Third time the charm, but the simplicity of the check makes it shorter.



Doubled | Tripled | Quadrupled



Why this works:



readLines() will actually reads the source file itself rather than stdin. Hence, adding lines just increments the length() of the vector returned by readLines(). Therefore, we compute !(1-length()) to obtain 1 whenever length()==1 and 0 when length()!=1, adding one to have the desired effect.






share|improve this answer































    1















    MATL, 9 bytes



    vxHQXH4=Q


    Uses n = 1.



    Try it online! Original, doubled, tripled, quadrupled.



    Explanation



    This uses clipboard H to store state information. Function H pastes the clipboard contents onto the stack. Function XH copies the top of the stack into the clipboard. The clipboard initially contains the number 2.



    Each time the snippet vxHQXH4=Q is run it does the following.
    The stack contents, if any, are deleted (vx). The clipboard contents are pushed (H) and incremented (Q), and the result is copied back into the clipboard (XH). This gives 4 the second time, and only that time.



    The number in the stack is tested for equality with 4 (4=) and incremented (Q). This gives 2 for 4 (second time), and 1 otherwise (any other time).






    share|improve this answer































      0















      Charcoal, 10 bytes



      ＰＩ⊕⁼²Ｌ⊞Ｏυω


      Try it online! Based on my answer to I double the source, you double the output! but compares the length to 2. Try it doubled. Try it tripled. Try it quadrupled. In verbose syntax this is Multiprint(Cast(Incremented(Equals(2, Length(PushOperator(u, w)))))));.






      share|improve this answer





























        0















        Python 2, 9 bytes



        Outputs via exit code. Full credit goes to Anders Kaseorg for this answer to I double the source, you double the output!.





        ';exit(2)


        Try it online! | Doubled | Tripled | Quadrupled



        Regularly, this raises a Syntax Error because the string is not closed properly and exists with exit code 1, then, when doubled, it becomes ';exit(2)';exit(2) which simply exits with code 2 because the string literal is now quoted properly and has no effect at all, and when repeated any other arbitrary number of times, it raises Syntax Errors.






        share|improve this answer





























          0















          Runic Enchantments, 29 bytes



          ^w '
          
/1@ 3
          
/ ~!4
          
2'51w
          
/yyy


          Try it online!



          Slight alteration from the Third Times A Charm entry, using Jo King's compressed version and swapping the two reflection locations.



          Twice



          Thrice



          And frice for good measure.






          share|improve this answer























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            5 Answers
            5






            active

            oldest

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            5 Answers
            5






            active

            oldest

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            active

            oldest

            votes






            active

            oldest

            votes









            2















            R, 27 25 bytes





            1+!1-length(readLines())


            Try it online!



            Inspired by rturnbull's answer to Third time the charm, but the simplicity of the check makes it shorter.



            Doubled | Tripled | Quadrupled



            Why this works:



            readLines() will actually reads the source file itself rather than stdin. Hence, adding lines just increments the length() of the vector returned by readLines(). Therefore, we compute !(1-length()) to obtain 1 whenever length()==1 and 0 when length()!=1, adding one to have the desired effect.






            share|improve this answer




























              2















              R, 27 25 bytes





              1+!1-length(readLines())


              Try it online!



              Inspired by rturnbull's answer to Third time the charm, but the simplicity of the check makes it shorter.



              Doubled | Tripled | Quadrupled



              Why this works:



              readLines() will actually reads the source file itself rather than stdin. Hence, adding lines just increments the length() of the vector returned by readLines(). Therefore, we compute !(1-length()) to obtain 1 whenever length()==1 and 0 when length()!=1, adding one to have the desired effect.






              share|improve this answer


























                2












                2








                2







                R, 27 25 bytes





                1+!1-length(readLines())


                Try it online!



                Inspired by rturnbull's answer to Third time the charm, but the simplicity of the check makes it shorter.



                Doubled | Tripled | Quadrupled



                Why this works:



                readLines() will actually reads the source file itself rather than stdin. Hence, adding lines just increments the length() of the vector returned by readLines(). Therefore, we compute !(1-length()) to obtain 1 whenever length()==1 and 0 when length()!=1, adding one to have the desired effect.






                share|improve this answer















                R, 27 25 bytes





                1+!1-length(readLines())


                Try it online!



                Inspired by rturnbull's answer to Third time the charm, but the simplicity of the check makes it shorter.



                Doubled | Tripled | Quadrupled



                Why this works:



                readLines() will actually reads the source file itself rather than stdin. Hence, adding lines just increments the length() of the vector returned by readLines(). Therefore, we compute !(1-length()) to obtain 1 whenever length()==1 and 0 when length()!=1, adding one to have the desired effect.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 5 hours ago

























                answered 5 hours ago









                Giuseppe

                16.5k31052




                16.5k31052























                    1















                    MATL, 9 bytes



                    vxHQXH4=Q


                    Uses n = 1.



                    Try it online! Original, doubled, tripled, quadrupled.



                    Explanation



                    This uses clipboard H to store state information. Function H pastes the clipboard contents onto the stack. Function XH copies the top of the stack into the clipboard. The clipboard initially contains the number 2.



                    Each time the snippet vxHQXH4=Q is run it does the following.
                    The stack contents, if any, are deleted (vx). The clipboard contents are pushed (H) and incremented (Q), and the result is copied back into the clipboard (XH). This gives 4 the second time, and only that time.



                    The number in the stack is tested for equality with 4 (4=) and incremented (Q). This gives 2 for 4 (second time), and 1 otherwise (any other time).






                    share|improve this answer




























                      1















                      MATL, 9 bytes



                      vxHQXH4=Q


                      Uses n = 1.



                      Try it online! Original, doubled, tripled, quadrupled.



                      Explanation



                      This uses clipboard H to store state information. Function H pastes the clipboard contents onto the stack. Function XH copies the top of the stack into the clipboard. The clipboard initially contains the number 2.



                      Each time the snippet vxHQXH4=Q is run it does the following.
                      The stack contents, if any, are deleted (vx). The clipboard contents are pushed (H) and incremented (Q), and the result is copied back into the clipboard (XH). This gives 4 the second time, and only that time.



                      The number in the stack is tested for equality with 4 (4=) and incremented (Q). This gives 2 for 4 (second time), and 1 otherwise (any other time).






                      share|improve this answer


























                        1












                        1








                        1







                        MATL, 9 bytes



                        vxHQXH4=Q


                        Uses n = 1.



                        Try it online! Original, doubled, tripled, quadrupled.



                        Explanation



                        This uses clipboard H to store state information. Function H pastes the clipboard contents onto the stack. Function XH copies the top of the stack into the clipboard. The clipboard initially contains the number 2.



                        Each time the snippet vxHQXH4=Q is run it does the following.
                        The stack contents, if any, are deleted (vx). The clipboard contents are pushed (H) and incremented (Q), and the result is copied back into the clipboard (XH). This gives 4 the second time, and only that time.



                        The number in the stack is tested for equality with 4 (4=) and incremented (Q). This gives 2 for 4 (second time), and 1 otherwise (any other time).






                        share|improve this answer















                        MATL, 9 bytes



                        vxHQXH4=Q


                        Uses n = 1.



                        Try it online! Original, doubled, tripled, quadrupled.



                        Explanation



                        This uses clipboard H to store state information. Function H pastes the clipboard contents onto the stack. Function XH copies the top of the stack into the clipboard. The clipboard initially contains the number 2.



                        Each time the snippet vxHQXH4=Q is run it does the following.
                        The stack contents, if any, are deleted (vx). The clipboard contents are pushed (H) and incremented (Q), and the result is copied back into the clipboard (XH). This gives 4 the second time, and only that time.



                        The number in the stack is tested for equality with 4 (4=) and incremented (Q). This gives 2 for 4 (second time), and 1 otherwise (any other time).







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited 3 hours ago

























                        answered 4 hours ago









                        Luis Mendo

                        73.9k886291




                        73.9k886291























                            0















                            Charcoal, 10 bytes



                            ＰＩ⊕⁼²Ｌ⊞Ｏυω


                            Try it online! Based on my answer to I double the source, you double the output! but compares the length to 2. Try it doubled. Try it tripled. Try it quadrupled. In verbose syntax this is Multiprint(Cast(Incremented(Equals(2, Length(PushOperator(u, w)))))));.






                            share|improve this answer


























                              0















                              Charcoal, 10 bytes



                              ＰＩ⊕⁼²Ｌ⊞Ｏυω


                              Try it online! Based on my answer to I double the source, you double the output! but compares the length to 2. Try it doubled. Try it tripled. Try it quadrupled. In verbose syntax this is Multiprint(Cast(Incremented(Equals(2, Length(PushOperator(u, w)))))));.






                              share|improve this answer
























                                0












                                0








                                0







                                Charcoal, 10 bytes



                                ＰＩ⊕⁼²Ｌ⊞Ｏυω


                                Try it online! Based on my answer to I double the source, you double the output! but compares the length to 2. Try it doubled. Try it tripled. Try it quadrupled. In verbose syntax this is Multiprint(Cast(Incremented(Equals(2, Length(PushOperator(u, w)))))));.






                                share|improve this answer













                                Charcoal, 10 bytes



                                ＰＩ⊕⁼²Ｌ⊞Ｏυω


                                Try it online! Based on my answer to I double the source, you double the output! but compares the length to 2. Try it doubled. Try it tripled. Try it quadrupled. In verbose syntax this is Multiprint(Cast(Incremented(Equals(2, Length(PushOperator(u, w)))))));.







                                share|improve this answer












                                share|improve this answer



                                share|improve this answer










                                answered 5 hours ago









                                Neil

                                79k744175




                                79k744175























                                    0















                                    Python 2, 9 bytes



                                    Outputs via exit code. Full credit goes to Anders Kaseorg for this answer to I double the source, you double the output!.





                                    ';exit(2)


                                    Try it online! | Doubled | Tripled | Quadrupled



                                    Regularly, this raises a Syntax Error because the string is not closed properly and exists with exit code 1, then, when doubled, it becomes ';exit(2)';exit(2) which simply exits with code 2 because the string literal is now quoted properly and has no effect at all, and when repeated any other arbitrary number of times, it raises Syntax Errors.






                                    share|improve this answer


























                                      0















                                      Python 2, 9 bytes



                                      Outputs via exit code. Full credit goes to Anders Kaseorg for this answer to I double the source, you double the output!.





                                      ';exit(2)


                                      Try it online! | Doubled | Tripled | Quadrupled



                                      Regularly, this raises a Syntax Error because the string is not closed properly and exists with exit code 1, then, when doubled, it becomes ';exit(2)';exit(2) which simply exits with code 2 because the string literal is now quoted properly and has no effect at all, and when repeated any other arbitrary number of times, it raises Syntax Errors.






                                      share|improve this answer
























                                        0












                                        0








                                        0







                                        Python 2, 9 bytes



                                        Outputs via exit code. Full credit goes to Anders Kaseorg for this answer to I double the source, you double the output!.





                                        ';exit(2)


                                        Try it online! | Doubled | Tripled | Quadrupled



                                        Regularly, this raises a Syntax Error because the string is not closed properly and exists with exit code 1, then, when doubled, it becomes ';exit(2)';exit(2) which simply exits with code 2 because the string literal is now quoted properly and has no effect at all, and when repeated any other arbitrary number of times, it raises Syntax Errors.






                                        share|improve this answer













                                        Python 2, 9 bytes



                                        Outputs via exit code. Full credit goes to Anders Kaseorg for this answer to I double the source, you double the output!.





                                        ';exit(2)


                                        Try it online! | Doubled | Tripled | Quadrupled



                                        Regularly, this raises a Syntax Error because the string is not closed properly and exists with exit code 1, then, when doubled, it becomes ';exit(2)';exit(2) which simply exits with code 2 because the string literal is now quoted properly and has no effect at all, and when repeated any other arbitrary number of times, it raises Syntax Errors.







                                        share|improve this answer












                                        share|improve this answer



                                        share|improve this answer










                                        answered 5 hours ago









                                        Mr. Xcoder

                                        31.4k759198




                                        31.4k759198























                                            0















                                            Runic Enchantments, 29 bytes



                                            ^w '
                                            
/1@ 3
                                            
/ ~!4
                                            
2'51w
                                            
/yyy


                                            Try it online!



                                            Slight alteration from the Third Times A Charm entry, using Jo King's compressed version and swapping the two reflection locations.



                                            Twice



                                            Thrice



                                            And frice for good measure.






                                            share|improve this answer




























                                              0















                                              Runic Enchantments, 29 bytes



                                              ^w '
                                              
/1@ 3
                                              
/ ~!4
                                              
2'51w
                                              
/yyy


                                              Try it online!



                                              Slight alteration from the Third Times A Charm entry, using Jo King's compressed version and swapping the two reflection locations.



                                              Twice



                                              Thrice



                                              And frice for good measure.






                                              share|improve this answer


























                                                0












                                                0








                                                0







                                                Runic Enchantments, 29 bytes



                                                ^w '
                                                
/1@ 3
                                                
/ ~!4
                                                
2'51w
                                                
/yyy


                                                Try it online!



                                                Slight alteration from the Third Times A Charm entry, using Jo King's compressed version and swapping the two reflection locations.



                                                Twice



                                                Thrice



                                                And frice for good measure.






                                                share|improve this answer















                                                Runic Enchantments, 29 bytes



                                                ^w '
                                                
/1@ 3
                                                
/ ~!4
                                                
2'51w
                                                
/yyy


                                                Try it online!



                                                Slight alteration from the Third Times A Charm entry, using Jo King's compressed version and swapping the two reflection locations.



                                                Twice



                                                Thrice



                                                And frice for good measure.







                                                share|improve this answer














                                                share|improve this answer



                                                share|improve this answer








                                                edited 2 hours ago

























                                                answered 5 hours ago









                                                Draco18s

                                                1,226618




                                                1,226618






























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                                                    この記事は検証可能な参考文献や出典が全く示されていないか、不十分です。 出典を追加して記事の信頼性向上にご協力ください。 （ 2019年1月 ） 「 サソリ 」のその他の用法については「サソリ (曖昧さ回避)」をご覧ください。 「 スコーピオン 」と「 スコルピオン 」はこの項目へ転送されています。その他の用法については「スコーピオン」をご覧ください。 サソリ目 生息年代: 430–0 Ma PreЄ Є O S D C P T J K Pg N シルル紀前期-現世 ダイオウサソリ（ Pandinus Imperator ） 分類 界 : 動物界 Animalia 門 : 節足動物門 Arthropoda 亜門 : 鋏角亜門 Chelicerata 綱 : クモガタ綱 Arachnida 目 : サソリ目 Scorpiones 学名 Scorpiones C. L. Koch, 1837 英名 Scorpion 上科 Pseudochactoidea キョクトウサソリ上科 Buthoidea Chaeriloidea Chactoidea Iuroidea Scorpionoidea サソリ （ サソリ類 、 蠍 、 蝎 、 scorpion ）は、鋏角亜門・クモガタ綱の サソリ目 （ Scorpiones ）に属する節足動物の総称である。体の前端に鋏型の触肢、後端に毒針を有する捕食者である。 1700種以上を含め、最古の化石記録は4億3千万年前のシルル紀まで遡る。有毒生物として広く知られるが、人間の命にかかわる毒を持つものはごく一部の種類に過ぎない。 目次 1 形態 1.1 前体 1.2 後体 1.2.1 中体 1.2.2 終体 2 雌雄 3 生態 3.1 天敵 3.2 生殖 4 分布 5 毒 6 蛍光現象 7 分類
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                                                    広島県道265号伴広島線

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                                                    一般県道 広島県道265号伴広島線 路線延長 km 起点 広島県広島市安佐南区伴東7丁目 終点 広島県広島市中区榎町 接続する 主な道路 （記法） 広島県道38号広島豊平線 広島県道71号広島湯来線 山陽自動車道五日市IC 国道183号（ 国道261号重複） ■テンプレート（■ノート ■使い方） ■PJ道路 広島県道265号伴広島線 （ひろしまけんどう265ごう ともひろしません）は広島県広島市安佐南区から広島県広島市中区を結ぶ一般県道である。 目次 1 路線データ 2 通過する自治体 3 見どころ 4 接続道路 4.1 本線 4.2 旧道 5 別名 6 関連項目 路線データ 本線 起点：広島市安佐南区伴東7丁目・大原下橋南詰交差点（広島県道38号広島豊平線（本線・旧道）交点） 終点：広島市中区榎町・十日市交差点（国道183号（国道261号重用）交点） 総延長： 旧道 起点：広島市安佐南区伴東4丁目・新細坂交差点（広島県道38号広島豊平線交点） 終点：広島市安佐南区伴中央4丁目・寺組橋(南)交差点（広島県道265号伴広島線（本線）交点） 総延長： 通過する自治体 広島県 広島市（安佐南区、佐伯区、西区、中区） 見どころ 広島高速交通広島新交通1号線（アストラムライン） 広島広域公園 広島広域公園陸上競技場（広島ビッグアーチ） 己斐峠 己斐橋（太田川放水路） 天満橋（天満川） 接続道路 本線 広島県道38号広島豊平線（本線・旧道）（広島市安佐南区伴東7丁目・大原下橋南詰交差点〔起点〕） 広島県道71号広島湯来線（本線）（広島市安佐南区伴中央2丁目・伴交番入口交差点 - 広島市安佐南区伴中央4丁目・寺組橋(南)交差点間で重用） 広島県道71号広島湯来線（旧道）（広島県道265号伴広島線（旧道）重用）（広島市安佐南区伴中央4丁目・寺組橋(南)交差点） 広島県道71号広島湯来線（広島市安佐南区伴中央4丁目・寺組橋(南)交差点 - 広島市佐伯区五日市町石内・五月が丘(南)交差点間で重用）
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                                                    Setup Asymptote in Texstudio

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                                                    0 Good time of the day! I am trying to compile the following file: documentclass[12pt]{article} usepackage[inline]{asymptote} begin{document} Here is a venn diagram produced with Asymptote, drawn to width 4cm: defA{A} defB{V{B}} begin{figure} begin{center} begin{asy} size(4cm,0); pen colour1=red; pen colour2=green; pair z0=(0,0); pair z1=(-1,0); pair z2=(1,0); real r=1.5; path c1=circle(z1,r); path c2=circle(z2,r); fill(c1,colour1); fill(c2,colour2); picture intersection=new picture; fill(intersection,c1,colour1+colour2); clip(intersection,c2); add(intersection); draw(c1); draw(c2); //draw("$A$",box,z1)
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