Encode the date in Christmas Eve format












7














The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be 



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.






code-golf string date







share|improve this question
























  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 2




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    3 hours ago
















7














The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be 



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.






code-golf string date







share|improve this question
























  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 2




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    3 hours ago














7












7








7







The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be 



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.






code-golf string date







share|improve this question















The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be 



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.






code-golf string date




code-golf string date






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 53 mins ago

























asked 4 hours ago









PyRulez

3,34742054




3,34742054












  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 2




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    3 hours ago


















  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 2




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    3 hours ago
















Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
– Black Owl Kai
4 hours ago




Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
– Black Owl Kai
4 hours ago












@BlackOwlKai what cartoon?
– PyRulez
4 hours ago




@BlackOwlKai what cartoon?
– PyRulez
4 hours ago




2




2




A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
– Black Owl Kai
4 hours ago




A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
– Black Owl Kai
4 hours ago












@BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
– PyRulez
4 hours ago




@BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
– PyRulez
4 hours ago












You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
– Sparr
3 hours ago




You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
– Sparr
3 hours ago










2 Answers
2






active

oldest

votes


















2















R, 112 106 bytes





function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


Try it online!



Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



Pick the non-negative one and cat "Christmas" with that many "Eves".






share|improve this answer























  • You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    1 hour ago










  • Also would z[z>=0][1] work instead of min?
    – Giuseppe
    1 hour ago



















0















Perl 6, 61 bytes



say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


Try it online!



Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






share|improve this answer





















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    2 Answers
    2






    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer























    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      1 hour ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      1 hour ago
















    2















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer























    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      1 hour ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      1 hour ago














    2












    2








    2







    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 1 hour ago

























    answered 1 hour ago









    ngm

    3,21924




    3,21924












    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      1 hour ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      1 hour ago


















    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      1 hour ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      1 hour ago
















    You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    1 hour ago




    You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    1 hour ago












    Also would z[z>=0][1] work instead of min?
    – Giuseppe
    1 hour ago




    Also would z[z>=0][1] work instead of min?
    – Giuseppe
    1 hour ago











    0















    Perl 6, 61 bytes



    say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


    Try it online!



    Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






    share|improve this answer


























      0















      Perl 6, 61 bytes



      say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


      Try it online!



      Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






      share|improve this answer
























        0












        0








        0







        Perl 6, 61 bytes



        say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


        Try it online!



        Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






        share|improve this answer













        Perl 6, 61 bytes



        say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


        Try it online!



        Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 33 mins ago









        Sean

        3,28636




        3,28636






























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            サソリ

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            この記事は検証可能な参考文献や出典が全く示されていないか、不十分です。 出典を追加して記事の信頼性向上にご協力ください。 （ 2019年1月 ） 「 サソリ 」のその他の用法については「サソリ (曖昧さ回避)」をご覧ください。 「 スコーピオン 」と「 スコルピオン 」はこの項目へ転送されています。その他の用法については「スコーピオン」をご覧ください。 サソリ目 生息年代: 430–0 Ma PreЄ Є O S D C P T J K Pg N シルル紀前期-現世 ダイオウサソリ（ Pandinus Imperator ） 分類 界 : 動物界 Animalia 門 : 節足動物門 Arthropoda 亜門 : 鋏角亜門 Chelicerata 綱 : クモガタ綱 Arachnida 目 : サソリ目 Scorpiones 学名 Scorpiones C. L. Koch, 1837 英名 Scorpion 上科 Pseudochactoidea キョクトウサソリ上科 Buthoidea Chaeriloidea Chactoidea Iuroidea Scorpionoidea サソリ （ サソリ類 、 蠍 、 蝎 、 scorpion ）は、鋏角亜門・クモガタ綱の サソリ目 （ Scorpiones ）に属する節足動物の総称である。体の前端に鋏型の触肢、後端に毒針を有する捕食者である。 1700種以上を含め、最古の化石記録は4億3千万年前のシルル紀まで遡る。有毒生物として広く知られるが、人間の命にかかわる毒を持つものはごく一部の種類に過ぎない。 目次 1 形態 1.1 前体 1.2 後体 1.2.1 中体 1.2.2 終体 2 雌雄 3 生態 3.1 天敵 3.2 生殖 4 分布 5 毒 6 蛍光現象 7 分類
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            広島県道265号伴広島線

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            一般県道 広島県道265号伴広島線 路線延長 km 起点 広島県広島市安佐南区伴東7丁目 終点 広島県広島市中区榎町 接続する 主な道路 （記法） 広島県道38号広島豊平線 広島県道71号広島湯来線 山陽自動車道五日市IC 国道183号（ 国道261号重複） ■テンプレート（■ノート ■使い方） ■PJ道路 広島県道265号伴広島線 （ひろしまけんどう265ごう ともひろしません）は広島県広島市安佐南区から広島県広島市中区を結ぶ一般県道である。 目次 1 路線データ 2 通過する自治体 3 見どころ 4 接続道路 4.1 本線 4.2 旧道 5 別名 6 関連項目 路線データ 本線 起点：広島市安佐南区伴東7丁目・大原下橋南詰交差点（広島県道38号広島豊平線（本線・旧道）交点） 終点：広島市中区榎町・十日市交差点（国道183号（国道261号重用）交点） 総延長： 旧道 起点：広島市安佐南区伴東4丁目・新細坂交差点（広島県道38号広島豊平線交点） 終点：広島市安佐南区伴中央4丁目・寺組橋(南)交差点（広島県道265号伴広島線（本線）交点） 総延長： 通過する自治体 広島県 広島市（安佐南区、佐伯区、西区、中区） 見どころ 広島高速交通広島新交通1号線（アストラムライン） 広島広域公園 広島広域公園陸上競技場（広島ビッグアーチ） 己斐峠 己斐橋（太田川放水路） 天満橋（天満川） 接続道路 本線 広島県道38号広島豊平線（本線・旧道）（広島市安佐南区伴東7丁目・大原下橋南詰交差点〔起点〕） 広島県道71号広島湯来線（本線）（広島市安佐南区伴中央2丁目・伴交番入口交差点 - 広島市安佐南区伴中央4丁目・寺組橋(南)交差点間で重用） 広島県道71号広島湯来線（旧道）（広島県道265号伴広島線（旧道）重用）（広島市安佐南区伴中央4丁目・寺組橋(南)交差点） 広島県道71号広島湯来線（広島市安佐南区伴中央4丁目・寺組橋(南)交差点 - 広島市佐伯区五日市町石内・五月が丘(南)交差点間で重用）
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            Setup Asymptote in Texstudio

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            0 Good time of the day! I am trying to compile the following file: documentclass[12pt]{article} usepackage[inline]{asymptote} begin{document} Here is a venn diagram produced with Asymptote, drawn to width 4cm: defA{A} defB{V{B}} begin{figure} begin{center} begin{asy} size(4cm,0); pen colour1=red; pen colour2=green; pair z0=(0,0); pair z1=(-1,0); pair z2=(1,0); real r=1.5; path c1=circle(z1,r); path c2=circle(z2,r); fill(c1,colour1); fill(c2,colour2); picture intersection=new picture; fill(intersection,c1,colour1+colour2); clip(intersection,c2); add(intersection); draw(c1); draw(c2); //draw("$A$",box,z1)
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