What can you think of for the harmonic series?











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Background



When I attempt questions in real analysis, frequently I encounter the following expression like harmonic series:



$$1+frac{1}{2} + frac{1}{3} + dots + frac{1}{n}$$



To my surprise when I arrive at something like this ,the solution book does not give me a closed-form of this expression.



Question



So my question is a simple one. What can you think of for this series? And besides the fact that it does not converge is it related to any mathematics that you know? And most importantly, does it have a closed-form?










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  • 1




    It is divergent .....
    – neelkanth
    30 mins ago






  • 1




    Look out for the Euler-Mascheroni constant $gamma$ if you want to explore the mathematical content behind your question. The sum is asymptotically $ln n + gamma$. The error term can be analysed.
    – Mark Bennet
    29 mins ago










  • OP probably meant to say "does not converge," since it's like the most well-known fact about the series.
    – Eevee Trainer
    29 mins ago










  • @neelkanth the typo is corrected
    – hephaes
    14 mins ago















up vote
1
down vote

favorite












Background



When I attempt questions in real analysis, frequently I encounter the following expression like harmonic series:



$$1+frac{1}{2} + frac{1}{3} + dots + frac{1}{n}$$



To my surprise when I arrive at something like this ,the solution book does not give me a closed-form of this expression.



Question



So my question is a simple one. What can you think of for this series? And besides the fact that it does not converge is it related to any mathematics that you know? And most importantly, does it have a closed-form?










share|cite|improve this question




















  • 1




    It is divergent .....
    – neelkanth
    30 mins ago






  • 1




    Look out for the Euler-Mascheroni constant $gamma$ if you want to explore the mathematical content behind your question. The sum is asymptotically $ln n + gamma$. The error term can be analysed.
    – Mark Bennet
    29 mins ago










  • OP probably meant to say "does not converge," since it's like the most well-known fact about the series.
    – Eevee Trainer
    29 mins ago










  • @neelkanth the typo is corrected
    – hephaes
    14 mins ago













up vote
1
down vote

favorite









up vote
1
down vote

favorite











Background



When I attempt questions in real analysis, frequently I encounter the following expression like harmonic series:



$$1+frac{1}{2} + frac{1}{3} + dots + frac{1}{n}$$



To my surprise when I arrive at something like this ,the solution book does not give me a closed-form of this expression.



Question



So my question is a simple one. What can you think of for this series? And besides the fact that it does not converge is it related to any mathematics that you know? And most importantly, does it have a closed-form?










share|cite|improve this question















Background



When I attempt questions in real analysis, frequently I encounter the following expression like harmonic series:



$$1+frac{1}{2} + frac{1}{3} + dots + frac{1}{n}$$



To my surprise when I arrive at something like this ,the solution book does not give me a closed-form of this expression.



Question



So my question is a simple one. What can you think of for this series? And besides the fact that it does not converge is it related to any mathematics that you know? And most importantly, does it have a closed-form?







real-analysis number-theory harmonic-numbers






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share|cite|improve this question













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share|cite|improve this question








edited 14 mins ago

























asked 40 mins ago









hephaes

1617




1617








  • 1




    It is divergent .....
    – neelkanth
    30 mins ago






  • 1




    Look out for the Euler-Mascheroni constant $gamma$ if you want to explore the mathematical content behind your question. The sum is asymptotically $ln n + gamma$. The error term can be analysed.
    – Mark Bennet
    29 mins ago










  • OP probably meant to say "does not converge," since it's like the most well-known fact about the series.
    – Eevee Trainer
    29 mins ago










  • @neelkanth the typo is corrected
    – hephaes
    14 mins ago














  • 1




    It is divergent .....
    – neelkanth
    30 mins ago






  • 1




    Look out for the Euler-Mascheroni constant $gamma$ if you want to explore the mathematical content behind your question. The sum is asymptotically $ln n + gamma$. The error term can be analysed.
    – Mark Bennet
    29 mins ago










  • OP probably meant to say "does not converge," since it's like the most well-known fact about the series.
    – Eevee Trainer
    29 mins ago










  • @neelkanth the typo is corrected
    – hephaes
    14 mins ago








1




1




It is divergent .....
– neelkanth
30 mins ago




It is divergent .....
– neelkanth
30 mins ago




1




1




Look out for the Euler-Mascheroni constant $gamma$ if you want to explore the mathematical content behind your question. The sum is asymptotically $ln n + gamma$. The error term can be analysed.
– Mark Bennet
29 mins ago




Look out for the Euler-Mascheroni constant $gamma$ if you want to explore the mathematical content behind your question. The sum is asymptotically $ln n + gamma$. The error term can be analysed.
– Mark Bennet
29 mins ago












OP probably meant to say "does not converge," since it's like the most well-known fact about the series.
– Eevee Trainer
29 mins ago




OP probably meant to say "does not converge," since it's like the most well-known fact about the series.
– Eevee Trainer
29 mins ago












@neelkanth the typo is corrected
– hephaes
14 mins ago




@neelkanth the typo is corrected
– hephaes
14 mins ago










3 Answers
3






active

oldest

votes

















up vote
5
down vote













The harmonic series diverges, which is somewhat surprising because each term tends to zero as $ntoinfty$. However, the problem is that each term does not tend to zero fast enough.



A function which generalises this series is the Riemann zeta function $$zeta(s)=sum_{n=1}^inftyfrac{1}{n^s}$$
Which converges for $text{Re}(s)>1$. For example,



$$zeta(2)=frac{pi^2}{6}.$$



Euler gave a general formula for $zeta(2n)$ in terms of the Bernoulli numbers, but no closed form is known yet for odd arguments.



It can also be analytically continued to $mathbb{C}setminus{1}$. There is a singularity ar $s=1$.



Zeros of this function lie on the negative even integers (the trivial zeros), whereas the non trivial (purely complex) zeros are all known to lie in the critical strip. In fact it is hypothesised that they all lie on the critical line $s=1/2+it$, which you may know is called the Riemann Hypothesis. If true, this has big implications concerning the distribution of the primes, and many conjectured theorems in Analytic Number Theory.



Coming back to "$zeta(1)$" for a moment, as mentioned in the other answer, it pops up in the definition of Euler's gamma constant,



$$gamma=lim_{ntoinfty}sum_{k=1}^nfrac{1}{k}-log n,$$



where $gamma$ constant with



$$gammaapprox
0.57721566490...$$



It is not yet known whether $gamma$ is irrational, unlike $zeta(2n)$, and also $zeta(3)$ which was proved to be irrational by Apéry.






share|cite|improve this answer






























    up vote
    3
    down vote













    If I remember correctly, there is a sort of closed form:



    $$1 + frac{1}{2} + frac{1}{3} + frac{1}{4} + ... + frac{1}{n} = sum_{k=1}^n frac{1}{k} = ln(n) + gamma + epsilon_k$$



    $epsilon_k$ in this constant is a constant proportional to $1/2k$, and thus $epsilon_k to 0$ as $k to infty$.



    $gamma$ denotes the Euler-Mascheroni constant, defined by the limiting difference between the natural logarithm and the harmonic series, i.e.



    $${displaystyle {begin{aligned}gamma &=lim _{nto infty }left(-ln n+sum _{k=1}^{n}{frac {1}{k}}right)\[5px]end{aligned}}}$$



    Granted, I don't think this is really in line with what you want because ... well, it's sort of like a self-referential thing. "Oh, the harmonic series is given by a function, an error constant, and this special constant that comes from the difference from the series and that other function under certain conditions." It's mostly a personal thing so it doesn't mesh quite well with me?



    Beyond that I don't really have anything to offer - specifically with relations of the series to mathematics I know - that I wouldn't just be regurgitating from Wikipedia. Weirdly it hasn't popped up much in my coursework thus far.






    share|cite|improve this answer




























      up vote
      0
      down vote













      It diverges because, if you look at the partial sums, $s_{2n}-s_n=frac1{2n}+frac1{2n-1}+cdots+frac1{n+1}ge ncdot frac1{2n}=frac12,,forall n$. Thus it isn't Cauchy.






      share|cite|improve this answer























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        3 Answers
        3






        active

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        3 Answers
        3






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        active

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        up vote
        5
        down vote













        The harmonic series diverges, which is somewhat surprising because each term tends to zero as $ntoinfty$. However, the problem is that each term does not tend to zero fast enough.



        A function which generalises this series is the Riemann zeta function $$zeta(s)=sum_{n=1}^inftyfrac{1}{n^s}$$
        Which converges for $text{Re}(s)>1$. For example,



        $$zeta(2)=frac{pi^2}{6}.$$



        Euler gave a general formula for $zeta(2n)$ in terms of the Bernoulli numbers, but no closed form is known yet for odd arguments.



        It can also be analytically continued to $mathbb{C}setminus{1}$. There is a singularity ar $s=1$.



        Zeros of this function lie on the negative even integers (the trivial zeros), whereas the non trivial (purely complex) zeros are all known to lie in the critical strip. In fact it is hypothesised that they all lie on the critical line $s=1/2+it$, which you may know is called the Riemann Hypothesis. If true, this has big implications concerning the distribution of the primes, and many conjectured theorems in Analytic Number Theory.



        Coming back to "$zeta(1)$" for a moment, as mentioned in the other answer, it pops up in the definition of Euler's gamma constant,



        $$gamma=lim_{ntoinfty}sum_{k=1}^nfrac{1}{k}-log n,$$



        where $gamma$ constant with



        $$gammaapprox
        0.57721566490...$$



        It is not yet known whether $gamma$ is irrational, unlike $zeta(2n)$, and also $zeta(3)$ which was proved to be irrational by Apéry.






        share|cite|improve this answer



























          up vote
          5
          down vote













          The harmonic series diverges, which is somewhat surprising because each term tends to zero as $ntoinfty$. However, the problem is that each term does not tend to zero fast enough.



          A function which generalises this series is the Riemann zeta function $$zeta(s)=sum_{n=1}^inftyfrac{1}{n^s}$$
          Which converges for $text{Re}(s)>1$. For example,



          $$zeta(2)=frac{pi^2}{6}.$$



          Euler gave a general formula for $zeta(2n)$ in terms of the Bernoulli numbers, but no closed form is known yet for odd arguments.



          It can also be analytically continued to $mathbb{C}setminus{1}$. There is a singularity ar $s=1$.



          Zeros of this function lie on the negative even integers (the trivial zeros), whereas the non trivial (purely complex) zeros are all known to lie in the critical strip. In fact it is hypothesised that they all lie on the critical line $s=1/2+it$, which you may know is called the Riemann Hypothesis. If true, this has big implications concerning the distribution of the primes, and many conjectured theorems in Analytic Number Theory.



          Coming back to "$zeta(1)$" for a moment, as mentioned in the other answer, it pops up in the definition of Euler's gamma constant,



          $$gamma=lim_{ntoinfty}sum_{k=1}^nfrac{1}{k}-log n,$$



          where $gamma$ constant with



          $$gammaapprox
          0.57721566490...$$



          It is not yet known whether $gamma$ is irrational, unlike $zeta(2n)$, and also $zeta(3)$ which was proved to be irrational by Apéry.






          share|cite|improve this answer

























            up vote
            5
            down vote










            up vote
            5
            down vote









            The harmonic series diverges, which is somewhat surprising because each term tends to zero as $ntoinfty$. However, the problem is that each term does not tend to zero fast enough.



            A function which generalises this series is the Riemann zeta function $$zeta(s)=sum_{n=1}^inftyfrac{1}{n^s}$$
            Which converges for $text{Re}(s)>1$. For example,



            $$zeta(2)=frac{pi^2}{6}.$$



            Euler gave a general formula for $zeta(2n)$ in terms of the Bernoulli numbers, but no closed form is known yet for odd arguments.



            It can also be analytically continued to $mathbb{C}setminus{1}$. There is a singularity ar $s=1$.



            Zeros of this function lie on the negative even integers (the trivial zeros), whereas the non trivial (purely complex) zeros are all known to lie in the critical strip. In fact it is hypothesised that they all lie on the critical line $s=1/2+it$, which you may know is called the Riemann Hypothesis. If true, this has big implications concerning the distribution of the primes, and many conjectured theorems in Analytic Number Theory.



            Coming back to "$zeta(1)$" for a moment, as mentioned in the other answer, it pops up in the definition of Euler's gamma constant,



            $$gamma=lim_{ntoinfty}sum_{k=1}^nfrac{1}{k}-log n,$$



            where $gamma$ constant with



            $$gammaapprox
            0.57721566490...$$



            It is not yet known whether $gamma$ is irrational, unlike $zeta(2n)$, and also $zeta(3)$ which was proved to be irrational by Apéry.






            share|cite|improve this answer














            The harmonic series diverges, which is somewhat surprising because each term tends to zero as $ntoinfty$. However, the problem is that each term does not tend to zero fast enough.



            A function which generalises this series is the Riemann zeta function $$zeta(s)=sum_{n=1}^inftyfrac{1}{n^s}$$
            Which converges for $text{Re}(s)>1$. For example,



            $$zeta(2)=frac{pi^2}{6}.$$



            Euler gave a general formula for $zeta(2n)$ in terms of the Bernoulli numbers, but no closed form is known yet for odd arguments.



            It can also be analytically continued to $mathbb{C}setminus{1}$. There is a singularity ar $s=1$.



            Zeros of this function lie on the negative even integers (the trivial zeros), whereas the non trivial (purely complex) zeros are all known to lie in the critical strip. In fact it is hypothesised that they all lie on the critical line $s=1/2+it$, which you may know is called the Riemann Hypothesis. If true, this has big implications concerning the distribution of the primes, and many conjectured theorems in Analytic Number Theory.



            Coming back to "$zeta(1)$" for a moment, as mentioned in the other answer, it pops up in the definition of Euler's gamma constant,



            $$gamma=lim_{ntoinfty}sum_{k=1}^nfrac{1}{k}-log n,$$



            where $gamma$ constant with



            $$gammaapprox
            0.57721566490...$$



            It is not yet known whether $gamma$ is irrational, unlike $zeta(2n)$, and also $zeta(3)$ which was proved to be irrational by Apéry.







            share|cite|improve this answer














            share|cite|improve this answer



            share|cite|improve this answer








            edited 3 mins ago

























            answered 31 mins ago









            Antinous

            5,62542051




            5,62542051






















                up vote
                3
                down vote













                If I remember correctly, there is a sort of closed form:



                $$1 + frac{1}{2} + frac{1}{3} + frac{1}{4} + ... + frac{1}{n} = sum_{k=1}^n frac{1}{k} = ln(n) + gamma + epsilon_k$$



                $epsilon_k$ in this constant is a constant proportional to $1/2k$, and thus $epsilon_k to 0$ as $k to infty$.



                $gamma$ denotes the Euler-Mascheroni constant, defined by the limiting difference between the natural logarithm and the harmonic series, i.e.



                $${displaystyle {begin{aligned}gamma &=lim _{nto infty }left(-ln n+sum _{k=1}^{n}{frac {1}{k}}right)\[5px]end{aligned}}}$$



                Granted, I don't think this is really in line with what you want because ... well, it's sort of like a self-referential thing. "Oh, the harmonic series is given by a function, an error constant, and this special constant that comes from the difference from the series and that other function under certain conditions." It's mostly a personal thing so it doesn't mesh quite well with me?



                Beyond that I don't really have anything to offer - specifically with relations of the series to mathematics I know - that I wouldn't just be regurgitating from Wikipedia. Weirdly it hasn't popped up much in my coursework thus far.






                share|cite|improve this answer

























                  up vote
                  3
                  down vote













                  If I remember correctly, there is a sort of closed form:



                  $$1 + frac{1}{2} + frac{1}{3} + frac{1}{4} + ... + frac{1}{n} = sum_{k=1}^n frac{1}{k} = ln(n) + gamma + epsilon_k$$



                  $epsilon_k$ in this constant is a constant proportional to $1/2k$, and thus $epsilon_k to 0$ as $k to infty$.



                  $gamma$ denotes the Euler-Mascheroni constant, defined by the limiting difference between the natural logarithm and the harmonic series, i.e.



                  $${displaystyle {begin{aligned}gamma &=lim _{nto infty }left(-ln n+sum _{k=1}^{n}{frac {1}{k}}right)\[5px]end{aligned}}}$$



                  Granted, I don't think this is really in line with what you want because ... well, it's sort of like a self-referential thing. "Oh, the harmonic series is given by a function, an error constant, and this special constant that comes from the difference from the series and that other function under certain conditions." It's mostly a personal thing so it doesn't mesh quite well with me?



                  Beyond that I don't really have anything to offer - specifically with relations of the series to mathematics I know - that I wouldn't just be regurgitating from Wikipedia. Weirdly it hasn't popped up much in my coursework thus far.






                  share|cite|improve this answer























                    up vote
                    3
                    down vote










                    up vote
                    3
                    down vote









                    If I remember correctly, there is a sort of closed form:



                    $$1 + frac{1}{2} + frac{1}{3} + frac{1}{4} + ... + frac{1}{n} = sum_{k=1}^n frac{1}{k} = ln(n) + gamma + epsilon_k$$



                    $epsilon_k$ in this constant is a constant proportional to $1/2k$, and thus $epsilon_k to 0$ as $k to infty$.



                    $gamma$ denotes the Euler-Mascheroni constant, defined by the limiting difference between the natural logarithm and the harmonic series, i.e.



                    $${displaystyle {begin{aligned}gamma &=lim _{nto infty }left(-ln n+sum _{k=1}^{n}{frac {1}{k}}right)\[5px]end{aligned}}}$$



                    Granted, I don't think this is really in line with what you want because ... well, it's sort of like a self-referential thing. "Oh, the harmonic series is given by a function, an error constant, and this special constant that comes from the difference from the series and that other function under certain conditions." It's mostly a personal thing so it doesn't mesh quite well with me?



                    Beyond that I don't really have anything to offer - specifically with relations of the series to mathematics I know - that I wouldn't just be regurgitating from Wikipedia. Weirdly it hasn't popped up much in my coursework thus far.






                    share|cite|improve this answer












                    If I remember correctly, there is a sort of closed form:



                    $$1 + frac{1}{2} + frac{1}{3} + frac{1}{4} + ... + frac{1}{n} = sum_{k=1}^n frac{1}{k} = ln(n) + gamma + epsilon_k$$



                    $epsilon_k$ in this constant is a constant proportional to $1/2k$, and thus $epsilon_k to 0$ as $k to infty$.



                    $gamma$ denotes the Euler-Mascheroni constant, defined by the limiting difference between the natural logarithm and the harmonic series, i.e.



                    $${displaystyle {begin{aligned}gamma &=lim _{nto infty }left(-ln n+sum _{k=1}^{n}{frac {1}{k}}right)\[5px]end{aligned}}}$$



                    Granted, I don't think this is really in line with what you want because ... well, it's sort of like a self-referential thing. "Oh, the harmonic series is given by a function, an error constant, and this special constant that comes from the difference from the series and that other function under certain conditions." It's mostly a personal thing so it doesn't mesh quite well with me?



                    Beyond that I don't really have anything to offer - specifically with relations of the series to mathematics I know - that I wouldn't just be regurgitating from Wikipedia. Weirdly it hasn't popped up much in my coursework thus far.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered 30 mins ago









                    Eevee Trainer

                    1,869216




                    1,869216






















                        up vote
                        0
                        down vote













                        It diverges because, if you look at the partial sums, $s_{2n}-s_n=frac1{2n}+frac1{2n-1}+cdots+frac1{n+1}ge ncdot frac1{2n}=frac12,,forall n$. Thus it isn't Cauchy.






                        share|cite|improve this answer



























                          up vote
                          0
                          down vote













                          It diverges because, if you look at the partial sums, $s_{2n}-s_n=frac1{2n}+frac1{2n-1}+cdots+frac1{n+1}ge ncdot frac1{2n}=frac12,,forall n$. Thus it isn't Cauchy.






                          share|cite|improve this answer

























                            up vote
                            0
                            down vote










                            up vote
                            0
                            down vote









                            It diverges because, if you look at the partial sums, $s_{2n}-s_n=frac1{2n}+frac1{2n-1}+cdots+frac1{n+1}ge ncdot frac1{2n}=frac12,,forall n$. Thus it isn't Cauchy.






                            share|cite|improve this answer














                            It diverges because, if you look at the partial sums, $s_{2n}-s_n=frac1{2n}+frac1{2n-1}+cdots+frac1{n+1}ge ncdot frac1{2n}=frac12,,forall n$. Thus it isn't Cauchy.







                            share|cite|improve this answer














                            share|cite|improve this answer



                            share|cite|improve this answer








                            edited 7 mins ago

























                            answered 16 mins ago









                            Chris Custer

                            9,5303624




                            9,5303624






























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