Unable to print * (star) value with echo











up vote
0
down vote

favorite












I have,



my.sh



while IFS= read -r line ; do

v1="$line";

t1=`echo $line | awk -F= '{print $2}'`

echo "$t1"

done < $1


sample.txt



say=hello

test=0 0/15 * * * ?

logs=valuelogs


Output :



[root@centos gen]# ./my.sh test.txt

hello

0 0/15 hello.txt 2.txt tmp.log my.sh sample.txt test.sh test.txt hello.txt 

2.txt tmp.log my.sh sample.txt test.sh test.txt hello.txt 2.txt tmp.log 

my.sh sample.txt test.sh test.txt ?

valuelogs


Here we get bad output due to executed command like echo * & its give list of file on current directory as output.



Is there any alternative solution for same ?






linux bash shell-script centos







share|improve this question






















  • Related: When is double-quoting necessary?
    – Kusalananda
    yesterday















up vote
0
down vote

favorite












I have,



my.sh



while IFS= read -r line ; do

v1="$line";

t1=`echo $line | awk -F= '{print $2}'`

echo "$t1"

done < $1


sample.txt



say=hello

test=0 0/15 * * * ?

logs=valuelogs


Output :



[root@centos gen]# ./my.sh test.txt

hello

0 0/15 hello.txt 2.txt tmp.log my.sh sample.txt test.sh test.txt hello.txt 

2.txt tmp.log my.sh sample.txt test.sh test.txt hello.txt 2.txt tmp.log 

my.sh sample.txt test.sh test.txt ?

valuelogs


Here we get bad output due to executed command like echo * & its give list of file on current directory as output.



Is there any alternative solution for same ?






linux bash shell-script centos







share|improve this question






















  • Related: When is double-quoting necessary?
    – Kusalananda
    yesterday













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have,



my.sh



while IFS= read -r line ; do

v1="$line";

t1=`echo $line | awk -F= '{print $2}'`

echo "$t1"

done < $1


sample.txt



say=hello

test=0 0/15 * * * ?

logs=valuelogs


Output :



[root@centos gen]# ./my.sh test.txt

hello

0 0/15 hello.txt 2.txt tmp.log my.sh sample.txt test.sh test.txt hello.txt 

2.txt tmp.log my.sh sample.txt test.sh test.txt hello.txt 2.txt tmp.log 

my.sh sample.txt test.sh test.txt ?

valuelogs


Here we get bad output due to executed command like echo * & its give list of file on current directory as output.



Is there any alternative solution for same ?






linux bash shell-script centos







share|improve this question













I have,



my.sh



while IFS= read -r line ; do

v1="$line";

t1=`echo $line | awk -F= '{print $2}'`

echo "$t1"

done < $1


sample.txt



say=hello

test=0 0/15 * * * ?

logs=valuelogs


Output :



[root@centos gen]# ./my.sh test.txt

hello

0 0/15 hello.txt 2.txt tmp.log my.sh sample.txt test.sh test.txt hello.txt 

2.txt tmp.log my.sh sample.txt test.sh test.txt hello.txt 2.txt tmp.log 

my.sh sample.txt test.sh test.txt ?

valuelogs


Here we get bad output due to executed command like echo * & its give list of file on current directory as output.



Is there any alternative solution for same ?






linux bash shell-script centos




linux bash shell-script centos






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked yesterday









Nullpointer

2571416




2571416












  • Related: When is double-quoting necessary?
    – Kusalananda
    yesterday


















  • Related: When is double-quoting necessary?
    – Kusalananda
    yesterday
















Related: When is double-quoting necessary?
– Kusalananda
yesterday




Related: When is double-quoting necessary?
– Kusalananda
yesterday










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










The problem is in the echo $line inside the back quotes. Double quote the variable to prevent wildcard expansion:



t1=`echo "$line" | awk -F= '{print $2}'`





share|improve this answer





















  • Thanks Bro, It's work for me
    – Nullpointer
    yesterday


















up vote
2
down vote













You can rewrite your shell script as



awk -F= '{print $2}' "$1"


and avoid all the shell handling entirely (apart from the single quotes here and the $1 parameter expansion which you want anyway); or even as an AWK script



#!/usr/bin/awk -f



BEGIN { FS="=" }



{ print $2 }





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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote



    accepted










    The problem is in the echo $line inside the back quotes. Double quote the variable to prevent wildcard expansion:



    t1=`echo "$line" | awk -F= '{print $2}'`





    share|improve this answer





















    • Thanks Bro, It's work for me
      – Nullpointer
      yesterday















    up vote
    3
    down vote



    accepted










    The problem is in the echo $line inside the back quotes. Double quote the variable to prevent wildcard expansion:



    t1=`echo "$line" | awk -F= '{print $2}'`





    share|improve this answer





















    • Thanks Bro, It's work for me
      – Nullpointer
      yesterday













    up vote
    3
    down vote



    accepted







    up vote
    3
    down vote



    accepted






    The problem is in the echo $line inside the back quotes. Double quote the variable to prevent wildcard expansion:



    t1=`echo "$line" | awk -F= '{print $2}'`





    share|improve this answer












    The problem is in the echo $line inside the back quotes. Double quote the variable to prevent wildcard expansion:



    t1=`echo "$line" | awk -F= '{print $2}'`






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered yesterday









    choroba

    26.2k44672




    26.2k44672












    • Thanks Bro, It's work for me
      – Nullpointer
      yesterday


















    • Thanks Bro, It's work for me
      – Nullpointer
      yesterday
















    Thanks Bro, It's work for me
    – Nullpointer
    yesterday




    Thanks Bro, It's work for me
    – Nullpointer
    yesterday












    up vote
    2
    down vote













    You can rewrite your shell script as



    awk -F= '{print $2}' "$1"


    and avoid all the shell handling entirely (apart from the single quotes here and the $1 parameter expansion which you want anyway); or even as an AWK script



    #!/usr/bin/awk -f
    

    
BEGIN { FS="=" }
    

    
{ print $2 }





    share|improve this answer



























      up vote
      2
      down vote













      You can rewrite your shell script as



      awk -F= '{print $2}' "$1"


      and avoid all the shell handling entirely (apart from the single quotes here and the $1 parameter expansion which you want anyway); or even as an AWK script



      #!/usr/bin/awk -f
      

      
BEGIN { FS="=" }
      

      
{ print $2 }





      share|improve this answer

























        up vote
        2
        down vote










        up vote
        2
        down vote









        You can rewrite your shell script as



        awk -F= '{print $2}' "$1"


        and avoid all the shell handling entirely (apart from the single quotes here and the $1 parameter expansion which you want anyway); or even as an AWK script



        #!/usr/bin/awk -f
        

        
BEGIN { FS="=" }
        

        
{ print $2 }





        share|improve this answer














        You can rewrite your shell script as



        awk -F= '{print $2}' "$1"


        and avoid all the shell handling entirely (apart from the single quotes here and the $1 parameter expansion which you want anyway); or even as an AWK script



        #!/usr/bin/awk -f
        

        
BEGIN { FS="=" }
        

        
{ print $2 }






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited yesterday

























        answered yesterday









        Stephen Kitt

        162k24360438




        162k24360438






























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