Temperature coefficient MOSFET vs. temperature coefficient of BJT












2














If you use transistors for an amplifier scheme, you want to make sure that when you parallel devices, you don't start to conduct more current if your transistors heat up.



I know that when using MOSFETs you always have negative feedback. If one takes more current, it will heat up more, and therefore the resistance will become bigger, and you will conduct less.



When using a BJT the device that dissipates the most current, will heat up most and will start conducting even more. This is unsafe and to solve this I always place a small resistance in series with the emitter.



But what is the physical explanation that in a MOSFET you have this positive temperature coefficient and in a BJT you have this negative coefficient?










share|improve this question





























    2














    If you use transistors for an amplifier scheme, you want to make sure that when you parallel devices, you don't start to conduct more current if your transistors heat up.



    I know that when using MOSFETs you always have negative feedback. If one takes more current, it will heat up more, and therefore the resistance will become bigger, and you will conduct less.



    When using a BJT the device that dissipates the most current, will heat up most and will start conducting even more. This is unsafe and to solve this I always place a small resistance in series with the emitter.



    But what is the physical explanation that in a MOSFET you have this positive temperature coefficient and in a BJT you have this negative coefficient?










    share|improve this question



























      2












      2








      2







      If you use transistors for an amplifier scheme, you want to make sure that when you parallel devices, you don't start to conduct more current if your transistors heat up.



      I know that when using MOSFETs you always have negative feedback. If one takes more current, it will heat up more, and therefore the resistance will become bigger, and you will conduct less.



      When using a BJT the device that dissipates the most current, will heat up most and will start conducting even more. This is unsafe and to solve this I always place a small resistance in series with the emitter.



      But what is the physical explanation that in a MOSFET you have this positive temperature coefficient and in a BJT you have this negative coefficient?










      share|improve this question















      If you use transistors for an amplifier scheme, you want to make sure that when you parallel devices, you don't start to conduct more current if your transistors heat up.



      I know that when using MOSFETs you always have negative feedback. If one takes more current, it will heat up more, and therefore the resistance will become bigger, and you will conduct less.



      When using a BJT the device that dissipates the most current, will heat up most and will start conducting even more. This is unsafe and to solve this I always place a small resistance in series with the emitter.



      But what is the physical explanation that in a MOSFET you have this positive temperature coefficient and in a BJT you have this negative coefficient?







      mosfet amplifier bjt temperature parallel






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 53 mins ago









      Peter Mortensen

      1,58031422




      1,58031422










      asked 4 hours ago









      J. Joly

      113




      113






















          1 Answer
          1






          active

          oldest

          votes


















          3














          I do not know the answer to your question about physic behind this.



          But your statement about MOSFET temperature coefficient is only true when MOSFET work as a switch.



          In linear region (saturation) most MOSFET will have as a negative temperature coefficient as BJT have.



          And in general terms, the MOSFET can have negative, positive and zero temperature coefficient.
          And we can see this on Transfer characteristic Id=f(Vgs) in the datasheet.



          enter image description here



          More here



          https://www.infineon.com/dgdl/Infineon-ApplicationNote_Linear_Mode_Operation_Safe_Operation_Diagram_MOSFETs-AN-v01_00-EN.pdf?fileId=db3a30433e30e4bf013e3646e9381200



          https://www.onsemi.com/pub/Collateral/AND8199-D.PDF






          share|improve this answer





















          • okay good sidenote that I didn't know. Thanks, I'll keep this in mind! I was talking about an amplifier circuit, so as you mentioned I was using the MOSFET as a switch. But still have to keep your comment in mind! Thanks!
            – J. Joly
            4 hours ago










          • Related: electronics.stackexchange.com/a/357641/17387
            – try-catch-finally
            4 hours ago






          • 1




            @J.Joly Are you building a class D amplifier?
            – G36
            3 hours ago










          • I'm not building it, I'm trying to analyse it. MOSFET power amplifier
            – J. Joly
            3 hours ago








          • 3




            That schematic shows a linear (not switching) amplifier so you are NOT using the MOSFET as a switch.
            – Brian Drummond
            2 hours ago











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3














          I do not know the answer to your question about physic behind this.



          But your statement about MOSFET temperature coefficient is only true when MOSFET work as a switch.



          In linear region (saturation) most MOSFET will have as a negative temperature coefficient as BJT have.



          And in general terms, the MOSFET can have negative, positive and zero temperature coefficient.
          And we can see this on Transfer characteristic Id=f(Vgs) in the datasheet.



          enter image description here



          More here



          https://www.infineon.com/dgdl/Infineon-ApplicationNote_Linear_Mode_Operation_Safe_Operation_Diagram_MOSFETs-AN-v01_00-EN.pdf?fileId=db3a30433e30e4bf013e3646e9381200



          https://www.onsemi.com/pub/Collateral/AND8199-D.PDF






          share|improve this answer





















          • okay good sidenote that I didn't know. Thanks, I'll keep this in mind! I was talking about an amplifier circuit, so as you mentioned I was using the MOSFET as a switch. But still have to keep your comment in mind! Thanks!
            – J. Joly
            4 hours ago










          • Related: electronics.stackexchange.com/a/357641/17387
            – try-catch-finally
            4 hours ago






          • 1




            @J.Joly Are you building a class D amplifier?
            – G36
            3 hours ago










          • I'm not building it, I'm trying to analyse it. MOSFET power amplifier
            – J. Joly
            3 hours ago








          • 3




            That schematic shows a linear (not switching) amplifier so you are NOT using the MOSFET as a switch.
            – Brian Drummond
            2 hours ago
















          3














          I do not know the answer to your question about physic behind this.



          But your statement about MOSFET temperature coefficient is only true when MOSFET work as a switch.



          In linear region (saturation) most MOSFET will have as a negative temperature coefficient as BJT have.



          And in general terms, the MOSFET can have negative, positive and zero temperature coefficient.
          And we can see this on Transfer characteristic Id=f(Vgs) in the datasheet.



          enter image description here



          More here



          https://www.infineon.com/dgdl/Infineon-ApplicationNote_Linear_Mode_Operation_Safe_Operation_Diagram_MOSFETs-AN-v01_00-EN.pdf?fileId=db3a30433e30e4bf013e3646e9381200



          https://www.onsemi.com/pub/Collateral/AND8199-D.PDF






          share|improve this answer





















          • okay good sidenote that I didn't know. Thanks, I'll keep this in mind! I was talking about an amplifier circuit, so as you mentioned I was using the MOSFET as a switch. But still have to keep your comment in mind! Thanks!
            – J. Joly
            4 hours ago










          • Related: electronics.stackexchange.com/a/357641/17387
            – try-catch-finally
            4 hours ago






          • 1




            @J.Joly Are you building a class D amplifier?
            – G36
            3 hours ago










          • I'm not building it, I'm trying to analyse it. MOSFET power amplifier
            – J. Joly
            3 hours ago








          • 3




            That schematic shows a linear (not switching) amplifier so you are NOT using the MOSFET as a switch.
            – Brian Drummond
            2 hours ago














          3












          3








          3






          I do not know the answer to your question about physic behind this.



          But your statement about MOSFET temperature coefficient is only true when MOSFET work as a switch.



          In linear region (saturation) most MOSFET will have as a negative temperature coefficient as BJT have.



          And in general terms, the MOSFET can have negative, positive and zero temperature coefficient.
          And we can see this on Transfer characteristic Id=f(Vgs) in the datasheet.



          enter image description here



          More here



          https://www.infineon.com/dgdl/Infineon-ApplicationNote_Linear_Mode_Operation_Safe_Operation_Diagram_MOSFETs-AN-v01_00-EN.pdf?fileId=db3a30433e30e4bf013e3646e9381200



          https://www.onsemi.com/pub/Collateral/AND8199-D.PDF






          share|improve this answer












          I do not know the answer to your question about physic behind this.



          But your statement about MOSFET temperature coefficient is only true when MOSFET work as a switch.



          In linear region (saturation) most MOSFET will have as a negative temperature coefficient as BJT have.



          And in general terms, the MOSFET can have negative, positive and zero temperature coefficient.
          And we can see this on Transfer characteristic Id=f(Vgs) in the datasheet.



          enter image description here



          More here



          https://www.infineon.com/dgdl/Infineon-ApplicationNote_Linear_Mode_Operation_Safe_Operation_Diagram_MOSFETs-AN-v01_00-EN.pdf?fileId=db3a30433e30e4bf013e3646e9381200



          https://www.onsemi.com/pub/Collateral/AND8199-D.PDF







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 4 hours ago









          G36

          4,9051511




          4,9051511












          • okay good sidenote that I didn't know. Thanks, I'll keep this in mind! I was talking about an amplifier circuit, so as you mentioned I was using the MOSFET as a switch. But still have to keep your comment in mind! Thanks!
            – J. Joly
            4 hours ago










          • Related: electronics.stackexchange.com/a/357641/17387
            – try-catch-finally
            4 hours ago






          • 1




            @J.Joly Are you building a class D amplifier?
            – G36
            3 hours ago










          • I'm not building it, I'm trying to analyse it. MOSFET power amplifier
            – J. Joly
            3 hours ago








          • 3




            That schematic shows a linear (not switching) amplifier so you are NOT using the MOSFET as a switch.
            – Brian Drummond
            2 hours ago


















          • okay good sidenote that I didn't know. Thanks, I'll keep this in mind! I was talking about an amplifier circuit, so as you mentioned I was using the MOSFET as a switch. But still have to keep your comment in mind! Thanks!
            – J. Joly
            4 hours ago










          • Related: electronics.stackexchange.com/a/357641/17387
            – try-catch-finally
            4 hours ago






          • 1




            @J.Joly Are you building a class D amplifier?
            – G36
            3 hours ago










          • I'm not building it, I'm trying to analyse it. MOSFET power amplifier
            – J. Joly
            3 hours ago








          • 3




            That schematic shows a linear (not switching) amplifier so you are NOT using the MOSFET as a switch.
            – Brian Drummond
            2 hours ago
















          okay good sidenote that I didn't know. Thanks, I'll keep this in mind! I was talking about an amplifier circuit, so as you mentioned I was using the MOSFET as a switch. But still have to keep your comment in mind! Thanks!
          – J. Joly
          4 hours ago




          okay good sidenote that I didn't know. Thanks, I'll keep this in mind! I was talking about an amplifier circuit, so as you mentioned I was using the MOSFET as a switch. But still have to keep your comment in mind! Thanks!
          – J. Joly
          4 hours ago












          Related: electronics.stackexchange.com/a/357641/17387
          – try-catch-finally
          4 hours ago




          Related: electronics.stackexchange.com/a/357641/17387
          – try-catch-finally
          4 hours ago




          1




          1




          @J.Joly Are you building a class D amplifier?
          – G36
          3 hours ago




          @J.Joly Are you building a class D amplifier?
          – G36
          3 hours ago












          I'm not building it, I'm trying to analyse it. MOSFET power amplifier
          – J. Joly
          3 hours ago






          I'm not building it, I'm trying to analyse it. MOSFET power amplifier
          – J. Joly
          3 hours ago






          3




          3




          That schematic shows a linear (not switching) amplifier so you are NOT using the MOSFET as a switch.
          – Brian Drummond
          2 hours ago




          That schematic shows a linear (not switching) amplifier so you are NOT using the MOSFET as a switch.
          – Brian Drummond
          2 hours ago


















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