How to count the number of instances of a certain process by canonical path (with arguments)?
Let's say I run the following commands:
sleep 500
/bin/sleep 500
sleep 30
What I'm interested is, how to count the number of instances of the sleep program, with certain arguments (in this case the only argument is 500).
So in the example above, if I count the number of instances of /bin/sleep 500, it should return 2.
I tried this: pgrep -xfc '/bin/sleep 500', but since it exactly matched the argument in the parenthesis, sleep 500 isn't counted.
ps
edited 8 mins ago
Rui F Ribeiro
40.1k1479136
asked May 25 '16 at 16:29
mythicmythic
1435
add a comment |
Let's say I run the following commands:
sleep 500
/bin/sleep 500
sleep 30
What I'm interested is, how to count the number of instances of the sleep program, with certain arguments (in this case the only argument is 500).
So in the example above, if I count the number of instances of /bin/sleep 500, it should return 2.
I tried this: pgrep -xfc '/bin/sleep 500', but since it exactly matched the argument in the parenthesis, sleep 500 isn't counted.
ps
edited 8 mins ago
Rui F Ribeiro
40.1k1479136
asked May 25 '16 at 16:29
mythicmythic
1435
Are you running a system with a/procfilesystem? That makes it easier to find the pathname of each process's executable.
– Mark Plotnick
May 25 '16 at 18:13
@MarkPlotnick Yes, I am
– mythic
May 25 '16 at 18:49
add a comment |
Let's say I run the following commands:
sleep 500
/bin/sleep 500
sleep 30
What I'm interested is, how to count the number of instances of the sleep program, with certain arguments (in this case the only argument is 500).
So in the example above, if I count the number of instances of /bin/sleep 500, it should return 2.
I tried this: pgrep -xfc '/bin/sleep 500', but since it exactly matched the argument in the parenthesis, sleep 500 isn't counted.
ps
edited 8 mins ago
Rui F Ribeiro
40.1k1479136
asked May 25 '16 at 16:29
mythicmythic
1435
Let's say I run the following commands:
sleep 500
/bin/sleep 500
sleep 30
What I'm interested is, how to count the number of instances of the sleep program, with certain arguments (in this case the only argument is 500).
So in the example above, if I count the number of instances of /bin/sleep 500, it should return 2.
I tried this: pgrep -xfc '/bin/sleep 500', but since it exactly matched the argument in the parenthesis, sleep 500 isn't counted.
ps
ps
edited 8 mins ago
Rui F Ribeiro
40.1k1479136
asked May 25 '16 at 16:29
mythicmythic
1435
edited 8 mins ago
Rui F Ribeiro
40.1k1479136
asked May 25 '16 at 16:29
mythicmythic
1435
edited 8 mins ago
Rui F Ribeiro
40.1k1479136
edited 8 mins ago
Rui F Ribeiro
40.1k1479136
edited 8 mins ago
Rui F Ribeiro
40.1k1479136
40.1k1479136
asked May 25 '16 at 16:29
mythicmythic
1435
asked May 25 '16 at 16:29
mythicmythic
1435
asked May 25 '16 at 16:29
mythicmythic
1435
1435
Are you running a system with a/procfilesystem? That makes it easier to find the pathname of each process's executable.
– Mark Plotnick
May 25 '16 at 18:13
@MarkPlotnick Yes, I am
– mythic
May 25 '16 at 18:49
add a comment |
Are you running a system with a/procfilesystem? That makes it easier to find the pathname of each process's executable.
– Mark Plotnick
May 25 '16 at 18:13
@MarkPlotnick Yes, I am
– mythic
May 25 '16 at 18:49
Are you running a system with a
/proc filesystem? That makes it easier to find the pathname of each process's executable.– Mark Plotnick
May 25 '16 at 18:13
Are you running a system with a
/proc filesystem? That makes it easier to find the pathname of each process's executable.– Mark Plotnick
May 25 '16 at 18:13
@MarkPlotnick Yes, I am
– mythic
May 25 '16 at 18:49
@MarkPlotnick Yes, I am
– mythic
May 25 '16 at 18:49
add a comment |
3 Answers
3
active
oldest
votes
In your example you can go with:
pgrep -fc 'sleep 500'
It matches both /bin/sleep 500 and sleep 500.
Or if you want to be more precise:
pgrep -fc 'sleep 500$'
answered May 25 '16 at 21:50
lgagginilgaggini
41026
add a comment |
On GNU system:
$ ps --no-header -C sleep -o args | grep -Ec ' 500( |$)'
2
answered May 25 '16 at 17:08
cuonglmcuonglm
104k24203302
add a comment |
On systems that support a Linux-like /proc:
#!/bin/sh
if [ $# != 2 ]
then
echo usage: "$0" pathname commandline_regexp
exit 1
fi
cd /proc
for p in [0-9]*
do
exe=$(readlink $p/exe 2>/dev/null)
if [ "$exe" = "$1" ] &&
cat $p/cmdline 2>/dev/null | tr '' ' ' | grep -q -- "$2"
then
echo match $p
fi
done
example:
$ sleep 500&
[3] 18280
$ sleep 600&
[4] 18281
$ ./rpgrep /bin/sleep '.*sleep 500 $'
match 18280
$ ./rpgrep /bin/sleep '.*sleep.*00'
match 18280
match 18281
Notes:
- the
2>/dev/nulland the separatecatprocess are used to cope with the possibility that processes may disappear while the script is running.
answered May 25 '16 at 19:43
Mark PlotnickMark Plotnick
18.2k24065
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
In your example you can go with:
pgrep -fc 'sleep 500'
It matches both /bin/sleep 500 and sleep 500.
Or if you want to be more precise:
pgrep -fc 'sleep 500$'
answered May 25 '16 at 21:50
lgagginilgaggini
41026
add a comment |
In your example you can go with:
pgrep -fc 'sleep 500'
It matches both /bin/sleep 500 and sleep 500.
Or if you want to be more precise:
pgrep -fc 'sleep 500$'
answered May 25 '16 at 21:50
lgagginilgaggini
41026
add a comment |
In your example you can go with:
pgrep -fc 'sleep 500'
It matches both /bin/sleep 500 and sleep 500.
Or if you want to be more precise:
pgrep -fc 'sleep 500$'
answered May 25 '16 at 21:50
lgagginilgaggini
41026
In your example you can go with:
pgrep -fc 'sleep 500'
It matches both /bin/sleep 500 and sleep 500.
Or if you want to be more precise:
pgrep -fc 'sleep 500$'
answered May 25 '16 at 21:50
lgagginilgaggini
41026
edited May 25 '16 at 21:56
answered May 25 '16 at 21:50
lgagginilgaggini
41026
answered May 25 '16 at 21:50
lgagginilgaggini
41026
answered May 25 '16 at 21:50
lgagginilgaggini
41026
41026
add a comment |
add a comment |
On GNU system:
$ ps --no-header -C sleep -o args | grep -Ec ' 500( |$)'
2
answered May 25 '16 at 17:08
cuonglmcuonglm
104k24203302
add a comment |
On GNU system:
$ ps --no-header -C sleep -o args | grep -Ec ' 500( |$)'
2
answered May 25 '16 at 17:08
cuonglmcuonglm
104k24203302
add a comment |
On GNU system:
$ ps --no-header -C sleep -o args | grep -Ec ' 500( |$)'
2
answered May 25 '16 at 17:08
cuonglmcuonglm
104k24203302
On GNU system:
$ ps --no-header -C sleep -o args | grep -Ec ' 500( |$)'
2
answered May 25 '16 at 17:08
cuonglmcuonglm
104k24203302
answered May 25 '16 at 17:08
cuonglmcuonglm
104k24203302
answered May 25 '16 at 17:08
cuonglmcuonglm
104k24203302
answered May 25 '16 at 17:08
cuonglmcuonglm
104k24203302
104k24203302
add a comment |
add a comment |
On systems that support a Linux-like /proc:
#!/bin/sh
if [ $# != 2 ]
then
echo usage: "$0" pathname commandline_regexp
exit 1
fi
cd /proc
for p in [0-9]*
do
exe=$(readlink $p/exe 2>/dev/null)
if [ "$exe" = "$1" ] &&
cat $p/cmdline 2>/dev/null | tr '' ' ' | grep -q -- "$2"
then
echo match $p
fi
done
example:
$ sleep 500&
[3] 18280
$ sleep 600&
[4] 18281
$ ./rpgrep /bin/sleep '.*sleep 500 $'
match 18280
$ ./rpgrep /bin/sleep '.*sleep.*00'
match 18280
match 18281
Notes:
- the
2>/dev/nulland the separatecatprocess are used to cope with the possibility that processes may disappear while the script is running.
answered May 25 '16 at 19:43
Mark PlotnickMark Plotnick
18.2k24065
add a comment |
On systems that support a Linux-like /proc:
#!/bin/sh
if [ $# != 2 ]
then
echo usage: "$0" pathname commandline_regexp
exit 1
fi
cd /proc
for p in [0-9]*
do
exe=$(readlink $p/exe 2>/dev/null)
if [ "$exe" = "$1" ] &&
cat $p/cmdline 2>/dev/null | tr '' ' ' | grep -q -- "$2"
then
echo match $p
fi
done
example:
$ sleep 500&
[3] 18280
$ sleep 600&
[4] 18281
$ ./rpgrep /bin/sleep '.*sleep 500 $'
match 18280
$ ./rpgrep /bin/sleep '.*sleep.*00'
match 18280
match 18281
Notes:
- the
2>/dev/nulland the separatecatprocess are used to cope with the possibility that processes may disappear while the script is running.
answered May 25 '16 at 19:43
Mark PlotnickMark Plotnick
18.2k24065
add a comment |
On systems that support a Linux-like /proc:
#!/bin/sh
if [ $# != 2 ]
then
echo usage: "$0" pathname commandline_regexp
exit 1
fi
cd /proc
for p in [0-9]*
do
exe=$(readlink $p/exe 2>/dev/null)
if [ "$exe" = "$1" ] &&
cat $p/cmdline 2>/dev/null | tr '' ' ' | grep -q -- "$2"
then
echo match $p
fi
done
example:
$ sleep 500&
[3] 18280
$ sleep 600&
[4] 18281
$ ./rpgrep /bin/sleep '.*sleep 500 $'
match 18280
$ ./rpgrep /bin/sleep '.*sleep.*00'
match 18280
match 18281
Notes:
- the
2>/dev/nulland the separatecatprocess are used to cope with the possibility that processes may disappear while the script is running.
answered May 25 '16 at 19:43
Mark PlotnickMark Plotnick
18.2k24065
On systems that support a Linux-like /proc:
#!/bin/sh
if [ $# != 2 ]
then
echo usage: "$0" pathname commandline_regexp
exit 1
fi
cd /proc
for p in [0-9]*
do
exe=$(readlink $p/exe 2>/dev/null)
if [ "$exe" = "$1" ] &&
cat $p/cmdline 2>/dev/null | tr '' ' ' | grep -q -- "$2"
then
echo match $p
fi
done
example:
$ sleep 500&
[3] 18280
$ sleep 600&
[4] 18281
$ ./rpgrep /bin/sleep '.*sleep 500 $'
match 18280
$ ./rpgrep /bin/sleep '.*sleep.*00'
match 18280
match 18281
Notes:
- the
2>/dev/nulland the separatecatprocess are used to cope with the possibility that processes may disappear while the script is running.
answered May 25 '16 at 19:43
Mark PlotnickMark Plotnick
18.2k24065
edited May 26 '16 at 14:21
answered May 25 '16 at 19:43
Mark PlotnickMark Plotnick
18.2k24065
answered May 25 '16 at 19:43
Mark PlotnickMark Plotnick
18.2k24065
answered May 25 '16 at 19:43
Mark PlotnickMark Plotnick
18.2k24065
18.2k24065
add a comment |
add a comment |
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Are you running a system with a
/procfilesystem? That makes it easier to find the pathname of each process's executable.– Mark Plotnick
May 25 '16 at 18:13
@MarkPlotnick Yes, I am
– mythic
May 25 '16 at 18:49